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k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

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Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
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0 replies
jlacosta
Mar 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
special sets
ChubbyTomato426   0
24 minutes ago
Let $n$ be a positive integer. A subset $\{a, b, c, d\} \subseteq \{1, 2, . . . , 4n\}$ with four distinct elements is special if there exists a rearrangement $(x, y, z, w)$ of $(a, b, c, d)$ such that $xy -zw = 1$. Prove that the set $\{1, 2, . . . , 4n \}$ cannot be partitioned into $n$ special disjoint sets.
0 replies
ChubbyTomato426
24 minutes ago
0 replies
2, 4, 5-Nim
cjquines0   2
N 30 minutes ago by Mathdreams
Source: Philippines MO 2016/4
Two players, \(A\) (first player) and \(B\), take alternate turns in playing a game using 2016 chips as follows: the player whose turn it is, must remove \(s\) chips from the remaining pile of chips, where \(s \in \{ 2,4,5 \}\). No one can skip a turn. The player who at some point is unable to make a move (cannot remove chips from the pile) loses the game. Who among the two players can force a win on this game?
2 replies
cjquines0
Jan 21, 2017
Mathdreams
30 minutes ago
old and easy imo inequality
Valentin Vornicu   211
N 36 minutes ago by Mathdreams
Source: IMO 2000, Problem 2, IMO Shortlist 2000, A1
Let $ a, b, c$ be positive real numbers so that $ abc = 1$. Prove that
\[ \left( a - 1 + \frac 1b \right) \left( b - 1 + \frac 1c \right) \left( c - 1 + \frac 1a \right) \leq 1.
\]
211 replies
Valentin Vornicu
Oct 24, 2005
Mathdreams
36 minutes ago
2013 Stats Sprint #28
Rice_Farmer   18
N an hour ago by Aaronjudgeisgoat
Is there a better way than just partitioning casework bash this?
18 replies
+1 w
Rice_Farmer
Mar 17, 2025
Aaronjudgeisgoat
an hour ago
Number of sign change in cos ka
Rohit-2006   2
N an hour ago by Rohit-2006
Let $0\leq\alpha\leq\pi$. Denote by $V_n(\alpha)$ the number of changes of signs in the
sequence
$$1, cos \alpha, cos 2\alpha, . . . , cos n\alpha.$$Then prove that
$$\lim_{n\rightarrow\infty}\frac{V_n(\alpha)}{n}=\frac{\alpha}{\pi}$$.
2 replies
Rohit-2006
2 hours ago
Rohit-2006
an hour ago
Collinearity with orthocenter
liberator   178
N an hour ago by endless_abyss
Source: IMO 2013 Problem 4
Let $ABC$ be an acute triangle with orthocenter $H$, and let $W$ be a point on the side $BC$, lying strictly between $B$ and $C$. The points $M$ and $N$ are the feet of the altitudes from $B$ and $C$, respectively. Denote by $\omega_1$ is the circumcircle of $BWN$, and let $X$ be the point on $\omega_1$ such that $WX$ is a diameter of $\omega_1$. Analogously, denote by $\omega_2$ the circumcircle of triangle $CWM$, and let $Y$ be the point such that $WY$ is a diameter of $\omega_2$. Prove that $X,Y$ and $H$ are collinear.

Proposed by Warut Suksompong and Potcharapol Suteparuk, Thailand
178 replies
liberator
Jan 4, 2016
endless_abyss
an hour ago
Obsolete NT
GreekIdiot   1
N an hour ago by amapstob
Source: older isl
Find all $n \in \mathbb{N}$ greater than $1$, such that, if $gcd(a,b)=1$, then $a \equiv b \: mod \: n \iff ab \equiv 1 \: mod \: n$
1 reply
GreekIdiot
3 hours ago
amapstob
an hour ago
Nice problem
hanzo.ei   0
an hour ago
Given two positive integers \( m, n \) satisfying \( m > n \) and their sum is an even number, consider the quadratic polynomial:

