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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

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Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
mathcounts state score thread
Soupboy0   68
N 7 minutes ago by Eddie_tiger
\begin{table}[]
\begin{tabular}{llllll}
Username & Score & Sprint & Target & Nats? & Sillies \\
     Soupboy0    &     40  &     24   &   16     &    yes  &    6     \\
         &       &        &        &       &         \\
         &       &        &        &       &        
\end{tabular}\end{table}
68 replies
Soupboy0
Apr 1, 2025
Eddie_tiger
7 minutes ago
2025 MATHCOUNTS State Hub
SirAppel   384
N 19 minutes ago by sadas123
Previous Years' "Hubs": (2022) (2023) (2024)Please Read

Now that it's April and we're allowed to discuss, and no one else has made this yet ...
[list=disc]
[*] CA: 43 (45 44 43 43 43 42 42 41 41 41)
[*] NJ: 43 (45 44 44 43 39 42 40 40 39 38) *
[*] NY: 42 (43 42 42 42 41 40)
[*] TX: 42 (43 43 43 42 42 40 40 38 38 38)
[*] MA: 41 (45 43 42 41)
[*] WA: 41 (41 45 42 41 41 41 41 41 41 40) *
[*] FL: 39 (42 41 40 39 38 37 37)
[*] IN: 39 (41 40 40 39 36 35 35 35 34 34)
[*] NC: 39 (42 42 41 39)
[*] IL: 38 (41 40 39 38 38 38)
[*] OR: 38 (44 41? 38 38)
[*] PA: 38 (41 40 40 38 38 37 36 36 34 34) *
[*] MD: 37 (43 39 39 37 37 37)
[*] CT: 36 (44 39? 38 36 34 34 34 34)
[*] MI: 36 (39 41 41 36 37 37 36 36 36 36) *
[*] MN: 36 (40 36 36 36 35 35 35 34)
[*] CO: 35 (41 37 37 35 35 35 ?? 31 31 30) *
[*] GA: 35 (38 37 36 35 34 34 34 34 34 33)
[*] OH: 35 (41 37 36 35)
[*] AR: 34 (46 45 35 34 33 31 31 31 29 29)
[*] WI: 34 (40 37 37 34 35 30 28 29 29 29) *
[*] HI: 32 (35 34 32 32)
[*] NH: 31 (42 35 33 31 30)
[*] DE: 30 (34 33 32 30 30 29 28 27 26? 24)
[*] SC: 30 (33 33 31 30)
[*] IA: 29 (33 30 31 29 29 29 29 29 29 29 29 29) *
[*] NE: 28 (34 30 28 28 27 27 26 26 25 25)
[*] SD: 22 (30 29 24 22 22 22 21 21 20 20)
[/list]
Cutoffs Unknown

* means that CDR is official in that state.

Notes

For those asking about the removal of the tiers, I'd like to quote Jason himself:
[quote=peace09]
learn from my mistakes
[/quote]

Help contribute by sharing your state's cutoffs!
As per last year's guidelines, refrain from problem discussion until their official release on the MATHCOUNTS website.
384 replies
SirAppel
Apr 1, 2025
sadas123
19 minutes ago
STATE SOLUTIONS AND STUFF DROPPED!!!
Soupboy0   29
N 24 minutes ago by Andyluo
https://www.mathcounts.org/resources/past-competitions
29 replies
+1 w
Soupboy0
Yesterday at 5:44 PM
Andyluo
24 minutes ago
FTW tournament!
evt917   238
N an hour ago by K124659
[center]Since all FTW tournaments have dramatically failed, I'm trying a different format. Here is how it works:

1. Type \signup{your rating (type 800 for unrated)}

2. You will pick who you want to play with. You can play if they accept your challenge. So basically the players run everything. Just don't intentionally play low-rated people. Also try to play different people so everyone gets a chance to play! ONLY two player games.

3. If you win, you get 2 points. Ties get one point, and losses get zero.

4. I do not know everybody's time preferences. Because so, I will announce in advance which two players will be playing, so they themselves can organize a game themselves. Remember, THE PLAYERS ARE ORGANIZING THE GAMES THEMSELVES!!! The format is up to them, but please make the time control at least 20 seconds. Please announce the results of the game here so i can update the scoreboard. Games can be unrated.

recommended format if you cannot decide



5. The tournament goes on until april 18th! Extremely long, right? Note that you can still signup after the first games has started, but you will have a disadvantage because some people who signed up as soon as the tournament started already has points.

