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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

Are you interested in working towards MATHCOUNTS and don’t know where to start? We have you covered! If you have taken Prealgebra, then you are ready for MATHCOUNTS/AMC 8 Basics. Already aiming for State or National MATHCOUNTS and harder AMC 8 problems? Then our MATHCOUNTS/AMC 8 Advanced course is for you.

Summer camps are starting next month at the Virtual Campus in math and language arts that are 2 - to 4 - weeks in duration. Spaces are still available - don’t miss your chance to have an enriching summer experience. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following upcoming events:
[list][*]May 9th, 4:30pm PT/7:30pm ET, Casework 2: Overwhelming Evidence — A Text Adventure, a game where participants will work together to navigate the map, solve puzzles, and win! All are welcome.
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[*]May 20th, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 1 Math Jam, Problems 1 to 4, join the Canada/USA Mathcamp staff for this exciting Math Jam, where they discuss solutions to Problems 1 to 4 of the 2025 Mathcamp Qualifying Quiz!
[*]May 21st, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 2 Math Jam, Problems 5 and 6, Canada/USA Mathcamp staff will discuss solutions to Problems 5 and 6 of the 2025 Mathcamp Qualifying Quiz![/list]
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0 replies
jlacosta
May 1, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Permutation with no two prefix sums dividing each other
Assassino9931   2
N 29 minutes ago by Assassino9931
Source: Bulgaria Team Contest, March 2025, oVlad
Does there exist an infinite sequence of positive integers $a_1, a_2 \ldots$, such that every positive integer appears exactly once as a member of the sequence and $a_1 + a_2 + \cdots + a_i$ divides $a_1 + a_2 + \cdots + a_j$ if and only if $i=j$?
2 replies
Assassino9931
an hour ago
Assassino9931
29 minutes ago
Sum of Good Indices
raxu   25
N 3 hours ago by cj13609517288
Source: TSTST 2015 Problem 1
Let $a_1, a_2, \dots, a_n$ be a sequence of real numbers, and let $m$ be a fixed positive integer less than $n$. We say an index $k$ with $1\le k\le n$ is good if there exists some $\ell$ with $1\le \ell \le m$ such that $a_k+a_{k+1}+...+a_{k+\ell-1}\ge0$, where the indices are taken modulo $n$. Let $T$ be the set of all good indices. Prove that $\sum\limits_{k \in T}a_k \ge 0$.

Proposed by Mark Sellke
25 replies
raxu
Jun 26, 2015
cj13609517288
3 hours ago
f(x^2+y^2+z^2)=f(xy)+f(yz)+f(zx)
dangerousliri   7
N 3 hours ago by jasperE3
Source: FEOO, Shortlist A4
Find all functions $f:\mathbb{R}^+\rightarrow\mathbb{R}$ such that for any positive real numbers $x, y$ and $z$,
$$f(x^2+y^2+z^2)=f(xy)+f(yz)+f(zx)$$
Proposed by ThE-dArK-lOrD, and Papon Tan Lapate, Thailand
7 replies
dangerousliri
May 31, 2020
jasperE3
3 hours ago
IMO Genre Predictions
ohiorizzler1434   24
N 3 hours ago by Miquel-point
Everybody, with IMO upcoming, what are you predictions for the problem genres?


Personally I predict: predict
24 replies
ohiorizzler1434
Saturday at 6:51 AM
Miquel-point
3 hours ago
foldina a rectangle paper 3 times
parmenides51   1
N 4 hours ago by TheBaiano
Source: 2023 May Olympiad L2 p4
Matías has a rectangular sheet of paper $ABCD$, with $AB<AD$.Initially, he folds the sheet along a straight line $AE$, where $E$ is a point on the side $DC$ , so that vertex $D$ is located on side $BC$, as shown in the figure. Then folds the sheet again along a straight line $AF$, where $F$ is a point on side $BC$, so that vertex $B$ lies on the line $AE$; and finally folds the sheet along the line $EF$. Matías observed that the vertices $B$ and $C$ were located on the same point of segment $AE$ after making the folds. Calculate the measure of the angle $\angle DAE$.
IMAGE
1 reply
parmenides51
Mar 24, 2024
TheBaiano
4 hours ago
Arbitrary point on BC and its relation with orthocenter
falantrng   33
N 6 hours ago by Thapakazi
Source: Balkan MO 2025 P2
In an acute-angled triangle \(ABC\), \(H\) be the orthocenter of it and \(D\) be any point on the side \(BC\). The points \(E, F\) are on the segments \(AB, AC\), respectively, such that the points \(A, B, D, F\) and \(A, C, D, E\) are cyclic. The segments \(BF\) and \(CE\) intersect at \(P.\) \(L\) is a point on \(HA\) such that \(LC\) is tangent to the circumcircle of triangle \(PBC\) at \(C.\) \(BH\) and \(CP\) intersect at \(X\). Prove that the points \(D, X, \) and \(L\) lie on the same line.

