The Angle Bisector Theorem

by aoum, Mar 16, 2025, 10:06 PM

The Angle Bisector Theorem: A Fundamental Result in Geometry

The Angle Bisector Theorem is a fundamental theorem in Euclidean geometry that describes a relationship between the sides of a triangle and the segments formed by an angle bisector. This theorem is particularly useful in solving geometric problems involving proportionality and triangle ratios.

https://upload.wikimedia.org/wikipedia/commons/thumb/d/d1/Triangle_ABC_with_bisector_AD.svg/240px-Triangle_ABC_with_bisector_AD.svg.png

1. Statement of the Angle Bisector Theorem

In a triangle $ABC$, let the angle bisector of $\angle BAC$ intersect side $BC$ at a point $D$. Then, the Angle Bisector Theorem states:

\[
\frac{AB}{AC} = \frac{BD}{DC}.
\]
In other words, the angle bisector divides the opposite side into two segments that are proportional to the lengths of the other two sides.

Additionally, if the angle bisector is internal (dividing the angle inside the triangle), the following relationships hold:

\[
BD = \frac{AB \cdot BC}{AB + AC}, \quad DC = \frac{AC \cdot BC}{AB + AC}.
\]
2. Proof of the Angle Bisector Theorem

We will prove the theorem using the concept of similar triangles.

Consider $\triangle ABD$ and $\triangle ACD$:

1. Since $\overline{AD}$ is the angle bisector, we have:

\[
\angle BAD = \angle CAD.
\]
2. $\angle ABD = \angle ACD$ (vertically opposite angles are equal).

By the Angle-Angle (AA) Similarity Criterion, we conclude:

\[
\triangle ABD \sim \triangle ACD.
\]
Since the triangles are similar, corresponding side lengths are proportional:

\[
\frac{AB}{AC} = \frac{BD}{DC}.
\]
This completes the proof.

3. Converse of the Angle Bisector Theorem

The converse is also true:

If a point $D$ on side $BC$ of $\triangle ABC$ satisfies:

\[
\frac{AB}{AC} = \frac{BD}{DC},
\]
then $AD$ is the angle bisector of $\angle BAC$.

Proof: Using the same argument in reverse, we can show that $\triangle ABD \sim \triangle ACD$, implying that $\overline{AD}$ bisects the angle.

4. The Exterior Angle Bisector Theorem

If an external angle bisector of $\angle BAC$ intersects side $BC$ at $D$, the analogous relationship holds:

\[
\frac{AB}{AC} = \frac{BD}{DC},
\]
but this time, the segments $BD$ and $DC$ are on opposite sides of the extension.

5. Applications of the Angle Bisector Theorem

The Angle Bisector Theorem is useful in several geometric contexts:
  • Finding Unknown Lengths: If you know the lengths of two sides and one segment, you can calculate the other segment using proportionality.
  • Proving Similarity and Congruence: It can be used to establish the similarity of triangles in more complex geometric constructions.
  • Solving Geometry Olympiad Problems: Many competition problems use the angle bisector theorem to derive key relationships.

Example Problem 1:

In $\triangle ABC$, the angle bisector of $\angle BAC$ meets $BC$ at $D$. If $AB = 8$, $AC = 6$, and $BC = 14$, find the lengths of $BD$ and $DC$.

Solution:

By the Angle Bisector Theorem:

\[
\frac{BD}{DC} = \frac{AB}{AC} = \frac{8}{6} = \frac{4}{3}.
\]
Let $BD = 4x$ and $DC = 3x$. Since $BD + DC = BC = 14$:

\[
4x + 3x = 14 \implies 7x = 14 \implies x = 2,
\]
So,

\[
BD = 4(2) = 8, \quad DC = 3(2) = 6.
\]
Answer: $BD = 8$, $DC = 6$.

Example Problem 2:

Prove that the internal and external angle bisectors of an angle of a triangle are perpendicular.

Solution:

Let $\overline{AD}$ be the internal angle bisector and $\overline{AE}$ be the external angle bisector of $\angle BAC$. By construction, these two lines divide the angle into complementary parts:

\[
\angle BAD + \angle BAE = 90^\circ.
\]
Thus, they are perpendicular.

6. Generalized Angle Bisector Theorem

For any cevian (a line segment from a vertex to the opposite side) dividing the opposite side in a ratio $\frac{m}{n}$, the following holds:

\[
\frac{AB}{AC} = \frac{m}{n}.
\]
The angle bisector is a special case where $m = AB$ and $n = AC$.

7. Conclusion

The Angle Bisector Theorem is a powerful tool in geometry, linking angle division with side ratios. Its simplicity and versatility make it indispensable in solving advanced geometry problems.

References

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aoum
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  • No, but it is a lot to take in. Also, could you do the Gamma Function next?

    by HacheB2031, Today at 3:04 AM

  • Am I going too fast? Would you like me to slow down?

    by aoum, Yesterday at 11:34 PM

  • Seriously, how do you make these so fast???

    by HacheB2031, Yesterday at 6:45 AM

  • I am now able to make clickable images in my posts! :)

    by aoum, Mar 29, 2025, 10:42 PM

  • Am I doing enough? Are you all expecting more from me?

    by aoum, Mar 29, 2025, 12:31 AM

  • That's all right.

    by aoum, Mar 28, 2025, 10:46 PM

  • sorry i couldn't contribute, was working on my own blog and was sick, i'll try to contribute more

    by HacheB2031, Mar 28, 2025, 2:41 AM

  • Nice blog!
    I found it through blogroll.

    by yaxuan, Mar 26, 2025, 5:26 AM

  • How are you guys finding my blog?

    by aoum, Mar 24, 2025, 4:50 PM

  • insanely high quality!

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  • Thanks! Happy to hear that!

    by aoum, Mar 23, 2025, 7:26 PM

  • They look really nice!

    by kamuii, Mar 23, 2025, 1:50 AM

  • I've embedded images and videos in my posts now. How do they look? (Please refrain from using my code. :noo:)

    by aoum, Mar 20, 2025, 8:58 PM

  • This is a nice blog! :)

    by charking, Mar 18, 2025, 7:48 PM

  • Are you guys actually reading my posts? Am I doing too much?

    by aoum, Mar 17, 2025, 11:35 PM

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