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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

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[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
P>2D
gwen01   2
N 11 minutes ago by Rohit-2006
Source: Baltic Way 1992 #18
Show that in a non-obtuse triangle the perimeter of the triangle is always greater than two times the diameter of the circumcircle.
2 replies
gwen01
Feb 18, 2009
Rohit-2006
11 minutes ago
Symmedian
Pomegranat   0
11 minutes ago
Source: Russian geometry olympiad
In triangle $ABC$, point $M$ is the midpoint of $BC$, $P$ the point of intersection of the tangents at points $B$ and $C$ of the circumscribed circle of $ABC$, $N$ is the midpoint of the segment $MP$. The segment $AN$ meets the circumcircle $ABC$ at the point $Q$. Prove that $\angle PMQ = \angle MAQ$.
0 replies
Pomegranat
11 minutes ago
0 replies
inequality with interesting conditions
Cobedangiu   1
N 13 minutes ago by Cobedangiu
Let $x,y,z>0$:
1 reply
Cobedangiu
14 minutes ago
Cobedangiu
13 minutes ago
Hard geometry proof
radhoan_rikto-   1
N 14 minutes ago by GreekIdiot
Source: BDMO 2025
Let ABC be an acute triangle and D the foot of the altitude from A onto BC. A semicircle with diameter BC intersects segments AB,AC and AD in the points F,E and X respectively.The circumcircles of the triangles DEX and DFX intersect BC in L and N respectively, other than D. Prove that BN=LC.
1 reply
radhoan_rikto-
Apr 25, 2025
GreekIdiot
14 minutes ago
Inspired by JK1603JK
sqing   0
18 minutes ago
Source: Own
Let $ a,b,c $ be reals such that $  abc\neq 0$ and $ a+b+c=0.  $ Prove that
$$\left|\frac{a-b}{c}\right|+k\left|\frac{b-c}{a} \right|+k^2\left|\frac{c-a}{b} \right|\ge 3(k+1)$$Where $ k>0.$
$$\left|\frac{a-b}{c}\right|+2\left|\frac{b-c}{a} \right|+4\left|\frac{c-a}{b} \right|\ge 9$$
0 replies
sqing
18 minutes ago
0 replies
problem interesting
Cobedangiu   9
N 22 minutes ago by Cobedangiu
Let $a=3k^2+3k+1 (a,k \in N)$
$i)$ Prove that: $a^2$ is the sum of $3$ square numbers
$ii)$ Let $b \vdots a$ and $b$ is the sum of $3$ square numbers. Prove that: $b^n$ is the sum of $3$ square numbers
9 replies
Cobedangiu
Yesterday at 5:06 AM
Cobedangiu
22 minutes ago
4-var inequality
RainbowNeos   0
31 minutes ago
Given $a,b,c,d>0$, show that
\[\frac{a}{b}+\frac{b}{c}+\frac{c}{d}+\frac{d}{a}\geq 4+\frac{8(a-c)^2}{(a+b+c+d)^2}.\]
0 replies
1 viewing
RainbowNeos
31 minutes ago
0 replies
Find all integer pairs (m,n) such that 2^n! + 1 | 2^m! + 19
Goblik   0
an hour ago
Find all positive integer pairs $(m,n)$ such that $2^{n!} + 1 | 2^{m!} + 19$
0 replies
+1 w
Goblik
an hour ago
0 replies
Junior Balkan Mathematical Olympiad 2024- P3
Lukaluce   15
N an hour ago by MATHS_ENTUSIAST
Source: JBMO 2024
Find all triples of positive integers $(x, y, z)$ that satisfy the equation

$$2020^x + 2^y = 2024^z.$$
Proposed by Ognjen Tešić, Serbia
15 replies
Lukaluce
Jun 27, 2024
MATHS_ENTUSIAST
an hour ago
AD is Euler line of triangle IKL
VicKmath7   16
N an hour ago by ErTeeEs06
Source: IGO 2021 Advanced P5
Given a triangle $ABC$ with incenter $I$. The incircle of triangle $ABC$ is tangent to $BC$ at $D$. Let $P$ and $Q$ be points on the side BC such that $\angle PAB = \angle BCA$ and $\angle QAC = \angle ABC$, respectively. Let $K$ and $L$ be the incenter of triangles $ABP$ and $ACQ$, respectively. Prove that $AD$ is the Euler line of triangle $IKL$.

