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- ...the origin and select a point on each line to define vectors <math>\mathbf{v}_{i}=(x_{i},y_{i})</math>. <cmath>\mathbf{v}_1\cdot\mathbf{v}_2 = v_{1}v_{2}\cos\theta \quad\mathrm{and}\quad5 KB (895 words) - 15:03, 8 June 2023
- <li><math>\log_b{(uv)}=\log_b u + \log_b v.</math></li><p>5 KB (680 words) - 16:40, 22 April 2024
- Let <math>V</math> and <math>F</math> be the vertex and focus of the Parabola <math>P(x8 KB (1,223 words) - 15:02, 27 November 2022
- ...an upright V.}\\ \textbf{(D)}\ \text{Two line segments forming an inverted V.}\\ \textbf{(E)}\ \text{None of these.}</math>1 KB (193 words) - 10:42, 6 July 2020
- ...d a horizontal circle of radius <math>r</math> with a constant speed <math>v</math>, in a conical pendulum. The center of the circle is vertically below ...ath>16 kg</math> which slides at a speed of <math>v</math>, with <math>u > v</math>. Block A slides east while Block B slides in west. The surface has c2 KB (439 words) - 11:52, 1 August 2020
- ...th>x=PT</math>, where the length <math>O_{1}O_{2}</math> splits as <math>u+v</math>. Because the lines <math>PQ</math> and <math>O_{1}O_{2}</math> are p ...u^{2}+(r+x)^{2}-u(r+x) \\ \triangle O_{1}OT&:(r+R_{1})^{2}=v^{2}+(r+x)^{2}+v(r+x)\end{align*}</cmath>17 KB (2,852 words) - 03:59, 7 February 2024
- Lucky Seven V ARE YOU XPERIENCED? V3 KB (452 words) - 10:21, 17 November 2022
- Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such15 KB (2,383 words) - 09:49, 25 June 2023
- Denote <math>u = 1 - x</math>, <math>v = 1 - y</math>, <math>w = 1 - z</math>. \sqrt{(1-u)(1+v)} + \sqrt{(1+u)(1-v)} & = 1 \hspace{1cm} (1) \\15 KB (2,208 words) - 01:25, 1 February 2024
- ...t{10}} , \sqrt{10} \right)</math>, <math>Q = \left( \sqrt{10} , \frac{10 - v}{\sqrt{10}} \right)</math>. We have <math>m_{HP} = \frac{3}{6 - u}</math> and <math>m_{PQ} = - \frac{v}{u}</math>.16 KB (2,274 words) - 09:02, 10 December 2022
- Let <math>O</math> be the center of the base, <math>V</math> be the vertex of the base.8 KB (1,314 words) - 03:54, 5 July 2022
- pair A, B, C, D, E, F, G, H, A1, B1, C1, D1, E1, F1, G1, H1, V; V = (3,0);24 KB (3,567 words) - 18:14, 30 August 2022
- Now here comes the smart part. Substitute <math>y = \sqrt[3]{u} - \sqrt[3]{v}</math>. ...<math>u - 3\sqrt[3]{u^2v} + 3\sqrt[3]{uv^2} - v + p\sqrt[3]{u} - p\sqrt[3]{v} + q = 0</math>. Simplification:6 KB (1,059 words) - 16:36, 26 July 2024
- Let <math>u = 10 – y, v = 9 – x.</math> https://www.youtube.com/watch?v=jDP2PErthkg5 KB (794 words) - 15:36, 30 August 2022
- ...3}</math> then we can find a line <math>\ell</math> perpendicular to <math>v</math> such that <math>\ell</math> separates <math>S</math>, and any point Suppose there is no such direction <math>v</math>, then <math>S</math> is contained in a box with side length <math>n^3 KB (577 words) - 13:15, 3 September 2024
- Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such ...d <math>Y</math> be the orthogonal projections of <math>F</math> and <math>V</math> onto <math>AQ</math>. Because <math>AF < AV</math>, there are two po4 KB (796 words) - 17:33, 13 July 2021