Proposed by Theoklitos Parayiou, Cyprus
33 replies
falantrng
Apr 27, 2025
Thapakazi
6 hours ago
Geometry with orthocenter config
thdnder   6
N Yesterday at 6:15 PM by ohhh
Source: Own
Let $ABC$ be a triangle, and let $AD, BE, CF$ be its altitudes. Let $H$ be its orthocenter, and let $O_B$ and $O_C$ be the circumcenters of triangles $AHC$ and $AHB$. Let $G$ be the second intersection of the circumcircles of triangles $FDO_B$ and $EDO_C$. Prove that the lines $DG$, $EF$, and $A$-median of $\triangle ABC$ are concurrent.
6 replies
thdnder
Apr 29, 2025
ohhh
Yesterday at 6:15 PM
Mock 22nd Thailand TMO P9
korncrazy   2
N Yesterday at 4:42 PM by Tkn
Source: own
Let $H_A,H_B,H_C$ be the feet of the altitudes of the triangle $ABC$ from $A,B,C$, respectively. $P$ is the point on the circumcircle of the triangle $ABC$, $H$ is the orthocenter of the triangle $ABC$, and the incircle of triangle $H_AH_BH_C$ has radius $r$. Let $T_A$ be the point such that $T_A$ and $H$ are on the opposite side of $H_BH_C$, line $T_AP$ is perpendicular to the line $H_BH_C$, and the distance from $T_A$ to line $H_BH_C$ is $r$. Define $T_B$ and $T_C$ similarly. Prove that $T_A,T_B,T_C$ are collinear.
2 replies
korncrazy
Apr 13, 2025
Tkn
Yesterday at 4:42 PM
Minimizing Triangle Area
v_Power   1
N Yesterday at 3:44 PM by lele0305
Hi,

I am trying to solve this question:
A square piece of toast ABCD of side length 1 and centre O is cut in half to form two equal pieces ABC and CDA. If the triangle ABC has to be cut into two parts of equal area, one would usually cut along the line of symmetry BO. However, there are other ways of doing this. Find, with justification, the length and location of the shortest straight cut which divides the triangle ABC into two parts of equal area.
I have worked out that the length is sqrt(sqrt(2)-1) using calculus, but I was wondering if there was a way to solve it without using calculus?
1 reply
v_Power
Yesterday at 2:45 PM
lele0305
Yesterday at 3:44 PM
Prove XBY equal to angle C
nataliaonline75   1
N Yesterday at 3:05 PM by cj13609517288
Let $M$ be the midpoint of $BC$ on triangle $ABC$. Point $X$ lies on segment $AC$ such that $AX=BX$ and $Y$ on line $AM$ such that $XY//AB$. Prove that $\angle XBY = \angle ACB$.
1 reply
nataliaonline75
Yesterday at 2:47 PM
cj13609517288
Yesterday at 3:05 PM
Inequality related to geometry
ducthien   0
Yesterday at 2:56 PM
Let \( ABCD \) be a convex quadrilateral. The diagonals \( AC \) and \( BD \) intersect at \( P \), with \( \angle APD = 60^\circ \). Let \( E, F, G, \) and \( H \) be the midpoints of sides \( AB, BC, CD \), and \( DA \), respectively. Find the greatest positive real number \( k \) such that
\[
EG + 3FH \geq k \cdot d + (1 - k) \cdot s,
\]where \( s \) is the semiperimeter of \( ABCD \) and \( d \) is the sum of the lengths of its diagonals (i.e., \( d = AC + BD \)). Determine when equality holds.

