G 4 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

by utkarshgupta, Oct 12, 2014, 2:33 AM

OK !
This one was actually quite simple.

Problem (ISL 2001 G4) :
Let $M$ be a point in the interior of triangle $ABC$. Let $A'$ lie on $BC$ with $MA'$ perpendicular to $BC$. Define $B'$ on $CA$ and $C'$ on $AB$ similarly. Define

\[
p(M) = \frac{MA' \cdot MB' \cdot MC'}{MA \cdot MB \cdot MC}.
\]

Determine, with proof, the location of $M$ such that $p(M)$ is maximal. Let $\mu(ABC)$ denote this maximum value. For which triangles $ABC$ is the value of $\mu(ABC)$ maximal ?

Solution :
The solution is actually smaller than the question :P

Let $\angle BAM= \angle 1$, $\angle CAM= \angle 2$, $\angle ACM= \angle 3$, $\angle BCM= \angle 4$, $\angle CBM= \angle 5$, $\angle ABM= \angle 6$


Quite simply,
$p(M)^2=\prod _{i=1}^{6} \sin (\angle i) \le (\sin (\frac{\sum \angle i}{6})^6 = \frac{1}{2^6}$

$p(M)=\frac{1}{8}$ holds when the triangle is equilateral and $M$ is circumcentre
This post has been edited 1 time. Last edited by utkarshgupta, Jan 2, 2015, 12:42 PM

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Stay insane,Coz it's your will, labour and pain,which takes you to the top of the mountain.

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  • Let's all echo what's written in the blog description - Stay Insane / 'Cause it's your labor, will and pain/ That takes you to the top of soda fountain :D

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    I may try some combinatorics :P

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