people in the circle

by Pomegranat, May 12, 2025, 3:03 AM

Let $n \geq 5$ people be arranged in a circle, numbered clockwise from $1$ to $n$. These people are eliminated one by one in order, until only one person remains. The elimination follows this rule: among the remaining people, start counting clockwise from the person with the smallest number, and eliminate the $n$-th person in that count. Then, among the remaining people, start counting again from the person with the smallest number and eliminate the $n$-th person. Repeat this process until only one person remains. Let $W(n)$ denote the number of the last remaining person.

For example, when $n = 5$, people are eliminated in the following order: $5, 1, 3, 2$. Thus, $W(5) = 4$. It is known that $W(n) = n - 4$ under certain conditions. Prove that the necessary and sufficient condition for this is that both $n + 1$ and $n/2$ are prime numbers.

Set Partition

by Butterfly, May 12, 2025, 1:06 AM

For the set of positive integers $\{1,2,…,n\}(n\ge 3)$, no matter how its elements are partitioned into two subsets, at least one of the subsets must contain three numbers $a,b,c$ ($a=b$ is allowed) such that $ab=c$. Find the minimal $n$.

Diophantine involving cube

by Sadigly, May 11, 2025, 10:13 PM

Easy inequality...

by Sadigly, May 11, 2025, 9:57 PM

$x,y,z\in\mathbb{R^+}$. If $xyz=1$, then prove the following: $$\sum\frac{x^6+2}{x^3}\geq3(\frac{x}{y}+\frac{y}{z}+\frac{z}{x})$$

hard inequality omg

by tokitaohma, May 11, 2025, 5:24 PM

1. Given $a, b, c > 0$ and $abc=1$
Prove that: $ \sqrt{a^2+1} + \sqrt{b^2+1} + \sqrt{c^2+1} \leq \sqrt{2}(a+b+c) $

2. Given $a, b, c > 0$ and $a+b+c=1 $
Prove that: $ \dfrac{\sqrt{a^2+2ab}}{\sqrt{b^2+2c^2}} + \dfrac{\sqrt{b^2+2bc}}{\sqrt{c^2+2a^2}} + \dfrac{\sqrt{c^2+2ca}}{\sqrt{a^2+2b^2}} \geq \dfrac{1}{a^2+b^2+c^2} $

ISI UGB 2025 P4

by SomeonecoolLovesMaths, May 11, 2025, 11:24 AM

Let $S^1 = \{ z \in \mathbb{C} \mid |z| =1 \}$ be the unit circle in the complex plane. Let $f \colon S^1 \longrightarrow S^2$ be the map given by $f(z) = z^2$. We define $f^{(1)} \colon = f$ and $f^{(k+1)} \colon = f \circ f^{(k)}$ for $k \geq 1$. The smallest positive integer $n$ such that $f^{(n)}(z) = z$ is called the period of $z$. Determine the total number of points in $S^1$ of period $2025$.
(Hint : $2025 = 3^4 \times 5^2$)

Divisibilty...

by Sadigly, May 10, 2025, 9:07 PM

Find all $4$ consecutive even numbers, such that the sum of their squares divides the square of their product.
This post has been edited 1 time. Last edited by Sadigly, Yesterday at 7:50 AM

Old hard problem

by ItzsleepyXD, Apr 25, 2025, 4:15 AM

Let $ABC$ be a triangle and let $O$ be its circumcenter and $I$ its incenter.
Let $P$ be the radical center of its three mixtilinears and let $Q$ be the isogonal conjugate of $P$.
Let $G$ be the Gergonne point of the triangle $ABC$.
Prove that line $QG$ is parallel with line $OI$ .

Points Lying on its Cevian Triangle's Thomson Cubic

by Feuerbach-Gergonne, Jul 19, 2024, 8:46 AM

Given $\triangle ABC$ and a point $P$, let $\triangle DEF$ be the cevian triangle of $P$ with respect to $\triangle ABC$. Let $H$ be the orthocenter of $\triangle ABC$, and denote the isotomic conjugate of $H, P$ with respect to $\triangle ABC$ by $X, Q$, respectively. Let the centroid of $\triangle DEF$ be $M$, and denote the isogonal conjugate of $P$ with respect to $\triangle DEF$ by $R$. Prove that
$$
P, Q, X \text{ are collinear} \iff P, R, M \text{ are collinear}. 
$$or in brief
$$
P \in \text{ K007 of } \triangle ABC \iff P \in \text{ K002 of } \triangle DEF. 
$$
Attachments:
This post has been edited 1 time. Last edited by Feuerbach-Gergonne, Jul 19, 2024, 8:50 AM
Reason: Attachment

The Return of Triangle Geometry

by peace09, Jul 17, 2024, 12:00 PM

Let $N$ be a positive integer. Prove that there exist three permutations $a_1,\dots,a_N$, $b_1,\dots,b_N$, and $c_1,\dots,c_N$ of $1,\dots,N$ such that \[\left|\sqrt{a_k}+\sqrt{b_k}+\sqrt{c_k}-2\sqrt{N}\right|<2023\]for every $k=1,2,\dots,N$.
This post has been edited 1 time. Last edited by peace09, Jul 17, 2024, 12:14 PM
L

"Do not worry too much about your difficulties in mathematics, I can assure you that mine are still greater." - Albert Einstein

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