- ...ur squares on the middle of the edges after n moves, and <math>V_n</math> (V for vertex) be the probability that Frieda is on a corner after n moves. Th https://youtube.com/watch?v=kHLR57iP0cU17 KB (2,801 words) - 15:35, 30 August 2024
- ...>u</math> and <math>v</math> in <math>G</math>. Every tree that has <math>|V|=n</math> vertices has exactly <math>n-1</math> edges. ...t union of trees. The number of trees in a forest could be found by <math>|V|-|E|</math>.2 KB (435 words) - 19:13, 5 July 2024
- V&=\frac16\cdot AB\cdot AD\cdot BD \\3 KB (496 words) - 19:12, 28 October 2022
- ...tuy + vy^2 + svy + tv</math>, simplifying to <math>y^4 + (s + u)y^3 + (t + v + su)y^2 + (sv + tu)y + tv</math>. [[Equating coefficients]] gives the foll ...begin{cases} s + u = 0 \text{ since the } y^3 \text{ term is 0} \\ p = t + v + su \\ q = sv + tu \\ r = tv \end{cases}</math>13 KB (2,376 words) - 16:56, 19 February 2024
- ...</math> and <math>2</math> along <math>\textbf{u}</math> and <math>\textbf{v}</math> respectively, then find <cmath>\sum_{i=1}^{n}\|\textbf{r}_i\|^2.</c7 KB (1,159 words) - 09:15, 30 July 2024
- ...đến sâu răng, mất răng. Vì vậy, cần phát hiện kịp thời và điều trị đúng cách mòn cổ răng. ...rãnh này, lâu dần tạo mảng bám, gây viêm nhiễm, tụt lợi và ảnh hưởng tới thẩm mỹ. Cổ răng mòn nhiều thậm chí có5 KB (1,261 words) - 05:15, 7 January 2021
- ...math> OV</math> (but not in <math> \vec{OV}</math>) for some vertex <math> V</math> of the polygon. Each two of these lines are obtained one from anothe2 KB (284 words) - 11:02, 30 January 2021
- label("V",(1.5,.3),N); ...>\text{(A)}\ \text{Z} \qquad \text{(B)}\ \text{U} \qquad \text{(C)}\ \text{V} \qquad \text{(D)}\ \ \text{W} \qquad \text{(E)}\ \text{Y}</math>1,023 bytes (167 words) - 15:57, 4 July 2023
- If <math>V = gt + V_0</math> and <math>S = \frac {1}{2}gt^2 + V_0t</math>, then <math> <math> \textbf{(A)}\ \frac{2S}{V+V_0}\qquad737 bytes (129 words) - 22:53, 12 February 2021
- ...$c$", D--C, N); label("$d$",D--A,W); label("$u$",D--B,2*dir(170)); label("$v$",A--C,S); ...c, d</math>, be the sides, <math>s</math> the semiperimeter, and <math>u, v</math>, the diagonals. Then the area, <math>K</math>, is given by <cmath>K10 KB (1,669 words) - 17:33, 12 January 2024
- Denote <math>D' – A' = 2\vec V.</math> ...\triangle A'C'E'</math> into <math>\triangle D'F'B'</math> is <math>2\vec {V.}</math>5 KB (875 words) - 00:26, 23 May 2023
- ...<math>n=2k+1</math>, just take <math>(u,v)= (k+1,k)</math> which <math>u^2-v^2=n</math>. Thus the only answer is <math>\boxed{f\equiv 1}</math> and we a https://www.youtube.com/watch?v=Q1NUBUYvOJc8 KB (1,494 words) - 18:07, 19 August 2024
- ...th>t</math> is square free and <math>gcd(u,v,w) = 1</math>, find <math>t+u+v+w</math> if <math>x=\cos 20^o</math> and <math>y=\sin 20^o</math>.8 KB (1,385 words) - 12:55, 23 June 2021
- We could assume a variable <math>v</math> which equals to both <math>\log_{20x} (22x)</math> and <math>\log_{2 So that <math>(20x)^v=22x \textcircled{1}</math>5 KB (778 words) - 18:14, 30 January 2024
- ...s, plus the outer region, <math>E</math> is the number of edges, and <math>V</math> is the number of vertices. Temporarily disregarding the intersection <math>V=V_{i}+210=222</math>12 KB (2,025 words) - 14:56, 25 January 2024
