Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

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[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Geo Mock #10
Bluesoul   1
N 28 minutes ago by vanstraelen
Consider acute $\triangle{ABC}$ with $AB=10$, $AC<BC$ and area $135$. The circle $\omega$ with diameter $AB$ meets $BC$ at $E$. Let the orthocenter of the triangle be $H$, connect $CH$ and extend to meet $\omega$ at $N$ such that $NC>HC$ and $NE$ is the diameter of $\omega$. Draw the circumcircle $\Gamma$ of $\triangle{AHB}$, chord $XY$ of $\Gamma$ is tangent to $\omega$ and it passes through $N$, compute $XY$.
1 reply
Bluesoul
Apr 1, 2025
vanstraelen
28 minutes ago
KSEA NMSC Mock Contest Group B (Last Problem)
Shiyul   2
N 2 hours ago by Shiyul
Let $a_n$ be a sequence defined by $a_n = a^2 + 1$. Then the product of four consecutive terms in $a_n$ can be written as the product of two terms in $a_n$. Find $p + q$ if $(a_(11))(a_(12))(a_(13))(a_(14)) = (a_p)(a_q)$.
2 replies
Shiyul
5 hours ago
Shiyul
2 hours ago
Inequalities
sqing   4
N 5 hours ago by sqing
Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=11.$ Prove that
$$a+ab+abc\leq\frac{49}{6}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=10.$ Prove that
$$a+ab+abc\leq\frac{169}{24}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=14.$ Prove that
$$a+ab+abc\leq\frac{63+5\sqrt 5}{6}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=32.$ Prove that
$$a+ab+abc\leq48+\frac{64\sqrt{2}}{3}$$
4 replies
sqing
Apr 1, 2025
sqing
5 hours ago
Geo Mock #9
Bluesoul   1
N 5 hours ago by vanstraelen
Consider $\triangle{ABC}$ with $AB=12, AC=22$. The points $D,E$ lie on $AB,AC$ respectively, such that $\frac{AD}{BD}=\frac{AE}{CE}=3$. Extend $CD,BE$ to meet the circumcircle of $\triangle{ABC}$ at $P,Q$ respectively. Let the circumcircles of $\triangle{ADP}, \triangle{AEQ}$ meet at points $A,T$. Extend $AT$ to $BC$ at $R$, given $AR=16$, find $[ABC]$.
1 reply
Bluesoul
Apr 1, 2025
vanstraelen
5 hours ago
No more topics!
KVS IOQM P2
akv_6721   7
N Oct 28, 2022 by Hexagon_6-
If $ABCD$ is a rectangle and $P$ is a point inside it such that $AP=33, BP=16, DP=63$.
Find $CP$.
7 replies
akv_6721
Jan 30, 2021
Hexagon_6-
Oct 28, 2022
KVS IOQM P2
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akv_6721
28 posts
#1
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If $ABCD$ is a rectangle and $P$ is a point inside it such that $AP=33, BP=16, DP=63$.
Find $CP$.
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Hamroldt
744 posts
#3
Y by
Coord bash to get $56$
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ATGY
2502 posts
#4
Y by
wrong lol
ignoreeeeeeeeeeeeeeeeeeeeee
This post has been edited 1 time. Last edited by ATGY, Jan 30, 2021, 2:56 PM
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Hamroldt
744 posts
#5
Y by
ATGY wrote:
Prabh1512 wrote:
Cheese

Can confirm. Will just be $79 - 33 = 46$.

No ATGY that’s wrong, I made the dumbest mistake possible. That’s because in that case $AP=CP$ which violates the problem conditions !
This post has been edited 1 time. Last edited by Hamroldt, Jan 30, 2021, 10:11 AM
Reason: Edit !
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L567
1184 posts
#6 • 1 Y
Y by fungarwai
Simple, by british flag theorem, $x^2 + 33^2 = 16^2 + 63^2$, simplify to get $x = 56$
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Ninjasolver0201
722 posts
#7
Y by
That is called British Flag Theorem, but this proved by basic Pythagorus Theorem. Answer is $\boxed{56}$.
This post has been edited 1 time. Last edited by Ninjasolver0201, Jan 30, 2021, 1:30 PM
Reason: Add
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ATGY
2502 posts
#8
Y by
Sorry for my mistake!
Use british flag theorem to get:
$$63^2 + 16^2 - 33^2 = 3136 = 56^2$$So our answer is $56$.
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Hexagon_6-
23 posts
#9
Y by
Same question appear in 2012 prmo and this question also given in ncert 10th textbook
This post has been edited 1 time. Last edited by Hexagon_6-, Oct 28, 2022, 4:37 PM
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