Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Classic Invariant
Mathdreams   0
33 minutes ago
Source: 2025 Nepal Mock TST Day 1 Problem 1

Prajit and Kritesh challenge each other with a marble game. In a bag, there are initially $2024$ red marbles and $2025$ blue marbles. The rules of the game are as follows:

Move: In each turn, a player (either Prajit or Kritesh) removes two marbles from the bag.

If the two marbles are of the same color, they are both discarded and a red marble is added to the bag.
If the two marbles are of different colors, they are both discarded and a blue marble is added to the bag.

The game continues by repeating the above move.

Prove that no matter what sequence of moves is made, the process always terminates with exactly one marble left. In addition, find the possible colors of the marble remaining.
0 replies
Mathdreams
33 minutes ago
0 replies
law of log
Miranda2829   15
N 2 hours ago by Lankou
5log (5²) + 8 ˡºᵍ₈4 =

is this answer 6?
15 replies
Miranda2829
Today at 2:12 AM
Lankou
2 hours ago
Two problems
Vulch   1
N 2 hours ago by Lankou
Solve the following problems:
1 reply
Vulch
3 hours ago
Lankou
2 hours ago
geometry problem
kjhgyuio   1
N 3 hours ago by kjhgyuio
........
1 reply
kjhgyuio
3 hours ago
kjhgyuio
3 hours ago
No more topics!
k 2018 IGO Elementary level P1
bgn   7
N Sep 12, 2019 by Eliti
As shown below, there is a $40\times30$ paper with a filled $10\times5$ rectangle inside of it. We want to cut out the filled rectangle from the paper using four straight cuts. Each straight cut is a straight line that divides the paper into two pieces, and we keep the piece containing the filled rectangle. The goal is to minimize the total length of the straight cuts. How to achieve this goal, and what is that minimized length? Show the correct cuts and write the final answer. There is no need to prove the answer.

Proposed by Morteza Saghafian
7 replies
bgn
Sep 20, 2018
Eliti
Sep 12, 2019
2018 IGO Elementary level P1
G H J
G H BBookmark kLocked kLocked NReply
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bgn
178 posts
#1 • 1 Y
Y by Adventure10
As shown below, there is a $40\times30$ paper with a filled $10\times5$ rectangle inside of it. We want to cut out the filled rectangle from the paper using four straight cuts. Each straight cut is a straight line that divides the paper into two pieces, and we keep the piece containing the filled rectangle. The goal is to minimize the total length of the straight cuts. How to achieve this goal, and what is that minimized length? Show the correct cuts and write the final answer. There is no need to prove the answer.

Proposed by Morteza Saghafian
Attachments:
This post has been edited 1 time. Last edited by bgn, Sep 20, 2018, 7:53 AM
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enthusiast101
1086 posts
#3 • 2 Y
Y by Adventure10, Mango247
Is it 65??
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InternetPerson10
450 posts
#4 • 2 Y
Y by Adventure10, Mango247
Solution
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enthusiast101
1086 posts
#5 • 2 Y
Y by Adventure10, Mango247
:) yes! But how can we prove this is shortest length??
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NikoIsLife
9657 posts
#6 • 2 Y
Y by Adventure10, Mango247
enthusiast101 wrote:
:) yes! But how can we prove this is shortest length??

Well, there are only $4!=24$ "optimal" ways to cut the paper, which is just a few. It suffices to check them all.
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InternetPerson10
450 posts
#8 • 2 Y
Y by Adventure10, Mango247
It might just be casework XD

Try cutting horizontally first (making a cut of length 40). whatever you do next, you can't get lower than 65.
Then, try cutting the left edge first. The next cut must be of length 30. Since we need to make two more cuts (at least 5), this won't work.
Then check all cases for cutting the right edge first - you'll find 65 to be the shortest. :)
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Shkev
16 posts
#9 • 2 Y
Y by Adventure10, Mango247
There’s an answer key here from the official website: http://igo-official.ir/wp-content/uploads/2018/09/The_fifth_IGO_en.pdf#page6
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Eliti
31 posts
#10 • 1 Y
Y by Adventure10
65 is answear thats easy
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