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k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

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Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
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[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
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0 replies
jlacosta
Mar 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Number theory question with many (confusing) variables
urfinalopp   1
N an hour ago by mathprodigy2011
Given m,n,p,q \in \mathbb{N+}, find all solutions to 2^{m}3^{n}+5^{p}=7^{q}$

One of the paths I've found is to boil it down to solving two non-simultaneous equations 2^{m_1}+5^{n_1}=7^{q_1} and
7^{m_1}+5^{n_1}=2^{q_1} but its too hard. Any other approaches/solutions or a continuation of this path?
1 reply
urfinalopp
3 hours ago
mathprodigy2011
an hour ago
Dealing with Multiple Circles
Wildabandon   4
N an hour ago by Double07
Source: PEMNAS Brawijaya University Senior High School Semifinal 2023 P4
A non-isosceles triangle $ABC$ and $\ell$ is tangent to the circumcircle of triangle $ABC$ through point $C$. Points $D$ and $E$ are the midpoints of segments $BC$ and $CA$ respectively, then line $AD$ and line $BE$ intersect $\ell$ at points $A_1$ and $B_1$ respectively. Line $AB_1$ and line $BA_1$ intersect the circumcircle of triangle $ABC$ at points $X$ and $Y$ respectively. Prove that $X$, $Y$, $D$ and $E$ concyclic.
4 replies
Wildabandon
Dec 1, 2024
Double07
an hour ago
Thanks u!
Ruji2018252   1
N an hour ago by pco
Jqkrjfđrfffffff
1 reply
Ruji2018252
an hour ago
pco
an hour ago
funny title
nguyenvana   1
N an hour ago by pco
Source: no from book
Find all the functions f: R+ to R+ which satisfy the functional equation:
f(2f(x)+f(y)+xy)=xy+2x+y (x,y R+)
1 reply
nguyenvana
3 hours ago
pco
an hour ago
FB = BK , circumcircle and altitude related (In the World of Mathematics 516)
parmenides51   4
N an hour ago by Nioronean
Let $BT$ be the altitude and $H$ be the intersection point of the altitudes of triangle $ABC$. Point $N$ is symmetric to $H$ with respect to $BC$. The circumcircle of triangle $ATN$ intersects $BC$ at points $F$ and $K$. Prove that $FB = BK$.

(V. Starodub, Kyiv)
4 replies
parmenides51
Apr 19, 2020
Nioronean
an hour ago
subsets of subset has same sum
61plus   3
N an hour ago by sttsmet
Source: 2015 China TST 2 Day 2 Q2
Set $S$ to be a subset of size $68$ of $\{1,2,...,2015\}$. Prove that there exist $3$ pairwise disjoint, non-empty subsets $A,B,C$ such that $|A|=|B|=|C|$ and $\sum_{a\in A}a=\sum_{b\in B}b=\sum_{c\in C}c$
3 replies
61plus
Mar 19, 2015
sttsmet
an hour ago
Dear Sqing: So Many Inequalities...
hashtagmath   23
N an hour ago by MTA_2024
I have noticed thousands upon thousands of inequalities that you have posted to HSO and was wondering where you get the inspiration, imagination, and even the validation that such inequalities are true? Also, what do you find particularly appealing and important about specifically inequalities rather than other branches of mathematics? Thank you :)
23 replies
hashtagmath
Oct 30, 2024
MTA_2024
an hour ago
(ab)^2 + (bc)^2 + (ca)^2
GorgonMathDota   13
N an hour ago by ektorasmiliotis
Source: Shortlist BMO 2019, A5
Let $a,b,c$ be positive real numbers, such that $(ab)^2 + (bc)^2 + (ca)^2 = 3$. Prove that
\[ (a^2 - a + 1)(b^2 - b + 1)(c^2 - c + 1) \ge 1. \]
Proposed by Florin Stanescu (wer), România
13 replies
GorgonMathDota
Nov 7, 2020
ektorasmiliotis
an hour ago
weird combinatorics/algebra
Dr.Poe98   1
N an hour ago by americancheeseburger4281
Source: Brazil Cono Sur TST 2024 - T3/P2
For each natural number $n\ge3$, let $m(n)$ be the maximum number of points inside or on the sides of a regular $n$-agon of side $1$ such that the distance between any two points is greater than $1$. Prove that $m(n)\ge n$ for $n>6$.
1 reply
Dr.Poe98
Oct 21, 2024
americancheeseburger4281
an hour ago
A nice problem
hanzo.ei   0
an hour ago

