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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
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0 replies
jlacosta
Apr 2, 2025
0 replies
Website to learn math
hawa   68
N 32 minutes ago by GallopingUnicorn45
Hi, I'm kinda curious what website do yall use to learn math, like i dont find any website thats fun to learn math
68 replies
hawa
Apr 9, 2025
GallopingUnicorn45
32 minutes ago
Can someone explain this one
hawa   10
N Yesterday at 8:23 PM by VivaanKam
Suppose n is the largest integer obtained by solving the following inequality:

3+9+18+30+...+n
n < 2021.
10 replies
hawa
Yesterday at 1:36 AM
VivaanKam
Yesterday at 8:23 PM
Alcumus specs
YeohZY   5
N Yesterday at 7:23 PM by PikaPika999
Hi, can I ask about how Alcumus gives you points? (I mean the number on the red/orange/green/blue line on top that gains once you get correct answers. I'll just call it the score). I want to get my score up to 100, but I always can't and get stuck at like 98 or sth. Why is this so, and also how does alcumus make that "score" higher?
5 replies
YeohZY
Apr 27, 2025
PikaPika999
Yesterday at 7:23 PM
Inequalities
sqing   16
N Yesterday at 5:25 PM by martianrunner
Let $ a,b \in [0 ,1] . $ Prove that
$$\frac{a}{ 1-ab+b }+\frac{b }{ 1-ab+a } \leq 2$$$$ \frac{a}{ 1+ab+b^2 }+\frac{b }{ 1+ab+a^2 }+\frac{ab }{2+ab }  \leq 1$$$$\frac{a}{ 1-ab+b^2 }+\frac{b }{ 1-ab+a^2 }+\frac{1 }{1+ab  }\leq \frac{5}{2}$$$$\frac{a}{ 1-ab+b^2 }+\frac{b }{ 1-ab+a^2 }+\frac{1 }{1+2ab  }\leq \frac{7}{3}$$$$\frac{a}{ 1+ab+b^2 }+\frac{b }{ 1+ab+a^2 } +\frac{ab }{1+ab }\leq \frac{7}{6 }$$
16 replies
sqing
Apr 25, 2025
martianrunner
Yesterday at 5:25 PM
Math Problem I cant figure out how to do without bashing
equalsmc2   3
N Yesterday at 3:55 PM by NovaFrost
Hi,
I cant figure out how to do these 2 problems without bashing. Do you guys have any ideas for an elegant solution? Thank you!
Prob 1.
An RSM sports field has a square shape. Poles with letters M, A, T, H are located at the corners of the square (see the diagram). During warm up, a student starts at any pole, runs to another pole along a side of the square or across the field along diagonal MT (only in the direction from M to T), then runs to another pole along a side of the square or along diagonal MT, and so on. The student cannot repeat a run along the same side/diagonal of the square in the same direction. For instance, she cannot run from M to A twice, but she can run from M to A and at some point from A to M. How many different ways are there to complete the warm up that includes all nine possible runs (see the diagram)? One possible way is M-A-T-H-M-H-T-A-M-T (picture attached)

Prob 2.
In the expression 5@5@5@5@5 you replace each of the four @ symbols with either +, or, or x, or . You can insert one or more pairs of parentheses to control the order of operations. Find the second least whole number that CANNOT be the value of the resulting expression. For example, each of the numbers 25=5+5+5+5+5 and 605+(5+5)×5+5 can be the value of the resulting expression.

Prob 3. (This isnt bashing I don't understand how to do it though)
Suppose BC = 3AB in rectangle ABCD. Points E and F are on side BC such that BE = EF = FC. Compute the sum of the degree measures of the four angles EAB, EAF, EAC, EAD.

