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- #REDIRECT[[Isogonal conjugate]]31 bytes (3 words) - 17:18, 8 May 2021
- '''Isogonal conjugates''' are pairs of [[point]]s in the [[plane]] with respect to a ce == The isogonal theorem ==50 KB (8,743 words) - 18:35, 15 February 2025
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- ==Solution 5 (Isogonal lines with respect to A angle bisesector)== ...x}{AC\sin y}</cmath> and multiplying these together proves the formula for isogonal lines. Hence, we have <cmath>\frac{BE}{15-BE}\cdot \frac{9}{6}=\frac{169}{114 KB (2,340 words) - 16:38, 21 August 2024
- * [[Isogonal conjugates]] and [[Isotomic conjugates]]2 KB (242 words) - 10:16, 18 June 2023
- * The orthocenter and the circumcenter of a triangle are [[isogonal conjugate]]s.6 KB (875 words) - 02:22, 19 February 2025
- *[[Isogonal conjugate]]59 KB (10,203 words) - 04:47, 30 August 2023
- #REDIRECT[[Isogonal conjugate]]31 bytes (3 words) - 17:18, 8 May 2021
- '''Isogonal conjugates''' are pairs of [[point]]s in the [[plane]] with respect to a ce == The isogonal theorem ==50 KB (8,743 words) - 18:35, 15 February 2025
- ''Proof.'' This is fairly easy to prove (as H, O are isogonal conjugates, plus using SAS similarity), but the author lacks time to write === Solution 6 (isogonal conjugates) ===20 KB (3,565 words) - 11:54, 1 May 2024
- <math>L</math> is the isogonal conjugate of a point <math>G</math> with respect to a triangle <math>\trian4 KB (624 words) - 18:19, 15 February 2025
- E lies on the isoptic cubic of ABCD, so it has an isogonal conjugate in ABCD.4 KB (679 words) - 05:42, 1 October 2024
- By isogonal conjugacy, <math>I_aA_1,I_bB_1I_cC_1</math> concur at the Bevan point <math3 KB (553 words) - 09:41, 17 January 2016
- ...pect to triangle <math>BCR</math>, <math>P</math> and <math>Q_1</math> are isogonal conjugates. Therefore, <math>Q_1</math> and <math>Q_2</math> lie on the ref Point <math>Q_1</math> isogonal conjugate of a point <math>P</math> with respect to a triangle <math>\trian5 KB (846 words) - 18:22, 15 February 2025
- == Product of isogonal segments == [[File:Isogonal formulas.png|350px|right]]36 KB (7,195 words) - 09:24, 23 April 2025
- .... Thus points <math>F</math> and <math>M</math> map to each other, and are isogonal. It follows that <math>AF</math> is a symmedian of <math>\triangle{ABC}</ma15 KB (2,516 words) - 17:28, 17 September 2024
- Thus <math>B'</math> is the intersection of the isogonal of <math>B</math> with respect to <math>\angle P</math> Analogously, <math>A'</math> is the intersection of the isogonal of <math>A</math> with respect to <math>\angle P</math>5 KB (767 words) - 22:32, 2 May 2023
- Note that lines <math>AC, AX</math> are isogonal in <math>\triangle ABD</math>, so an inversion centered at <math>A</math> w ...th> are isogonal in <math>\triangle ABD</math> and <math>CD, CE</math> are isogonal in <math>\triangle CDB</math>. From the law of sines it follows that2 KB (354 words) - 10:20, 23 April 2023
- 1 be the isogonal14 KB (2,904 words) - 18:24, 16 May 2017
- -Isogonal -Isogonal6 KB (908 words) - 02:35, 23 January 2024
- Since <math>P</math> is the isogonal conjugate of <math>N</math>, <math>\measuredangle PEA = \measuredangle MEC4 KB (654 words) - 20:13, 12 April 2021
- Since <math>P</math> is the isogonal conjugate of <math>N</math>, <math>\measuredangle PEA = \measuredangle MEC4 KB (620 words) - 22:51, 18 October 2022
- ...= \angle AUF \implies</math> points <math>H</math> and <math>P</math> are isogonal conjugate with respect <math>\triangle UVW.</math>10 KB (1,751 words) - 15:34, 25 November 2022