Given a nonzero real number \(a\) and a polynomial \(P(x)\) with real coefficients of degree \(n\) (\(n > 1\)) such that \(P(x)\) has no real roots. Prove that the polynomial
\[
Q(x) \;=\; P(x) \;+\; a\,P'(x) \;+\; a^2\,P''(x) \;+\; \dots \;+\; a^n\,P^{(n)}(x)
\]has no real roots.
0 replies
hanzo.ei
an hour ago
0 replies
interesting algebra/geometry
Dr.Poe98   2
N an hour ago by americancheeseburger4281
Source: Brazil Cono Sur TST 2024 - T2/P4
In the cartesian plane, consider the subset of all the points with both integer coordinates. Prove that it is possible to choose a finite non-empty subset $S$ of these points in such a way that any line $l$ that forms an angle of $90^{\circ},0^{\circ},135^{\circ}$ or $45^{\circ}$ with the positive horizontal semi-axis intersects $S$ at exactly $2024$ points or at no points.
2 replies
Dr.Poe98
Oct 21, 2024
americancheeseburger4281
an hour ago
Round up to the nearest power of two
navi_09220114   1
N 2 hours ago by ja.
Source: Own. Malaysian IMO TST 2025 P6
A sequence $2^{a_1}, 2^{a_2}, \cdots,2^{a_m}$ is called good, if $a_i$ are non-negative integers, and $a_{i+1}-a_{i}$ is either $0$ or $1$ for all $1\le i\le m-1$.

Fix a positive integer $n$, and Ivan has a whiteboard with some ones written on it. In each step, he may erase any good sequence $2^{a_1}, 2^{a_2}, \cdots,2^{a_m}$ that appears on the whiteboard, and then he writes the number $2^k$ such that $$2^{k-1}<2^{a_1}+2^{a_2}+\cdots+2^{a_m}\le 2^{k}$$Suppose Ivan starts with the least possible number of ones to obtain $2^n$ after some steps, determine the minimum number of steps he will need in order to do so.

Proposed by Ivan Chan Kai Chin
1 reply
navi_09220114
6 hours ago
ja.
2 hours ago
Inequalities
sqing   3
N 3 hours ago by sqing
Let $ a,b> 0$ and $ a+b=1 . $ Prove that
$$ \frac{1}{a}+\frac{1}{b}\geq \frac{4+\frac{k}{4096}}{1+ ka^7b^7}$$Where $\frac{8192}{3}\geq  k>0 .$
$$ \frac{1}{a}+\frac{1}{b}\geq \frac{\frac{14}{3}}{1+ \frac{8192}{3}a^7b^7}$$
3 replies
1 viewing
sqing
4 hours ago
sqing
3 hours ago
Inequalities
sqing   0
3 hours ago
Let $ a,b,c\geq 0 $ and $a+b+c=1$. Prove that$$a^3b+b^3c+c^3a+\frac{473}{256}abc\le\frac{27}{256}$$Equality holds when $ a=b=c=\frac{1}{3} $ or $ a=0,b=\frac{3}{4},c=\frac{1}{4} $ or $ a=\frac{1}{4} ,b=0,c=\frac{3}{4} $
or $ a=\frac{3}{4} ,b=\frac{1}{4},c=0. $
0 replies
sqing
3 hours ago
0 replies
2019 Chile Classification / Qualifying NMO Juniors XXXI
parmenides51   6
N Yesterday at 1:19 PM by bhontu
p1. Consider the sequence of positive integers $2, 3, 5, 6, 7, 8, 10, 11 ...$. which are not perfect squares. Calculate the $2019$-th term of the sequence.