P.S. These are from an RSM olympiad. The answers are
3 replies
equalsmc2
Apr 6, 2025
NovaFrost
Yesterday at 3:55 PM
Sequence
lgx57   7
N Yesterday at 3:38 PM by jasperE3
$a_1=1,a_{n+1}=a_n+\frac{1}{a_n}$. Find the general term of $\{a_n\}$.
7 replies
lgx57
Apr 27, 2025
jasperE3
Yesterday at 3:38 PM
Geometry Angle Chasing
Sid-darth-vater   6
N Yesterday at 2:18 PM by sunken rock
Is there a way to do this without drawing obscure auxiliary lines? (the auxiliary lines might not be obscure I might just be calling them obscure)

For example I tried rotating triangle MBC 80 degrees around point C (so the BC line segment would now lie on segment AC) but I couldn't get any results. Any help would be appreciated!
6 replies
Sid-darth-vater
Apr 21, 2025
sunken rock
Yesterday at 2:18 PM
Inequlities
sqing   26
N Yesterday at 1:27 PM by sqing
Let $ a,b,c\geq 0 $ and $ a^2+ab+bc+ca=3 .$ Prove that$$\frac{1}{1+a^2}+ \frac{1}{1+b^2}+  \frac{1}{1+c^2} \geq \frac{3}{2}$$$$\frac{1}{1+a^2}+ \frac{1}{1+b^2}+ \frac{1}{1+c^2}-bc \geq -\frac{3}{2}$$
26 replies
sqing
Jul 19, 2024
sqing
Yesterday at 1:27 PM
BABBAGE'S THEOREM EXTENSION
Mathgloggers   0
Yesterday at 12:18 PM
A few days ago I came across. this interesting result is someone interested in proving this.

