Functional Equations

by utkarshgupta, Jan 29, 2015, 1:57 PM

Here are some easy ones :P

Problem 1 :

Let $f:R \to R$ be a function such that
\[f(f(x))=x^3+\frac{3}{4}x\]
for all $x \in R$.
Prove that there exists three distinct real numbers $a,b,c$ such that $f(a)+f(b)+f(c)=0$.

Solution :

$(a,b,c)=(f(y),f(0),f(-y))$ clearly satisfy the equation for all $y \in R$ so

Now we are just left to show that there exists some $y$ such that $f(y),f(0),f(-y)$ are all distinct which is obvious as $x^3+\frac{3}{4}x$ has only one real root so we are done :)


Problem 2 :

Find all functions $f:R \to R$ that satisfy
\[f(xy)=f(x)y^2+f(y)-1\]
for all $x,y \in R$

Solution 1:
Set $x=y=0$

Solution 2:
Compare $P(1,x)$ and $P(x,1)$

Solution 3:
$f(x)y^2+f(y)-1=f(y)x^2+f(x)-1$
$\implies \frac{f(x)}{x^2-1}=\frac {f(y)}{y^2-1}$
$\implies f(x)=(x^2-1)c$

These all give no solutions :P

Comment

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Wait... Q2 was just RIP.. i saw the question and wondered what i am missing after x=y=0 :D :P

by TheOneYouWant, Nov 18, 2015, 11:30 AM

Stay insane,Coz it's your will, labour and pain,which takes you to the top of the mountain.

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