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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
3 M G
BBookmark  VNew Topic kLocked
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First Poster
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k a My Retirement & New Leadership at AoPS
rrusczyk   1571
N Mar 26, 2025 by SmartGroot
I write today to announce my retirement as CEO from Art of Problem Solving. When I founded AoPS 22 years ago, I never imagined that we would reach so many students and families, or that we would find so many channels through which we discover, inspire, and train the great problem solvers of the next generation. I am very proud of all we have accomplished and I’m thankful for the many supporters who provided inspiration and encouragement along the way. I'm particularly grateful to all of the wonderful members of the AoPS Community!

I’m delighted to introduce our new leaders - Ben Kornell and Andrew Sutherland. Ben has extensive experience in education and edtech prior to joining AoPS as my successor as CEO, including starting like I did as a classroom teacher. He has a deep understanding of the value of our work because he’s an AoPS parent! Meanwhile, Andrew and I have common roots as founders of education companies; he launched Quizlet at age 15! His journey from founder to MIT to technology and product leader as our Chief Product Officer traces a pathway many of our students will follow in the years to come.

Thank you again for your support for Art of Problem Solving and we look forward to working with millions more wonderful problem solvers in the years to come.

And special thanks to all of the amazing AoPS team members who have helped build AoPS. We’ve come a long way from here:IMAGE
1571 replies
rrusczyk
Mar 24, 2025
SmartGroot
Mar 26, 2025
k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

Are you ready to level up with Olympiad training? Registration is open with early bird pricing available for our WOOT programs: MathWOOT (Levels 1 and 2), CodeWOOT, PhysicsWOOT, and ChemWOOT. What is WOOT? WOOT stands for Worldwide Online Olympiad Training and is a 7-month high school math Olympiad preparation and testing program that brings together many of the best students from around the world to learn Olympiad problem solving skills. Classes begin in September!

Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
Our full course list for upcoming classes is below:
All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Mar 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
9 Mathcounts school round 2025
wisewigglyjaguar   101
N 9 minutes ago by wuwang2002
I have been doing one set weekly, so I think I will do ok. How about you?

Edit:41 votes!
Edit: Thank you for 80 votes on Christmas Eve! :pilot:
Edit: 100 VOTES! :what?:
Edit: 150 VOTES! :coolspeak:
Edit: 200 VOTES!! :o
Edit: 275 VoTeS!!! :blush:
Edit: 300 VOtES!! :ninja:
101 replies
wisewigglyjaguar
Dec 23, 2024
wuwang2002
9 minutes ago
Any SMT Online team needs one more member?
maxamc   1
N 16 minutes ago by Inaaya
Hi, I moved from Washington State to New Hampshire recently and at this moment I have not found a local team yet for this year's SMT. I am an 8th grader and last year I took SMT with the Washington Rainier Team. I did take USAJMO, and 2 years ago I was also with the Washington State Team at MATHCOUNTS Nationals. If your team needs one more member, please message me! Appreciate it! Thanks!
1 reply
+1 w
maxamc
an hour ago
Inaaya
16 minutes ago
Sums Powers of Roots
CornSaltButter   23
N 18 minutes ago by AshAuktober
Source: AMC 12A 2019 #17
Let $s_k$ denote the sum of the $\textit{k}$th powers of the roots of the polynomial $x^3-5x^2+8x-13$. In particular, $s_0=3$, $s_1=5$, and $s_2=9$. Let $a$, $b$, and $c$ be real numbers such that $s_{k+1} = a \, s_k + b \, s_{k-1} + c \, s_{k-2}$ for $k = 2$, $3$, $....$ What is $a+b+c$?