\[
P(x) = x^2 - (m^2 - m + 1)x + (m^2 - n^2 - m)(n^2 + 1).
\]
Prove that all roots of \( P(x) \) are positive integers but are not perfect squares.
0 replies
hanzo.ei
an hour ago
0 replies
Checkerboard
Ecrin_eren   4
N an hour ago by Ecrin_eren
On an 8×8 checkerboard, what is the minimum number of squares that must be marked (including the marked ones) so that every square has exactly one marked neighbor? (We define neighbors as squares that share a common edge, and a square is not considered a neighbor of itself.)
4 replies
Ecrin_eren
Mar 21, 2025
Ecrin_eren
an hour ago
a^2+b^2+c^2=2(ab+bc+ca)
sqing   13
N an hour ago by sqing
Source: Own
Let $a,b,c>0 $ and $a^2+b^2+c^2=2(ab+bc+ca).$ Prove that
$$a^3+b^3+c^3\geq \frac{33}{2}abc$$$$a^2(b+c)+c^2(a+b)\geq \frac{5}{2}abc$$$$a(b^2+c^2)+b(c^2+a^2)+c(a^2+b^2)\geq \frac{21}{2}abc$$$$\left( \frac{a}{b} + \frac{b}{c} \right) \left( \frac{b}{a} + \frac{a}{c} \right) \geq\frac{25}{16}$$$$\left( \frac{a}{b} + \frac{b}{c} \right) \left( \frac{b}{a} + \frac{a}{c} \right)\left( \frac{c}{a} + \frac{c}{b} \right)\geq \frac{25}{2}$$
13 replies
sqing
Jul 17, 2022
sqing
an hour ago
1/sqrt(5) ???
navi_09220114   3
N 2 hours ago by math_comb01
Source: Own. Malaysian IMO TST 2025 P12
Two circles $\omega_1$ and $\omega_2$ are externally tangent at a point $A$. Let $\ell$ be a line tangent to $\omega_1$ at $B\neq A$ and $\omega_2$ at $C\neq A$. Let $BX$ and $CY$ be diameters in $\omega_1$ and $\omega_2$ respectively. Suppose points $P$ and $Q$ lies on $\omega_2$ such that $XP$ and $XQ$ are tangent to $\omega_2$, and points $R$ and $S$ lies on $\omega_1$ such that $YR$ and $YS$ are tangent to $\omega_1$.

a) Prove that the points $P$, $Q$, $R$, $S$ lie on a circle $\Gamma$.

b) Prove that the four segments $XP$, $XQ$, $YR$, $YS$ determine a quadrilateral with an incircle $\gamma$, and its radius is $\displaystyle\frac{1}{\sqrt{5}}$ times the radius of $\Gamma$.

Proposed by Ivan Chan Kai Chin
3 replies
navi_09220114
Yesterday at 1:10 PM
math_comb01
2 hours ago
Basic Maths
JetFire008   12
N 4 hours ago by ChaitraliKA
Find $x$: $\sqrt{9}x=18$
12 replies
JetFire008
Mar 21, 2025
ChaitraliKA
4 hours ago
Mathcounts STRATEGIES
Existing_Human1   29
N 4 hours ago by drhong
Hello commuinty!

I am wondering what your strategies are for mathcounts. Please note I do not mean tips. These can be for all rounds, but please specify. BTW, this is for state, but it can apply to any competition.

Ex:
Team - sit in a specific order
Target - do the easiest first
Sprint - go as fast as possible

