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Page title matches

• Jugemu Jugemu Goko no Surikire Kaijarisuigyo no Suigyomatsu Unraimatsu Furaimatsu Ku Neru Tokoro ni Sumu Tokoro Yabura Koji no Bura Koji Paipo-paipo Paipo no ShuringanShuringan no Gurindai Gurindai no Ponpokopi no Ponpokona no Chokyumei no Chosuke.
  ...rindai no Ponpokopi no Ponpokona no Chokyumei no Chosuke. That is the full name of a legendary user named duskstream. It is also duskstream's WiFi password
  611 bytes (89 words) - 16:32, 12 July 2022
• Steve has one quarter, two nickels and three pennies. Assuming no items are free, for how many different-priced items could Steve individually pay for with exact change?
  Steve can use no quarters or one quarter, for two possibilities.
  605 bytes (93 words) - 23:18, 1 January 2024
• If no one shares an office, in how many ways can 3 people be assigned to 5 different offices? (Each person gets exactly one office).
  254 bytes (42 words) - 16:52, 28 February 2021
• The table shows the percent of families in Mathville that have $0, 1, 2, 3$ and $4$ or more children. If there are a total of $10,250$ families, how many are there with no children?
  ...there are a total of <math>10,250</math> families, how many are there with no children?
  214 bytes (35 words) - 09:55, 1 August 2022

Page text matches

• Pythagorean Theorem
  ...e [[Primitive Pythagorean Triple]]s, those in which the three numbers have no common [[divisor]], are most interesting. A few of them are: There are no more cases as the hypotenuse has to be greater than the leg.
  5 KB (886 words) - 21:12, 22 January 2024
• Main Page
  During AMC 10/12 testing week, the AoPS Wiki is in read-only mode. No edits can be made.
  2 KB (258 words) - 14:05, 15 November 2023
• 2016 AMC 10A Problems/Problem 13
  ...t Edie and Dee were originally in seats 3 and 4. If this were so, there is no possible position for which Bea can move 2 seats to the right. The same app ==Solution 3 (no casework)==
  2 KB (402 words) - 14:54, 25 June 2023
• Mathematics scholarships
  ...du/%7Ecalculus/prize2005.html website] (NOTE: website from 2005, currently no plans for future competitions) ...ams.org/employment/mimoscow.html website] (NOTE: was not offered in 2010 - no longer funded)
  3 KB (409 words) - 15:02, 28 January 2022
• MATHCOUNTS
  {{Contest Info|name=MATHCOUNTS|region=USA|type=Free Response|difficulty=0.5 - 2.5|breakdown=<u> ...d the last 10 problems can be as hard as some of the Team Round questions. No calculators are allowed during this round.
  10 KB (1,497 words) - 11:42, 10 March 2024
• ICTM Math Contest
  *No calculator ...2 people in 12th grade, no more than 3 people in 11th grade or above, and no more than 4 people in 10th grade or above
  8 KB (1,182 words) - 14:26, 3 April 2024
• Art of Problem Solving
  The accomplishments of every student are unique, and there is no way to measure that success. However, we try to record and celebrate [[AoP
  5 KB (667 words) - 17:09, 3 July 2023
• Resources for mathematics competitions
  ...et-Union math competitions 1961-1986] - Many problems, no solutions. [Site no longer exists. Site has been replaced by a web capture] ...ympiad Math Madness] - Stacks of challenging problems, no solutions. [Site no longer exists. Site has been replaced by a web capture]
  15 KB (2,112 words) - 10:37, 6 May 2024
• William Lowell Putnam Mathematical Competition
  {{Contest Info|name=Putnam|region=USA|type=Proof|difficulty=7 - 9|breakdown=<u>Problem A/B, 1/2 ...average of the range of ranks that would have been attained had there been no tie -- that is, if the top three students tie, they are all awarded a rank
  4 KB (623 words) - 13:11, 20 February 2024
• AMC historical results
  ...IME would remain after the new year. Thus there are two "2021 AMC 10/12s", no "2021 AMC 8", and one “2021 AIME”. All future AMC contests will follow
  17 KB (1,921 words) - 13:00, 28 April 2024
• Inequality
  ...tor, resulting in a positive fraction and thus satisfying the inequality. No value between <math>x=-5</math> and <math>x=\frac{3}{2}</math> (except <mat
  12 KB (1,798 words) - 16:20, 14 March 2023
• United States of America Mathematical Talent Search
  {{Contest Info|name=USAMTS|region=USA|type=Proof|difficulty=3-6|breakdown=<u>Problem 1-2</u>: 3 ...TS) was initiated in the fall of 1989 through a regular column by the same name in Consortium, a quarterly newsletter published by COMAP.
