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Marking vertices in splitted triangle
mathisreal   2
N 40 minutes ago by sopaconk
Source: Mexico
Let $n$ be a positive integer. Consider a figure of a equilateral triangle of side $n$ and splitted in $n^2$ small equilateral triangles of side $1$. One will mark some of the $1+2+\dots+(n+1)$ vertices of the small triangles, such that for every integer $k\geq 1$, there is not any trapezoid(trapezium), whose the sides are $(1,k,1,k+1)$, with all the vertices marked. Furthermore, there are no small triangle(side $1$) have your three vertices marked. Determine the greatest quantity of marked vertices.
2 replies
mathisreal
Feb 7, 2022
sopaconk
40 minutes ago
distance of a point from incircle equals to a diameter of incircle
parmenides51   5
N an hour ago by Captainscrubz
Source: 2019 Oral Moscow Geometry Olympiad grades 8-9 p1
In the triangle $ABC, I$ is the center of the inscribed circle, point $M$ lies on the side of $BC$, with $\angle BIM = 90^o$. Prove that the distance from point $M$ to line $AB$ is equal to the diameter of the circle inscribed in triangle $ABC$
5 replies
parmenides51
May 21, 2019
Captainscrubz
an hour ago
f(a + b) = f(a) + f(b) + f(c) + f(d) in N-{O}, with 2ab = c^2 + d^2
parmenides51   8
N 4 hours ago by TiagoCavalcante
Source: RMM Shortlist 2016 A1
Determine all functions $f$ from the set of non-negative integers to itself such that $f(a + b) = f(a) + f(b) + f(c) + f(d)$, whenever $a, b, c, d$, are non-negative integers satisfying $2ab = c^2 + d^2$.
8 replies
parmenides51
Jul 4, 2019
TiagoCavalcante
4 hours ago
Functional Inequality Implies Uniform Sign
peace09   33
N 5 hours ago by ezpotd
Source: 2023 ISL A2
Let $\mathbb{R}$ be the set of real numbers. Let $f:\mathbb{R}\rightarrow\mathbb{R}$ be a function such that \[f(x+y)f(x-y)\geqslant f(x)^2-f(y)^2\]for every $x,y\in\mathbb{R}$. Assume that the inequality is strict for some $x_0,y_0\in\mathbb{R}$.

Prove that either $f(x)\geqslant 0$ for every $x\in\mathbb{R}$ or $f(x)\leqslant 0$ for every $x\in\mathbb{R}$.
33 replies
peace09
Jul 17, 2024
ezpotd
5 hours ago
Trapezium problem very nice
manlio   2
N 5 hours ago by alexheinis
Given trapezium ABCD with basis AB and CD parallel. Choose a point E on side BC and a point F on side AD such that AE Is parallel to FC . Prove that DE Is parallel to FB.
2 replies
manlio
Yesterday at 11:00 AM
alexheinis
5 hours ago
Labelling edges of Kn
oVlad   1
N 6 hours ago by TopGbulliedU
Source: Romania Junior TST 2025 Day 2 P3
Let $n\geqslant 3$ be an integer. Ion draws a regular $n$-gon and all its diagonals. On every diagonal and edge, Ion writes a positive integer, such that for any triangle formed with the vertices of the $n$-gon, one of the numbers on its edges is the sum of the two other numbers on its edges. Determine the smallest possible number of distinct values that Ion can write.
1 reply
oVlad
May 6, 2025
TopGbulliedU
6 hours ago
c^a + a = 2^b
Havu   8
N 6 hours ago by MathematicalArceus
Find $a, b, c\in\mathbb{Z}^+$ such that $a,b,c$ coprime, $a + b = 2c$ and $c^a + a = 2^b$.
8 replies
Havu
May 10, 2025
MathematicalArceus
6 hours ago
Concurrence of lines defined by intersections of circles
Lukaluce   1
N 6 hours ago by sarjinius
Source: 2025 Macedonian Balkan Math Olympiad TST Problem 2
Let $\triangle ABC$ be an acute-angled triangle and $A_1, B_1$, and $C_1$ be the feet of the altitudes from $A, B$, and $C$, respectively. On the rays $AA_1, BB_1$, and $CC_1$, we have points $A_2, B_2$, and $C_2$ respectively, lying outside of $\triangle ABC$, such that
\[\frac{A_1A_2}{AA_1} = \frac{B_1B_2}{BB_1} = \frac{C_1C_2}{CC_1}.\]If the intersections of $B_1C_2$ and $B_2C_1$, $C_1A_2$ and $C_2A_1$, and $A_1B_2$ and $A_2B_1$ are $A', B'$, and $C'$ respectively, prove that $AA', BB'$, and $CC'$ have a common point.
1 reply
Lukaluce
Apr 14, 2025
sarjinius
6 hours ago
Factorial Divisibility
Aryan-23   45
N 6 hours ago by MathematicalArceus
Source: IMO SL 2022 N2
Find all positive integers $n>2$ such that
$$ n! \mid \prod_{ p<q\le n, p,q \, \text{primes}} (p+q)$$
45 replies
Aryan-23
Jul 9, 2023
MathematicalArceus
6 hours ago
Multiple of multinomial coefficient is an integer
orl   14
N 6 hours ago by mickeymouse7133
Source: Romanian Master in Mathematics 2009, Problem 1
For $ a_i \in \mathbb{Z}^ +$, $ i = 1, \ldots, k$, and $ n = \sum^k_{i = 1} a_i$, let $ d = \gcd(a_1, \ldots, a_k)$ denote the greatest common divisor of $ a_1, \ldots, a_k$.
Prove that $ \frac {d} {n} \cdot \frac {n!}{\prod\limits^k_{i = 1} (a_i!)}$ is an integer.

