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• 1993 AIME Problems/Problem 15
  3 KB (449 words) - 21:39, 21 September 2023
• 1994 AIME Problems/Problem 15
  .../2,Fb,12,-35); D(La,bluedots);D(Lb,bluedots);D(endptproject((C+P)/2,Fc,18,-15),bluedots);D(IP(La,Lb),blue);
  4 KB (717 words) - 22:20, 3 June 2021
• 1995 AIME Problems/Problem 15
  ...ve. This is an infinite geometric series whose sum is <math>\frac{3/64}{1-(15/32)}=\frac{3}{34}</math>, so the answer is <math>\boxed{037}</math>. ...e roll <math>4</math> consecutive <tt>H</tt>'s, and there is a <math>\frac{15}{16}</math> probability we roll a <tt>T</tt>. Thus,
  6 KB (979 words) - 13:20, 11 April 2022
• 1996 AIME Problems/Problem 15
  ...\Longrightarrow \cos 2\theta = \frac{\sqrt{3}}{2} \Longrightarrow \theta = 15^{\circ}</math>. The answer is <math>\lfloor 1000r \rfloor = \left\lfloor 10 ...cdot 4}}{8} = \frac {\sqrt {6} \pm \sqrt {2}}{4}</math>, so <math>\theta = 15^{\circ}</math> (as the other roots are too large to make sense in context).
  5 KB (710 words) - 21:04, 14 September 2020
• 1997 AIME Problems/Problem 15
  4 KB (609 words) - 22:49, 17 July 2023
• 1998 AIME Problems/Problem 15
  9 KB (1,671 words) - 22:10, 15 March 2024
• 1999 AIME Problems/Problem 15
  ...has pairwise parallel planar and oppositely equal length (<math>4\sqrt{13},15,17</math>) edges and can be inscribed in a parallelepiped (rectangular box) <math>q^2+r^2=15^2</math>
  7 KB (1,169 words) - 15:28, 13 May 2024
• 2000 AIME I Problems/Problem 15
  Round 7: <math>b</math> to <math>b</math>, <math>15</math> to right, <math>16</math> left in deck, <math>n = -2 + 8k</math>, be ...ans our sieving process will return to normal after Round 7, with <math>31-15=16</math> cards remaining. Since <math>16</math> is a perfect power of <mat
  15 KB (2,673 words) - 19:16, 6 January 2024
• 2001 AIME I Problems/Problem 15
  11 KB (1,837 words) - 18:53, 22 January 2024
• 2002 AIME I Problems/Problem 15
  7 KB (1,181 words) - 20:32, 8 January 2024
• 2003 AIME I Problems/Problem 15
  8 KB (1,382 words) - 14:23, 29 December 2022
• 2003 AIME II Problems/Problem 15
  4 KB (675 words) - 17:23, 30 July 2022
• 2002 AIME II Problems/Problem 15
  7 KB (1,182 words) - 09:56, 7 February 2022
• 2001 AIME II Problems/Problem 15
  4 KB (518 words) - 15:01, 31 December 2021
• 2000 AIME II Problems/Problem 15
  3 KB (469 words) - 21:14, 7 July 2022
• 2005 AMC 10B Problems/Problem 15
  45 bytes (5 words) - 16:48, 16 July 2011
• Mock AIME 1 2006-2007 Problems/Problem 15
  3 KB (414 words) - 13:45, 19 February 2016
• Mock AIME 2 2006-2007 Problems/Problem 15
  4 KB (739 words) - 17:04, 24 November 2023
• 2005 AMC 10A Problems/Problem 15
  2 KB (306 words) - 19:29, 13 December 2021
• 2004 AMC 10A Problems/Problem 15
  3 KB (457 words) - 02:16, 5 July 2021