  4 KB (613 words) - 13:08, 18 July 2023
• AMC 8
  ...eir school to take the more challenging [[AMC 10]] exam. However, there is no requirement for the AMC 10 besides the fact that you have to be 10<math>^\t {{Contest Info|name=AMC 8|region=USA|type=Multiple Choice|difficulty=1 - 1.5|breakdown=<u>Probl
  4 KB (558 words) - 22:25, 28 April 2024
• American Invitational Mathematics Examination
  {{Contest Info|name=AIME|region=USA|type=Free Response|difficulty=3-6|breakdown=<u>Problem 1-5< ...0 to 999, inclusive, making guessing almost futile. Wrong answers receive no credit, while correct answers receive one point of credit, making the maxim
  8 KB (1,057 words) - 12:02, 25 February 2024
• American Mathematics Competitions
  ...s vary widely in difficulty. All three of the tests are designed such that no background in [[calculus]], [[analysis]], or any other higher mathematics i
  5 KB (696 words) - 03:47, 24 December 2019
• 2015 IMO Problems
  <math>\mathcal{S}</math>, there is no point <math>P</math> in <math>\mathcal{S}</math> such that
  4 KB (692 words) - 22:33, 15 February 2021
• United States of America Mathematical Olympiad
  {{Contest Info|name=USAMO|region=USA|type=Proof|difficulty=7-9|breakdown=<u>Problem 1/4</u>: 7< ...da. Qualification is based on [[AMC 10]], [[AMC 12]], and [[AIME]] scores. No calculators are allowed on this two day, 9 hour exam (two 4.5 hour sessions
  6 KB (869 words) - 12:52, 20 February 2024
• Joining an ARML team
  ...s team were regular attendees at SDMC. Also, since the 2007 team contained no seniors, the organizers for the 2008 team are not planning on extending inv The coach is Dr. Kent Merryfield, a professor at CSULB. His AoPS user name is Kent Merryfield. Please contact him for further information.
  21 KB (3,500 words) - 18:41, 23 April 2024
• Mu Alpha Theta
  ...into regionals, invitationals, states, and national competitions. There is no need to progress through the levels- you simply register and you can partic
  4 KB (632 words) - 17:09, 11 October 2020
• Factoring
  ...even]], <math>(-b)^n + b^n = 2b^n</math>, rather than 0, so this gives us no useful information.
  3 KB (532 words) - 22:00, 13 January 2024
• Pigeonhole Principle
  # Seven line segments, with lengths no greater than 10 inches, and no shorter than 1 inch, are given. Show that one can choose three of them to r ...n</math> such that it is always possible to arrange the committees so that no senator hates another senator on his or her committee. ([[Pigeonhole Princi
  11 KB (1,985 words) - 21:03, 5 August 2023
• Relatively prime
  ...n) = 1</math>. Equivalently, <math>m</math> and <math>n</math> must have no [[prime]] divisors in common. The positive integers <math>m</math> and <ma
  2 KB (245 words) - 15:51, 25 February 2020
• 1965 AHSME Problems/Problem 40
  ...>x \neq 10</math> and <math>x < -9</math> or <math>x > 3</math>, there are no solutions for <math>x</math>. ...e force and checking each value individually, we can assert that there are no such solutions for <math>x</math>, leaving us with only <math>1</math> solu
  3 KB (571 words) - 00:42, 22 October 2021
• Principle of Inclusion-Exclusion
  .... Compute the number of ways they can arrange themselves in line such that no three consecutive people are in increasing order of height, from front to b
  9 KB (1,703 words) - 07:25, 24 March 2024
• 2020 CIME II Problems/Problem 10
  ...+b</math>; hence <math>a+b</math> is a multiple of <math>c</math> which is no more than <math>2c+6</math>. It follows that <math>a+b\in\{c,2c,3c,4c,5c\}< Case IV) <math>a+b=4c\Rightarrow (4a-1)(4b-1)=65</math> for which there are no solutions.