6. Once you are done with your game, you can find a new opponent and play with them if they want. Note that you must play opponents within the tournament. If you play in the tournament, you are automatically signed up. Have fun!


[rule]

Questions and Answers

All signups and ratings

[rule]

LIVE LEADERBOARD:

1st place: 37 points | 12W 2L 3T | Yrock
2nd place: 14 points | 6W 3L 2T | jb2015007
3rd place: 4 points | 1W 2L 0T | IcyFire500

4th place: 3 points | 1W 6L 1T | sadas123
5th place: 0 points | 0W 1L 0T | NS0004
238 replies
evt917
Thursday at 9:34 PM
K124659
an hour ago
Geo Mock #10
Bluesoul   2
N 6 hours ago by Bluesoul
Consider acute $\triangle{ABC}$ with $AB=10$, $AC<BC$ and area $135$. The circle $\omega$ with diameter $AB$ meets $BC$ at $E$. Let the orthocenter of the triangle be $H$, connect $CH$ and extend to meet $\omega$ at $N$ such that $NC>HC$ and $NE$ is the diameter of $\omega$. Draw the circumcircle $\Gamma$ of $\triangle{AHB}$, chord $XY$ of $\Gamma$ is tangent to $\omega$ and it passes through $N$, compute $XY$.
2 replies
Bluesoul
Apr 1, 2025
Bluesoul
6 hours ago
Inequalities
sqing   4
N Yesterday at 3:28 PM by sqing
Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=11.$ Prove that
$$a+ab+abc\leq\frac{49}{6}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=10.$ Prove that
$$a+ab+abc\leq\frac{169}{24}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=14.$ Prove that
$$a+ab+abc\leq\frac{63+5\sqrt 5}{6}$$Let $ a, b,c\geq 0 $ and $ 2a+3b+ 4c=32.$ Prove that
$$a+ab+abc\leq48+\frac{64\sqrt{2}}{3}$$
4 replies
sqing
Apr 1, 2025
sqing
Yesterday at 3:28 PM
Geo Mock #9
Bluesoul   1
N Yesterday at 3:19 PM by vanstraelen
Consider $\triangle{ABC}$ with $AB=12, AC=22$. The points $D,E$ lie on $AB,AC$ respectively, such that $\frac{AD}{BD}=\frac{AE}{CE}=3$. Extend $CD,BE$ to meet the circumcircle of $\triangle{ABC}$ at $P,Q$ respectively. Let the circumcircles of $\triangle{ADP}, \triangle{AEQ}$ meet at points $A,T$. Extend $AT$ to $BC$ at $R$, given $AR=16$, find $[ABC]$.
1 reply
Bluesoul
Apr 1, 2025
vanstraelen
Yesterday at 3:19 PM
Regarding IMO prepartion
omega2007   0
Yesterday at 3:14 PM
<Hey Everyone'>
I'm 10 grader student and Im starting prepration for maths olympiad..>>> From scratch (not 2+2=4 )

Do you haves compilled resources of Handouts,
PDF,
Links,
List of books topic wise

which are shared on AOPS (and from your prespective) for maths olympiad and any useful thing, which will help me in boosting Maths olympiad prepration.
0 replies
omega2007
Yesterday at 3:14 PM
0 replies
Geo Mock #6
Bluesoul   1
N Yesterday at 1:59 PM by vanstraelen
Consider triangle $ABC$ with $AB=5, BC=8, AC=7$, denote the incenter of the triangle as $I$. Extend $BI$ to meet the circumcircle of $\triangle{AIC}$ at $Q\neq I$, find the length of $QC$.
1 reply
Bluesoul
Apr 1, 2025
vanstraelen
Yesterday at 1:59 PM
Congruence
Ecrin_eren   1
N Yesterday at 1:39 PM by Ecrin_eren
Find the number of integer pairs (x, y) satisfying the congruence equation:

3y² + 3x²y + y³ ≡ 3x² (mod 41)

for 0 ≤ x, y < 41.

1 reply
Ecrin_eren
Thursday at 10:34 AM
Ecrin_eren
Yesterday at 1:39 PM
Probability
Ecrin_eren   1
N Yesterday at 1:38 PM by Ecrin_eren
In a board, James randomly writes A , B or C in each cell. What is the probability that, for every row and every column, the number of A 's modulo 3 is equal to the number of B's modulo 3?