I just made up the examples, and you will probably have better strategies, so if you want to help out, please do
29 replies
+1 w
Existing_Human1
Mar 20, 2025
drhong
4 hours ago
quadratics
luciazhu1105   24
N 5 hours ago by cheltstudent
I really need help on quadratics and I don't know why I also kinda need a bit of help on graphing functions and finding the domain and range of them.
24 replies
luciazhu1105
Feb 14, 2025
cheltstudent
5 hours ago
I think I regressed at math
PaperMath   20
N Mar 18, 2025 by jlcong
I found the slip of paper a few days ago that I think I wrote when I was in kindergarten. It is just a sequence of numbers and you have to find the next number, the pattern is $1,2,5,40,1280,?$. I couldn't solve this and was wondering if any of you can find the pattern
20 replies
PaperMath
Mar 8, 2025
jlcong
Mar 18, 2025
I think I regressed at math
G H J
G H BBookmark kLocked kLocked NReply
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PaperMath
958 posts
#1
Y by
I found the slip of paper a few days ago that I think I wrote when I was in kindergarten. It is just a sequence of numbers and you have to find the next number, the pattern is $1,2,5,40,1280,?$. I couldn't solve this and was wondering if any of you can find the pattern
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IsaacShi
256 posts
#2 • 1 Y
Y by ChickensEatGrass
And you wrote that in kindergarten ?
This post has been edited 1 time. Last edited by IsaacShi, Mar 8, 2025, 4:20 AM
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Disjunction
104 posts
#3
Y by
The only thing that can be deduced from this is a fourth difference of $1143$.
Not even too sure about this since the sample is extremely small.
Someone try to find the type of sequence.
This post has been edited 2 times. Last edited by Disjunction, Mar 8, 2025, 4:24 AM
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Yrock
1214 posts
#4
Y by
I cant find it either :facepalm: I think it's a recursion..

@bove bruh

*searching in OEIS*

EDIT: not in OEIS..
This post has been edited 2 times. Last edited by Yrock, Mar 8, 2025, 4:23 AM
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aidan0626
1765 posts
#5 • 2 Y
Y by giratina3, MathPerson12321
The pattern is clearly $a_n=\frac{381}{8}n^{4}-\frac{1885}{4}n^{3}+\frac{13103n^{2}}{8}-\frac{9313n}{4}+1115$, and thus the next term is $a_6=6,041.$
This post has been edited 1 time. Last edited by aidan0626, Mar 8, 2025, 4:24 AM
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Disjunction
104 posts
#6
Y by
aidan0626 wrote:
The pattern is clearly $a_n=\frac{381}{8}x^{4}-\frac{1885}{4}x^{3}+\frac{13103x^{2}}{8}-\frac{9313x}{4}+1115$, and thus the next term is $a_6=6,041.$

Careful there. The fourth difference seen is 1143. However, we don't know if it's constant since our sample size is limited to the fourth difference. Based on the given terms, however, that seems fair enough, although there's no way to prove that it's true as we can't prove the consistency of the fourth difference.
This post has been edited 2 times. Last edited by Disjunction, Mar 8, 2025, 4:27 AM
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Disjunction
104 posts
#7
Y by
Also, @aidan0626, it appears that you performed a quartic regression. Since we don't have any more information about the terms, we can't tell if the overall sequence will act this way. It only works for the terms that are given since it goes up to the fourth difference (quartic).
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Disjunction
104 posts
#8
Y by
Conclusion: The pattern has an infinite number of solutions so long as it fits the terms given.
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aidan0626
1765 posts
#9
Y by
Apologies. The sequence is clearly
\begin{align*}
a_n=\begin{cases}
1 & n=1\\
2 & n=2\\
5 & n=3\\
40 & n=4\\
1280 & n=5\\
69420 & n\ge 6,n\pmod{2}=0\\
1434 & n\ge6,n\pmod{2}=1
\end{cases}\end{align*}
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Disjunction
104 posts
#10
Y by
aidan0626 wrote:
Apologies. The sequence is clearly
\begin{align*}
a_n=\begin{cases}
1 & n=1\\
2 & n=2\\
5 & n=3\\
40 & n=4\\
1280 & n=5\\
69420 & n\ge 6,n\pmod{2}=0\\
1434 & n\ge6,n\pmod{2}=1
\end{cases}\end{align*}

Hey, it could be! Lol.
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fossasor
519 posts
#11 • 2 Y
Y by ChickensEatGrass, AccurateArmadillo7676
I have a theory: you know how sometimes preschoolers will be like "I can write cursive!" and hold up a piece of paper with nonsensical squiggly lines? Maybe this is like that. You saw other sequence problems in kindergarten, so you decided to create one and wrote some random numbers that seemed to kind of have a pattern.