  2 KB (332 words) - 09:37, 30 December 2021
• Cauchy-Schwarz Inequality
  ...triangle <math>T </math> whose side lengths are all positive integers with no common divisor and determine those integers.
  13 KB (2,048 words) - 15:28, 22 February 2024
• Fermat's Little Theorem
  ...es of the theorem by <math>a</math>. The restated form is nice because we no longer need to restrict ourselves to integers <math>{a}</math> not divisibl
  16 KB (2,675 words) - 10:57, 7 March 2024
• Number theory/Advanced
  ...written as an expansion in the parameter <math>q=e^{2\pi i z}</math> with no negative exponents:
  5 KB (849 words) - 16:14, 18 May 2021
• 1959 IMO Problems/Problem 2
  This tells there that there is no solution for (b), since we must have <math>A^2 \ge 2</math> ...h>x \in \left[\frac{1}{2}, 1\right]</math> is a solution for (a); there is no solution for (b); there is one solution for (c), which is <math>x=\frac{3}{
  3 KB (466 words) - 12:04, 12 April 2024
• 1970 IMO Problems/Problem 6
  ...onsider all possible triangles having these point as vertices. Prove that no more than <math>70 \%</math> of these triangles are acute-angled.
  1 KB (234 words) - 19:26, 14 July 2017
• Divisibility rules
  ...550</math>. Difference: <math>D = 49</math>. <math>A = 50 \cdot D</math>? No!
  8 KB (1,315 words) - 18:18, 2 March 2024
• Triangle
  A '''scalene''' triangle has no congruent sides, and also no congruent angles (this can be proven by the converse of the Hinge Theorem).
  4 KB (628 words) - 17:17, 17 May 2018
• Constructive counting
  ...that each entry is between <math>2</math> and <math>9</math> inclusive and no two consecutive entries are equal?'' ...luding <math>2</math> and <math>9</math>; the key restriction here is that no two boxes right next to each other can have the same number.
  12 KB (1,896 words) - 23:55, 27 December 2023
• Casework
  ...>. But the question mandates that <math>y</math> is positive, so there are no solutions when <math>x \geq 3</math>. Thus, there are <math>68+53=121</math
  5 KB (709 words) - 10:28, 19 February 2024
• Prime number
  ...6</math>; <math>2^{2^6} + 1 = 274177\cdot 67280421310721</math>. In fact, no other Fermat primes have been found to date.
  6 KB (985 words) - 12:38, 25 February 2024
• Complementary counting
  ...use a complementary approach. The total number of positive integers, with no restrictions, is <math>99</math> integers. What we don't want are the multi ...git positive integers. What we don't want are the four-digit integers with no digit that is a two or three, Using a [[Constructive counting | constructiv
  8 KB (1,192 words) - 17:20, 16 June 2023
• Integer
  ...depending on whether <math>a</math> can be divided by <math>b</math> with no remainder.