$\boxed{\sum_{k=1}^{p-1} \frac{1}{k} \equiv \sum_{k=p+1}^{2p-1} \frac{1}{k} \equiv \sum_{k=2p+1}^{3p-1}\frac{1}{k} \equiv.....\sum_{k=p(p-1)+1}^{p^2-1}\frac{1}{k} \equiv 0(mod p^2)}$
0 replies
Mathgloggers
Yesterday at 12:18 PM
0 replies
N.S. condition of passing a fixed point for a function
Kunihiko_Chikaya   1
N Yesterday at 11:29 AM by Mathzeus1024
Let $ f(t)$ be a function defined in any real numbers $ t$ with $ f(0)\neq 0.$ Prove that on the $ x-y$ plane, the line $ l_t : tx+f(t) y=1$ passes through the fixed point which isn't on the $ y$ axis in regardless of the value of $ t$ if only if $ f(t)$ is a linear function in $ t$.
1 reply
Kunihiko_Chikaya
Sep 6, 2009
Mathzeus1024
Yesterday at 11:29 AM
Dot product
SomeonecoolLovesMaths   4
N Yesterday at 11:25 AM by quasar_lord
How to prove that dot product is distributive?
4 replies
SomeonecoolLovesMaths
Monday at 6:06 PM
quasar_lord
Yesterday at 11:25 AM
Inequalities
sqing   6
N Yesterday at 8:58 AM by sqing
Let $a,b,c\geq 0,ab+bc+ca>0$ and $a+b+c=3$. Prove that
$$\frac{8}{3}\leq\frac{(a+b)(b+c)(c+a)}{ab+bc+ca}\leq 3$$$$3\leq\frac{(a+b)(2b+c)(c+a)}{ab+bc+ca}\leq 6$$$$\frac{3}{2}\leq\frac{(a+b)(2b+c)(c+ a)}{ab+bc+2ca}\leq 6$$$$1\leq\frac{(a+b)(2b+c)(c+ a)}{ab+bc+ 3ca}\leq 6$$
6 replies
sqing
Dec 22, 2023
sqing
Yesterday at 8:58 AM
BrUMO 2025 Team Round Problem 3
lpieleanu   2
N Yesterday at 8:57 AM by nehareddyk009
Bruno and Brutus are running on a circular track with a $20$ foot radius. Bruno completes $5$ laps every hour, while Brutus completes $7$ laps every hour. If they start at the same point but run in opposite directions, how far along the track’s circumference (in feet) from the starting point are they when they meet for the sixth time? Note: Do not count the moment they start running as a meeting point.
2 replies
lpieleanu
Apr 27, 2025
nehareddyk009
Yesterday at 8:57 AM
Inequalities
sqing   6
N Yesterday at 8:42 AM by sqing
Let $x\in(-1,1). $ Prove that
$$  \dfrac{1}{\sqrt{1-x^2}} + \dfrac{1}{2+ x^2}  \geq  \dfrac{3}{2}$$$$ \dfrac{2}{\sqrt{1-x^2}} + \dfrac{1}{1+x^2} \geq 3$$
6 replies
sqing
Apr 26, 2025
sqing
Yesterday at 8:42 AM
I think I regressed at math
PaperMath   66
N Apr 18, 2025 by mathkiddus
I found the slip of paper a few days ago that I think I wrote when I was in kindergarten. It is just a sequence of numbers and you have to find the next number, the pattern is $1,2,5,40,1280,?$. I couldn't solve this and was wondering if any of you can find the pattern
66 replies
PaperMath
Mar 8, 2025
mathkiddus
Apr 18, 2025
I think I regressed at math
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PaperMath
957 posts
#1 • 5 Y
Y by Cinnamon.-.Roll, PikaPika999, GodGodGodGodGoose, RainbowJessa, jkim0656
I found the slip of paper a few days ago that I think I wrote when I was in kindergarten. It is just a sequence of numbers and you have to find the next number, the pattern is $1,2,5,40,1280,?$. I couldn't solve this and was wondering if any of you can find the pattern
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IsaacShi
370 posts
#2 • 4 Y
Y by ChickensEatGrass, PikaPika999, GodGodGodGodGoose, RainbowJessa
And you wrote that in kindergarten ?
This post has been edited 1 time. Last edited by IsaacShi, Mar 8, 2025, 4:20 AM
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Disjunction
112 posts
#3 • 3 Y
Y by PikaPika999, GodGodGodGodGoose, RainbowJessa
The only thing that can be deduced from this is a fourth difference of $1143$.
Not even too sure about this since the sample is extremely small.
Someone try to find the type of sequence.
This post has been edited 2 times. Last edited by Disjunction, Mar 8, 2025, 4:24 AM
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Yrock
1275 posts
#4 • 3 Y
Y by PikaPika999, GodGodGodGodGoose, RainbowJessa
I cant find it either :facepalm: I think it's a recursion..

@bove bruh

*searching in OEIS*

EDIT: not in OEIS..
This post has been edited 2 times. Last edited by Yrock, Mar 8, 2025, 4:23 AM
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aidan0626
1875 posts
#5 • 6 Y
Y by giratina3, MathPerson12321, PikaPika999, GodGodGodGodGoose, RainbowJessa, Wesoar
The pattern is clearly $a_n=\frac{381}{8}n^{4}-\frac{1885}{4}n^{3}+\frac{13103n^{2}}{8}-\frac{9313n}{4}+1115$, and thus the next term is $a_6=6,041.$
This post has been edited 1 time. Last edited by aidan0626, Mar 8, 2025, 4:24 AM
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Disjunction
112 posts
#6 • 3 Y
Y by PikaPika999, GodGodGodGodGoose, RainbowJessa
aidan0626 wrote:
The pattern is clearly $a_n=\frac{381}{8}x^{4}-\frac{1885}{4}x^{3}+\frac{13103x^{2}}{8}-\frac{9313x}{4}+1115$, and thus the next term is $a_6=6,041.$