p2. In a triangle $ABC$, let $D$ be the midpoint of side $BC$ and $E$ be the midpoint of segment $AD$. Lines $AC$ and $BE$ intersect at $F$. Show that $3AF = AC$.


p3. Find all positive integers $n$ such that $n! + 2019$ is a square perfect.


p4. In a party, there is a certain group of people, none of whom has more than $3$ friends in this. However, if two people are not friends at least they have a friend in this party. What is the largest possible number of people in the party?
6 replies
parmenides51
Oct 11, 2021
bhontu
Yesterday at 1:19 PM
2019 Chile Classification / Qualifying NMO Juniors XXXI
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parmenides51
30628 posts
#1 • 2 Y
Y by Lilathebee, ImSh95
p1. Consider the sequence of positive integers $2, 3, 5, 6, 7, 8, 10, 11 ...$. which are not perfect squares. Calculate the $2019$-th term of the sequence.


p2. In a triangle $ABC$, let $D$ be the midpoint of side $BC$ and $E$ be the midpoint of segment $AD$. Lines $AC$ and $BE$ intersect at $F$. Show that $3AF = AC$.


p3. Find all positive integers $n$ such that $n! + 2019$ is a square perfect.


p4. In a party, there is a certain group of people, none of whom has more than $3$ friends in this. However, if two people are not friends at least they have a friend in this party. What is the largest possible number of people in the party?
This post has been edited 3 times. Last edited by parmenides51, Sep 4, 2022, 4:14 PM
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Arrowhead575
2281 posts
#2 • 1 Y
Y by ImSh95
p3
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JanHaj
31 posts
#3 • 1 Y
Y by ImSh95
p1.
Firstly we find the number whose square is strictly less than $2019$:
$$44^2=1936 < 2019 < 2025=45^2$$So,that number is $44$.
This tells us that there are $44$ perfect squares smaller than $2019.$
Now, we define the following sequences as:
$$1, 2, 3, 4, 5..., 2019\quad (1)$$$$2, 3, 5, 6, 7..., 2019\quad (2)$$To get the second sequence we have simply removed the numbers which are perfect squares up to 2019 from sequence $(1)$ (which like we said, there are 44), we now know that sequence $(1)$ has 2019 elements, so to make sequence $(2)$ have 2019 elements we need to add $44$ numbers after the $2019$, so:
$$2, 3, 5, 6, 7..., 2019\Rightarrow 2,3,5...,2019,2020,2021,2022,2023,2024,\boxed{2025},2026...\quad (2.1)$$Notice that after adding those number we have passed $2025$ which is a perfect square,so it must be removed from our sequence.
Now sequence $(2.1)$ has $2018$ elements so we must add $1$ more number to the sequence (for it to have 2019 elements).
Thus, the 2019-th term of this sequence is $2019+44+1=\boxed{2064}$
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MC413551
2228 posts
#4 • 1 Y
Y by ImSh95
For p2 just use mass points
Make A 10 so then D is also 10 and then E is 20.
B is 5 and so is C.
That means F is 15
So the ratio of AF to FC is 1:2
So AF to AC is 1/3
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LolMathZ13PR
1 post
#6
Y by
broder supongo que eres de chile dime como puedo publicar aqui
Quote:
Quote:
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liyufish
12 posts
#7
Y by
A problem that looks like p1 but a little harder:
Consider the sequence $a_n$ which include all positive integers that are not perfect squares. Prove: for any positive integer n, $\lvert a_n-n-\sqrt n \rvert <\frac{1}{2}$
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bhontu
12 posts
#8
Y by
p2 is trivial with menelaus, and p4 is just 5 which is also trivial if you know the proof of R(3,3)=6
This post has been edited 1 time. Last edited by bhontu, Yesterday at 1:20 PM
Reason: solving p4
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