$\textbf{(A)} \; -6 \qquad \textbf{(B)} \; 0 \qquad \textbf{(C)} \; 6 \qquad \textbf{(D)} \; 10 \qquad \textbf{(E)} \; 26$
23 replies
+1 w
CornSaltButter
Feb 8, 2019
AshAuktober
18 minutes ago
Challenge for the community
MTA_2024   17
N 27 minutes ago by fake123
This is a challenge to the whole AoPS community I bet you can't prove this basic inequality: $$(X_1+X_2+\cdots+X_n)(\dfrac{1}{X_1}+\dfrac{1}{X_2}+\cdots+\dfrac{1}{X_n})\geq n^2$$by $15$ different methods. The same inequality can be used twice but in different ways, dm me if you have any question about the rules.
Feelin good for this one.
17 replies
+1 w
MTA_2024
3 hours ago
fake123
27 minutes ago
Perpendicular following tangent circles
buzzychaoz   19
N 35 minutes ago by cursed_tangent1434
Source: China Team Selection Test 2016 Test 2 Day 2 Q6
The diagonals of a cyclic quadrilateral $ABCD$ intersect at $P$, and there exist a circle $\Gamma$ tangent to the extensions of $AB,BC,AD,DC$ at $X,Y,Z,T$ respectively. Circle $\Omega$ passes through points $A,B$, and is externally tangent to circle $\Gamma$ at $S$. Prove that $SP\perp ST$.
19 replies
buzzychaoz
Mar 21, 2016
cursed_tangent1434
35 minutes ago
A projectional vision in IGO
Shayan-TayefehIR   15
N an hour ago by mcmp
Source: IGO 2024 Advanced Level - Problem 3
In the triangle $\bigtriangleup ABC$ let $D$ be the foot of the altitude from $A$ to the side $BC$ and $I$, $I_A$, $I_C$ be the incenter, $A$-excenter, and $C$-excenter, respectively. Denote by $P\neq B$ and $Q\neq D$ the other intersection points of the circle $\bigtriangleup BDI_C$ with the lines $BI$ and $DI_A$, respectively. Prove that $AP=AQ$.

Proposed Michal Jan'ik - Czech Republic
15 replies
Shayan-TayefehIR
Nov 14, 2024
mcmp
an hour ago
An alien statement I came across
GreekIdiot   2
N an hour ago by DVDthe1st
Source: Some article I read a while ago, cannot find it...
Let $\mathbb{P} \subset \mathbb{N}$ be a set that intersects all non-finite integer arithmetic progressions, $\mathbb {A}$ be the set of prime divisors of $a^n-1$ and $\mathbb {B}$ be the set of prime divisors of $b^n-1$. Suppose $\mathbb {B} \subset \mathbb {A} \hspace{2 mm} \forall \hspace{2mm} n \in \mathbb{P}$. Prove that $b=a^k$, $k \in \mathbb {N}$
2 replies
GreekIdiot
Feb 15, 2025
DVDthe1st
an hour ago
Circles tangent to BC at B and C
MarkBcc168   9
N an hour ago by channing421
Source: ELMO Shortlist 2024 G3
Let $ABC$ be a triangle, and let $\omega_1,\omega_2$ be centered at $O_1$, $O_2$ and tangent to line $BC$ at $B$, $C$ respectively. Let line $AB$ intersect $\omega_1$ again at $X$ and let line $AC$ intersect $\omega_2$ again at $Y$. If $Q$ is the other intersection of the circumcircles of triangles $ABC$ and $AXY$, then prove that lines $AQ$, $BC$, and $O_1O_2$ either concur or are all parallel.

Advaith Avadhanam
9 replies
MarkBcc168
Jun 22, 2024
channing421
an hour ago
Iran TST 2009-Day3-P3
khashi70   66
N an hour ago by ihategeo_1969
In triangle $ABC$, $D$, $E$ and $F$ are the points of tangency of incircle with the center of $I$ to $BC$, $CA$ and $AB$ respectively. Let $M$ be the foot of the perpendicular from $D$ to $EF$. $P$ is on $DM$ such that $DP = MP$. If $H$ is the orthocenter of $BIC$, prove that $PH$ bisects $ EF$.
66 replies
khashi70
May 16, 2009
ihategeo_1969
an hour ago
BAMO Geo
jsdd_   19
N 2 hours ago by LeYohan
Source: BAMO 1999/p2
Let $O = (0,0), A = (0,a), and B = (0,b)$, where $0<b<a$ are reals. Let $\Gamma$ be a circle with diameter $\overline{AB}$ and let $P$ be any other point on $\Gamma$. Line $PA$ meets the x-axis again at $Q$. Prove that angle $\angle BQP = \angle BOP$.
19 replies
jsdd_
Aug 11, 2019
LeYohan
2 hours ago
complex bash oops
megahertz13   2
N 2 hours ago by lpieleanu
Source: PUMaC Finals 2016 A3
On a cyclic quadrilateral $ABCD$, let $M$ and $N$ denote the midpoints of $\overline{AB}$ and $\overline{CD}$. Let $E$ be the projection of $C$ onto $\overline{AB}$ and let $F$ be the reflection of $N$ over the midpoint of $\overline{DE}$. Assume $F$ lies in the interior of quadrilateral $ABCD$. Prove that $\angle BMF = \angle CBD$.
2 replies
megahertz13
Nov 5, 2024
lpieleanu
2 hours ago
Counting Numbers
steven_zhang123   0
2 hours ago
Source: China TST 2001 Quiz 8 P3
Let the decimal representations of numbers $A$ and $B$ be given as: $A = 0.a_1a_2\cdots a_k > 0$, $B = 0.b_1b_2\cdots b_k > 0$ (where $a_k, b_k$ can be 0), and let $S$ be the count of numbers $0.c_1c_2\cdots c_k$ such that $0.c_1c_2\cdots c_k < A$ and $0.c_kc_{k-1}\cdots c_1 < B$ ($c_k, c_1$ can also be 0). (Here, $0.c_1c_2\cdots c_r (c_r \neq 0)$ is considered the same as $0.c_1c_2\cdots c_r0\cdots0$).