  2 KB (296 words) - 15:04, 5 August 2022
• Mathematical Kangaroo
  ...he test is worth 4 points, and the remaining problems are worth 5 points. No penalty or partial credit is given to unanswered or incorrectly answered qu ...nutes is given to solve all problems, each with exactly 5 answer choices. No problems require the use of a calculator, and calculators of all types are
  6 KB (936 words) - 15:38, 22 February 2024
• Pi
  ...lementary Chebyshev's estimate <math>D_n\le n^{\sqrt n}\cdot 4^n</math> is no longer sufficient).
  8 KB (1,469 words) - 21:11, 16 September 2022
• Fibonacci sequence
  # Seven line segments, with lengths no greater than 10 inches, and no shorter than 1 inch, are given. Show that one can choose three of them to r
  6 KB (957 words) - 23:49, 7 March 2024
• Fundamental Theorem of Calculus
  ...me <math>{t}</math> is <math>e^{t^2}</math> meters/second. (Yes, probably no object really moves this way, but just pretend.) ''Approximately'' how far
  11 KB (2,082 words) - 15:23, 2 January 2022
• Polygon
  ...ve vertices. Most frequently, one deals with ''simple polygons'' in which no two edges are allowed to intersect. (In fact, the adjective "simple" is al
  2 KB (372 words) - 19:04, 30 May 2015
• 2011 AMC 10B Problems/Problem 4
  Since there are no restrictions on cost paid besides <math>A<B</math>, we can use an example w
  1 KB (249 words) - 13:05, 24 January 2024
• Complex number
  ...e square of a [[real number]] cannot be [[negative]], so this equation has no solutions in the real numbers. However, it is possible to define a number,
  5 KB (860 words) - 15:36, 10 December 2023
• Georgia ARML
  ...RML/Welcome.html Georgia ARML page] - note that the author of this page is no longer, and thus this page is perpetually stuck in 2006. For instance, GA A
  1 KB (186 words) - 11:52, 4 June 2012
• Fermat's Last Theorem
  ...ve [[integers]] <math>a,b,c,n</math> with <math>n \geq 3</math>, there are no solutions to the equation <math>a^n + b^n = c^n</math>.
  3 KB (453 words) - 11:13, 9 June 2023
• Geometry
  *A [[point]] is a geometric structure with no area, length, width, or dimension. Its only property is space. It is said t ...ne]] satisfying a [[linear]] [[function]]. It has length and position, but no other properties. It is one-dimensional. A [[line segment]] means a finite
  3 KB (393 words) - 07:59, 25 September 2020
• Diophantine equation
  ...owever, <math>17</math> will never be a multiple of <math>3</math>, hence, no solutions exist. An equation of form <math>x^4+y^4=z^2</math> has no [[integer]] solutions, as follows:
  9 KB (1,434 words) - 13:10, 20 February 2024
• 1985 IMO Problems/Problem 5
  ==Solution 3 (No Miquel's point)==
  3 KB (496 words) - 13:35, 18 January 2023
• Exponentiation
  ...if a equation has [[parentheses]] or the first one performed when there is no parentheses.
  5 KB (803 words) - 16:25, 10 August 2020
• Riemann Hypothesis
  * The zeta function has no zeros with real part between <math>\frac{1}{2}</math> and 1
  2 KB (425 words) - 12:01, 20 October 2016
• Fundamental Theorem of Algebra
  ...at <math>P(z)</math> is a complex polynomial of degree <math>n</math> with no complex roots; without loss of generality, suppose that <math>P</math> is [
  5 KB (832 words) - 14:22, 11 January 2024
• International Mathematical Olympiad
  {{Contest Info|name=IMO |region=International|type=Proof|difficulty=5.5 - 10|breakdown=<u>Probl There is no official team competition. Unofficially, however, the scores of each team
  3 KB (490 words) - 03:32, 23 July 2023
• Prime Number Theorem
  has no zeros on the line <math>\Re s = 1</math>, and from this deduced <math>\zeta(1+ri)</math> has no zeros was about 25 pages long; Hadamard's
  10 KB (1,729 words) - 19:52, 21 October 2023
• Mock AMC
  ...ular in the months leading up to the actual [[AMC]] competition. There is no guarantee that community members will make Mock AMCs in any given year, but
  51 KB (6,175 words) - 20:58, 6 December 2023
• Permutation
  A permutation in which no object remains in the same place it started is called a [[derangement]].