Page text matches

• Factorial
  * <math>15! = 1307674368000</math>
  10 KB (809 words) - 16:40, 17 March 2024
• 2006 AIME II
  * [[2006 AIME II Problems/Problem 15]]
  1 KB (133 words) - 12:32, 22 March 2011
• Fermat's Little Theorem
  ...he units digit of <math>k^2 + 2^k</math>? ([[2008 AMC 12A Problems/Problem 15]])
  16 KB (2,658 words) - 16:02, 8 May 2024
• Alabama ARML
  ...9, Alabama did not send a team, but Grissom High in Alabama sent a team of 15 students to compete.
  2 KB (258 words) - 00:50, 28 December 2021
• LaTeX
  <cmath>1+2+3+4+5+\sin \pi = \frac{5\cdot 6}{2}+0=15.</cmath>
  1 KB (164 words) - 19:09, 14 February 2024
• North Carolina MathCounts
  * 2013 - Nikhil Reddy (15), Angela Deng (40), Lloyd Liu (42), Andrew Zhang, Coach: Michael Pillsbury
  4 KB (582 words) - 21:40, 14 May 2024
• Orthic triangle
  ...Y=15</math>. Compute the product <math>AB\cdot AC</math>. (AIME II, 2019, 15)
  8 KB (1,408 words) - 11:54, 8 December 2021
• Recursion
  * [[2004_AIME_I_Problems#Problem_15| 2004 AIME I Problem 15]]
  2 KB (316 words) - 16:03, 1 January 2024
• Combinatorial identity
  ....com/wiki/index.php/2021_AMC_12A_Problems/Problem_15 2021 AMC 12A Problem 15]
  12 KB (1,994 words) - 10:13, 8 June 2024
• Composite number
  4 6 8 9 10 12 14 15 16 18 20 21 22 24 25 26 27 28 30 32 33 34 35 36 38 39 40 42 44 45 46 48 49 ⇒ 13,15,17...... all are sum of 2 composites Hence, any odd positive ≥ 13 can be
  6 KB (350 words) - 12:58, 26 September 2023
• Circle
  ...cycle); dot("$A$",(8,0), 1.25*S); dot("$B$",(8,15), 1.25*N); dot("$C$",(-8,15), 1.25*N); dot("$D$",(-8,0), 1.25*S); dot("$E$",(17,0), 1.25*S); dot("$F$",
  9 KB (1,581 words) - 18:59, 9 May 2024
• Ellipse
  ...prime integers, find <math> p+q. </math> ([[2005 AIME II Problems/Problem 15|Source]])
  5 KB (892 words) - 21:52, 1 May 2021
• Multiple
  ...nite]] number of multiples. As an example, some of the multiples of 15 are 15, 30, 45, 60, and 75.
  860 bytes (142 words) - 22:51, 26 January 2021
• Least common multiple
  ...multiply the results together. For example, to find the LCM of 8, 12 and 15, write: <math>15 = 3^1\cdot 5^1</math>
  2 KB (383 words) - 10:49, 4 September 2022
• Math Bee
  ...tes, while the second phase has 20 free-response questions to be solved in 15 minutes.
  1 KB (197 words) - 10:59, 14 April 2024
• Math Day at the Beach
  This round lasts 45 minutes and consists of 15 multiple-choice questions. Scoring consists of:
  4 KB (644 words) - 12:56, 29 March 2017
• Writing scholarships
  ...uch as creative writing or journalism. Apply for this USD 500 award by May 15 of each year, including a 400-600 word short story in prose or in script.
  7 KB (1,039 words) - 18:45, 18 January 2024
• National Scholarships
  * [[Best Buy @15 Scholarship]] of <dollar/>1,000 for students in grades 9-12. [https://www.a
  4 KB (538 words) - 00:48, 28 January 2024
• Law of Cosines
  label("d",(15,0),(0,-1)); \qquad \mathrm{(B) \ } 8/\sqrt{15}
  6 KB (1,003 words) - 00:02, 20 May 2024
• Chicago ARML
  The [[Chicago ARML]] team consists of four groups of approximately 15 high school students. The four groups are:
  2 KB (236 words) - 12:06, 7 June 2024

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