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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Hardest N7 in history
OronSH   24
N a minute ago by awesomeming327.
Source: ISL 2023 N7
Let $a,b,c,d$ be positive integers satisfying \[\frac{ab}{a+b}+\frac{cd}{c+d}=\frac{(a+b)(c+d)}{a+b+c+d}.\]Determine all possible values of $a+b+c+d$.
24 replies
+1 w
OronSH
Jul 17, 2024
awesomeming327.
a minute ago
How can I prove boundness?
davichu   0
3 minutes ago
Source: Evan Chen introduction to functional equations
Solve $f(t^2+u)=tf(t)+f(u)$ over $\mathbb{R}$

Is easy to show that f satisfies Cauchy's functional equation, but I can't find any other property to show that $f$ is linear
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davichu
3 minutes ago
0 replies
Good Permutations in Modulo n
swynca   6
N 5 minutes ago by EVKV
Source: BMO 2025 P1
An integer $n > 1$ is called $\emph{good}$ if there exists a permutation $a_1, a_2, a_3, \dots, a_n$ of the numbers $1, 2, 3, \dots, n$, such that:
$(i)$ $a_i$ and $a_{i+1}$ have different parities for every $1 \leq i \leq n-1$;
$(ii)$ the sum $a_1 + a_2 + \cdots + a_k$ is a quadratic residue modulo $n$ for every $1 \leq k \leq n$.
Prove that there exist infinitely many good numbers, as well as infinitely many positive integers which are not good.
6 replies
swynca
4 hours ago
EVKV
5 minutes ago
Combo problem about regular polygons
NJAX   1
N 9 minutes ago by Titibuuu
Source: 1st TASIMO, Day1 Problem3
$Abdulqodir$ cut out $2024$ congruent regular $n-$gons from a sheet of paper and placed these $n-$gons on the table such that some parts of each of these $n-$gons may be covered by others. We say that a vertex of one of the afore-mentioned $n-$gons is $visible$ if it is not in the interior of another $n-$gon that is placed on top of it. For any $n>2$ determine the minimum possible number of visible vertices.

