Basic Graph Theory

by utkarshgupta, Mar 23, 2015, 4:42 PM

Problem :
All the vertices of a graph have degree $3$. Proof that the graph has a cycle.

Solution 1 :

Consider any connected subgraph of this graph.
Since a tree has at least one vertex with degree $1$, the given subgraph has a cycle.

Solution 2 :
Since a tree, always has a vertex with degree $1$, if we show that the graph is connected, we are done.
Consider a vertex $X$ which is connected to vertices $A_i$ and not connected to $B_j$
If some $B_l$ is connected to some $A_m$, we will have $B_l$ connected to $X$ a contradiction.

Thus we have $B_j$ and $X \cup A_i$ are disjoint subgraphs.

Thus by the induction hypothesis, we are done.

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Err, so I was going through your blog...

Are you sure that all graphs with minimum degree $\geq 3$ are connected? Or maybe you meant something else? Because I don't think that's true :maybe: :maybe: For example, consider two disjoint complete graphs each of size 4.

Also, any graph with minimum degree $>1$ has a cycle. The condition that the graph is 3-regular is way too strong, isn't it? :P

by AnonymousBunny, May 8, 2015, 9:27 PM

Stay insane,Coz it's your will, labour and pain,which takes you to the top of the mountain.

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  • I have no plans for this blog right now....
    No time here people !
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    I may try some combinatorics :P

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