Im trying to slove this question
0 replies
ducthien
Yesterday at 2:56 PM
0 replies
trig relation with two equal circles, each passing through center of other
parmenides51   4
N Yesterday at 2:48 PM by Captainscrubz
Source: Sharygin 2010 Final 10.2
Each of two equal circles $\omega_1$ and $\omega_2$ passes through the center of the other one. Triangle $ABC$ is inscribed into $\omega_1$, and lines $AC, BC$ touch $\omega_2$ . Prove that $cosA + cosB  = 1$.
4 replies
parmenides51
Nov 25, 2018
Captainscrubz
Yesterday at 2:48 PM
angle chasing, tangents at circumcircle of a right triangle
parmenides51   1
N Yesterday at 2:29 PM by CovertQED
Source: China Northern MO 2015 10.2 CNMO
It is known that $\odot O$ is the circumcircle of $\vartriangle ABC$ wwith diameter $AB$. The tangents of $\odot O$ at points $B$ and $C$ intersect at $P$ . The line perpendicular to $PA$ at point $A$ intersects the extension of $BC$ at point $D$. Extend $DP$ at length $PE = PB$. If $\angle ADP = 40^o$ , find the measure of $\angle E$.
1 reply
parmenides51
Oct 28, 2022
CovertQED
Yesterday at 2:29 PM
Showing Tangency
Itoz   0
Yesterday at 1:57 PM
Source: Own
The circumcenter of $\triangle ABC$ is $O$. Line $AO$ meets line $BC$ at point $D$, and there is a point $E$ on $\odot(ABC)$ such that $AE \perp BC$. Line $DE$ intersects $\odot(ABC)$ at point $F$. The perpendicular bisector of line segment $BC$ intersects line $AB$ at point $K$, and line $AB$ intersects $\odot(CFK)$ at point $L$.

Prove that $\odot(AFL)$ is tangent to $\odot (OBC)$.
0 replies
Itoz
Yesterday at 1:57 PM
0 replies
Great sequence problem
Assassino9931   1
N Apr 30, 2025 by internationalnick123456
Source: Balkan MO Shortlist 2024 N4
Let $k$ be a positive integer. Determine all sequences $(a_n)_{n\geq 1}$ of positive integers such that
$$ a_{n+2}(a_{n+1} - k) = a_n(a_{n+1} + k) $$for all positive integers $n$.
1 reply
Assassino9931
Apr 27, 2025
internationalnick123456
Apr 30, 2025
Great sequence problem
G H J
Source: Balkan MO Shortlist 2024 N4
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Assassino9931
1321 posts
#1 • 1 Y
Y by nbasrl
Let $k$ be a positive integer. Determine all sequences $(a_n)_{n\geq 1}$ of positive integers such that
$$ a_{n+2}(a_{n+1} - k) = a_n(a_{n+1} + k) $$for all positive integers $n$.
Z K Y
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internationalnick123456
134 posts
#2 • 1 Y
Y by nbasrl
First, observe that \( a_n > k,\forall n\in\mathbb N\).
If there exists some \( m \) such that \( a_{m+1} = a_m + k \), then by induction it follows that \( a_{n+1} = a_n + k ,\forall n\in\mathbb N\), which forms a valid sequence.
Now assume for the sake of contradiction that \( a_{n+1} \neq a_n + k,\forall n \in \mathbb{N} \). Then, we have:
$$
\frac{a_{n+2}}{a_{n+1} + k} = \frac{a_n}{a_{n+1} - k}\Leftrightarrow 
\frac{a_{n+2}}{a_{n+2} - a_{n+1} - k} = \frac{a_n}{a_n + k - a_{n+1}}
$$$$\Leftrightarrow \frac{a_{n+2} - a_{n+1} - k}{a_{n+1} - a_n - k} = -\frac{a_{n+2}}{a_n}$$Hence, we obtain
$$
\frac{a_{n+2} - a_{n+1} - k}{a_2 - a_1 - k} = (-1)^n \cdot \frac{a_{n+2} a_{n+1}}{a_2 a_1},\forall n\in\mathbb N
$$$\Rightarrow |a_{n+2} - a_{n+1} - k| = c \cdot a_{n+2} a_{n+1}$, where $c = \left| \dfrac{a_2 - a_1 - k}{a_2 a_1} \right|$
However, since \( a_{n+2} > a_n \), it follows that \( \displaystyle \lim_{n \to \infty} a_n = +\infty \). For sufficiently large \( n \), the left-hand side grows linearly while the right-hand side grows quadratically:
$$
|a_{n+2} - a_{n+1} - k| < 2 \max\{a_{n+2}, a_{n+1}\} < c \cdot a_{n+2} a_{n+1}
$$which is a contradiction.
Thus, $a_{n+1} = a_n + k,\forall n\in\mathbb N$.
Z K Y
N Quick Reply
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