I hate to be pessimistic, but that might be the case.
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Gavin_Deng
756 posts
#12
Y by
I finally understand why he chose “papermath” as his username.
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Charizard_637
87 posts
#13
Y by
WAIT WAIT WAIT I THINK I SOLVED IT
and I swear on my entire math career I didn’t use any sort of ai I sat at my desk for an hour) I made nats at Mathcounts this year)

Quadruple each term:
4, 8, 20, 160, 5120
160 = 4^2 * 20 / 2
5120 = 8^2 * 160 / 2
A possible sequence could be a(n) = (a(n-3))^2 * a(n-1). This gives probable cause that the next term is 20^2 * 5120 / 2 =1,024,000, but remember we quadrupled at the beginning, so let’s unquadruple; 256,000
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Charizard_637
87 posts
#14
Y by
Charizard_637 wrote:
WAIT WAIT WAIT I THINK I SOLVED IT
and I swear on my entire math career I didn’t use any sort of ai I sat at my desk for an hour) I made nats at Mathcounts this year)

Quadruple each term:
4, 8, 20, 160, 5120
160 = 4^2 * 20 / 2
5120 = 8^2 * 160 / 2
A possible sequence could be a(n) = (a(n-3))^2 * a(n-1). This gives probable cause that the next term is 20^2 * 5120 / 2 =1,024,000, but remember we quadrupled at the beginning, so let’s unquadruple; 256,000

This is obviously subjective to being incorrect, but the sample size for this kind of sequence is too small, leaving endless possibilities. I believe mine was one of the most straightforward, although I hope someone can find an even better tentative one.
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Yrock
1214 posts
#15
Y by
Gaslighted ChatGPT into solving this... Used both of SirAppel's functions.. so 69420!
hidden for length
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c_double_sharp
292 posts
#16 • 3 Y
Y by DhruvJha, MathPerson12321, ChickensEatGrass
charizard try not to flex making nats for 2 microseconds challenge:

is it possible that your kindergarten handwriting is awful and you misread a number or two?
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Pikachu19
699 posts
#17
Y by
Yrock wrote:
Gaslighted ChatGPT into solving this... Used both of SirAppel's functions.. so 69420!
hidden for length

why not just put the pattern into the ai
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Charizard_637
87 posts
#18
Y by
c_double_sharp wrote:
charizard try not to flex making nats for 2 microseconds challenge:

is it possible that your kindergarten handwriting is awful and you misread a number or two?

I'm so sorry I didn't mean to flex like that, wanted to emphasize a lot on the line and btw I was not supposed to make nats I locked in out of nowhere
also trying to assemble my MN team so sorry to appear boasty
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MathPerson12321
3616 posts
#19
Y by
Charizard_637 wrote:
c_double_sharp wrote:
charizard try not to flex making nats for 2 microseconds challenge:

is it possible that your kindergarten handwriting is awful and you misread a number or two?

I'm so sorry I didn't mean to flex like that, wanted to emphasize a lot on the line and btw I was not supposed to make nats I locked in out of nowhere
also trying to assemble my MN team so sorry to appear boasty

You’ve said this like 10000 times I’ve already asked you to stop and clearly you aren’t.
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Charizard_637
87 posts
#20
Y by
MathPerson12321 wrote:
Charizard_637 wrote:
c_double_sharp wrote:
charizard try not to flex making nats for 2 microseconds challenge:

is it possible that your kindergarten handwriting is awful and you misread a number or two?

I'm so sorry I didn't mean to flex like that, wanted to emphasize a lot on the line and btw I was not supposed to make nats I locked in out of nowhere
also trying to assemble my MN team so sorry to appear boasty

You’ve said this like 10000 times I’ve already asked you to stop and clearly you aren’t.

I think I've said this like 4x, I wont post it anywhere honestly now anyone who wants to know knows there's just no point
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jlcong
364 posts
#21
Y by
Someone said i regressed and will continue to regress, how can i counter?
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