- ...\qquad \text{(iii) }x+y\ge a\\ \\ \qquad \text{(iv) }x+a\ge y\qquad \text{(v) }y+a\ge x</math>665 bytes (119 words) - 18:31, 28 August 2023
- ...t,st),E); label("M",(cu,su),N);label("P",(cu,st),S); label("C",(cos(v),sin(v)),W); //Credit to Zimbalono for the diagram </asy>864 bytes (169 words) - 16:47, 23 June 2021
- ...th>C(1) = 0</math> and our recursive rules for <math>C(n)</math> and <math>V(n)</math> as follows: n & V(n) & C(n) \\ \hline8 KB (1,309 words) - 00:31, 6 January 2023
- .../math> bisects the angle between <math>\mathbf{u}</math> and <math>\mathbf{v}</math>.14 KB (2,223 words) - 14:27, 1 September 2024
- ...h>. Hence, <math>B = \left( - 1 , u \right)</math>, <math>D = \left( 0 , - v \right)</math>. The slope of <math>AD</math> is <math>m_{AD} = \frac{v}{3}</math>.5 KB (756 words) - 03:40, 23 January 2023
- v v2 KB (278 words) - 19:55, 15 September 2024
- Let <math>G</math> be a graph with the set of vertices <math>V=\{v_1,v_2,v_3,\ldots, v_n\}</math>. We define its adjacency matrix <math>\1 KB (264 words) - 11:26, 3 March 2022
- ...> the formula for variance if <math>X</math> is a [[population]] is <cmath>V = \frac{1}{n}\sum_{i=1}^n (x_i - \overline{x})^2.</cmath> Additionally, <math>V = \sigma^2</math> where <math>\sigma</math> is the population [[standard de749 bytes (122 words) - 19:16, 3 March 2022
- ...>, (2) <math>\hat{x}\equiv x\pmod{p^{n-k}}</math> and (3) <math>k=v(p'(x))=v(p'(\hat{x}))</math>. <center><cmath>v=u+p^{n-2k}zs\in u+p\mathbb{Z}_p\subset \mathbb{Z}_p^{\times}</cmath></cente13 KB (2,298 words) - 23:34, 28 May 2023
- pair o = (0, 0), u = (1, 0), v = 0.8*dir(40), w = dir(70); draw(o--u--(u+v));7 KB (1,154 words) - 12:54, 20 February 2024
- ...t{R}(\text{T}))</math> where <math>\text{R}(\text{T})=\{\text{T}(x)~|~x\in V\}</math>. In other words, rank is the dimension of the linear transformati ...aim that if <math>\beta=\{v_1,v_2,\ldots, v_n\}</math> is a basis of <math>V</math>, then5 KB (893 words) - 22:41, 28 May 2022
- ...math> In accordance with Claim, <math>\angle BVD = \angle HVE \implies B', V,</math> and <math>B</math> are collinear.10 KB (1,751 words) - 15:34, 25 November 2022
- ...mathbf{n}\,dS,</cmath> where <math>R</math> is a region whose volume <math>V(R)</math> shrinks to <math>0</math> about the point <math>p</math>, <math>\ ...mathbf{n}\,dS,</cmath> where <math>R</math> is a region whose volume <math>V(R)</math> shrinks to <math>0</math> about the point <math>p</math>, <math>\7 KB (1,189 words) - 06:00, 21 December 2022
- ...the three roots of the polynomial. The lengthened prism's volume is <cmath>V = (a+2)(b+2)(c+2) = abc+2ac+2ab+2bc+4a+4b+4c+8 = abc + 2(ab+ac+bc) + 4(a+b+ We can substitute these into the expression, obtaining <cmath>V = \frac{6}{10} + 2\left(\frac{29}{10}\right) + 4\left(\frac{39}{10}\right)7 KB (1,111 words) - 21:00, 21 February 2024
- ...e R.H.S. is a not a perfect square. Thus, the number of positive <math>(u, v)</math> is equal to the number of positive divisors of <math>2 r^2</math>. ...n if <math>(a, b)</math> with <math>a = 2 r - u</math> and <math>b = 2 r - v</math>.7 KB (1,271 words) - 12:09, 4 January 2024
