no. of divisors of the form

by S_14159, Apr 10, 2025, 9:25 AM

If $P=2^5 \cdot 3^6 \cdot 5^4 \cdot 7^3$ then number of positive integral divisors of $``P"$

(A) of form $(2 n+3), n \in \mathbb{N}$, is $=138$
(B) of form $(4 n+1), n \in \mathbb{W}$, is $=70$
(C) of form $(6 n+3), n \in \mathbb{W}$, is $=120$
(D) of form $(4 n+3), n \in \mathbb{W}$, is $=56$

(more than one option may be correct)

max n with n times n square are black

by NicoN9, Apr 10, 2025, 9:19 AM

Find the maximum positive integer $n$ such that for $45\times 45$ grid, no matter how you paint $2022$ unit squares black, there exists $n\times n$ square with all unit square painted black.

BDE tangent to EF

by NicoN9, Apr 10, 2025, 9:10 AM

Let $ABC$ be a triangle with $AB=5$, $BC=7$, $CA=6$. Let $D, E$, and $F$ be points lying on sides $BC, CA, AB$, respectively. Given that $A, B, D, E$, and $B, C, E, F$ are cyclic respectively, and the circumcircle of $BDE$ are tangent to line $EF$, find the length of segment $AE$.
This post has been edited 2 times. Last edited by NicoN9, an hour ago
Reason: Source

Inspired by old results

by sqing, Apr 10, 2025, 8:28 AM

Let $a ,b,c \geq 0 $ and $a+b+c=1$. Prove that
$$\frac{1}{2}\leq \frac{ \left(1-a^{2}\right)^2+2\left(1-b^{2}\right) \left(1-c^{2}\right) }{\left(1+a\right)\left(1+b\right)\left(1+c\right)}\leq 1$$$$1 \leq \frac{\left(1-a^{2}\right)^{2}+2\left(1-b^{2}\right) +\left(1-c^{2}\right)^{2}}{\left(1+a\right)\left(1+b\right)\left(1+c\right)}\leq \frac{3}{2}$$
This post has been edited 1 time. Last edited by sqing, 2 hours ago

Prove that x1=x2=....=x2025

by Rohit-2006, Apr 9, 2025, 5:22 AM

The real numbers $x_1,x_2,\cdots,x_{2025}$ satisfy,
$$x_1+x_2=2\bar{x_1}, x_2+x_3=2\bar{x_2},\cdots, x_{2025}+x_1=2\bar{x_{2025}}$$Where {$\bar{x_1},\cdots,\bar{x_{2025}}$} is a permutation of $x_1,x_2,\cdots,x_{2025}$. Prove that $x_1=x_2=\cdots=x_{2025}$
This post has been edited 1 time. Last edited by Rohit-2006, Yesterday at 5:23 AM

Orthocenter config once again

by Assassino9931, Apr 8, 2025, 1:53 PM

Let \( ABC \) be an acute triangle with \( AB < AC \), midpoint $M$ of side $BC$, altitude \( AD \) (\( D \in BC \)), and orthocenter \( H \). A circle passes through points \( B \) and \( D \), is tangent to line \( AB \), and intersects the circumcircle of triangle \( ABC \) at a second point \( Q \). The circumcircle of triangle \( QDH \) intersects line \( BC \) at a second point \( P \). Prove that the lines \( MH \) and \( AP \) are perpendicular.

interesting ineq

by nikiiiita, Jan 29, 2025, 10:27 AM

Given $a,b,c$ are positive real numbers satisfied $a^3+b^3+c^3=3$. Prove that:
$$\sqrt{2ab+5c^{2}+2a}+\sqrt{2bc+5a^{2}+2b}+\sqrt{2ac+5b^{2}+2c}\le3\sqrt{3\left(a+b+c\right)}$$
This post has been edited 1 time. Last edited by nikiiiita, Jan 29, 2025, 10:29 AM

