Help with Competitive Geometry?

by REACHAW, Apr 14, 2025, 11:51 PM

Hi everyone,
I'm struggling a lot with geometry. I've found algebra, number theory, and even calculus to be relatively intuitive. However, when I took geometry, I found it very challenging. I stumbled my way through the class and can do the basic 'textbook' geometry problems, but still struggle a lot with geometry in competitive math. I find myself consistently skipping the geometry problems during contests (even the easier/first ones).

It's difficult for me to see the solution path. I can do the simpler textbook tasks (eg. find congruent triangles) but not more complex ones (eg. draw these two lines to form similar triangles).

Do you have any advice, resources, or techniques I should try?

Algebra book recomndaitons

by idk12345678, Apr 14, 2025, 10:45 PM

Im currently reading EGMO by Evan Chen and i was wondering if there was a similar book for olympiad algebra. I have egmo for geo and aops intermediate c&p for combo, and the intermediate number thoery transcripts for nt, but i couldnt really find anything for alg

US Puzzle Championship Scorecards

by djmathman, Apr 14, 2025, 5:52 PM

Some of the discussion in the Contests & Programs SMT thread reminded me of Scorecards puzzles from the US Puzzle Championship. They behave similarly to "24 game" puzzles, but the allowable operations are slightly expanded.
Scorecards rules wrote:
Operations are limited to addition ("+"), subtraction ("-"), multiplication ("x"), division ("/"), and exponentiation ("^").
Decimal points may be used; ...; use minus sign ("-") to indicate negative values. Use parentheses if needed to disambiguate operator precedence.
As an example, the puzzle $11 \leftarrow 5,8,9$ would have answer $8 + 9^{.5} = 11$.

These have appeared on the USPC three years: 2018, 2022, and 2023. Try your hand at these! Some of them are much more devious than they first appear.
  1. 2018
    1. $30\leftarrow 4, 5, 8$
    2. $25\leftarrow 2,6,9$
    3. $23\leftarrow 4,5,9$
  2. 2022
    1. $13\leftarrow 3,6,7$
    2. $24\leftarrow 3,8,8$
    3. $25\leftarrow 3,3,4$
  3. 2023
    1. $26\leftarrow 5,5,6$
    2. $15\leftarrow 2,6,8$
    3. $11\leftarrow 2,8,9$
This post has been edited 1 time. Last edited by djmathman, Yesterday at 5:54 PM

Algebra Problems

by ilikemath247365, Apr 14, 2025, 4:52 PM

Find all real $(a, b)$ with $a + b = 1$ such that

$(a + \frac{1}{a})^{2} + (b + \frac{1}{b})^{2} = \frac{25}{2}$.
L

Find the angle

by pythagorazz, Apr 14, 2025, 9:07 AM

Let $X$ be a point inside equilateral triangle $ABC$ such that $AX=\sqrt{2},BX=3$, and $CX=\sqrt{5}$. Find the measure of $\angle{AXB}$ in degrees.

Trigonometry

by pythagorazz, Apr 14, 2025, 9:03 AM

Let \( A \), \( B \), and \( C \) be the angles of an acute triangle such that
\[
\cos^2 A + \cos^2 B + 2 \sin A \sin B \cos C = \frac{34}{25},
\]and
\[
\cos^2 B + \cos^2 C + 2 \sin B \sin C \cos A = \frac{34}{25}.
\]Find
\[
\cos^2 C + \cos^2 A + 2 \sin C \sin A \cos B.
\]

Vietnam Mock Test

by imnotgoodatmathsorry, Apr 13, 2025, 4:13 PM

Second Entrance Mock test for grade 10 specialized in Mathematics at High School for Gifted Students, HNUE, Vietnam
13/4/2025

Problem 1:
1) Let $a,b$ be positive reals. Prove that: $\frac{a}{a+1} + \frac{b}{b+2} < \frac{\sqrt{a} + \sqrt{b}}{2}$
2) In a small garden there are $3$ rabbits and $3$ carrots. Each rabbit will choose randomly a carrot to eat. Find the probability of a carrot was chose by less than $2$ rabbit.
Problem 2:
1) Solve the equation system: $(x+y)(x^2+y^2)=567$ and $\sqrt{xy}(x+y)^2=243$
2) Let $a,b,c$ be positive rational numbers such that: $a+b+c=2\sqrt{abc}$
Problem 3:
Let triangle $ABC$ ($\angle A$, $\angle B$, $\angle C < 90$) with excircle $(O)$ and incircle $(I)$. Incircle $(I)$ touches $BC,CA,AB$ at $D,E,F$. The excircle with the diameter of $AI$ cuts excircle $(O)$ at $K$ ($K \neq A$). $KD$ cuts the excircle with the diameter of $AI$ at $P$ ($P \neq K$) and $AK$ cuts $BC$ at $Q$. Prove that:
1) $\Delta KEC$ ~ $\Delta KFB$ and $KD$ is the bisector of $\angle BKC$
2) $AP \bot  BC$
3) $IQ$ is the tangent line of the excircle of $\Delta IBC$
Problem 4,5: (will type tomorrow)
Attachments:
This post has been edited 1 time. Last edited by imnotgoodatmathsorry, Sunday at 4:14 PM

how many quadrilaterals ?

by Ecrin_eren, Apr 13, 2025, 4:01 PM

"All the diagonals of an 11-gon are drawn. How many quadrilaterals can be formed using these diagonals as sides? (The vertices of the quadrilaterals are selected from the vertices of the 11-gon.)"