  3 KB (422 words) - 11:01, 25 December 2020
• Riemann zeta function
  <math>\zeta(s)</math> has no zeros for <math>\Re s > 1</math>. Indeed, suppose this Since the [[gamma function]] has no zeros, it follows that these
  9 KB (1,547 words) - 03:04, 13 January 2021
• Modular arithmetic/Introduction
  ...>3</math>, or <math>4</math> in modulo 5, we give these integers their own name: the '''[[residue class]]es''' modulo 5. In general, for a natural number No, you cannot. Rewriting the question, we see that it asks us to find an inte
  15 KB (2,396 words) - 20:24, 21 February 2024
• Uncountable
  A [[set]] <math>S</math> is said to be '''uncountable''' if there is no [[injection]] <math>f:S\to\mathbb{N}</math>. Assuming the [[Axiom of choice
  2 KB (403 words) - 20:53, 13 October 2019
• Modular arithmetic/Intermediate
  <math>c_i</math> is a member of the set {1, 2, 3}. Since no <math>c_i</math> divides 7, 7 may be factored and <math>7\frac{k_2-k_1}{c_i
  14 KB (2,317 words) - 19:01, 29 October 2021
• Limit
  ...f(x)</math> to be to its limit value. Then the formal definition says that no matter how close we want to be (for ''any'' <math>\epsilon > 0</math>), we ...ghtarrow 0}\frac{1}{x}</math> does not exist, since, in fact, there exists no <math>\epsilon</math> for which there exists <math>\delta</math> satisfying
  7 KB (1,325 words) - 13:51, 1 June 2015
• 2006 AIME I Problems/Problem 13
  Since there is no obvious way to approach this problem, we start by experimenting with small
  10 KB (1,702 words) - 00:45, 16 November 2023
• 2006 AIME I Problems/Problem 10
  ...e [[concave]] hexagonal region of the squares equally (as of yet, there is no substantiation that such would work, and definitely will not work in genera
  4 KB (731 words) - 17:59, 4 January 2022
• 2006 AIME I Problems/Problem 8
  ...6-h^4</math> specifically must be in the form <math>n^2/4</math>. There is no restriction on h as long as it is a positive real number, so all we have to
  5 KB (730 words) - 15:05, 15 January 2024
• 2006 AMC 12B Problems
  ...ams of lemon juice and 386 calories in 100 grams of sugar. Water contains no calories. How many calories are in 200 grams of her lemonade?
  13 KB (2,058 words) - 12:36, 4 July 2023
• 2006 AMC 12A Problems
  <math>(1)</math> No two consecutive integers belong to <math>S</math>. ...th>S</math> contains <math>k</math> elements, then <math>S</math> contains no number less than <math>k</math>.
  15 KB (2,223 words) - 13:43, 28 December 2020
• 2004 AMC 12A Problems
  ...at-granddaughters. How many of Bertha's daughters and grand-daughters have no daughters?
  13 KB (1,953 words) - 00:31, 26 January 2023
• 2003 AMC 12A Problems
  ...rst <math>5</math> letters, no B's in the next <math>5</math> letters, and no C's in the last <math>5</math> letters?
  13 KB (1,955 words) - 21:06, 19 August 2023
• 2001 AMC 12 Problems
  ...est such trip? (Note: Two edges of a tetrahedron are opposite if they have no common endpoint.)
