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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Geometry
Whatisthepurposeoflife   0
37 minutes ago
Source: Lithuania TST 2013
From the point of intersection of the bisectors of the acute triangle ABC (where AB > AC), the base of the perpendicular descending from the point of intersection of the bisectors of the acute triangle ABC to the side BC is the point D. Find the ratio BD : BA if AD is the bisector of the angle BAC.
0 replies
Whatisthepurposeoflife
37 minutes ago
0 replies
Sets with ab+1-closure
pieater314159   28
N 40 minutes ago by john0512
Source: ELMO 2019 Problem 5, 2019 ELMO Shortlist N3
Let $S$ be a nonempty set of positive integers such that, for any (not necessarily distinct) integers $a$ and $b$ in $S$, the number $ab+1$ is also in $S$. Show that the set of primes that do not divide any element of $S$ is finite.

Proposed by Carl Schildkraut
28 replies
pieater314159
Jun 25, 2019
john0512
40 minutes ago
Zack likes Moving Points
pinetree1   72
N 2 hours ago by endless_abyss
Source: USA TSTST 2019 Problem 5
Let $ABC$ be an acute triangle with orthocenter $H$ and circumcircle $\Gamma$. A line through $H$ intersects segments $AB$ and $AC$ at $E$ and $F$, respectively. Let $K$ be the circumcenter of $\triangle AEF$, and suppose line $AK$ intersects $\Gamma$ again at a point $D$. Prove that line $HK$ and the line through $D$ perpendicular to $\overline{BC}$ meet on $\Gamma$.

Gunmay Handa
72 replies
pinetree1
Jun 25, 2019
endless_abyss
2 hours ago
Find all primes of the form n^n + 1 less than 10^{19}
Math5000   2
N 2 hours ago by SomeonecoolLovesMaths
Find all primes of the form $n^n + 1$ less than $10^{19}$

The first two primes are obvious: $n = 1, 2$ yields the primes $2, 5$. After that, it is clear that $n$ has to be even to yield an odd number.

So, $n = 2k \implies p = (2k)^{2k} + 1 \implies p-1 = (2k)^{k^2} = 2^{k^2}k^{k^2}$. All of these transformations don't seem to help. Is there any theorem I can use? Or is there something I'm missing?

2 replies
Math5000
Oct 15, 2019
SomeonecoolLovesMaths
2 hours ago
IMO ShortList 2002, geometry problem 1
orl   47
N 2 hours ago by Avron
Source: IMO ShortList 2002, geometry problem 1
Let $B$ be a point on a circle $S_1$, and let $A$ be a point distinct from $B$ on the tangent at $B$ to $S_1$. Let $C$ be a point not on $S_1$ such that the line segment $AC$ meets $S_1$ at two distinct points. Let $S_2$ be the circle touching $AC$ at $C$ and touching $S_1$ at a point $D$ on the opposite side of $AC$ from $B$. Prove that the circumcentre of triangle $BCD$ lies on the circumcircle of triangle $ABC$.
47 replies
orl
Sep 28, 2004
Avron
2 hours ago
2^2^n+2^2^{n-1}+1-Iran 3rd round-Number Theory 2007
Amir Hossein   5
N 2 hours ago by SomeonecoolLovesMaths
Prove that $2^{2^{n}}+2^{2^{{n-1}}}+1$ has at least $n$ distinct prime divisors.
5 replies
Amir Hossein
Jul 28, 2010
SomeonecoolLovesMaths
2 hours ago
This problem has unintended solution, found by almost all who solved it :(
mshtand1   5
N 3 hours ago by iliya8788
Source: Ukrainian Mathematical Olympiad 2025. Day 2, Problem 11.7
Given a triangle \(ABC\), an arbitrary point \(D\) is chosen on the side \(AC\). In triangles \(ABD\) and \(CBD\), the angle bisectors \(BK\) and \(BL\) are drawn, respectively. The point \(O\) is the circumcenter of \(\triangle KBL\). Prove that the second intersection point of the circumcircles of triangles \(ABL\) and \(CBK\) lies on the line \(OD\).