Inequalities

by sqing, Apr 9, 2025, 2:40 PM

Let $ a,b,c $ be real numbers so that $ a+2b+3c=2 $ and $ 2ab+6bc+3ca =1. $ Show that
$$-\frac{1}{6} \leq ab-bc+ ca\leq \frac{1}{2}$$$$\frac{5-\sqrt{61}}{9} \leq a-b+c\leq \frac{5+\sqrt{61}}{9} $$
This post has been edited 1 time. Last edited by sqing, Apr 9, 2025, 2:41 PM

Probability

by Ecrin_eren, Apr 3, 2025, 11:21 AM

In a board, James randomly writes A , B or C in each cell. What is the probability that, for every row and every column, the number of A 's modulo 3 is equal to the number of B's modulo 3?

Random Random FE

by utkarshgupta, Feb 16, 2017, 2:09 AM

Problem :
Find all functions $f : Let $$f:\mathbb{R}\to \mathbb{R}$ such that
$$f(x^{2}+y+f(y))=2y+f(x)^2$$

Okay....
Here it goes...

Solution :
Let $P(x,y)$ be the assertion
$$f(x^{2}+y+f(y))=2y+f(x)^2.$$
And let $k=\frac{-f(0)^2}{2}$
$$P(0,k) \implies f(k)=0$$
Now let if possible, there exist some $a \neq k$ such that $f(a)=0$,
$P(0,a) \implies f(a) = f(0)^2 + 2a \neq 0$

A contradiction !

Hence $f(t) = 0 \implies t = k$.

Let $f(0)=c$ then $k = \frac{-c^2}{2}$.

$$P(k,0) \implies f(k^2+f(0)) = f(k)^2 = 0$$$$\implies k^2 + c = k$$$$\implies c = 0,2$$
Let if possible $c=2 \implies k=-2$
Then $P(0,0) \implies f(2) = 4$
$P(0,k) \implies f(2) = 0$

A contradiction !

$$\boxed {f(0) = 0}$$And there exists no $a \neq 0$ such that $f(a)=0$

$$P(x,\frac{-f(x)^2}{2}) \implies f(x^2 + \frac{-f(x)^2}{2} + f(\frac{-f(x)^2}{2})) = 0$$$$\implies x^2 + \frac{-f(x)^2}{2} + f(\frac{-f(x)^2}{2}) = 0$$
Thus if $f(a) = f(b)$ then $a^2 = b^2$

Let if possible $f(a) = f(-a)$ for some $a \neq 0$
$$f(a + f(a)) = 2a = -f(-a + f(-a))$$
Hence $$f((a+f(a))^2) = f((-a+f(a))^2)$$Since $x^2 > 0$...
We must have $a^2+f(a)^2+2af(a) = a^2 + f(a)^2 - 2af(a)$
That is either $a= 0$ or $f(a) = 0$
A contradiction !

Hence $f$ is injective.


$$P(x,0) \implies f(x^2) = f(x)^2 \ge 0$$$$P(0,y) \implies f(y+f(y)) = 2y$$
Let $z^2 - y^2 + f(z^2) - f(y^2) = x^2$ (assume greater than zero or else we can assume it to be equal to $-x^2$)
$$P(x^2,y^2) \implies f(x^2+y^2 + f(y^2)) = f(x^2) + 2y^2$$$$P(0,z^2) \implies f(z^2+f(z^2)) = 2z^2$$$$\implies f(x^2 + f(z^2) - f(y^2)) = 2(y^2-z^2) = f(x^2 + f(x^2))$$Since $f$ is injective
$$f(x^2+y^2) = f(x^2) + f(y^2)$$.
We also have $-f(x) = f(-x)$ and $f(x^2) > 0$
So by Cauchy we are done !

That is $\boxed {f(x)=x}$ is the only solution !
This post has been edited 2 times. Last edited by utkarshgupta, Feb 16, 2017, 4:31 AM

Stay insane,Coz it's your will, labour and pain,which takes you to the top of the mountain.

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utkarshgupta
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  • Here goes first post of 2025! Great blog.

    by math_holmes15, Jan 14, 2025, 8:53 AM

  • First post of 2024

    by Yiyj1, Feb 8, 2024, 5:40 AM

  • First post of 2023

    by HoRI_DA_GRe8, Jul 22, 2023, 7:45 AM

  • Nice blog ! Your isogonality lemma is really powerful !

    by 554183, Oct 14, 2021, 8:55 AM

  • Post plss....

    by samrocksnature, Apr 11, 2021, 10:12 PM

  • alas,this is ded

    by Hamroldt, Mar 18, 2021, 4:13 PM

  • Thanks for the nice blog.

    by Feridimo, Mar 6, 2020, 4:17 PM

  • I think this might be silly but ... when should we expect to have another post ?? I am very keen to see it :D

    by gamerrk1004, Nov 4, 2019, 4:54 PM

  • Let's all echo what's written in the blog description - Stay Insane / 'Cause it's your labor, will and pain/ That takes you to the top of soda fountain :D

    by Kayak, Oct 2, 2017, 7:18 PM

  • hey utkarsh jee is over now ... continue your elementary blog pleaseeeeeee!

    by kk108, Jun 17, 2017, 11:19 AM

  • Congrats on becoming a contest moderator!

    by Ankoganit, Mar 9, 2017, 5:22 AM

  • INTERSTING BLOG

    by kk108, Feb 19, 2017, 2:04 PM

  • I have no plans for this blog right now....
    No time here people !
    But lets see....
    I may try some combinatorics :P

    by utkarshgupta, Feb 15, 2017, 12:47 PM

  • Thanks for the nice blog!

    by Orkhan-Ashraf_2002, Feb 13, 2017, 6:34 PM

  • Revive it!!!
    Best blog out there, for sure!

    by rmtf1111, Jan 12, 2017, 6:02 PM

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