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k a My Retirement & New Leadership at AoPS
rrusczyk   1573
N Yesterday at 11:40 PM by SmartGroot
I write today to announce my retirement as CEO from Art of Problem Solving. When I founded AoPS 22 years ago, I never imagined that we would reach so many students and families, or that we would find so many channels through which we discover, inspire, and train the great problem solvers of the next generation. I am very proud of all we have accomplished and I’m thankful for the many supporters who provided inspiration and encouragement along the way. I'm particularly grateful to all of the wonderful members of the AoPS Community!

I’m delighted to introduce our new leaders - Ben Kornell and Andrew Sutherland. Ben has extensive experience in education and edtech prior to joining AoPS as my successor as CEO, including starting like I did as a classroom teacher. He has a deep understanding of the value of our work because he’s an AoPS parent! Meanwhile, Andrew and I have common roots as founders of education companies; he launched Quizlet at age 15! His journey from founder to MIT to technology and product leader as our Chief Product Officer traces a pathway many of our students will follow in the years to come.

Thank you again for your support for Art of Problem Solving and we look forward to working with millions more wonderful problem solvers in the years to come.

And special thanks to all of the amazing AoPS team members who have helped build AoPS. We’ve come a long way from here:IMAGE
1573 replies
rrusczyk
Mar 24, 2025
SmartGroot
Yesterday at 11:40 PM
k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

Are you ready to level up with Olympiad training? Registration is open with early bird pricing available for our WOOT programs: MathWOOT (Levels 1 and 2), CodeWOOT, PhysicsWOOT, and ChemWOOT. What is WOOT? WOOT stands for Worldwide Online Olympiad Training and is a 7-month high school math Olympiad preparation and testing program that brings together many of the best students from around the world to learn Olympiad problem solving skills. Classes begin in September!

Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
Our full course list for upcoming classes is below:
All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Mar 2, 2025
0 replies
Table tennis mini-tournament
oVlad   14
N 3 minutes ago by mathfun07
Source: All-Russian MO 2023 Final stage 10.4
There is a queue of $n{}$ girls on one side of a tennis table, and a queue of $n{}$ boys on the other side. Both the girls and the boys are numbered from $1{}$ to $n{}$ in the order they stand. The first game is played by the girl and the boy with the number $1{}$ and then, after each game, the loser goes to the end of their queue, and the winner remains at the table. After a while, it turned out that each girl played exactly one game with each boy. Prove that if $n{}$ is odd, then a girl and a boy with odd numbers played in the last game.

Proposed by A. Gribalko
14 replies
+1 w
oVlad
Apr 23, 2023
mathfun07
3 minutes ago
Counting
weamher   0
14 minutes ago
Source: Own
Consider a $n \times n$ grid. We color the squares with three colors: blue, red, and yellow. Two squares are defined as opposite if they share a vertex but not an edge. A valid coloring is a coloring such that no two squares that are red and blue are opposite each other. Count the number of valid colorings.
0 replies
weamher
14 minutes ago
0 replies
Inequality with a weird sum
prtoi   1
N 16 minutes ago by lbh_qys
Let $a_i$ be positive real numbers such that $a_1+a_2+...+a_n=n$. Prove that: $$\sum_{i=1}^{n}(\frac{a_i^3+1}{a_i^2+1})\ge n$$
1 reply
prtoi
an hour ago
lbh_qys
16 minutes ago
Cyclic Configuration Implies Isosceles
maka_moli   2
N 18 minutes ago by Tsikaloudakis
Given an acute triangle $ABC$, points $D$ and $E$ are in segments $AB$ and $AC$ respectively such that $CD \perp BE$. Let $G$ be the intersection of $CD$ and $BE$ and $F$ be the intersection of $ED$ and $BC$. If $ACGF$ is a cyclic quadrilateral prove that $|FC|=|AC|$
2 replies
maka_moli
Mar 25, 2025
Tsikaloudakis
18 minutes ago
Time Scale Calculus- Dynamical inequalities
ehuseyinyigit   2
N Yesterday at 6:13 PM by ehuseyinyigit
Does Maclaurin's Inequality have a dynamic version in time scale calculus, especially for diamond alpha calculus?
2 replies
ehuseyinyigit
Mar 23, 2025
ehuseyinyigit
Yesterday at 6:13 PM
polynomial with real coefficients
Peter   7
N Yesterday at 5:00 PM by quasar_lord
Source: IMC 1998 day 1 problem 5
Let $P$ be a polynomial of degree $n$ with only real zeros and real coefficients.
Prove that for every real $x$ we have $(n-1)(P'(x))^2\ge nP(x)P''(x)$. When does equality occur?
7 replies
Peter
Nov 1, 2005
quasar_lord
Yesterday at 5:00 PM
Differentiation Marathon!
LawofCosine   190
N Yesterday at 3:28 PM by rchokler
Hello, everybody!