Maximum number of m-tastic numbers

by Tsukuyomi, Jul 10, 2018, 1:11 PM

Call a rational number short if it has finitely many digits in its decimal expansion. For a positive integer $m$, we say that a positive integer $t$ is $m-$tastic if there exists a number $c\in \{1,2,3,\ldots ,2017\}$ such that $\dfrac{10^t-1}{c\cdot m}$ is short, and such that $\dfrac{10^k-1}{c\cdot m}$ is not short for any $1\le k<t$. Let $S(m)$ be the set of $m-$tastic numbers. Consider $S(m)$ for $m=1,2,\ldots{}.$ What is the maximum number of elements in $S(m)$?
This post has been edited 2 times. Last edited by v_Enhance, Jan 20, 2022, 1:01 AM
Reason: fix "the the"

Matrices :D :D :D

by utkarshgupta, Jul 4, 2016, 3:56 AM

Long time people :P
This sure is nice and I wouldn't have been able to solve it without first solving the $3 \times 3$ version.

Problem (Romanian Mathematical Olympiad Grade XI) :
Let $ A=(a_{ij})_{1\leq i,j\leq n}$ be a real $ n\times n$ matrix, such that $ a_{ij} + a_{ji} = 0$, for all $ i,j$. Prove that for all non-negative real numbers $ x,y$ we have \[ \det(A+xI_n)\cdot \det(A+yI_n) \geq \det (A+\sqrt{xy}I_n)^2.\]
Solution :
Let $f(x)=det(A+xI_{n})$
Obviously $f$ is a polynomial.
So we have to show that $f(x)f(y) \ge f(\sqrt{xy})^2$

But the above result will follow directly once we establish that all the coefficients of $f$ are positive.
$f(0)=0$ obviously.

I will call the kind of matrices asked in the question as ski matrix.
To show this I will use induction on the order of the matrix.
Let the result be true for all such $n-1 \times n-1$ ski matrices.

Now consider any $n \times n$ such ski matrix and call it $f_n(x)$.
Then,
$$f_n(x) = \int^{x}_{0} f_{n}^{'}(x)$$But obviously since $f_{n}^{'}(x)$ is a sum of determinants of ski matrices of the order $n-1 \times n-1$, all it's coefficients by the induction hypothesis are positive and hence so are it's integrals (except the constants which we have already established as zero).

Hence $f(x)$ has all it's coefficients positive and hence by Cauchy Schwartz inequality, we are done.

Angle EBA is equal to Angle DCB

by WakeUp, Nov 6, 2011, 1:25 PM

Let $ABCD$ be a convex quadrilateral such that $\angle ADB=\angle BDC$. Suppose that a point $E$ on the side $AD$ satisfies the equality
\[AE\cdot ED + BE^2=CD\cdot AE.\]
Show that $\angle EBA=\angle DCB$.

if xy+xz+yz+2xyz+1 prove that...

by behdad.math.math, Sep 25, 2008, 8:17 PM

if xy+xz+yz+2xyz+1 prove that x+y+z>=3/2

Stay insane,Coz it's your will, labour and pain,which takes you to the top of the mountain.

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  • First post of 2024

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  • First post of 2023

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  • Nice blog ! Your isogonality lemma is really powerful !

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  • Post plss....

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  • alas,this is ded

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  • Thanks for the nice blog.

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  • I think this might be silly but ... when should we expect to have another post ?? I am very keen to see it :D

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  • Let's all echo what's written in the blog description - Stay Insane / 'Cause it's your labor, will and pain/ That takes you to the top of soda fountain :D

    by Kayak, Oct 2, 2017, 7:18 PM

  • hey utkarsh jee is over now ... continue your elementary blog pleaseeeeeee!

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  • Congrats on becoming a contest moderator!

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  • INTERSTING BLOG

    by kk108, Feb 19, 2017, 2:04 PM

  • I have no plans for this blog right now....
    No time here people !
    But lets see....
    I may try some combinatorics :P

    by utkarshgupta, Feb 15, 2017, 12:47 PM

  • Thanks for the nice blog!

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  • Revive it!!!
    Best blog out there, for sure!

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