  13 KB (1,957 words) - 12:53, 24 January 2024
• 2003 AMC 12B Problems
  ...is 28 inches wide, but he overlaps each cut by 4 inches to make sure that no grass is missed. he walks at the rate of 5000 feet per hour while pushing t Penniless Pete's piggy bank has no pennies in it, but it has 100 coins, all nickels, dimes, and quarters, whos
  13 KB (1,987 words) - 18:53, 10 December 2022
• 2005 AMC 12B Problems
  ...umbers is <math>221</math>. None of the eight digits is <math>0</math> and no two of them are the same. Which of the following is '''not''' included amon ...nt vertices, each with equal [[probability]]. What is the probability that no two ants arrive at the same vertex?
  12 KB (1,781 words) - 12:38, 14 July 2022
• 2006 AMC 12B Problems/Problem 6
  ...ams of lemon juice and 386 calories in 100 grams of sugar. Water contains no calories. How many calories are in 200 grams of her lemonade?
  978 bytes (145 words) - 13:57, 4 December 2015
• 2006 AMC 12B Problems/Problem 7
  If there was no restriction, there would be 4!=24 ways to sit. However, only 2/4 of the peo
  1 KB (213 words) - 15:33, 9 April 2024
• 2006 AMC 12B Problems/Problem 9
  a. <math>c=2</math>. No such number exists.
  3 KB (409 words) - 17:10, 30 April 2024
• 2006 AMC 12B Problems/Problem 19
  ...8</math>, which is not divisible by <math>4</math>), which means there are no <math>2</math>, <math>4</math>, <math>6</math>, or <math>8</math> year olds
  4 KB (696 words) - 09:47, 10 August 2015
• 2006 AMC 12A Problems/Problem 14
  ...at <math>300p + 210g = 30(10p + 7g)</math> is divisible by <math>30</math> no matter what <math>p</math> and <math>g</math> are, so our answer must be di
  3 KB (442 words) - 03:13, 8 August 2022
• 2006 AMC 12A Problems/Problem 20
  ...to visit <math>D</math> on the plane of <math>ABC</math> last, as there is no way in and out from <math>D</math>.
  5 KB (908 words) - 19:23, 22 September 2022
• 2006 AMC 12A Problems/Problem 25
  <math>(1)</math> No two consecutive [[integer]]s belong to <math>S</math>. ...</math> contains <math>k</math> [[element]]s, then <math>S</math> contains no number less than <math>k</math>.
  8 KB (1,405 words) - 11:52, 27 September 2022
• 2005 AMC 12A Problems/Problem 25
  ...d as many solutions as possible, until it becomes intuitive that there are no more size of triangles left.
  4 KB (498 words) - 00:46, 4 August 2023
• 2005 AMC 12B Problems/Problem 3
  This was just a simple manipulation of the equation. No solving was needed!
  978 bytes (156 words) - 14:14, 14 December 2021
• 2005 AMC 12B Problems/Problem 4
  Here, only the <math>A</math>'s matter... No complicated stuff!
  1 KB (197 words) - 14:16, 14 December 2021
• 2005 AMC 12B Problems/Problem 11
  ==Solution 5 (Quick if no time)==
  4 KB (607 words) - 21:01, 20 May 2023
• 2005 AMC 12B Problems/Problem 15
  ...umbers is <math>221</math>. None of the eight digits is <math>0</math> and no two of them are the same. Which of the following is '''not''' included amon
  2 KB (411 words) - 21:02, 21 December 2020
• 2005 AMC 12B Problems/Problem 17
  As <math>a,b,c,d</math> must all be rational, and there are no powers of <math>3</math> or <math>7</math> in <math>10^{2005}</math>, <math
  1 KB (159 words) - 21:18, 21 December 2020
• 2005 AMC 12B Problems/Problem 23
  No other value of <math>a + b</math> is possible for all members of <math>S</m
  5 KB (786 words) - 16:49, 31 January 2023
• 2005 AMC 12B Problems/Problem 25
  ...nt vertices, each with equal [[probability]]. What is the probability that no two ants arrive at the same vertex? ...choose the 4 vertices that have a cross section as a square, there exists no connecting diagonal.
