[/quote]
,
![$P \in \mathbb R[x,y]$](http://latex.artofproblemsolving.com/8/a/0/8a0576299e976c51607959fb68c7c742b2a49c6a.png)
with ![$P \not\in \mathbb R[x] \cup \mathbb R[y]$](http://latex.artofproblemsolving.com/a/f/7/af71ba8c643d5bd8a2928fa6714ccd91713bd641.png)
and 
homeomorphismes of 
,
is an homoemorphisme too.
on the diagonal 
of a given rectangle 
,
.
is the intersection point between 
and the parallel line to 
that contains 
.
is equilateral if and only if 
checkered board is cut into several squares with integer side length. The size of a square is it's side length.
such that 
is divisible by 
,
is divisible by 
,
is divisible by 
.
?
and a positive integer 
is given.
and for each 
![\[f_n(k)=\frac{a_n+\dots+a_{k+1}}{n-k}-\frac{a_k+\dots+a_1}{k}\]](http://latex.artofproblemsolving.com/0/4/1/041f80cf63f17c0f62c166021af474a5d305eb87.png)
Then for every integer 
the condition![\[a_{n+1}=\max_{0\leq k<n}(f_n(k))\]](http://latex.artofproblemsolving.com/b/1/f/b1f5aff787de8fc9c113cf8441a6b2900a19f24f.png)
is satisfied. Prove that this sequence must be eventually constant.
be a positive integer. We are given a 
board whose unit squares are colored in black and white in such way that starting with the top left square, every third diagonal is colored in black and the rest of the board is in white. In one move, one can take a 
square and change the color of all its squares in such way that white squares become orange, orange ones become black and black ones become white. Find all 
flips (if 
)
![$Q\in \{-1,1,0\}[x]$](http://latex.artofproblemsolving.com/b/4/0/b404c8d6415aaf3d4442cc5381f582c1f8f8b996.png)
with 
.![$\exists P \in \mathbb Z[x]$](http://latex.artofproblemsolving.com/a/2/e/a2e67dd74df9971ca90d1a5d81c1c8e1f3982276.png)
palindrom with 
?
to 
and city 
has a bidirectional road of lengths 
if and only if 
and 
is a prime number.
and incircle touching 
at 
.
be the antipode of 
in the circumcircle of 
is chosen on the internal angle bisector of 
such that 
.
,
be the midpoint of 
.
for which:
for all 
.
particles on a circle situated at the vertices of a regular 
be the smallest number of collisions after which all particles return to their original positions. Find 
Y by
An acute triangle is a triangle that has all angles less that 
( is a Right Angle). Let 
be a right-angled triangle with 
Let 
be the altitude from 
to 
and let 
be the intersection of the angle bisector of 
with 
Let 
be the altitude from to 
Prove that the circumcircle of 
passes through the midpoint of 
( is a Right Angle). Let 
be a right-angled triangle with 
Let 
be the altitude from 
to 
and let 
be the intersection of the angle bisector of 
with 
Let 
be the altitude from to 
Prove that the circumcircle of 
passes through the midpoint of 
This post has been edited 1 time. Last edited by PEKKA, Jan 19, 2024, 4:17 PM
Reason: latex
Reason: latex
are concyclic. Let 
and let 
Then angle chasing tells us that 
and we're done
be 
.
the angle 
.
.
.
.
,
.
,
is cyclic. 
,
(angles sum in right 
)
because of (1)
is isosceles with base 
cyclic
as 
)
