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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

Are you interested in working towards MATHCOUNTS and don’t know where to start? We have you covered! If you have taken Prealgebra, then you are ready for MATHCOUNTS/AMC 8 Basics. Already aiming for State or National MATHCOUNTS and harder AMC 8 problems? Then our MATHCOUNTS/AMC 8 Advanced course is for you.

Summer camps are starting next month at the Virtual Campus in math and language arts that are 2 - to 4 - weeks in duration. Spaces are still available - don’t miss your chance to have an enriching summer experience. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following upcoming events:
[list][*]May 9th, 4:30pm PT/7:30pm ET, Casework 2: Overwhelming Evidence — A Text Adventure, a game where participants will work together to navigate the map, solve puzzles, and win! All are welcome.
[*]May 19th, 4:30pm PT/7:30pm ET, What's Next After Beast Academy?, designed for students finishing Beast Academy and ready for Prealgebra 1.
[*]May 20th, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 1 Math Jam, Problems 1 to 4, join the Canada/USA Mathcamp staff for this exciting Math Jam, where they discuss solutions to Problems 1 to 4 of the 2025 Mathcamp Qualifying Quiz!
[*]May 21st, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 2 Math Jam, Problems 5 and 6, Canada/USA Mathcamp staff will discuss solutions to Problems 5 and 6 of the 2025 Mathcamp Qualifying Quiz![/list]
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0 replies
jlacosta
May 1, 2025
0 replies
x is rational implies y is rational
pohoatza   44
N 14 minutes ago by ezpotd
Source: IMO Shortlist 2006, N2, VAIMO 2007, Problem 6
For $ x \in (0, 1)$ let $ y \in (0, 1)$ be the number whose $ n$-th digit after the decimal point is the $ 2^{n}$-th digit after the decimal point of $ x$. Show that if $ x$ is rational then so is $ y$.

Proposed by J.P. Grossman, Canada
44 replies
pohoatza
Jun 28, 2007
ezpotd
14 minutes ago
Multiplicative function
Tales   37
N 18 minutes ago by ezpotd
Source: IMO Shortlist 2004, number theory problem 2
The function $f$ from the set $\mathbb{N}$ of positive integers into itself is defined by the equality \[f(n)=\sum_{k=1}^{n} \gcd(k,n),\qquad n\in \mathbb{N}.\]
a) Prove that $f(mn)=f(m)f(n)$ for every two relatively prime ${m,n\in\mathbb{N}}$.

b) Prove that for each $a\in\mathbb{N}$ the equation $f(x)=ax$ has a solution.

c) Find all ${a\in\mathbb{N}}$ such that the equation $f(x)=ax$ has a unique solution.
37 replies
Tales
Mar 23, 2005
ezpotd
18 minutes ago
NICE INEQUALITY
Kyleray   3
N 26 minutes ago by sqing
Let's $a,b,c>0$. Prove:
$$(\frac{a}{b+c}+\frac{b}{c+a})(\frac{b}{c+a}+\frac{c}{a+b})(\frac{c}{a+b}+\frac{a}{b+c})\geq \frac{(a+b+c)^2}{3(ab+bc+ca)}$$$\text{P/S: No mapple, please :(}$
3 replies
1 viewing
Kyleray
Mar 11, 2021
sqing
26 minutes ago
Tough inequality
TUAN2k8   4
N 29 minutes ago by cazanova19921
Source: Own
Let $n \ge 2$ be an even integer and let $x_1,x_2,...,x_n$ be real numbers satisfying $x_1^2+x_2^2+...+x_n^2=n$.
Prove that
$\sum_{1 \le i < j \le n} \frac{x_ix_j}{x_i^2+x_j^2+1} \ge \frac{-n}{6}$
4 replies
TUAN2k8
May 28, 2025
cazanova19921
29 minutes ago
No more topics!
midpoint wanted, equilateral triangles on sides of a triangle related
parmenides51   1
N May 13, 2023 by Bexultan
Source: 2006 Oral Moscow Geometry Olympiad grades 8-9 p5
Equilateral triangles $ABC_1, BCA_1, CAB_1$ are built on the sides of the triangle $ABC$ to the outside. On the segment $A_1B_1$ to the outer side of the triangle $A_1B_1C_1$, an equilateral triangle $A_1B_1C_2$ is constructed. Prove that $C$ is the midpoint of the segment $C_1C_2$.

(A. Zaslavsky)
1 reply
parmenides51
Oct 17, 2020
Bexultan
May 13, 2023
midpoint wanted, equilateral triangles on sides of a triangle related
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Source: 2006 Oral Moscow Geometry Olympiad grades 8-9 p5
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parmenides51
30653 posts
#1
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Equilateral triangles $ABC_1, BCA_1, CAB_1$ are built on the sides of the triangle $ABC$ to the outside. On the segment $A_1B_1$ to the outer side of the triangle $A_1B_1C_1$, an equilateral triangle $A_1B_1C_2$ is constructed. Prove that $C$ is the midpoint of the segment $C_1C_2$.

(A. Zaslavsky)
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Bexultan
178 posts
#2
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The solution will consist of two parts. In the first part, we will prove that the points $C$, $C_1$, $C_2$ are collinear using Torrichelli point. In the second part we will be proving that $CC_1=CC_2$ using rotations


Part 1: Proving that $C$, $C_1$ and $C_2$ are collinear
Let $AA_1\cap BB_1=T$. Then $T$ is the Torrichelli point of triangle $ABC$ and $T$ is the Torichelli point of triangle $A_1B_1C$. So $C$, $T$, $C_1$ are collinear. Analogously, points $C$, $C_2$ and $T$ are collinear. This means that points $C$, $C_1$, $C_2$ all lie on line $CT$, hence are collinear

Part 2: Proving $CC_1=CC_2$
Let's prove that $AA_1=BB_1$. Consider rotation centered at point $C$ taking $B_1$ to $A$, then $B$ is taken to $AA_1$, meaning that the segment $BB_1$ is taken to $AA_1$. Analogously, rotating around $B$ you can get $CC_1=AA_1$. Thus, $AA_1=BB_1=CC_1$. Note that the same can be done with vertices of triangle $A_1B_1C_2$ proving $CC_2=AA_1=BB_1$. From this follows, that $CC_1=CC_2$
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This post has been edited 2 times. Last edited by Bexultan, Jul 19, 2023, 11:20 AM
Reason: typo
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