ka April Highlights and 2025 AoPS Online Class Information
jlacosta0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.
WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.
Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!
Prealgebra 1
Sunday, Apr 13 - Aug 10
Tuesday, May 13 - Aug 26
Thursday, May 29 - Sep 11
Sunday, Jun 15 - Oct 12
Monday, Jun 30 - Oct 20
Wednesday, Jul 16 - Oct 29
Introduction to Algebra A
Monday, Apr 7 - Jul 28
Sunday, May 11 - Sep 14 (1:00 - 2:30 pm ET/10:00 - 11:30 am PT)
Wednesday, May 14 - Aug 27
Friday, May 30 - Sep 26
Monday, Jun 2 - Sep 22
Sunday, Jun 15 - Oct 12
Thursday, Jun 26 - Oct 9
Tuesday, Jul 15 - Oct 28
Introduction to Counting & Probability
Wednesday, Apr 16 - Jul 2
Thursday, May 15 - Jul 31
Sunday, Jun 1 - Aug 24
Thursday, Jun 12 - Aug 28
Wednesday, Jul 9 - Sep 24
Sunday, Jul 27 - Oct 19
Introduction to Number Theory
Thursday, Apr 17 - Jul 3
Friday, May 9 - Aug 1
Wednesday, May 21 - Aug 6
Monday, Jun 9 - Aug 25
Sunday, Jun 15 - Sep 14
Tuesday, Jul 15 - Sep 30
Introduction to Algebra B
Wednesday, Apr 16 - Jul 30
Tuesday, May 6 - Aug 19
Wednesday, Jun 4 - Sep 17
Sunday, Jun 22 - Oct 19
Friday, Jul 18 - Nov 14
Introduction to Geometry
Wednesday, Apr 23 - Oct 1
Sunday, May 11 - Nov 9
Tuesday, May 20 - Oct 28
Monday, Jun 16 - Dec 8
Friday, Jun 20 - Jan 9
Sunday, Jun 29 - Jan 11
Monday, Jul 14 - Jan 19
Intermediate: Grades 8-12
Intermediate Algebra
Monday, Apr 21 - Oct 13
Sunday, Jun 1 - Nov 23
Tuesday, Jun 10 - Nov 18
Wednesday, Jun 25 - Dec 10
Sunday, Jul 13 - Jan 18
Thursday, Jul 24 - Jan 22
MATHCOUNTS/AMC 8 Basics
Wednesday, Apr 16 - Jul 2
Friday, May 23 - Aug 15
Monday, Jun 2 - Aug 18
Thursday, Jun 12 - Aug 28
Sunday, Jun 22 - Sep 21
Tues & Thurs, Jul 8 - Aug 14 (meets twice a week!)
MATHCOUNTS/AMC 8 Advanced
Friday, Apr 11 - Jun 27
Sunday, May 11 - Aug 10
Tuesday, May 27 - Aug 12
Wednesday, Jun 11 - Aug 27
Sunday, Jun 22 - Sep 21
Tues & Thurs, Jul 8 - Aug 14 (meets twice a week!)
AMC 10 Problem Series
Friday, May 9 - Aug 1
Sunday, Jun 1 - Aug 24
Thursday, Jun 12 - Aug 28
Tuesday, Jun 17 - Sep 2
Sunday, Jun 22 - Sep 21 (1:00 - 2:30 pm ET/10:00 - 11:30 am PT)
Monday, Jun 23 - Sep 15
Tues & Thurs, Jul 8 - Aug 14 (meets twice a week!)
AMC 10 Final Fives
Sunday, May 11 - Jun 8
Tuesday, May 27 - Jun 17
Monday, Jun 30 - Jul 21
AMC 12 Problem Series
Tuesday, May 27 - Aug 12
Thursday, Jun 12 - Aug 28
Sunday, Jun 22 - Sep 21
Wednesday, Aug 6 - Oct 22
Introduction to Programming with Python
Thursday, May 22 - Aug 7
Sunday, Jun 15 - Sep 14 (1:00 - 2:30 pm ET/10:00 - 11:30 am PT)
Tuesday, Jun 17 - Sep 2
Monday, Jun 30 - Sep 22
Hi, I'm currently in 8th grade and I have about 6 months left to prepare for the AMC 10, and I really want to qualify for AIME and get above a 100. I took the AMC 8 this year and did really bad, with a score of 16, and a 35 on the MATHCOUNTS Chapter test. I have a feeling I would get about a 70 on the AMC 10 now, so I want to be able to improve by 30 points in 6 months. Is that possible? I have summer break coming up so I feel like I could study for about 4 hours a day every single day, and I'm willing to if that's what it takes. Do you have any ideas for what resources I should use? I know about Alcumus and I have some of the AOPS books, but not all of them. If you have any tips, let me know. Thank you so much!