Prove: $\left| S - 10^k AB \right| \leq 9k.$
0 replies
steven_zhang123
2 hours ago
0 replies
Perfect Numbers
steven_zhang123   0
2 hours ago
Source: China TST 2001 Quiz 8 P2
If the sum of all positive divisors (including itself) of a positive integer $n$ is $2n$, then $n$ is called a perfect number. For example, the sum of the positive divisors of 6 is $1 + 2 + 3 + 6 = 2 \times 6$, hence 6 is a perfect number.
Prove: There does not exist a perfect number of the form $p^a q^b r^c$, where $a, b, c$ are positive integers, and $p, q, r$ are odd primes.
0 replies
steven_zhang123
2 hours ago
0 replies
Roots of unity
steven_zhang123   0
2 hours ago
Source: China TST 2001 Quiz 8 P1
Let $k, n$ be positive integers, and let $\alpha_1, \alpha_2, \ldots, \alpha_n$ all be $k$-th roots of unity, satisfying:
\[
\alpha_1^j + \alpha_2^j + \cdots + \alpha_n^j = 0 \quad \text{for any } j (0 < j < k).
\]Prove that among $\alpha_1, \alpha_2, \ldots, \alpha_n$, each $k$-th root of unity appears the same number of times.
0 replies
steven_zhang123
2 hours ago
0 replies
Portia's vs. Lara's school
MathArt4   24
N Mar 23, 2025 by JetFire008
Source: 2021 AMC 10A #2
Portia’s high school has $3$ times as many students as Lara’s high school. The two high schools have a total of
$2600$ students. How many students does Portia’s high school have?

$\textbf{(A) }600 \qquad \textbf{(B) }650 \qquad \textbf{(C) }1950 \qquad \textbf{(D) }2000 \qquad \textbf{(E) }2050$
24 replies
MathArt4
Feb 5, 2021
JetFire008
Mar 23, 2025
Portia's vs. Lara's school
G H J
G H BBookmark kLocked kLocked NReply
Source: 2021 AMC 10A #2
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MathArt4
3674 posts
#1 • 5 Y
Y by son7, icematrix2, jhu08, megarnie, Asmaa
Portia’s high school has $3$ times as many students as Lara’s high school. The two high schools have a total of
$2600$ students. How many students does Portia’s high school have?

$\textbf{(A) }600 \qquad \textbf{(B) }650 \qquad \textbf{(C) }1950 \qquad \textbf{(D) }2000 \qquad \textbf{(E) }2050$
This post has been edited 4 times. Last edited by nsato, Dec 30, 2021, 8:19 PM
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MinnesotaMath
3172 posts
#3 • 4 Y
Y by son7, icematrix2, jhu08, Creeperboat
x=lara's, 3x=portia's, 4x=2600, 3x=1950, ans is C
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ShockFish
2394 posts
#4 • 3 Y
Y by son7, icematrix2, jhu08
We get the equation

$4x=2600$ --> $x = 650$ --> $3x = 650 \cdot 3 = 1950$ so (C)
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franzliszt
23531 posts
#5 • 3 Y
Y by son7, icematrix2, jhu08
Write \begin{align*}3l&=p\\ l+p&=2600.\end{align*}Solving with Cramer's Rule gives $p=1950$ or $C$.
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MathArt4
3674 posts
#6 • 2 Y
Y by icematrix2, jhu08
Or just multiply $2600$ by $\frac{3}{4}$ to get $\boxed{1950}$.
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HrishiP
1346 posts
#8 • 2 Y
Y by icematrix2, jhu08
Solution 2
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DAIjeremy
2 posts
#9 • 2 Y
Y by icematrix2, jhu08
x+3x=4x; 4x=2600, so x=650. So among these, we've known that Portia’s high school have 1950 student
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RedFireTruck
4221 posts
#11 • 2 Y
Y by icematrix2, jhu08
$\frac342600=\boxed{1950}$
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OlympusHero
17020 posts
#12 • 3 Y
Y by icematrix2, jhu08, Mango247
Solution
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peace09
5417 posts
#13 • 1 Y
Y by jhu08
Problem #2: Portia's high school has 3 times as many students as Lara's high school. The two high schools have a total of 2600 students. How many students does Portia's high school have?
$\textbf{(A)}~600 \qquad \textbf{(B)}~650 \qquad \textbf{(C)}~1950 \qquad \textbf{(D)}~2000 \qquad \textbf{(E)}~2050$