This is a differentiation marathon. It is just like an ordinary marathon, where you can post problems and provide solutions to the problem posted by the previous user. You can only post differentiation problems (not including integration and differential equations) and please don't make it too hard!

Have fun!

(Sorry about the bad english)
190 replies
LawofCosine
Feb 1, 2025
rchokler
Yesterday at 3:28 PM
An interesting question about series
Ayoubgg   2
N Yesterday at 1:56 PM by solyaris
Calculate $\sum_{n=1}^{+\infty} \frac{(-1)^n}{F_n F_{n+2}}$ where $(F_n)$ denotes the Fibonacci sequence.**
2 replies
Ayoubgg
Mar 23, 2025
solyaris
Yesterday at 1:56 PM
Matrix problem
hef4875   2
N Yesterday at 1:02 PM by Filipjack
The matrix \( A = (a_{ij}) \in Mat_p(\mathbb{C}) \) is defined by the conditions
\( a_{12} = a_{23} = \dots = a_{(p-1)p} = 1 \) and \( a_{ij} = 0 \) for a set of indices \( (i,j) \).
Prove that there do not exist nonzero matrices \( B, C \in Mat_p(\mathbb{C}) \) satisfying the equation
\[
(I_p + A)^n = B^n + C^n.
\]$\forall$ $n$ is a postive integer.
2 replies
hef4875
Yesterday at 9:49 AM
Filipjack
Yesterday at 1:02 PM
Prove f(x) >= 0
shangyang   3
N Yesterday at 12:36 PM by solyaris
Let \( f \) be a function that is at least twice differentiable on an open interval containing \( [0, 2\pi] \). Given that
\[
f(0) = f(2\pi) = f'(0) = f'(2\pi) = 0
\]and
\[
f(x) + f''(x) \geq 0, \quad \forall x \in [0,2\pi].
\]Prove that \( f(x) \geq 0 \) for all \( x \in [0,2\pi] \).
3 replies
shangyang
Yesterday at 5:47 AM
solyaris
Yesterday at 12:36 PM
Gaussian integral
soruz   3
N Yesterday at 8:25 AM by Mathzeus1024
Exist a method of calculation for $ \int e^{-x^2}\,dx $, with help of $ e^{i \phi}=cos \phi  + i sin \phi $ and Moivre's formula.
3 replies
soruz
Oct 20, 2013
Mathzeus1024
Yesterday at 8:25 AM
Finding supremum of a weird function
pokoknyaakuimut   4
N Yesterday at 6:56 AM by MihaiT
Find $\text{sup}\{2^{2x}+2^{\frac{1}{2x}}:x\in\mathbb{R}, x<0\}$. Easy to guess that the answer is $1$, but I haven't found the reason yet. :(
4 replies
pokoknyaakuimut
Feb 14, 2025
MihaiT
Yesterday at 6:56 AM
Limit conundrum
MetaphysicalWukong   3
N Yesterday at 4:48 AM by HacheB2031
Source: UNSW
Why is the last statement not true? And how do we know the selected option is true?
3 replies
MetaphysicalWukong
Mar 25, 2025
HacheB2031
Yesterday at 4:48 AM
real analysis
ay19bme   3
N Tuesday at 8:46 PM by ay19bme
...........................
3 replies
ay19bme
Tuesday at 4:19 PM
ay19bme
Tuesday at 8:46 PM
2025 Caucasus MO Juniors P4
BR1F1SZ   0
Yesterday at 12:57 AM
Source: Caucasus MO
In a convex quadrilateral $ABCD$, diagonals $AC$ and $BD$ are equal, and they intersect at $E$. Perpendicular bisectors of $AB$ and $CD$ intersect at point $P$ lying inside triangle $AED$, and perpendicular bisectors of $BC$ and $DA$ intersect at point $Q$ lying inside triangle $CED$. Prove that $\angle PEQ = 90^\circ$.
0 replies
BR1F1SZ
Yesterday at 12:57 AM
0 replies
2025 Caucasus MO Juniors P4
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Source: Caucasus MO
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BR1F1SZ
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In a convex quadrilateral $ABCD$, diagonals $AC$ and $BD$ are equal, and they intersect at $E$. Perpendicular bisectors of $AB$ and $CD$ intersect at point $P$ lying inside triangle $AED$, and perpendicular bisectors of $BC$ and $DA$ intersect at point $Q$ lying inside triangle $CED$. Prove that $\angle PEQ = 90^\circ$.
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