Proposed by Anton Trygub
5 replies
mshtand1
Mar 14, 2025
iliya8788
3 hours ago
3 var inquality
sqing   1
N 3 hours ago by hashtagmath
Source: Own
Let $ a,b,c>0 $ and $ \dfrac{a}{bc}+\dfrac{2b}{ca}+\dfrac{5c}{ab}\leq 12.$ Prove that$$ a^2+b^2+c^2\geq 1$$
1 reply
sqing
Apr 6, 2025
hashtagmath
3 hours ago
a_n >= 1/n if a_{n+1}^2 + a_{n+1} = a_n, a_1=1 , a_i>=0
parmenides51   11
N 3 hours ago by richrow12
Source: Canadian Junior Mathematical Olympiad - CJMO 2020 p1
Let $a_1, a_2, a_3, . . .$ be a sequence of positive real numbers that satisfies $a_1 = 1$ and $a^2_{n+1} + a_{n+1} = a_n$ for every natural number $n$. Prove that $a_n  \ge \frac{1}{n}$ for every natural number $n$.
11 replies
parmenides51
Jul 15, 2020
richrow12
3 hours ago
Don't bite me for this straightforward sequence
Assassino9931   4
N 4 hours ago by RagvaloD
Source: Bulgaria National Olympiad 2025, Day 1, Problem 1
Determine all infinite sequences $a_1, a_2, \ldots$ of real numbers such that
\[ a_{m^2 + m + n} = a_{m}^2 + a_m + a_n\]for all positive integers $m$ and $n$.
4 replies
Assassino9931
Today at 1:47 PM
RagvaloD
4 hours ago
Orthocenter config once again
Assassino9931   4
N 4 hours ago by cj13609517288
Source: Bulgaria National Olympiad 2025, Day 2, Problem 4
Let \( ABC \) be an acute triangle with \( AB < AC \), midpoint $M$ of side $BC$, altitude \( AD \) (\( D \in BC \)), and orthocenter \( H \). A circle passes through points \( B \) and \( D \), is tangent to line \( AB \), and intersects the circumcircle of triangle \( ABC \) at a second point \( Q \). The circumcircle of triangle \( QDH \) intersects line \( BC \) at a second point \( P \). Prove that the lines \( MH \) and \( AP \) are perpendicular.
4 replies
Assassino9931
Today at 1:53 PM
cj13609517288
4 hours ago
a functional equation on positive reals
littletush   10
N 4 hours ago by Frd_19_Hsnzde
Source: Czech and Slovak third round,2004,p6
Find all functions $f:\mathbb R^+ \rightarrow \mathbb R^+$ such that for all positive real numbers $x,y$,
\[x^2[f(x)+f(y)]=(x+y)f(yf(x)).\]
10 replies
littletush
Mar 3, 2012
Frd_19_Hsnzde
4 hours ago
Set with a property
socrates   4
N 4 hours ago by sadat465
Let $n\in \Bbb{N}, n \geq 4.$ Determine all sets $ A = \{a_1, a_2, . . . , a_n\} \subset \Bbb{N}$ containing $2015$ and having the property that $ |a_i - a_j|$ is prime, for all distinct $i, j\in \{1, 2, . . . , n\}.$
4 replies
socrates
May 29, 2015
sadat465
4 hours ago
Number Theory Chain!
JetFire008   21
N 4 hours ago by Primeniyazidayi
I will post a question and someone has to answer it. Then they have to post a question and someone else will answer it and so on. We can only post questions related to Number Theory and each problem should be more difficult than the previous. Let's start!

Question 1
21 replies
JetFire008
Yesterday at 7:14 AM
Primeniyazidayi
4 hours ago
Kosovo MO 2021 Grade 10, Problem 4
geometry6   10
N Jul 2, 2021 by lneis1
Let $M$ be the midpoint of segment $BC$ of $\triangle ABC$. Let $D$ be a point such that $AD=AB$, $AD\perp AB$ and points $C$ and $D$ are on different sides of $AB$. Prove that: $$\sqrt{AB\cdot AC+BC\cdot AM}\geq\frac{\sqrt{2}}{2}CD.$$
10 replies
geometry6
Feb 27, 2021
lneis1
Jul 2, 2021
Kosovo MO 2021 Grade 10, Problem 4
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G H BBookmark kLocked kLocked NReply
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geometry6
304 posts
#1
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Let $M$ be the midpoint of segment $BC$ of $\triangle ABC$. Let $D$ be a point such that $AD=AB$, $AD\perp AB$ and points $C$ and $D$ are on different sides of $AB$. Prove that: $$\sqrt{AB\cdot AC+BC\cdot AM}\geq\frac{\sqrt{2}}{2}CD.$$
This post has been edited 1 time. Last edited by geometry6, Feb 27, 2021, 7:18 PM
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mihaig
7339 posts
#2 • 1 Y
Y by Mango247
Let $A=x+yi,\text{where} \left(y>0\right),B=-1,C=1\implies D=x-y+(x+y+1)i.$ We thus need to prove
$$\sqrt{\left(x^2+y^2+1\right)^2-4x^2}+2\sqrt{x^2+y^2}\geq x^2+y^2+1+2y.$$After squaring, the latter writes as
$$\sqrt{\left(x^2+y^2+1\right)^2-4x^2}\cdot\sqrt{x^2+y^2}\geq y(x^2+y^2+1).$$We square this too and get $\left(x^2+y^2+1\right)^2\geq4(x^2+y^2),$ which is $AM-GM.$ Equality at $x=0,$ i.e. $AB=AC.$
We also get equality at $x^2+y^2=1,$ which makes the angle from $A$ right. I have the strong belief we are talking about Tereshin here.
This post has been edited 1 time. Last edited by mihaig, Feb 27, 2021, 10:58 PM
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mihaig
7339 posts
#3
Y by
I am interested in another approaches, but especially I want to see the official solution.
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geometry6
304 posts
#4
Y by
I tried using Ptolemy's ineq but I couldn't do it, btw @above nice solution.
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mihaig
7339 posts
#5 • 1 Y
Y by Circumcircle
See here my second solution. I once created a problem with a part from this configuration. But it was a locus problem. I liked this one.

