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k a June Highlights and 2025 AoPS Online Class Information
jlacosta   0
Jun 2, 2025
Congratulations to all the mathletes who competed at National MATHCOUNTS! If you missed the exciting Countdown Round, you can watch the video at this link. Are you interested in training for MATHCOUNTS or AMC 10 contests? How would you like to train for these math competitions in half the time? We have accelerated sections which meet twice per week instead of once starting on July 8th (7:30pm ET). These sections fill quickly so enroll today!

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Summer camps are starting this month at the Virtual Campus in math and language arts that are 2 - to 4 - weeks in duration. Spaces are still available - don’t miss your chance to have a transformative summer experience. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following upcoming events:
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0 replies
jlacosta
Jun 2, 2025
0 replies
Hardest Gaokao Problem
Bluesoul   10
N 3 minutes ago by Butterfly
Source: 2008 江西高考数学
Let function $f(x)=\frac{1}{\sqrt{1+x}}+\frac{1}{\sqrt{1+a}}+\sqrt{\frac{ax}{ax+8}}$ , $x$ lies on $(0,\infty)$

$(1)$ When $a=8$, determine when $f(x)$ is increasing or decreasing

$(2)$ Prove that for any positive number $a$, $1<f(x)<2$
10 replies
Bluesoul
Dec 21, 2021
Butterfly
3 minutes ago
Permutation guessing game
Rijul saini   3
N 3 minutes ago by Siddharth03
Source: India IMOTC Day 3 Problem 3
Let $n$ be a positive integer. Alice and Bob play the following game. Alice considers a permutation $\pi$ of the set $[n]=\{1,2, \dots, n\}$ and keeps it hidden from Bob. In a move, Bob tells Alice a permutation $\tau$ of $[n]$, and Alice tells Bob whether there exists an $i \in [n]$ such that $\tau(i)=\pi(i)$. Bob wins if he ever tells Alice the permutation $\pi$. Prove that Bob can win the game in at most $n \log_2(n) + 2025n$ moves.

Proposed by Siddharth Choppara and Shantanu Nene
3 replies
Rijul saini
Jun 4, 2025
Siddharth03
3 minutes ago
Inequality from China GaoKao
CeuAzul   4
N 14 minutes ago by Butterfly
Let $abc=8,a,b,c>0$
Prove that $1<\frac{1}{\sqrt{a+1}}+\frac{1}{\sqrt{b+1}}+\frac{1}{\sqrt{c+1}}<2$
4 replies
CeuAzul
Feb 23, 2018
Butterfly
14 minutes ago
Cyclic Quadrilateral in a Square
tobiSALT   5
N 44 minutes ago by MathLuis
Source: Cono Sur 2025 #1
Given a square $ABCD$, let $P$ be a point on the segment $BC$ and let $G$ be the intersection point of $AP$ with the diagonal $DB$. The line perpendicular to the segment $AP$ through $G$ intersects the side $CD$ at point $E$. Let $K$ be a point on the segment $GE$ such that $AK = PE$. Let $Q$ be the intersection point of the diagonal $AC$ and the segment $KP$.
Prove that the points $E, K, Q,$ and $C$ are concyclic.
5 replies
tobiSALT
Yesterday at 4:20 PM
MathLuis
44 minutes ago
1919 water square
NicoN9   2
N 3 hours ago by abbominable_sn0wman
We call a positive integer $c$ bigger than $10^4$ water if the last four digit is $1919$. Does there exists a water perfect square?
2 replies
NicoN9
4 hours ago
abbominable_sn0wman
3 hours ago
99...99400...009
NicoN9   2
N 3 hours ago by NicoN9
Let $k>2$ be a positive integer. Prove that\[
\underbrace{99\dots 99}_{k-1}4\underbrace{00\dots 00}_{k-1}9
\]can't be a prime number.
2 replies
NicoN9
4 hours ago
NicoN9
3 hours ago
quadratic equation solving with 399999999...
NicoN9   1
N 4 hours ago by LearnMath_105
Let $m$ be a positive integer. Solve over $\mathbb{R}$, the equation\[
x^2+2x-3\underbrace{99\dots 99}_{2m}.
\]
1 reply
NicoN9
4 hours ago
LearnMath_105
4 hours ago
Extended Wilson's?
NamelyOrange   2
N 5 hours ago by rhydon516
Let $\mathbb{Z}^*_n$ be the set of positive integers less than $n$ relatively prime to it. Is there a nice pattern for $\left(\prod_{k\in \mathbb{Z}^*_n} k\right) \text{ mod }n$? I know from a Wilson's theorem-style argument that it's either $1$ or $-1$, but when is it which?
2 replies
NamelyOrange
Yesterday at 5:41 PM
rhydon516
5 hours ago
Hockey Sticks and apple Pie
BadAtCompetitionMath21420   0
6 hours ago
How many triples of three-digit palindromes have a sum that is also a three-digit palindromes?