Dan Schwarz, Romania
14 replies
orl
Mar 7, 2009
mickeymouse7133
6 hours ago
Functional Equation from IMO
prtoi   1
N 6 hours ago by KAME06
Source: IMO
Question: $f(2a)+2f(b)=f(f(a+b))$
Solve for f:Z-->Z
My solution:
At a=0, $f(0)+2f(b)=f(f(b))$
Take t=f(b) to get $f(0)+2t=f(t)$
Therefore, f(x)=2x+n where n=f(0)
Could someone please clarify if this is right or wrong?
1 reply
prtoi
Yesterday at 8:07 PM
KAME06
6 hours ago
Concurrent in a pyramid
vanstraelen   1
N Yesterday at 7:53 PM by vanstraelen

Given a pyramid $(T,ABCD)$ where $ABCD$ is a parallelogram.
The intersection of the diagonals of the base is point $S$.
Point $A$ is connected to the midpoint of $[CT]$, point $B$ to the midpoint of $[DT]$,
point $C$ to the midpoint of $[AT]$ and point $D$ to the midpoint of $[BT]$.
a) Prove: the four lines are concurrent in a point $P$.
b) Calulate $\frac{TS}{TP}$.
1 reply
vanstraelen
May 10, 2025
vanstraelen
Yesterday at 7:53 PM
bisector of <BAC _|_AD, trapezium, AB = BE, AC = DE NZMO 2021 R1 p2
parmenides51   3
N Yesterday at 7:49 PM by LeYohan
Let $ABCD$ be a trapezium such that $AB\parallel CD$. Let $E$ be the intersection of diagonals $AC$ and $BD$. Suppose that $AB = BE$ and $AC = DE$. Prove that the internal angle bisector of $\angle BAC$ is perpendicular to $AD$.
3 replies
parmenides51
Sep 20, 2021
LeYohan
Yesterday at 7:49 PM
Radical Axes and circles
mathprodigy2011   4
N Apr 22, 2025 by spiderman0
Can someone explain how to do this purely geometrically?
4 replies
mathprodigy2011
Apr 22, 2025
spiderman0
Apr 22, 2025
Radical Axes and circles
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mathprodigy2011
335 posts
#1
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Can someone explain how to do this purely geometrically?
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SirAppel
879 posts
#2
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$AP$ is the radical axis, so then the intersection with $BC$ must have equal powers with respect to both circles, which only occurs when the segment is bisected
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mathprodigy2011
335 posts
#3
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SirAppel wrote:
$AP$ is the radical axis, so then the intersection with $BC$ must have equal powers with respect to both circles, which only occurs when the segment is bisected

thanks :)
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martianrunner
207 posts
#4
Y by
egmo grind :P
This post has been edited 1 time. Last edited by martianrunner, Apr 22, 2025, 4:33 AM
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spiderman0
11 posts
#5
Y by
Let AP intersect BC at M
By power of point we get $MB^2=MP \cdot MA =MC^2 $
Hence, $MB=MC$
This post has been edited 1 time. Last edited by spiderman0, Apr 22, 2025, 7:53 AM
Reason: Typo
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