Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Inspired by old results
sqing   0
a few seconds ago
Source: Own
Let $ a,b,c>0 $ and $ a+b+c=3. $ Prove that
$$ \frac{2}{a}+\frac {2}{ab}+\frac{1}{abc}\geq  4$$$$ \frac{1}{a}+\frac {1}{ab}+\frac{2}{abc}\geq  2+\sqrt 3$$$$ \frac{3}{a}+\frac {3}{ab}+\frac{1}{abc}\geq\frac {7+\sqrt {13}}{2}$$$$ \frac{1}{a}+\frac {1}{ab}+\frac{3}{abc}\geq\frac {5+\sqrt {21}}{2}$$$$ \frac{1}{a}+\frac {1}{ab}+\frac{4}{abc}\geq  3+2\sqrt 2$$
0 replies
sqing
a few seconds ago
0 replies
gcd (a^n+b,b^n+a) is constant
EthanWYX2009   80
N 10 minutes ago by santhoshn
Source: 2024 IMO P2
Determine all pairs $(a,b)$ of positive integers for which there exist positive integers $g$ and $N$ such that
$$\gcd (a^n+b,b^n+a)=g$$holds for all integers $n\geqslant N.$ (Note that $\gcd(x, y)$ denotes the greatest common divisor of integers $x$ and $y.$)

Proposed by Valentio Iverson, Indonesia
80 replies
EthanWYX2009
Jul 16, 2024
santhoshn
10 minutes ago
Benelux fe
ErTeeEs06   7
N 12 minutes ago by Rayanelba
Source: BxMO 2025 P1
Does there exist a function $f:\mathbb{R}\to \mathbb{R}$ such that $$f(x^2+f(y))=f(x)^2-y$$for all $x, y\in \mathbb{R}$?
7 replies
ErTeeEs06
an hour ago
Rayanelba
12 minutes ago
AZE JBMO TST
IstekOlympiadTeam   6
N 21 minutes ago by Namisgood
Source: AZE JBMO TST
Find all non-negative solutions to the equation $2013^x+2014^y=2015^z$
6 replies
IstekOlympiadTeam
May 2, 2015
Namisgood
21 minutes ago
No more topics!
(con)cyclic wanted, projections of vertices on medians related
parmenides51   3
N Aug 1, 2020 by parmenides51
Source: 2014 Saudi Arabia GMO TST day I p1
Let $ABC$ be a triangle with $\angle A < \angle B \le  \angle C$, $M$ and $N$ the midpoints of sides $CA$ and $AB$, respectively, and $P$ and $Q$ the projections of $B$ and $C$ on the medians $CN$ and $BM$, respectively. Prove that the quadrilateral $MNPQ$ is cyclic.
3 replies
parmenides51
Jul 31, 2020
parmenides51
Aug 1, 2020
(con)cyclic wanted, projections of vertices on medians related
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G H BBookmark kLocked kLocked NReply
Source: 2014 Saudi Arabia GMO TST day I p1
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parmenides51
30632 posts
#1 • 1 Y
Y by dchenmathcounts
Let $ABC$ be a triangle with $\angle A < \angle B \le  \angle C$, $M$ and $N$ the midpoints of sides $CA$ and $AB$, respectively, and $P$ and $Q$ the projections of $B$ and $C$ on the medians $CN$ and $BM$, respectively. Prove that the quadrilateral $MNPQ$ is cyclic.
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Awesome_guy
862 posts
#2 • 2 Y
Y by Mathlete2017, Mango247
The given angle conditions imply no configuration issues. Let medians $BM$ and $CN$ intersect at centroid $R$. Note that we wish to prove $RP\cdot RN = RQ \cdot RM$. Since $\angle CQB = \angle CPB=90^{\circ}$, $CBPQ$ is cyclic. PoP with respect to the circumcircle of $CBPQ$, yields $RP = \frac{RQ\cdot RB}{RC}$ and $RQ = \frac{RP\cdot RC}{RB}$. Thus we wish to prove $$\frac{RQ\cdot RB}{RC}\cdot RN = \frac{RP\cdot RC}{RB} \cdot RM \implies RB^2\cdot RQ \cdot RN = RC^2 \cdot RP \cdot RM.$$Note that $\triangle CRQ \sim \triangle BRP\implies \frac{CR}{RQ} = \frac{BR}{RP}$, thus we wish to prove $RB\cdot RN = RC \cdot RM$. This is true, since $RN = \frac{RC}{2}$ and $RM=\frac{RB}{2}$. $\blacksquare$
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dchenmathcounts
2443 posts
#3 • 1 Y
Y by Mathlete2017
Thanks for the good problems, parmenides51 - I swear half of my geometry handouts would be barren of examples/exercises if it weren't for the problems you post.

Solution

I just want to note that the weird angle conditions do not matter - my solution (and GeoGebra) do not care about configurations.
This post has been edited 1 time. Last edited by dchenmathcounts, Jul 31, 2020, 11:12 PM
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parmenides51
30632 posts
#4 • 3 Y
Y by Mathlete2017, dchenmathcounts, Inconsistent
all the problems that I post, are always mentioned their source (either a magazine or a contest)
there are a few problems that I have posted without source where the aops' admins are to blame for losing the source as they moved them from HSO to HSM and the source field was lost (as HSM has no source field)

I am glad that someone uses them, to provide a different problem set from the well known problems, as many Russian Constests are a lot worthy


Edit: If there is any problem posted in aops by me sourceless, just send me the link (PM) to search in my page for the correct source
This post has been edited 3 times. Last edited by parmenides51, Aug 2, 2020, 2:46 PM
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