- We denote by <math>\left( u, v \right)</math> the coordinates of circle <math>C_0</math>, and <math>r</mat u^2 + v^2 = \left( 8 - r \right)^2 . \hspace{1cm} (1)7 KB (1,202 words) - 01:15, 10 June 2023
- .../math>, define the binary operation <math>\otimes</math> by<cmath>u\otimes v=ac+bdi.</cmath>Suppose <math>z</math> is a complex number such that <math>z13 KB (2,107 words) - 08:20, 2 July 2024
- pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);20 KB (2,814 words) - 00:31, 19 September 2024
- <math>V=\pi{r^2}h</math> <math>V=\pi{r^2}(14-2r)</math>4 KB (697 words) - 17:07, 24 March 2023
- path v=(5,-0.5)--(5,0)--(5,1)--(6,1)--(6,2)--(6,3)--(6,4)--(7,4); draw(v,p);11 KB (1,834 words) - 22:01, 4 January 2024
- pair o = (0, 0), u = (1, 0), v = 0.8*dir(40), w = dir(70); draw(o--u--(u+v));15 KB (2,406 words) - 21:25, 5 September 2024
- <cmath> V = \frac{1}{3} \cdot x \cdot (S_1 + \sqrt{S_1S_2} + S_2) = \frac{1}{3} \cdot Let the volume without water be <math>V,</math> volume of the pyramid <math>SCGJ</math> be <math>U.</math>10 KB (1,574 words) - 16:42, 8 March 2024
- ...en so are <math>f(V)</math>, <math>V+W</math>, <math>V-W</math>, and <math>V \cdot W</math>.5 KB (772 words) - 08:50, 23 February 2023
- https://www.youtube.com/watch?v=f-d4mi-AyxQ Plugging in <math>A</math> and <math>B</math> gives <math>u=v=0</math>. Plugging in <math>P</math> gives7 KB (1,290 words) - 16:16, 15 September 2024
- Plugging in <math>A</math> and <math>B</math> gives <math>u=v=0</math>. Plugging in <math>P</math> gives4 KB (684 words) - 03:59, 31 August 2024
- <cmath>u = 5y - 1, v = 2x - 3y + 1 \implies u^2 - 5 v^2 = - 4 \implies</cmath>15 KB (2,351 words) - 08:28, 20 April 2023
- https://youtube.com/watch?v=LAuyU2OuVzE ...and <math>w=\frac{2b^3cx_0z_0}{c^2y_0^2-b^2z_0^2}</math>, so <cmath>\frac{v}{w}=\frac{b^2z_0}{c^2y_0},</cmath> which is the required condition for <mat14 KB (2,600 words) - 23:37, 10 March 2024
- ...n có biết tại sao SXMN lại có sức hấp dẫn như vậy hay không, hãy cùng lý giải qua bài <p><strong><span style="color: #000000;">XSMN phát triển với mục đích Ích nước lợi nhà</span></strong><11 KB (2,230 words) - 23:24, 9 May 2023
- 231. Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Gmaas no longer has an E88 KB (14,978 words) - 19:34, 3 September 2024
- ...math>AB</math> and <math>AC</math> meet the line <math>AU</math> and <math>V</math> and <math>W</math>, respectively. The lines <math>BV</math> and <ma736 bytes (124 words) - 23:58, 28 March 2024
- ...th>f(u) = f(t^{2}+v) = f^{-1}(v)+f(t)^{2}> f^{-1}(v) = f(f(f^{-1}(v))) = f(v)</math>. Hence f is strictly increasing. It is now clear that since <math>f1 KB (282 words) - 14:53, 12 March 2024
- ...sed as <math>(2u-3w, v+4w)</math> with <math>0\le u\le1</math>, <math>0\le v\le1,</math> and <math>0\le w\le1</math>?13 KB (1,959 words) - 13:42, 14 June 2024
- <math>V = \sqrt{(a^2 + b^2 - c^2)(b^2 + c^2 - a^2)(a^2 + c^2 - b^2)/72}</math> ...umes <cmath>[ABCI] + [ABDI] + [ACDI] + [BCDI] = V,</cmath> We have <cmath>V = \frac{4AR}{3}.</cmath> Plugging in and simplifying, we get <math>R = \fra14 KB (2,198 words) - 22:28, 30 July 2024