1 reply
Ecrin_eren
Thursday at 11:21 AM
Ecrin_eren
Yesterday at 1:38 PM
Excalibur Identity
jjsunpu   9
N Yesterday at 12:21 PM by fruitmonster97
proof is below
9 replies
jjsunpu
Thursday at 3:27 PM
fruitmonster97
Yesterday at 12:21 PM
.problem.
Cobedangiu   2
N Yesterday at 12:06 PM by Lankou
Find the integer coefficients after expanding Newton's binomial:
$$(\frac{3}{2}-\frac{2}{3}x^2)^n (n \in Z)$$
2 replies
Cobedangiu
Yesterday at 6:20 AM
Lankou
Yesterday at 12:06 PM
Inequalities
sqing   23
N Yesterday at 11:43 AM by sqing
Let $ a,b,c\geq 0 $ and $a+b+c=1$. Prove that
$$a^2+b^2+ ab +21abc\leq\frac{512}{441}$$Equality holds when $a=b=\frac{38}{21},c=\frac{5}{214}.$
$$a^2+b^2+ ab +19abc\leq\frac{10648}{9747}$$Equality holds when $a=b=\frac{22}{57},c=\frac{13}{57}.$
$$a^2+b^2+ ab +22abc\leq\frac{15625}{13068}$$Equality holds when $a=b=\frac{25}{66},c=\frac{8}{33}.$
23 replies
sqing
Mar 26, 2025
sqing
Yesterday at 11:43 AM
Something Horrible-a Challenge
Xueshuxue   23
N Mar 31, 2025 by Demetri
Hello, I was wondering if it's possible to make 8 with the numbers 5, 3, 5, and 7 under the following rules:
-You can only use 5 twice, 3 once, and 7 once.
-You must use all the numbers.
You can stack numbers to form larger numbers (example: I could take 3 and 5 and turn it into 35 or 53, or use 7, 3, and 5 to make 375.)
-You are allowed to use parentheses.
(Also, I already found out that no 3 digital numbers will work for the solution.)
23 replies
Xueshuxue
Mar 28, 2025
Demetri
Mar 31, 2025
Something Horrible-a Challenge
G H J
G H BBookmark kLocked kLocked NReply
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Xueshuxue
45 posts
#1
Y by
Hello, I was wondering if it's possible to make 8 with the numbers 5, 3, 5, and 7 under the following rules:
-You can only use 5 twice, 3 once, and 7 once.
-You must use all the numbers.
You can stack numbers to form larger numbers (example: I could take 3 and 5 and turn it into 35 or 53, or use 7, 3, and 5 to make 375.)
-You are allowed to use parentheses.
(Also, I already found out that no 3 digital numbers will work for the solution.)
Z K Y
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Inaaya
220 posts
#2
Y by
(5x3)-7 !!!
Z K Y
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sanaops9
817 posts
#3
Y by
you need to use both fives rbo

you didn't mention what functions to use so $\lfloor{\dfrac{55+3}{7}\rfloor}$
This post has been edited 1 time. Last edited by sanaops9, Mar 28, 2025, 7:28 PM
Z K Y
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derekwang2048
1208 posts
#4
Y by
if you're allowed to use more than just the basic operations, this is simple
This post has been edited 2 times. Last edited by derekwang2048, Mar 28, 2025, 7:29 PM
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sanaops9
817 posts
#5
Y by
@above, you can use \lfloor and \rfloor for left floor and right floor, respectively.

EDIT: ig u figured it out
This post has been edited 2 times. Last edited by sanaops9, Mar 28, 2025, 7:31 PM
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vincentwant
1282 posts
#6 • 1 Y
Y by ARWonder
Click to reveal hidden text
Z K Y
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Solocraftsolo
2458 posts
#7
Y by
the answer is obviously

\[|P\left(\left\lfloor \sqrt{\sqrt{\left\lceil \sqrt{\left\lfloor \sqrt{\left\lceil \sqrt{\sqrt{\left\lfloor \sqrt{\sqrt{\left\lceil \sqrt{\sqrt{\sqrt{5537}}}\right\rceil !!}}\right\rfloor !}}\right\rceil !}\right\rfloor !}\right\rceil !}}\right\rfloor\right)|\]

where the P function is the power set and the | | means cardinality
This post has been edited 1 time. Last edited by Solocraftsolo, Mar 28, 2025, 8:51 PM
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Leeoz
165 posts
#8 • 2 Y
Y by Exponent11, TTNT
chat gpt cooked
chat gpt wrote:
To make 8 using only the numbers **3**, **5**, **5**, and **7**, one possible solution is:

\[
(5 + 5) - (7 - 3) = 8
\]
Explanation:
- First, add the two 5s: \(5 + 5 = 10\).
- Then, subtract the difference between 7 and 3: \(7 - 3 = 4\).
- Finally, subtract 4 from 10: \(10 - 4 = 8\).

