2008 iTest Problems/Problem 32
Revision as of 20:50, 4 August 2018 by Rockmanex3 (talk | contribs) (Solution to Problem 32 (Credit to r_fractal))
Problem
A right triangle has perimeter , and the area of a circle inscribed in the triangle is
. Let A be the area of the triangle. Compute
.
Solution
We know the perimeter and area of incircle, so we can find the semiperimeter of the triangle and radius of the incircle and plug the values into the area formula
The semiperimeter of the triangle is The radius of the incircle is
. That means the area of the triangle is
By using a calculator (or noting that ), the value
is around
so
.
See Also
2008 iTest (Problems) | ||
Preceded by: Problem 31 |
Followed by: Problem 33 | |
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