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An arbitrary triangle ABC with orthocenter
is given. The inner and external bisectors of angle
intersect the line
at points
and
, respectively. Two circles are considered:
the circumcircle of the triangle
,
having segment
as it's diameter.
1. Let point
be such that
is the angle bisector of the triangle
. Prove that
is the external bisector of the same triangle.
2. Let
be a point of intersection of the circles
and
such that
and
lie on opposite sides wrt line
. Prove that the point
lies at the alitude
of the triangle
.
3. Let
be a point of intersection of the circles
and
such that the points
and
lie on the same side wrt line
. Prove that point
lies on the median
.
4. Prove that the tangent to the circle
and
at the point of intersection with the median
intersects the line
at the midpoint of the segment
.









1. Let point




2. Let









3. Let








4. Prove that the tangent to the circle





This post has been edited 3 times. Last edited by parmenides51, Mar 4, 2021, 9:51 PM