Proposed by David Hrushka, Slovakia
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NJAX
May 18, 2024
Titibuuu
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Double Sum
P162008   2
N an hour ago by soryn
Compute the value of $\Omega = \sum_{m=0}^{\infty} \sum_{n=0}^{\infty} \frac{\left(\frac{1}{4}\right)^{m+n}}{(2m + 1)(m + n + 1)}.$
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P162008
Yesterday at 9:31 AM
soryn
an hour ago
Combination
aria123   1
N 2 hours ago by aria123
Prove that three squares of side length $4$ cannot completely cover a square of side length $5$, if the three smaller squares do not overlap in their interiors (i.e., they may touch at edges or corners, but no part of one lies over another).
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aria123
Apr 15, 2025
aria123
2 hours ago
Inequalities
sqing   0
3 hours ago
Let \( x, y \geq  \frac{3}{2}  \). Prove that
$$ \frac{2}{1+xy} + x + y \geq  \frac{x}{y} + \frac{y}{x}+ \frac{21}{13}$$Let \( x, y \geq 2  \). Prove that
$$ \frac{2}{1+xy} + x + y \geq  \frac{x}{y} + \frac{y}{x}+ \frac{12}{5}$$Let \(0< x, y \leq \frac{3}{2}   \). Prove that
$$ \frac{2}{1+xy} + x + y \leq  \frac{x}{y} + \frac{y}{x}+\frac{21}{13}$$Let \(0< x, y \leq 2   \). Prove that
$$ \frac{2}{1+xy} + x + y \leq  \frac{x}{y} + \frac{y}{x}+\frac{12}{5}$$
0 replies
sqing
3 hours ago
0 replies
Number theory
MathsII-enjoy   2
N 3 hours ago by MathsII-enjoy
$Find$ $all$ $integers$ $n$ $such$ $that$ $n-1$ $and$ $\frac{n(n+1)}{2}$ $is$ $a$ $perfect$ $number$.
2 replies
MathsII-enjoy
Today at 5:21 AM
MathsII-enjoy
3 hours ago
Sequence
lgx57   5
N 3 hours ago by lgx57
$a_1=1,a_{n+1}=a_n+\frac{1}{a_n}$. Find the general term of $\{a_n\}$.
5 replies
lgx57
5 hours ago
lgx57
3 hours ago
set of sum of three or fewer powers of 2, 2024 TMC AIME Mock #13
parmenides51   5
N 3 hours ago by vincentwant
Let $S$ denote the set of all positive integers that can be expressed as a sum of three or fewer powers of $2$. Let $N$ be the smallest positive integer that cannot be expressed in the form $a-b$, where $a, b \in S$. Find the remainder when $N$ is divided by $1000$.
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parmenides51
Yesterday at 8:16 PM
vincentwant
3 hours ago
trigonogeometry 2024 TMC AIME Mock #15
parmenides51   3
N 3 hours ago by franklin2013
Let $\vartriangle ABC$ have angles $ \alpha, \beta$ and $\gamma$ such that $\cos (\alpha) = \frac1 3$ and $\cos (\beta) = \frac{1}{17}$ . Moreover, suppose that the product of the side lengths of the triangle is equal to its area. Let $(ABC)$ denote the circumcircle of $ABC$. Let $AO$ intersect $(BOC)$ at $D$, $BO$ intersect $(COA)$ at $ E$, and $CO$ intersect $(AOB)$ at $F$. If the area of $DEF$ can be written as $\frac{p\sqrt{r}}{q}$ for relatively prime integers $p$ and $q$ and squarefree $r$, find the sum of all prime factors of $q$, counting multiplicities (so the sum of prime factors of $48$ is $2 + 2 + 2 + 2 + 3 = 11$), given that $q$ has $30$ divisors.
3 replies
parmenides51
Yesterday at 8:22 PM
franklin2013
3 hours ago
Max and min of a/5+b/4+c/3+d/2 under a/4+b/3+c/2+d=1/2 and a^2/7+b^2/5+c^2/3+...
tom-nowy   1
N 4 hours ago by steve4916
Let $a, b, c, d$ be real numbers satisfying the following two conditions:
\begin{align*}
&\frac{a}{4}+\frac{b}{3}+\frac{c}{2}+d=\frac{1}{2}, \\
&\frac{a^2}{7}+\frac{b^2}{5}+\frac{c^2}{3}+d^2 + \frac{ab}{3}+\frac{2ac}{5}+\frac{ad}{2}
+\frac{bc}{2}+\frac{2bd}{3}+\frac{cd}{2}=\frac{1}{3} .
\end{align*}Find the possible maximum and minimum values of
$$\frac{a}{5}+\frac{b}{4}+\frac{c}{3}+\frac{d}{2}.$$
1 reply
tom-nowy
Today at 11:48 AM
steve4916
4 hours ago
20 fair coins are flipped, N of them land heads 2024 TMC AIME Mock #6
parmenides51   3
N 5 hours ago by ostriches88
$20$ fair coins are flipped. If $N$ of them land heads, find the expected value of $N^2$.
3 replies
parmenides51
Yesterday at 8:05 PM
ostriches88
5 hours ago
Inequalities
sqing   10
N 5 hours ago by sqing
Let $ a,b \in [0 ,1] . $ Prove that
$$\frac{a}{ 1-ab+b }+\frac{b }{ 1-ab+a } \leq 2$$$$ \frac{a}{ 1+ab+b^2 }+\frac{b }{ 1+ab+a^2 }+\frac{ab }{2+ab }  \leq 1$$$$\frac{a}{ 1-ab+b^2 }+\frac{b }{ 1-ab+a^2 }+\frac{1 }{1+ab  }\leq \frac{5}{2}$$$$\frac{a}{ 1-ab+b^2 }+\frac{b }{ 1-ab+a^2 }+\frac{1 }{1+2ab  }\leq \frac{7}{3}$$$$\frac{a}{ 1+ab+b^2 }+\frac{b }{ 1+ab+a^2 } +\frac{ab }{1+ab }\leq \frac{7}{6 }$$
10 replies
sqing
Apr 25, 2025
sqing
5 hours ago
VietNam MO 1968-Pr.2
chien than   1
N Feb 19, 2007 by yetti
$L$ and $M$ are two parallel lines a distance $d$ apart. Given $r$ and $x$, construct a triangle $ABC$, with $A$ on $L$, and $B$ and $C$ on $M$, such that the inradius is $r$, and angle $A = x$. Calculate angles $B$ and $C$ in terms of $d$, $r$ and $x$. If the incircle touches the side $BC$ at $D$, find a relation between $BD$ and $DC$
1 reply
chien than
Feb 18, 2007
yetti
Feb 19, 2007
VietNam MO 1968-Pr.2
G H J
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chien than
975 posts
#1 • 2 Y
Y by Adventure10, Mango247
$L$ and $M$ are two parallel lines a distance $d$ apart. Given $r$ and $x$, construct a triangle $ABC$, with $A$ on $L$, and $B$ and $C$ on $M$, such that the inradius is $r$, and angle $A = x$. Calculate angles $B$ and $C$ in terms of $d$, $r$ and $x$. If the incircle touches the side $BC$ at $D$, find a relation between $BD$ and $DC$
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yetti
2643 posts
#2 • 2 Y
Y by Adventure10, Mango247
$\rho = IA = \frac{r}{\cos \frac{A}{2}}$ is given, A is one of the 2 intersections of the line L and with circle $(I, \rho).$ Tangents to the incircle from A meet the line M at B, C. The circumcircle of the $\triangle IBC$ passes through the A-excenter $I_{a}$ of the $\triangle ABC$ and also through its reflection $I_{a}' \in ID$ in the perpendicular bisector of the side BC. Power of D to this circumcircle is $DB \cdot DC = DI \cdot DI_{a}' = rr_{a}.$ The incircle (I, r) and A-excircxle $(I_{a}, r_{a})$ are centrally similar with center A and coefficient $\frac{r}{r_{a}}= \frac{d-2r}{d},$ where d is the A-altitude of the $\triangle ABC.$ Hence $DB \cdot DC = rr_{a}= \frac{r^{2}d}{d-2r}.$ But

$\frac{r}{\tan \frac{B}{2}}\cdot \frac{r}{\tan \frac{C}{2}}= DB \cdot DC = \frac{r^{2}d}{d-2r},\ \ \ \tan \frac{B}{2}\tan \frac{C}{2}= \frac{d-2r}{d}$

which is power of the line L to the circle (I, r). On the other hand,

$\tan \frac{A}{2}\tan \frac{B}{2}+\tan \frac{B}{2}\tan \frac{C}{2}+\tan \frac{C}{2}\tan \frac{A}{2}= 1$

$\tan \frac{B}{2}+\tan \frac{C}{2}= \frac{1-\tan \frac{B}{2}\tan \frac{C}{2}}{\tan \frac{A}{2}}= \frac{2r}{d \tan \frac{A}{2}}$

which yields a quadratic equation for $\tan \frac{B}{2},\ \tan \frac{C}{2}$ with roots

$\tan \frac{B}{2},\ \tan \frac{C}{2}= \frac{r}{d \tan \frac{A}{2}}\left(1 \pm \sqrt{1-\frac{d(d-2r)}{r^{2}}\tan^{2}\frac{A}{2}}\right)$
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