Difference between revisions of "2008 iTest Problems/Problem 3"

(Created page with "(storyline deleted) What is the average of <math>181,</math> <math>197,</math> <math>203,</math> <math>204,</math> <math>212,</math> and <math>227?</math> ==Solution== The a...")
 
 
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==Problem==
  
What is the average of <math>181,</math> <math>197,</math> <math>203,</math> <math>204,</math> <math>212,</math> and <math>227?</math>
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Michael plays catcher for his school's baseball team. He has always been a great player behind the plate, but this year as a junior, Michael's offense is really improving.
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His batting average is <math>.417</math> after six games, and the team is <math>6-0</math> (six wins and no losses). They are off to their best start in years.
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On the way home from their sixth game, Michael notes to his father that the attendance seems to be increasing due to the team's great start, "There were <math>181</math>  
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people at the first game, then <math>197</math> at the second, <math>203</math> the third, <math>204</math> the fourth, <math>212</math> at the fifth, and there were <math>227</math> at today's game." Just then, Michael's
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genius younger brother Tony, just seven-years-old, computes the average attendance of the six games. What is their average? 
  
 
==Solution==
 
==Solution==
The average of <math>n</math> numbers is the sum of <math>n</math> numbers divided by <math>n.</math> Doing the following gives the answer as <math>\frac{181+197+203+204+212+227}{6}=\boxed{204.}</math>
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The average of <math>n</math> numbers is the sum of <math>n</math> numbers divided by <math>n.</math> Doing the following gives the answer as <math>\frac{181+197+203+204+212+227}{6}=\boxed{204}</math>.
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==See Also==
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{{2008 iTest box|num-b=2|num-a=4}}

Latest revision as of 00:14, 22 June 2018

Problem

Michael plays catcher for his school's baseball team. He has always been a great player behind the plate, but this year as a junior, Michael's offense is really improving. His batting average is $.417$ after six games, and the team is $6-0$ (six wins and no losses). They are off to their best start in years.

On the way home from their sixth game, Michael notes to his father that the attendance seems to be increasing due to the team's great start, "There were $181$ people at the first game, then $197$ at the second, $203$ the third, $204$ the fourth, $212$ at the fifth, and there were $227$ at today's game." Just then, Michael's genius younger brother Tony, just seven-years-old, computes the average attendance of the six games. What is their average?

Solution

The average of $n$ numbers is the sum of $n$ numbers divided by $n.$ Doing the following gives the answer as $\frac{181+197+203+204+212+227}{6}=\boxed{204}$.

See Also

2008 iTest (Problems)
Preceded by:
Problem 2
Followed by:
Problem 4
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