This gives you 8!
Z K Y
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ChickensEatGrass
42 posts
#9
Y by
Leeoz wrote:
chat gpt cooked
chat gpt wrote:
To make 8 using only the numbers **3**, **5**, **5**, and **7**, one possible solution is:

\[
(5 + 5) - (7 - 3) = 8
\]
Explanation:
- First, add the two 5s: \(5 + 5 = 10\).
- Then, subtract the difference between 7 and 3: \(7 - 3 = 4\).
- Finally, subtract 4 from 10: \(10 - 4 = 8\).

This gives you 8!

what the heck
Z K Y
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huajun78
49 posts
#11
Y by
Leeoz wrote:
chat gpt cooked
chat gpt wrote:
To make 8 using only the numbers **3**, **5**, **5**, and **7**, one possible solution is:

\[
(5 + 5) - (7 - 3) = 8
\]
Explanation:
- First, add the two 5s: \(5 + 5 = 10\).
- Then, subtract the difference between 7 and 3: \(7 - 3 = 4\).
- Finally, subtract 4 from 10: \(10 - 4 = 8\).

This gives you 8!

$6=8$, proof by ChatGPT
Z K Y
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SirAppel
863 posts
#12
Y by
$(5+3)^{\lfloor \frac{7}{5} \rfloor}$
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cheltstudent
550 posts
#13
Y by
$lcm(7,5) - 3^{3}=8$
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Soupboy0
277 posts
#14 • 1 Y
Y by PuppyPenguinDolphin
$\frac{5!}{3!}-5-7$
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Owen314159
11 posts
#15
Y by
Soupboy0 wrote:
$\frac{5!}{3!}-5-7$

I think this is the most normal sol
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RandomMathGuy500
54 posts
#16
Y by
chat gpt wrote:
You can make 8 using the numbers 5, 5, 3, and 7 with the following equation:
$(7+3)-(5+5)=8$
Z K Y
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Total_Awesomeness
240 posts
#17
Y by
derekwang2048 wrote:
if you're allowed to use more than just the basic operations, this is simple

ur not allowed to use 8
Z K Y
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happymoose666
294 posts
#18
Y by
he is not using 8, it's an equal sign
This post has been edited 1 time. Last edited by happymoose666, Mar 29, 2025, 10:37 PM
Reason: yes
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Total_Awesomeness
240 posts
#19
Y by
no at the end
he says that it equals the digit 8, which is not allowed
Z K Y
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sanaops9
817 posts
#20
Y by
Owen314159 wrote:
Soupboy0 wrote:
$\frac{5!}{3!}-5-7$

I think this is the most normal sol
vincentwant wrote:
Click to reveal hidden text

No vincent's was prolly the best and intended sol
Z K Y
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pieMax2713
4168 posts
#21
Y by
$|\{5, 5, 7\}|^3$ where | | denotes cardinality
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K1mchi_
6 posts
#22 • 1 Y
Y by ChickensEatGrass
(7!/(5!+3!))/5
I just used lots of factorial
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WiseHawkCuteFriendly
565 posts
#23
Y by
chat gpt wrote:
$\frac{7+5}{3}+5=8$,
reasoning: $\frac{12}{3}+5=8$
$4+5=8$
This post has been edited 2 times. Last edited by WiseHawkCuteFriendly, Mar 31, 2025, 1:46 AM
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happymoose666
294 posts
#24
Y by
Total_Awesomeness wrote:
no at the end
he says that it equals the digit 8, which is not allowed

But he meant $\frac{55+\lfloor{\sqrt3}\rfloor}{7}$ is equal to 8, so he solved the problem, he is not using eight
This post has been edited 2 times. Last edited by happymoose666, Mar 31, 2025, 1:21 PM
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Demetri
1204 posts
#25
Y by
Soupboy0 wrote:
$\frac{5!}{3!}-5-7$

I think this is the most normal sol
This doesn't use factorials
Click to reveal hidden text
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