- label("$v'$", (0, 2.18), NE); ...eed to find <math>v</math> with the largest imaginary part such that <math>v^2</math> lies on <math>\omega</math>.6 KB (1,055 words) - 21:58, 28 February 2024
- ...t, to find the amount of vertices we can use Euler's characteristic, <math>V - E + F = 2</math>, and therefore the amount of vertices is <math>12</math> By Euler's formula, which states that <math>v-e+f=2</math> for all convex polyhedra, we know that there are <math>2-f+e=113 KB (2,187 words) - 08:39, 5 September 2024
- ...nvex polyhedra, <math>V-E+F=2</math>. In our case, <math>V-24+12=2\implies V=14.</math> We know that <math>A+B</math> is the total number of vertices as Note that Euler's formula is <math>V+F-E=2</math>. We know <math>F=12</math> from the question. We also know <ma7 KB (1,171 words) - 21:11, 7 September 2024
- pair K, L, M, N, O, P, Q, R, S, T, U, V; pair K, L, M, N, O, P, Q, R, S, T, U, V;18 KB (2,765 words) - 19:17, 15 August 2024
- ...sed as <math>(2u-3w, v+4w)</math> with <math>0\le u\le1</math>, <math>0\le v\le1,</math> and <math>0\le w\le1</math>? ...h <math>x</math> and <math>y</math>. We first fix <math>u</math> and <math>v</math> to <math>0</math>, and graph <math>(-3w,4w)</math> from <math>0\le w6 KB (983 words) - 12:34, 24 July 2024
- V814 bytes (128 words) - 10:36, 11 November 2023
- Denote <math>m = k u</math> and <math>n = k v</math>. Thus, <math>{\rm gcd} \left( u, v \right) = 1</math>.4 KB (639 words) - 22:31, 9 July 2024
- pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);3 KB (445 words) - 19:58, 28 August 2024
- For complex number <math>u = a+bi</math> and <math>v = c+di</math> (where <math>i=\sqrt{-1}</math>), define the binary operation <math>u \otimes v = ac + bdi</math>1 KB (205 words) - 02:52, 20 November 2023
- https://www.youtube.com/watch?v=ejmrAJ9TpvM&ab_channel=MegaMathChannel ...math> is <math>u=v/|v|</math>, so <math>v \cdot u= v\cdot v = |v|^2/|v| = |v|</math>, which here is just <math>\sqrt{3^2+(-4)^2} =5</math>.12 KB (1,991 words) - 00:24, 19 July 2024
- Given the problem \( (f(x) + f(y))(f(u) + f(v)) = f(xu - yv) + f(xv - yu) \), we aim to find a function that satisfies it We start by considering the case when \( x = y = u = v = 0 \).2 KB (369 words) - 16:12, 26 March 2024
- The points <math>U \in AA''</math> and <math>V \in CC''</math> be such points that <math>L \in UV, UV \perp BB''.</math> Similarly points <math>V, M,</math> and <math>D</math> are collinear.14 KB (2,490 words) - 06:51, 6 June 2024
- * [[V Olimpiada Iberoamericana de Matemáticas (OIM) ]] Valladolid, España , 19 * [[X Olimpiada Iberoamericana de Matemáticas (OIM) ]] Región V, Chile , 199514 KB (1,323 words) - 12:18, 13 December 2023
- ...at if <math>x+yt+zt^2 \ne 0</math>, then there exist <math>u</math>, <math>v</math>, and <math>w</math> as rational numbers such that:511 bytes (84 words) - 13:28, 13 December 2023
- <math>V=\sum_{i}^{}2^ik_i=13^3</math> where <math>k_i</math> is the quantity of cub2 KB (387 words) - 10:29, 23 December 2023
- ...lar polygon with <math>n</math> sides, <math>n \ge 4</math>, and let <math>V</math> be a subset of <math>r</math> vertices of the polygon. Show that if vertices are in <math>V</math>.396 bytes (66 words) - 04:02, 14 December 2023
