[/quote]
,
be a quadrilateral inscribed in a circle 
.
,
,
,
,
,
,
,
.
lies over 
.
table filled with natural numbers, we say it is a divisor table if:
-
,
-
,
for every 
.
is given. Determine the smallest natural number 
,
be integers so that the integers 
are divisible by 
be a fixed integer. There are 
beads on a circular necklace. You wish to paint the beads using 
consecutive beads every color appears at least once. Find the largest value of 
for which this task is 
possible.
be a triangle 
)
are the altitudes of the triangle. The bisector of 
intersects 
at 
.
be a point such that 
and 
.
passes through the midpoint of 
.
is circumcircle of an acute triangle 
is midpoint of arc 
and 
is incenter of triangle 
intersect 
and 
.
such that 
is parallel to 
.
.
.
and 
such that
!
candy bars. Let N & M be positive integers, what is N+M?
Y by
The solution is wrong.
2/27 probability is for three flips, so the 'correct' answer from this solution should have been 27/2 * 3= 81/2 flips.
The correct answer for THT is 31/2.
The correct solution:
Let
be the expected number of flips to get HTT after getting an H.
Then = (case TT) 1/3 * 1/3 * 2 + (case TH) 1/3 * 2/3 * (+2) + (case H) 2/3 * (+1)
= 12
E = (case H) 2/3* (1+) + (case T) 1/3*(1+E)
E=27/2
The only argument that can be made for this solution is the answer of 1/P is correct for sequences of H followed by Ts.
2/27 probability is for three flips, so the 'correct' answer from this solution should have been 27/2 * 3= 81/2 flips.
The correct answer for THT is 31/2.
The correct solution:
Let
be the expected number of flips to get HTT after getting an H.Then
= (case TT) 1/3 * 1/3 * 2 + (case TH) 1/3 * 2/3 * (+2) + (case H) 2/3 * (+1)= 12E = (case H) 2/3* (1+
) + (case T) 1/3*(1+E)E=27/2
The only argument that can be made for this solution is the answer of 1/P is correct for sequences of H followed by Ts.