This is a problem I plan on adding to my competition, but I'm unsure if PIE was correct to use in the solution:
solution
Please critique this as hard as possible because I'm really uncomfortable with counting, and this problem has to be perfect.
0 replies
BadAtCompetitionMath21420
6 hours ago
0 replies
Polynomials
P162008   5
N Yesterday at 7:52 PM by RedFireTruck
P1. Find $p(0) + p(5)$ where $p$ is a monic polynomial of degree $4$ satisfying $p(r) = 2^r ; r = 1,2,3,4.$

P2. Find $p(1), p(-1)$ where $p$ is a polynomial of smallest degree possible satisfying $p(r) = \frac{1}{r^2 - 1}; r = 2,3,4,\cdots, 10.$

P3. Find $k$ and $p(0)$, if polynomial $p$ satisfies $x.p(x) + 1 = k\left(\prod_{i = 1}^{5} (x - i)\right).$

P4. Find $p(0)$ where $p$ is a polynomial of smallest degree satisfying $p(r) = \frac{1}{r}; r = 1,2,3,\cdots,10.$

P5. Find $p(0),p(6),k$ and $\alpha$ if polynomial $p$ satisfies $(x^2 - 6x).p(x) + 1 = k\left(\prod_{i=1}^{5} (x - i)\right)(x - \alpha).$

P6. If $f(x)$ is a polynomial of degree $50$ such that $f(x) = \frac{x}{x + 1}; x = 0,1,2,\cdots,50.$ Evaluate $f(-1).$
5 replies
P162008
Yesterday at 12:17 AM
RedFireTruck
Yesterday at 7:52 PM
Logarithms
P162008   1
N Yesterday at 7:51 PM by vanstraelen
Let $a = \frac{(\log_{2} 3 - \log_{5} 7)(\log_{2} 3 - \log_{7} 9)}{(\log_{3} 5 - \log_{5} 7)(\log_{3} 5 - \log_{7} 9)}, b = \frac{(\log_{2} 3 - \log_{3} 5)(\log_{2} 3 - \log_{7} 9)}{(\log_{5} 7 - \log_{3} 5)(\log_{5} 7 - \log_{7} 9)}$ and $c = \frac{(\log_{2} 3 - \log_{3} 5)(\log_{2} 3 - \log_{5} 7)}{(\log_{7} 9 - \log_{3} 5)(\log_{7} 9 - \log_{5} 7)}.$
Find the value of $\lfloor a + b + c \rfloor$ where $\lfloor.\rfloor$ denotes greatest integer function.
1 reply
P162008
May 30, 2025
vanstraelen
Yesterday at 7:51 PM
Pure algebra problem
lgx57   3
N Yesterday at 5:59 PM by trangbui
If $a_0=5$,$a_n=a_{n-1}+\dfrac{1}{a_{n-1}}$. Let $S=a_{1000}$
Calculate $S$.

PS1: The more precise decimal places there are, the better.(rounded down)
PS2: Please don't use python or C++, or this problem will be very easy.
3 replies
lgx57
Yesterday at 8:31 AM
trangbui
Yesterday at 5:59 PM
the Basics
wpdnjs   9
N Yesterday at 5:48 PM by MathRook7817
given that log base 3 of 2 is approximately 0.631, fin the smallest positivie integer a such that 3^a > 2^102.



somebody anyone pls help :wacko:
9 replies
wpdnjs
Yesterday at 3:00 AM
MathRook7817
Yesterday at 5:48 PM
Find the largest value of p
Darealzolt   4
N Yesterday at 5:46 PM by MathRook7817
It is known that
\[
\sqrt{x-3}+\sqrt{6-x} \leq p
\]In which \(x \in \mathbb{R}\), hence find the largest value of \(p\).
4 replies
Darealzolt
Yesterday at 4:24 PM
MathRook7817
Yesterday at 5:46 PM
SMO 2008 q2
dominicleejun   1
N Mar 30, 2018 by WizardMath
Source: SMO 2008, open, 2nd round
in the acute triangle $\triangle ABC$.
M is a point in the interior of the segment AC and N is a point on the extension of segment AC such that MN=AC.
let D,E be the feet of perpendiculars from M,N onto lines BC,AB respectively
prove that the orthocentre of $\triangle ABC$ lies on circumcircle of $\triangle BED$
1 reply
dominicleejun
Mar 30, 2018
WizardMath
Mar 30, 2018
SMO 2008 q2
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G H BBookmark kLocked kLocked NReply
Source: SMO 2008, open, 2nd round
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dominicleejun
1097 posts
#1 • 2 Y
Y by Adventure10, Mango247
in the acute triangle $\triangle ABC$.
M is a point in the interior of the segment AC and N is a point on the extension of segment AC such that MN=AC.
let D,E be the feet of perpendiculars from M,N onto lines BC,AB respectively
prove that the orthocentre of $\triangle ABC$ lies on circumcircle of $\triangle BED$
Z K Y
The post below has been deleted. Click to close.
This post has been deleted. Click here to see post.
WizardMath
2487 posts
#2 • 3 Y
Y by GoldGirl, Adventure10, Mango247
Let $MD, NE$ meet at $X$. The orthocenter of $ABC$ is $H$. Then $AHC$ and $MXN$ are congruent, so $HX \parallel AC \perp BH$, so $\angle BHX = 90^\circ = \angle BMX = \angle BNX$, so done.
Z K Y
N Quick Reply
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