Let be an acute triangle. Tangents on the circumscribed circle of triangle at points and intersect at point . Let and be a foot of the altitudes from onto and and let be the midpoint of . Prove:
A) Prove that is the orthocenter of the triangle .
B) Prove that cuts in half.
It builds human-readable logic paths by recursively tracing contradictions, repairing structure, and collapsing ambiguity — not by invoking any external symbolic solver.
These results were produced by a recursive symbolic cognition framework called AGI-Origin, designed to simulate semi-AGI through contradiction collapse, symbolic feedback, and recursion-based error repair.
These were solved without using any symbolic computation engine or solver.
Instead, the solutions were derived using a recursive symbolic framework called AGI-Origin, based on:
- Contradiction collapse
- Self-correcting recursion
- Symbolic anchoring and logical repair
Full PDF: [Upload to Dropbox/Google Drive/Notion or arXiv link when ready]
This effort surpasses AlphaGeometry’s previous 25/30 mark by covering:
- Algebra
- Combinatorics
- Geometry
- Functional Equations
Each solution follows a rigorous logical path and is written in fully human-readable format — no machine code or symbolic solvers were used.
I would greatly appreciate any feedback on the solution structure, logic clarity, or symbolic methodology.
The school A has m1 boys and m2 girls, and ,the school B has n1 boys and n2 girls. Each school is represented by one team formed by p students,boys and girls. If f(k) is the number of cases for which,the twice schools has,togheter k girls, fund f(k) and the valute of k, for which f(k) is maximum.
Let and be positive integers with . In a group of people, each one or always
speak the truth or always lie. Arnaldo can ask questions for any of these people
provided these questions are of the type: “In set , what is the parity of people who speak to
true? ”, where is a subset of size of the set of people. The answer can only
be “” or “”.
a) For which values of and is it possible to determine which people speak the truth and
which people always lie?
b) What is the minimum number of questions required to determine which people
speak the truth and which people always lie, when that number is finite?
We let the circle equation be . We can solve for : Due to tangency, there is only one solution of , and we have a double root and @rchokler's solution 2 is also algebraic and works well.
This post has been edited 1 time. Last edited by joeym2011, Apr 12, 2025, 12:26 AM
We set two equations: Substituting into the second equation yields Expanding gives Combining like terms, we get We know that there are only two solutions that are negations of each other, so Since we want the roots to be negations of each other, the discriminant is equal to So, we need Solving for gives
This post has been edited 4 times. Last edited by ReticulatedPython, Apr 12, 2025, 12:35 AM
We set two equations: Substituting into the second equation yields Expanding gives Combining like terms, we get We know that there are only two solutions that are negations of each other, so Since we want the roots to be negations of each other, the discriminant is equal to So, we need Solving for gives
This is exactly the method I used .
If you don't understand the meaning of this sentence " Since we want the roots to be negations of each other, the discriminant is equal to " , I'll explain it more :
If the discriminant were then the equation would have 2 different solutions for ( because the discriminant is positive ) , that means four 4 points of tangency which is not true .
This post has been edited 2 times. Last edited by mathmax001, Apr 12, 2025, 7:41 PM Reason: addendum
Since , and the equation of the circle we have is , we plug in to find that . Now, we can use the quadratic formula and get: , and since we want the discrimant to be , we just have that
also hi reticulated python!
also sorry for a bad sol
i didnt have time to explain everything clearly
This post has been edited 1 time. Last edited by jb2015007, Apr 12, 2025, 7:42 PM
The equation of the circle is . Subbing in to find the intersection gets which is now since, the circle only intersects the parabola twice there must be 2 double roots so we consider the determinant which is which becomes so only since the radius can't be negative.
Since , and the equation of the circle we have is , we plug in to find that . Now, we can use the quadratic formula and get: , and since we want the discrimant to be , we just have that
also hi reticulated python!
also sorry for a bad sol
i didnt have time to explain everything clearly