Difference between revisions of "2006 AMC 12A Problems/Problem 11"

(See also)
 
(9 intermediate revisions by 5 users not shown)
Line 1: Line 1:
 +
{{duplicate|[[2006 AMC 12A Problems|2006 AMC 12A #11]] and [[2006 AMC 10A Problems/Problem 11|2008 AMC 10A #11]]}}
 
== Problem ==
 
== Problem ==
 +
Which of the following describes the graph of the equation <math>(x+y)^2=x^2+y^2</math>?
 +
 +
<math>\mathrm{(A)}\ \text{the empty set}\qquad\mathrm{(B)}\ \text{one point}\qquad\mathrm{(C)}\ \text{two lines}\qquad\mathrm{(D)}\ \text{a circle}\qquad\mathrm{(E)}\ \text{the entire plane}</math>
  
 
== Solution ==
 
== Solution ==
 +
<cmath>
 +
\begin{align*}(x+y)^2&=x^2+y^2\\
 +
x^2 + 2xy + y^2 &= x^2 + y^2\\
 +
2xy &= 0\end{align*}
 +
</cmath>
 +
Either <math> x = 0 </math> or <math> y = 0 </math>. The [[union]] of them is 2 lines, and thus the answer is <math>\mathrm{(C)}</math>.
 +
 +
<asy> draw((0,-50)--(0,50));draw((-50,0)--(50,0));</asy>
  
 
== See also ==
 
== See also ==
* [[2006 AMC 12A Problems]]
+
{{AMC12 box|year=2006|ab=A|num-b=10|num-a=12}}
 +
{{AMC10 box|year=2006|ab=A|num-b=10|num-a=12}}
 +
{{MAA Notice}}
 +
 
 +
[[Category:Introductory Algebra Problems]]

Latest revision as of 17:52, 3 July 2013

The following problem is from both the 2006 AMC 12A #11 and 2008 AMC 10A #11, so both problems redirect to this page.

Problem

Which of the following describes the graph of the equation $(x+y)^2=x^2+y^2$?

$\mathrm{(A)}\ \text{the empty set}\qquad\mathrm{(B)}\ \text{one point}\qquad\mathrm{(C)}\ \text{two lines}\qquad\mathrm{(D)}\ \text{a circle}\qquad\mathrm{(E)}\ \text{the entire plane}$

Solution

\begin{align*}(x+y)^2&=x^2+y^2\\ x^2 + 2xy + y^2 &= x^2 + y^2\\ 2xy &= 0\end{align*} Either $x = 0$ or $y = 0$. The union of them is 2 lines, and thus the answer is $\mathrm{(C)}$.

[asy] draw((0,-50)--(0,50));draw((-50,0)--(50,0));[/asy]

See also

2006 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2006 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png