Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Polynomials
CuriousBabu   9
N 14 minutes ago by lgx57
\[ 
\frac{(x+y+z)^5 - x^5 - y^5 - z^5}{(x+y)(y+z)(z+x)} = 0 
\]
Find the number of real solutions.
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Apr 14, 2025
lgx57
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ilikemath247365   8
N 20 minutes ago by lgx57
Find all real $(a, b)$ with $a + b = 1$ such that

$(a + \frac{1}{a})^{2} + (b + \frac{1}{b})^{2} = \frac{25}{2}$.
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Mathzeus1024   1
N 20 minutes ago by BS2012
Prove or disprove: $\exists x \in \mathbb{R}^{+}$ such that $\ln(x), \ln(2x), \ln(3x)$ are the lengths of a right triangle.
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How to prove one-one function
Vulch   7
N 24 minutes ago by SomeonecoolLovesMaths
Hello everyone,
I am learning functional equations.
To prove the below problem one -one function,I have taken two non-negative real numbers $ (1,2)$ from the domain $\Bbb R_{*},$ and put those numbers into the given function f(x)=1/x.It gives us 1=1/2.But it's not true.So ,it can't be one-one function.But in the answer,it is one-one function.Would anyone enlighten me where is my fault? Thank you!
7 replies
Vulch
Apr 11, 2025
SomeonecoolLovesMaths
24 minutes ago
No more topics!
\sqrt{d}=\sqrt{a}+\sqrt{b}, tangent balls in cylinder (2019 VWO Flanders MO p1)
parmenides51   1
N Aug 8, 2020 by mathverse06
Two touching balls with radii $a$ and $b$ are enclosed in a cylindrical tin of diameter $d$ . Both balls hit the top surface and the shell of the cylinder. The largest ball also hits the bottom surface. Show that $\sqrt{d} =\sqrt{a} +\sqrt{b}$
IMAGE
1 reply
parmenides51
Aug 8, 2020
mathverse06
Aug 8, 2020
\sqrt{d}=\sqrt{a}+\sqrt{b}, tangent balls in cylinder (2019 VWO Flanders MO p1)
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parmenides51
30629 posts
#1
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Two touching balls with radii $a$ and $b$ are enclosed in a cylindrical tin of diameter $d$ . Both balls hit the top surface and the shell of the cylinder. The largest ball also hits the bottom surface. Show that $\sqrt{d} =\sqrt{a} +\sqrt{b}$
https://1.bp.blogspot.com/-O4B3P3bghFs/Xy1fDv9zGkI/AAAAAAAAMSQ/ePLVnsXsRi0mz3SWBpIzfGdsizWoLmGVACLcBGAsYHQ/s0/flanders%2B2019%2Bp1.png
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mathverse06
561 posts
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One of the reasons why changing 3D to 2D is important.

[asy] /* Geogebra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki go to User:Azjps/geogebra */
import graph; size(10cm); 
real labelscalefactor = 0.5; /* changes label-to-point distance */
pen dps = linewidth(0.7) + fontsize(10); defaultpen(dps); /* default pen style */ 
pen dotstyle = black; /* point style */ 
real xmin = -15.36, xmax = 15.36, ymin = -7.04, ymax = 7.04;  /* image dimensions */
pen ccqqqq = rgb(0.8,0,0); pen ffdxqq = rgb(1,0.8431372549019608,0); 

draw((-7.2,3.88)--(-7.22,-1.84)--(0.44,-1.8)--(0.34,3.94)--cycle, linewidth(1.2)); 
draw(circle((-4.6,0.84), 2.616907150615757), linewidth(2) + ccqqqq); 
draw(circle((-1,2.56), 1.3730906283528068), linewidth(2) + ffdxqq); 
 /* draw figures */
draw((-7.2,3.88)--(-7.22,-1.84), linewidth(1.2)); 
draw((-7.22,-1.84)--(0.44,-1.8), linewidth(1.2)); 
draw((0.44,-1.8)--(0.34,3.94), linewidth(1.2)); 
draw((0.34,3.94)--(-7.2,3.88), linewidth(1.2)); 
 /* dots and labels */
dot((-7.2,3.88),dotstyle); 
label("$A$", (-7.12,4.08), NE * labelscalefactor); 
dot((-7.22,-1.84),dotstyle); 
label("$B$", (-7.14,-1.64), NE * labelscalefactor); 
dot((0.44,-1.8),dotstyle); 
label("$C$", (0.52,-1.6), NE * labelscalefactor); 
dot((0.34,3.94),dotstyle); 
label("$D$", (0.42,4.14), NE * labelscalefactor); 
clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle); 
 /* end of picture */
[/asy]

we get $a+b+2\sqrt{ab}=d$ Therefore, $\sqrt{d} =\sqrt{a} +\sqrt{b}$. Kinda went fast. Sorry about that.


PS: I drew the wrong diagram by mistake the large circle needs to touch the top.
This post has been edited 1 time. Last edited by mathverse06, Aug 8, 2020, 10:14 AM
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