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Tech support and questions about AoPS classes and materials
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Site Support Tech support and questions about AoPS classes and materials
Tech support and questions about AoPS classes and materials
3 M G
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P lies on BC
Melid   0
32 minutes ago
Source: own
In scalene triangle $ABC$, which doesn't have right angle, let $O$ be its circumcenter. Let $H_{1}$ and $H_{2}$ be orthocenters of triangle $ABO$ and $ACO$, respectively. Let $O_{1}$ be circumcenter of triangle $OH_{1}H_{2}$. If circle $ACO_{1}$ and circle $CH_{1}H_{2}$ intersect at $P$ for the second time, prove that $P$ lies on $BC$.
0 replies
Melid
32 minutes ago
0 replies
Polynomial functional equation
Fishheadtailbody   2
N an hour ago by Fishheadtailbody
Source: MACMO
$P(x)$ is a polynomial with real coefficients such that
\[ P(x)^2 - 1 = 4 P(x^2 - 4x + 1). \]Find $P(x)$.

fixed now
2 replies
Fishheadtailbody
Apr 18, 2025
Fishheadtailbody
an hour ago
Strange circles in an orthocenter config
VideoCake   2
N an hour ago by pi_quadrat_sechstel
Source: 2025 German MO, Round 4, Grade 12, P3
Let \(\overline{AD}\) and \(\overline{BE}\) be altitudes in an acute triangle \(ABC\) which meet at \(H\). Suppose that \(DE\) meets the circumcircle of \(ABC\) at \(P\) and \(Q\) such that \(P\) lies on the shorter arc of \(BC\) and \(Q\) lies on the shorter arc of \(CA\). Let \(AQ\) and \(BE\) meet at \(S\). Show that the circumcircles of \(BPE\) and \(QHS\) and the line \(PH\) concur.
2 replies
VideoCake
May 26, 2025
pi_quadrat_sechstel
an hour ago
Lines pass through a common point
April   5
N an hour ago by SatisfiedMagma
Source: Baltic Way 2008, Problem 18
Let $ AB$ be a diameter of a circle $ S$, and let $ L$ be the tangent at $ A$. Furthermore, let $ c$ be a fixed, positive real, and consider all pairs of points $ X$ and $ Y$ lying on $ L$, on opposite sides of $ A$, such that $ |AX|\cdot |AY| = c$. The lines $ BX$ and $ BY$ intersect $ S$ at points $ P$ and $ Q$, respectively. Show that all the lines $ PQ$ pass through a common point.
5 replies
April
Nov 23, 2008
SatisfiedMagma
an hour ago
Parameter and 4 variables
mihaig   1
N an hour ago by mihaig
Source: Own
Find the positive real constants $K$ such that
$$3\left(a^2+b^2+c^2+d^2\right)+4\left(abcd\right)^K\geq\left(a+b+c+d\right)^2$$for all $a,b,c,d\geq0$ satisfying $a+b+c+d\geq4.$
1 reply
mihaig
2 hours ago
mihaig
an hour ago
Old Inequality
giangtruong13   0
an hour ago
Let $a,b,c >0$ and $abc=1$. Prove that: $$  \sqrt{a^2-a+1}+\sqrt{b^2-b+1} +\sqrt{c^2-c+1} \ge a+b+c$$
0 replies
+1 w
giangtruong13
an hour ago
0 replies
How many friends can sit in that circle at most?
Arytva   0
an hour ago

A group of friends sits in a ring. Each friend picks a different whole number and holds a stone marked with it. Then they pass their stone one seat to the right so everyone ends up with two stones: one they made and one they received. Now they notice something odd: if your original number is $x$, your right-neighbor’s is $y$, and the next person over is $z$, then for every trio in the circle they see

$$
x + z = (2 - x)\,y.
$$
They want as many friends as possible before this breaks (since all stones must stay distinct).

How many friends can sit in that circle at most?
0 replies
Arytva
an hour ago
0 replies
Reflected point lies on radical axis
Mahdi_Mashayekhi   7
N an hour ago by amogususususus
Source: Iran 2025 second round P4
Given is an acute and scalene triangle $ABC$ with circumcenter $O$. $BO$ and $CO$ intersect the altitude from $A$ to $BC$ at points $P$ and $Q$ respectively. $X$ is the circumcenter of triangle $OPQ$ and $O'$ is the reflection of $O$ over $BC$. $Y$ is the second intersection of circumcircles of triangles $BXP$ and $CXQ$. Show that $X,Y,O'$ are collinear.
7 replies
Mahdi_Mashayekhi
Apr 19, 2025
amogususususus
an hour ago
Shortlist 2017/G3
fastlikearabbit   124
N 2 hours ago by ND_
Source: Shortlist 2017, Moldova TST 2018
Let $O$ be the circumcenter of an acute triangle $ABC$. Line $OA$ intersects the altitudes of $ABC$ through $B$ and $C$ at $P$ and $Q$, respectively. The altitudes meet at $H$. Prove that the circumcenter of triangle $PQH$ lies on a median of triangle $ABC$.
124 replies
+1 w
fastlikearabbit
Jul 10, 2018
ND_
2 hours ago
Is there a good solution?
sadwinter   0
2 hours ago
:maybe: :love: :love:
0 replies
sadwinter
2 hours ago
0 replies
a