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Number Theory
fasttrust_12-mn   5
N an hour ago by GreekIdiot
Source: Pan African Mathematics Olympiad p6
Find all integers $n$ for which $n^7-41$ is the square of an integer
5 replies
fasttrust_12-mn
Aug 16, 2024
GreekIdiot
an hour ago
Maximum number of nice subsets
FireBreathers   0
an hour ago
Given a set $M$ of natural numbers with $n$ elements with $n$ odd number. A nonempty subset $S$ of $M$ is called $nice$ if the product of the elements of $S$ divisible by the sum of the elements of $M$, but not by its square. It is known that the set $M$ itself is good. Determine the maximum number of $nice$ subsets (including $M$ itself).
0 replies
FireBreathers
an hour ago
0 replies
Floor double summation
CyclicISLscelesTrapezoid   52
N an hour ago by lpieleanu
Source: ISL 2021 A2
Which positive integers $n$ make the equation \[\sum_{i=1}^n \sum_{j=1}^n \left\lfloor \frac{ij}{n+1} \right\rfloor=\frac{n^2(n-1)}{4}\]true?
52 replies
CyclicISLscelesTrapezoid
Jul 12, 2022
lpieleanu
an hour ago
Polynomial
Z_.   1
N an hour ago by rchokler
Let \( m \) be an integer greater than zero. Then, the value of the sum of the reciprocals of the cubes of the roots of the equation
\[
mx^4 + 8x^3 - 139x^2 - 18x + 9 = 0
\]is equal to:
1 reply
Z_.
2 hours ago
rchokler
an hour ago
Existence of perfect squares
egxa   2
N 2 hours ago by pavel kozlov
Source: All Russian 2025 10.3
Find all natural numbers \(n\) for which there exists an even natural number \(a\) such that the number
\[
(a - 1)(a^2 - 1)\cdots(a^n - 1)
\]is a perfect square.
2 replies
egxa
Apr 18, 2025
pavel kozlov
2 hours ago
IMO 2014 Problem 4
ipaper   169
N 3 hours ago by YaoAOPS
Let $P$ and $Q$ be on segment $BC$ of an acute triangle $ABC$ such that $\angle PAB=\angle BCA$ and $\angle CAQ=\angle ABC$. Let $M$ and $N$ be the points on $AP$ and $AQ$, respectively, such that $P$ is the midpoint of $AM$ and $Q$ is the midpoint of $AN$. Prove that the intersection of $BM$ and $CN$ is on the circumference of triangle $ABC$.

Proposed by Giorgi Arabidze, Georgia.
169 replies
ipaper
Jul 9, 2014
YaoAOPS
3 hours ago
Inequalities
Scientist10   1
N 3 hours ago by Bergo1305
If $x, y, z \in \mathbb{R}$, then prove that the following inequality holds:
\[
\sum_{\text{cyc}} \sqrt{1 + \left(x\sqrt{1 + y^2} + y\sqrt{1 + x^2}\right)^2} \geq \sum_{\text{cyc}} xy + 2\sum_{\text{cyc}} x
\]
1 reply
Scientist10
5 hours ago
Bergo1305
3 hours ago
Tangents forms triangle with two times less area
NO_SQUARES   1
N 3 hours ago by Luis González
Source: Kvant 2025 no. 2 M2831
Let $DEF$ be triangle, inscribed in parabola. Tangents in points $D,E,F$ forms triangle $ABC$. Prove that $S_{DEF}=2S_{ABC}$. ($S_T$ is area of triangle $T$).
From F.S.Macaulay's book «Geometrical Conics», suggested by M. Panov
1 reply
NO_SQUARES
Today at 9:08 AM
Luis González
3 hours ago
FE solution too simple?
Yiyj1   9
N 3 hours ago by jasperE3
Source: 101 Algebra Problems from the AMSP
Find all functions $f: \mathbb{R} \rightarrow \mathbb{R}$ such that the equality $$f(f(x)+y) = f(x^2-y)+4f(x)y$$holds for all pairs of real numbers $(x,y)$.

My solution

I feel like my solution is too simple. Is there something I did wrong or something I missed?
9 replies
Yiyj1
Apr 9, 2025
jasperE3
3 hours ago
interesting function equation (fe) in IR
skellyrah   2
N 3 hours ago by jasperE3
Source: mine
find all function F: IR->IR such that $$ xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy) $$
2 replies
skellyrah
Today at 9:51 AM
jasperE3
3 hours ago
.problem.
Cobedangiu   4
N Apr 5, 2025 by Lankou
Find the integer coefficients after expanding Newton's binomial:
$$(\frac{3}{2}-\frac{2}{3}x^2)^n (n \in Z)$$
4 replies
Cobedangiu
Apr 4, 2025
Lankou
Apr 5, 2025
.problem.
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G H BBookmark kLocked kLocked NReply
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Cobedangiu
55 posts
#1
Y by
Find the integer coefficients after expanding Newton's binomial:
$$(\frac{3}{2}-\frac{2}{3}x^2)^n (n \in Z)$$
This post has been edited 1 time. Last edited by Cobedangiu, Apr 4, 2025, 6:20 AM
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Cobedangiu
55 posts
#2
Y by
...............
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Lankou
1390 posts
#3 • 1 Y
Y by Cobedangiu
$(\frac{3}{2}-\frac{2}{3}x^2)^n =\sum_{k=0}^n  {n\choose k} \cdot \left(\frac{3}{2}\right)^k \left(-\frac{2x^2}{3}\right)^{n-k}$
The coefficient is an integer when $n-k=k$
Coefficient$= {n\choose \frac{n}{2}}$
This post has been edited 1 time. Last edited by Lankou, Apr 4, 2025, 12:11 PM
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Cobedangiu
55 posts
#4
Y by
Lankou wrote:
$(\frac{3}{2}-\frac{2}{3}x^2)^n =\sum_{k=0}^n  {n\choose k} \cdot \left(\frac{3}{2}\right)^k \left(-\frac{2x^2}{3}\right)^{n-k}$
The coefficient is an integer when $n-k=k$
Coefficient$= {n\choose \frac{n}{2}}$

integer coefficients? ${n\choose \frac{n}{2}}$ not integer
This post has been edited 1 time. Last edited by Cobedangiu, Apr 5, 2025, 9:46 AM
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Lankou
1390 posts
#5 • 1 Y
Y by Cobedangiu
${n\choose \frac{n}{2}}$ always an integer
By the way it should be $(-1)^{\frac{n}{2}}{n\choose \frac{n}{2}}$
This post has been edited 3 times. Last edited by Lankou, Apr 5, 2025, 1:29 PM
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