- ...h> by 2000, and <math>y'</math> is the reminder of the division of <math>y+v'</math> by 2001. There are two ships on the board: the Martian one and the1 KB (256 words) - 04:26, 14 December 2023
- ...h> is greater than the ''dragonian distance'' from <math>C</math> to <math>V</math>.1,015 bytes (177 words) - 16:49, 14 December 2023
- 458 bytes (44 words) - 17:51, 14 December 2023
- X [[Olimpiada Iberoamericana de Matemáticas]] was held in Región V, Chile , 1995455 bytes (45 words) - 17:53, 14 December 2023
- ...here <math>d(v)</math> indicates the distance from <math>A</math> to <math>v</math>. Consider the outgoing edges <math>(A,X)</math> and <math>(A,M)</mat https://www.youtube.com/watch?v=RRTxlduaDs86 KB (989 words) - 00:33, 19 September 2024
- DVI is an exam in mathematics at the Moscow State University named after M.V. Lomonosov. The first four problems have a standard level. <cmath>\left\{\begin{array}{l} u = \sqrt {2} (x + y),\\v = 3y.\end{array}\right.</cmath>48 KB (8,214 words) - 08:59, 30 July 2024
- https://archifol.io/v/tjqbn89d https://archifol.io/v/brzmkkgh273 bytes (44 words) - 21:35, 1 April 2024
- ...e arc <math>\overset{\frown}{uv}</math>(excluding <math>u</math> and <math>v</math> ) contains only fixed points, and <math>l_i</math> is clockwise and ...\right),\left(w_2, w_3\right), \ldots,\left(w_{t-1}, w_t\right),\left(w_t, v\right),\left(w_{t-1}, w_t\right), \ldots,\left(w_2, w_3\right),\left(w_1, w8 KB (1,430 words) - 06:01, 25 May 2024
- ...e arc <math>\overset{\frown}{uv}</math>(excluding <math>u</math> and <math>v</math> ) contains only fixed points, and <math>l_i</math> is clockwise and ...\right),\left(w_2, w_3\right), \ldots,\left(w_{t-1}, w_t\right),\left(w_t, v\right),\left(w_{t-1}, w_t\right), \ldots,\left(w_2, w_3\right),\left(w_1, w8 KB (1,430 words) - 06:06, 25 May 2024
- 231. Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Gmaas no longer has an E69 KB (11,828 words) - 19:26, 3 September 2024
- .../math>, <math>3uv(u+v)</math> matches up with <math>-px</math>, and <math>(v^3+w^3)</math> matches up with <math>-q</math>. Things are about to get exci ...^3}{27}</math>. This may not sound exciting until our substitution <math>w=v^3</math>. We got rid of <math>u</math> and now we have <math>w^2+\left(q\ri4 KB (775 words) - 23:03, 22 August 2024
- A, F, I, V, r, h, 3, 6, ?, <, ., {, etc.102 bytes (17 words) - 19:20, 25 June 2024
- ...</math> and <math>2</math> along <math>\textbf{u}</math> and <math>\textbf{v}</math> respectively, then find <cmath>\sum_{i=1}^{n}\|\textbf{r}_i\|^2.</c ...>x'</math>-axis, perpendicular to the <math>y'</math>-axis, on which <math>v</math> now lies, as seen in the diagram below. Rotations do not affect the2 KB (353 words) - 14:20, 30 July 2024
- <cmath>V= \frac {lmn}{3} = \sqrt {\frac {(a^2+b^2-c^2)(a^2-b^2+c^2)(-a^{2}+b^{2}+c^{ <cmath>V= \frac {l \cdot m \cdot n}{3} = \sqrt {\frac {(a^2+b^2-c^2)(a^2-b^2+c^2)(-a19 KB (3,355 words) - 08:00, 22 August 2024
- <cmath>\frac{2^n}{n!}v^n~\text{where}~v=\frac{s}{\sqrt{2}}~\text{is the distance from the center of the cross-polyt1 KB (181 words) - 16:34, 20 August 2024