Careful there. The fourth difference seen is 1143. However, we don't know if it's constant since our sample size is limited to the fourth difference. Based on the given terms, however, that seems fair enough, although there's no way to prove that it's true as we can't prove the consistency of the fourth difference.
This post has been edited 2 times. Last edited by Disjunction, Mar 8, 2025, 4:27 AM
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Disjunction
112 posts
#7 • 3 Y
Y by PikaPika999, GodGodGodGodGoose, RainbowJessa
Also, @aidan0626, it appears that you performed a quartic regression. Since we don't have any more information about the terms, we can't tell if the overall sequence will act this way. It only works for the terms that are given since it goes up to the fourth difference (quartic).
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Disjunction
112 posts
#8 • 2 Y
Y by GodGodGodGodGoose, RainbowJessa
Conclusion: The pattern has an infinite number of solutions so long as it fits the terms given.
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aidan0626
1875 posts
#9 • 2 Y
Y by PikaPika999, GodGodGodGodGoose
Apologies. The sequence is clearly
\begin{align*}
a_n=\begin{cases}
1 & n=1\\
2 & n=2\\
5 & n=3\\
40 & n=4\\
1280 & n=5\\
69420 & n\ge 6,n\pmod{2}=0\\
1434 & n\ge6,n\pmod{2}=1
\end{cases}\end{align*}
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Disjunction
112 posts
#10 • 2 Y
Y by PikaPika999, GodGodGodGodGoose
aidan0626 wrote:
Apologies. The sequence is clearly
\begin{align*}
a_n=\begin{cases}
1 & n=1\\
2 & n=2\\
5 & n=3\\
40 & n=4\\
1280 & n=5\\
69420 & n\ge 6,n\pmod{2}=0\\
1434 & n\ge6,n\pmod{2}=1
\end{cases}\end{align*}

Hey, it could be! Lol.
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fossasor
593 posts
#11 • 4 Y
Y by ChickensEatGrass, AccurateArmadillo7676, PikaPika999, GodGodGodGodGoose
I have a theory: you know how sometimes preschoolers will be like "I can write cursive!" and hold up a piece of paper with nonsensical squiggly lines? Maybe this is like that. You saw other sequence problems in kindergarten, so you decided to create one and wrote some random numbers that seemed to kind of have a pattern.

I hate to be pessimistic, but that might be the case.
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Gavin_Deng
802 posts
#12 • 1 Y
Y by GodGodGodGodGoose
I finally understand why he chose “papermath” as his username.
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Charizard_637
109 posts
#13 • 2 Y
Y by PikaPika999, GodGodGodGodGoose
WAIT WAIT WAIT I THINK I SOLVED IT
and I swear on my entire math career I didn’t use any sort of ai I sat at my desk for an hour) I made nats at Mathcounts this year)

Quadruple each term:
4, 8, 20, 160, 5120
160 = 4^2 * 20 / 2
5120 = 8^2 * 160 / 2
A possible sequence could be a(n) = (a(n-3))^2 * a(n-1). This gives probable cause that the next term is 20^2 * 5120 / 2 =1,024,000, but remember we quadrupled at the beginning, so let’s unquadruple; 256,000
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Charizard_637
109 posts
#14 • 2 Y
Y by PikaPika999, GodGodGodGodGoose
Charizard_637 wrote:
WAIT WAIT WAIT I THINK I SOLVED IT
and I swear on my entire math career I didn’t use any sort of ai I sat at my desk for an hour) I made nats at Mathcounts this year)

Quadruple each term:
4, 8, 20, 160, 5120
160 = 4^2 * 20 / 2
5120 = 8^2 * 160 / 2
A possible sequence could be a(n) = (a(n-3))^2 * a(n-1). This gives probable cause that the next term is 20^2 * 5120 / 2 =1,024,000, but remember we quadrupled at the beginning, so let’s unquadruple; 256,000

This is obviously subjective to being incorrect, but the sample size for this kind of sequence is too small, leaving endless possibilities. I believe mine was one of the most straightforward, although I hope someone can find an even better tentative one.
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Yrock
1275 posts
#15 • 2 Y
Y by PikaPika999, GodGodGodGodGoose
Gaslighted ChatGPT into solving this... Used both of SirAppel's functions.. so 69420!
hidden for length
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