s11 was dumb i added wrong
s18 was dumb how did i not see that
s23 was dumb how did i not see that
s24 was dumb how am i not able to read properly
s27 was dumb like the official solution was assume rectangle
t6 was dumb like i did not calcbash enough terms
t8 was dumb how did i not see that
This post has been edited 1 time. Last edited by c_double_sharp, Apr 4, 2025, 6:07 PM
s11 was dumb i added wrong
s18 was dumb how did i not see that
s23 was dumb how did i not see that
s24 was dumb how am i not able to read properly
s27 was dumb like the official solution was assume rectangle
t6 was dumb like i did not calcbash enough terms
t8 was dumb how did i not see that
s11 was dumb i added wrong
s18 was dumb how did i not see that
s23 was dumb how did i not see that
s24 was dumb how am i not able to read properly
s27 was dumb like the official solution was assume rectangle
t6 was dumb like i did not calcbash enough terms
t8 was dumb how did i not see that
I also assume rectangle because I hate rigorous geometry
Can someone explain why the expectation is the reciprocal?
Because it's kind of like saying it has a in chance of happening, so it happens twice every times. This means that it is expected to happen once every times.
Bro, sprint 20 took the most time for me in the first 20. I can't believe that I actually did coordinate geometry on the real test on this problem!
I also almost trolled this problem. I miscalculated by somehow getting the square root of 49/25 but I clutched and caught my mistake to change it to the square root of 81/25 which is 9/5.
This post has been edited 1 time. Last edited by ilikemath247365, Apr 5, 2025, 6:01 PM
s11 was dumb i added wrong
s18 was dumb how did i not see that
s23 was dumb how did i not see that
s24 was dumb how am i not able to read properly
s27 was dumb like the official solution was assume rectangle
t6 was dumb like i did not calcbash enough terms
t8 was dumb how did i not see that
totally agree
fr tho
This post has been edited 1 time. Last edited by PikaPika999, Apr 6, 2025, 12:44 AM
i had seen some extremely trivial solution for p4 target that didn't even require a calculator but i forgot it now
does anyone have a non-bash solution for that one
here are 5 stupid solutions to target #4
sol 1 (sort of bash, most logical)
let the legs be and . Then we have From the latter two equations, we see that Squaring both sides, we have so Substituting we get so the hypotenuse has length
sol 2 (cheese, no bash)
let the legs of the triangle be and . Then we have Additionally, by the triangle inequality, we know the hypotenuse is less than , and because it is the longest side, it is greater than Also, because the question simply asks for the length of the hypotenuse without "simplest radical form" or "common fraction" at the end of the problem, we know the hypotenuse is an integer. Thus, the only numbers that can be the length of the hypotenuse are ,,,,, and . Plugging values into the equation in line yields
sol 3 (graphing calc)
obtain from before. Plug in and into your graphing calculator and find the intersection. We find the graphs roughly intersect at We use our calculator to find the sums of the squares of these two numbers, and get that the hypotenuse has length
sol 4 (even more cheese)
From solution 2, we know that the hypotenuse must be equal to ,,,,, or . Notice that the longer the hypotenuse is, the larger the area of the triangle. Additionally, the area of this triangle is much less than the perimeter, so we can assume the hypotenuse is as large as possible. The length of the hypotenuse is maximized when it is equal to
sol 5 (sol 2+3 equals 5)
From the triangle inequality, we know the hypotenuse is the longest side of the triangle and is less than . We know that (from solution 3), the longer leg is roughly . This means that for the hypotenuse to be the longest side, it must equal
This post has been edited 3 times. Last edited by Bummer12345, Apr 7, 2025, 1:09 PM Reason: latex
The official solution works because the coins follow a Binomial Distribution, which means that we have that where is the expected value, is the probability, and is the number of trials. This also follows from linearity of expectation on each of the groups of . Then, setting and gives the desired answer.
Alternatively, another easy solution is to use recursion: suppose that we want the expected number of rolls, , until an event happens with probability . Then, we have that which rearranges to the desired .
edit: thinking about it now im not completely sure this is valid because expected amount of rolls between HTH and TTT is different but whatever
This post has been edited 3 times. Last edited by happypi31415, Apr 7, 2025, 8:32 PM
target seems interesting
personal difficulty ratings: 1 is trivial, 10 is nats t8(from a year not named 2024 or 2023)
t1: 1, trivial, just average 9876 and 5432.
t2: 1.5 to 2, trivial but annoying.
First two seem hard to silly, esp. with 1 being so easy.
t3: 1 to 1.5, also trivial.
t4: 2 to 2.5, too easy for the placement.
Another very sweepable round, as intended. Nowhere near the difficulty of last year's t4(which was the only one i got wrong last year).
t5: 1 to 1.5, just floor(202/24)
t6: 6 to 7, imo perfect placement. nontrivial. Albeit you don't even have to find the intended solution, simply approximate 2^2025-1 to 2^2025 and plugging the first ~13 terms into a calc should give a good approximation.
t7: 3 to 3.5, fair placement. simple crt.
t8: 4 to 9, really just depends on your perception. there are definitely people who just assumed you can always reciprocate, but there are definitely people who tried much, much harder methods.