Proposed by Le Viet An, Vietnam
16 replies
VicKmath7
Dec 30, 2021
ErTeeEs06
an hour ago
Twin Prime Diophantine
awesomeming327.   22
N an hour ago by MATHS_ENTUSIAST
Source: CMO 2025
Determine all positive integers $a$, $b$, $c$, $p$, where $p$ and $p+2$ are odd primes and
\[2^ap^b=(p+2)^c-1.\]
22 replies
awesomeming327.
Mar 7, 2025
MATHS_ENTUSIAST
an hour ago
Inequality with 3 variables and a special condition
Nuran2010   3
N an hour ago by sqing
Source: Azerbaijan Al-Khwarizmi IJMO TST 2024
For positive real numbers $a,b,c$ we have $3abc \geq ab+bc+ca$.
Prove that:

$\frac{1}{a^3+b^3+c}+\frac{1}{b^3+c^3+a}+\frac{1}{c^3+a^3+b} \leq \frac{3}{a+b+c}$.

Determine the equality case.
3 replies
Nuran2010
Tuesday at 5:06 PM
sqing
an hour ago
Inspired by JK1603JK and arqady
sqing   1
N 2 hours ago by sqing
Source: Own
Let $ a,b,c $ be reals such that $  abc\neq 0$ and $ a+b+c=0.  $ Prove that
$$\left|\frac{a-2b}{c}\right|+\left|\frac{b-2c}{a} \right|+\left|\frac{c-2a}{b} \right|\ge \frac{1+3\sqrt{13+16\sqrt{2}}}{2}$$$$\left|\frac{a-3b}{c}\right|+\left|\frac{b-3c}{a}\right|+\left|\frac{c-3a}{b}\right|\ge  1+2\sqrt{13+16\sqrt{2}} $$
1 reply
sqing
2 hours ago
sqing
2 hours ago
An easiest problem ever
Asilbek777   0
2 hours ago
Simplify
0 replies
Asilbek777
2 hours ago
0 replies
Deriving Van der Waerden Theorem
Didier2   3
N Apr 1, 2025 by Didier2
Source: Khamovniki 2023-2024 (group 10-1)
Suppose we have already proved that for any coloring of $\Large \mathbb{N}$ in $r$ colors, there exists an arithmetic progression of size $k$. How can we derive Van der Waerden's theorem for $W(r, k)$ from this?
3 replies
Didier2
Mar 29, 2025
Didier2
Apr 1, 2025
Deriving Van der Waerden Theorem
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G H BBookmark kLocked kLocked NReply
Source: Khamovniki 2023-2024 (group 10-1)
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Didier2
72 posts
#1
Y by
Suppose we have already proved that for any coloring of $\Large \mathbb{N}$ in $r$ colors, there exists an arithmetic progression of size $k$. How can we derive Van der Waerden's theorem for $W(r, k)$ from this?
This post has been edited 2 times. Last edited by Didier2, Mar 29, 2025, 5:28 PM
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Didier2
72 posts
#2
Y by
My attempt to revive the topic).

I found a solution which uses induction on $r$ and Szemeredi's theorem. But this is, obviously, not the intended solution and so I wonder if there exists a solution which uses nothing but relatively elementary methods (maybe even the same induction on $r$, or on $k$). Thank you.
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rrrMath
67 posts
#3 • 1 Y
Y by Didier2
There is a theorem of compactness which states the following:
Let $X=\left\{x_1,x_2,...\right\}$ be a countable set and let A be some set of finite subsets of X.
Suppose for some natural k that for every k coloring of X, A must contain a monochromatic set.
The theorem states that there exists some n (dependent on k) such that for every k coloring of $\left\{x_1,...,x_n\right\}$, A contains a monochromatic set.

For our case we take A to be all arithmetic progressions of size k and $X=\mathbb{N}$, this immediately implies Van der Waerden.

You are welcome to try proving this theorem yourself, it only uses pure combinatorical arguments which don't require any extensive prior knowledge.
This post has been edited 2 times. Last edited by rrrMath, Mar 31, 2025, 10:17 AM
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Didier2
72 posts
#4
Y by
Nice, thank you very much! Can we prove it by contradiction?

If we suppose that for $\forall n$, there $\exists$ a $k$-coloring $C_n$ of $\{x_1, \dots, x_n \}$ such that $A$ doesn't contain monochromatic set. Then by Dirichlet, there must be infinitely many colorings $C_{n_1} \subset C_n$, such that $\{x_1\}$ are all colored in the same way. If repeat the argument for the $C_{n_1}$, then there are infinitely many $C_{n_2} \subset C_{n_1}$, so that the $\{x_1, x_2 \}$ are all colored in the same way. And so on. We will be gradually constructing the coloring of $\Large X$, call it $C$, where for any prefix $\{x_1, x_2, \dots, x_m \}$ there is no monochromatic set in $A$ if we only color this prefix. By the assumption, $C$ contains some monochromatic set $\{x_{a_1}, x_{a_2}, \dots, x_{a_s}\} \in A$. But that means if we only color prefix $\{x_1, x_2, \dots, x_{a_s}\}$ there exists a monochromatic set of $A$, which is a contradiction to the construction of $C$
This post has been edited 2 times. Last edited by Didier2, Apr 1, 2025, 8:30 AM
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