Let $A=x+yi,\text{where} \left(y>0\right),B=-1,C=1\implies D=x-y+(x+y+1)i.$ We thus need to prove
$$\sqrt{\left(x^2+y^2+1\right)^2-4x^2}+\sqrt{4x^2+4y^2}\geq x^2+y^2+1+2y.$$If $x=0$ or if $x^2+y^2=1,$ then we clearly have equality. Otherwise, since
$$\left(\left(x^2+y^2+1\right)^2,4y^2\right) \text{strictly majorize} \left(\left(x^2+y^2+1\right)^2-4x^2,4x^2+4y^2\right),\text{then by Karamata}$$$$\sqrt{\left(x^2+y^2+1\right)^2-4x^2}+\sqrt{4x^2+4y^2}>\sqrt{\left(x^2+y^2+1\right)^2}+\sqrt{4y^2}= x^2+y^2+1+2y.$$The proof is complete. Equality if and only if $AB=AC$ or $AB\perp AC.$
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itslumi
284 posts
#6 • 1 Y
Y by Mango247
i heard that there exists a " geometrical
" solution
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Circumcircle
68 posts
#7 • 3 Y
Y by geometry6, mihaig, Leartia
Let $E$ be a point such that $EA=AC$, $EA$ perpendicular to $AC$, and $B$ and $E$ on different sides with respect to $AC$.

$AD=AB$, $AC=AE$, $\angle DAC = 90 + \angle BAC = \angle BAE$ $\Rightarrow$ $\bigtriangleup DAC \cong \bigtriangleup BAE$ $\Rightarrow CD=BE$...(1).

Let $A'$ be the reflection of $A$ with respect to point $M$. From this, we have that $ABA'C$ is parallelogram $\Rightarrow AC=BA'$ and $\angle ABA' = 180 - \angle BAC$.

$AD=AB$, $AE=AC=BA'$, $\angle DAE = 360 - \angle DAB - \angle BAC - \angle CAE = 360 - 90 - \angle BAC - 90 = 180 - \angle BAC = \angle ABA'$. $\Rightarrow \bigtriangleup DAE \cong \bigtriangleup ABA'$ $\Rightarrow DE= AA' = 2AM$...(2).

From Pythagorean Theorem in $\bigtriangleup DAB$ and $\bigtriangleup EAC$, we can easily find that $DB=AB\cdot\sqrt{2}$ and $EC=AC\cdot\sqrt{2}$...(3).

From here, we use Ptolemy's inequality for quadrilateral $DECB$ and we have that $DB\cdot CE + BC\cdot DE \ge DC\cdot BE$ ...(4).

Substituting (1), (2), and (3) in (4), we have that $2AB\cdot AC + 2BC\cdot AM \ge CD^2$.


The conclusion follows.

Motivation to this solution: The LHS is symmetrical wrt to $B$ and $C$, so we try to take advantage of that.
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mihaig
7339 posts
#8 • 1 Y
Y by Circumcircle
Beautiful.
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mihaig
7339 posts
#9 • 2 Y
Y by Circumcircle, Mango247
At equality, if we fix $B$ and $C$ then $A$ describes the union of a line and a circle.
This post has been edited 1 time. Last edited by mihaig, Mar 3, 2021, 3:31 PM
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Wictro
118 posts
#10 • 2 Y
Y by Circumcircle, Leartia
Consider the point $E$, defined just like in post #7. Furthermore, let $X$ be the point where the A-Symmedian meets $(ABC)$. It is well known that $X$ lies on the A-Apollonian circle, so $XB/XC = AB/AC = AD/AE$. This, combined with the fact that $\angle{BXC} = \angle{DAE} = 180 - \angle{BAC}$, gives that $\triangle{BXC} \sim \triangle{DAE}$.
Now the simple length relations $DE/BC = AD/BX = AB/BX = AM/MC = 2AM/BC$ give that $DE = 2AM$.
Ptolemy on $BDEC$ finishes the problem since $BE = DC, BD = \sqrt{2}AB, CE = \sqrt{2}AC$.
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lneis1
243 posts
#11
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