Solution
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megarnie
5542 posts
#14 • 1 Y
Y by jhu08
Solution
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exp-ipi-1
1075 posts
#16 • 1 Y
Y by jhu08
$3x + x = 2600$
$4x=2600$
$x=650$
$3x=\boxed{1950}$
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Spakian
304 posts
#17 • 1 Y
Y by jhu08
MathArt4 wrote:
Portia’s high school has $3$ times as many students as Lara’s high school. The two high schools have a total of
$2600$ students. How many students does Portia’s high school have?
$\textbf{(A) }600 \qquad \textbf{(B) }650 \qquad \textbf{(C) }1950 \qquad \textbf{(D) }2000 \qquad \textbf{(E) }2050$

Click to reveal hidden text
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MONTGOMERY_BLAIR_STUDENT
17 posts
#18 • 1 Y
Y by centslordm
EDIT: Sorry guys, I did not know that the AMC is an outreach contest... I have redacted my overly harsh comment
2600/4*3=1950,QED!

Sent from Montgomery Blair HS
This post has been edited 1 time. Last edited by MONTGOMERY_BLAIR_STUDENT, Sep 9, 2021, 11:41 AM
Reason: Edit and also fixed typo
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jhu08
1949 posts
#19 • 3 Y
Y by DSL13, Mango247, Mango247
MONTGOMERY_BLAIR_STUDENT wrote:
这么简单的“题”居然都会有人做错,小学生平均三五秒解决
2600/4*3=950,QED!

Sent from Montgomery Blair HS

Basic translation: This "problem" is so easy, how come so many people got it wrong? Elementary school students can solve it in 3-5 seconds on average.

My verdict: You aren't in elementary school, you got your calculations wrong xD
This post has been edited 1 time. Last edited by jhu08, Sep 8, 2021, 4:34 PM
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Alex-131
5310 posts
#20 • 1 Y
Y by Mango247
Wow, from Montgomery Blair HS, looks like I have to write a letter to you explaining this problem
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Math-Infinity
36 posts
#21
Y by
2600 * 3/4 = 1950
This post has been edited 1 time. Last edited by Math-Infinity, Oct 23, 2021, 4:57 AM
Reason: latex error
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Inventor6
558 posts
#22
Y by
Three-quarters of 2600 is (C) 1950

It's hard to believe this would be on an AMC 10 at all
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Overlord123
799 posts
#23
Y by
Solution
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kante314
3099 posts
#24
Y by
Solution
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TheSocialPi
5 posts
#25
Y by
Easy Algebra Click to reveal hidden text
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Mr.Sharkman
490 posts
#26 • 1 Y
Y by Mango247
Let Lara's high school have $x$ people. Then portia's has $3x$. Thus $3x+x=2600$. Thus $x=650$, and $3x=1950$
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TheEvilMathematician
303 posts
#27
Y by
Answer is trivially just $\frac{2600}{4} * 3 \implies \boxed{1950}$.
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JH_K2IMO
125 posts
#28
Y by
Let's denote the number of students in Lara's high school as x .
Then, the number of students in Portia's high school is 3x . Since the total number of students is x + 3x = 4x = 2600 , we can solve for x :
x = 650. Therefore, the number of students in Portia's high school is 3x = 1950 .
The answer is C.
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JetFire008
115 posts
#29
Y by
Let the number of students in Lara's high school be $x$. Then Portia's high school has $3x$ students.
Total students = $x+3x=2600$
$$\implies 4x=2600$$$$\implies x=\frac{2600}{4}=650$$From the above result, the number of students in Lara's school is $3 \cdot 650=1950$. Hence the answer is (C) $1950$.
This post has been edited 1 time. Last edited by JetFire008, Mar 23, 2025, 12:21 PM
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