  10 KB (1,840 words) - 21:35, 7 September 2023
• Root (polynomial)
  ...the interval <math>(r,s)</math>. In particular, if <math>P'(x)</math> has no roots in an interval <math>(a,b)</math>, then <math>P(x)</math> has at most No similar formula exists for quintics or polynomials of any higher degree. Al
  8 KB (1,427 words) - 21:37, 13 March 2022
• Vertical line test
  The vertical line test states that a [[relation]] is a [[function]] if no vertical [[line]] intersects the graph in more than one point.
  659 bytes (114 words) - 10:41, 27 April 2024
• Set
  ...tually imagine those numbers flowing freely inside those curly braces with no preference given to any of them. What matters is that these four numbers ar Since there are no reals such that the square of it is less than 0, that set is the empty set.
  11 KB (2,021 words) - 00:00, 17 July 2011
• 1991 AJHSME Problems
  ...finishing second and <math>1</math> point for finishing third. There are no ties. What is the smallest number of points that a student must earn in th
  17 KB (2,246 words) - 13:37, 19 February 2020
• 2022 USAJMO Problems/Problem 1
  Condition <math>(1)</math> holds if no consecutive terms in <math>a_i</math> are equivalent modulo <math>m</math>,
  4 KB (792 words) - 00:29, 13 April 2024
• 2005 AIME II Problems/Problem 2
  ...6 is <math>{6 \choose3}</math>. After that, the three remaining rolls have no more configurations.
  4 KB (628 words) - 11:28, 14 April 2024
• Empty set
  ...set</math> or <math>\varnothing</math>) is the (unique) [[set]] containing no elements. It is therefore a [[subset]] of every set.
  489 bytes (84 words) - 21:33, 27 February 2020
• Problem solving
  ...dn’t solve a single one. That’s right – I was 0-for-60+. I came away no longer confident that I was good at math. I assumed that most of the other ...I realized that formula sheets are not really math. Memorizing formulas is no more mathematics than memorizing dates is history or memorizing spelling wo
  6 KB (1,039 words) - 17:43, 30 July 2018
• Research Science Institute
  ...na. (To this day, alumni of the program are known as "Rickoids".) RSI's name changed to Research Science Institute in 1987, following Admiral Rickover's ...m the United States. Admission to RSI is extremely competitive. There is no tuition or room-and-board charge to attend RSI. Students in all branches o
  2 KB (284 words) - 16:37, 6 July 2023
• 2005 AIME I Problems
  ...arranges the group in a formation with 7 more rows than columns, there are no members left over. Find the maximum number of members this band can have. .... He wants to stack the eight coins on a table into a single stack so that no two adjacent coins are face to face. Find the number of possible distinguis
  6 KB (983 words) - 05:06, 20 February 2019
• 2005 AIME I Problems/Problem 4
  ...arranges the group in a formation with 7 more rows than columns, there are no members left over. Find the maximum number of members this band can have. ...th>n(n + 7) = 14\cdot 21 = 294 = 17^2 + 5</math>, so this number works and no larger number can. Thus, the answer is <math>\boxed{294}</math>.
  8 KB (1,248 words) - 11:43, 16 August 2022
• 2005 AIME I Problems/Problem 5
  .... He wants to stack the eight coins on a table into a single stack so that no two adjacent coins are face to face. Find the number of possible distinguis ...e a string of tails followed by a string of heads, since after the first H no more tails can appear. The first H can occur in a maximum of eight times di
  5 KB (830 words) - 01:51, 1 March 2023
• 2005 AIME I Problems/Problem 9
  The unit cube at the center of our large cube has no exterior faces, so all of its orientations work.
  4 KB (600 words) - 21:44, 20 November 2023
• 2005 AIME I Problems/Problem 13
  # There are no right angle turns in the particle's path. ...h>3</math> <math>U</math>'s, and <math>2</math> <math>D</math>'s such that no two <math>R</math>'s or <math>U</math>'s are adjacent. The <math>D</math>'s
  5 KB (897 words) - 00:21, 29 July 2022

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