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k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

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Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
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0 replies
1 viewing
jlacosta
Mar 2, 2025
0 replies
Inequalities
lgx57   1
N 28 minutes ago by sqing
Let $a,b,c>0$,$\frac{a^2+b^2+c^2}{ab+bc+ca}=2$, find the minimum of

$$\frac{a^3+b^3+c^3}{abc}$$
1 reply
lgx57
an hour ago
sqing
28 minutes ago
that statement is true
pennypc123456789   2
N 35 minutes ago by pennypc123456789
we have $a^3+b^3 = 2$ and $3(a^4+b^4)+2a^4b^4 \le 8 $ , then we can deduce $a^2+b^2$ \le 2 $ ?
2 replies
pennypc123456789
6 hours ago
pennypc123456789
35 minutes ago
Inequalities
sqing   6
N 43 minutes ago by sqing
Let $ a,b,c\geq 0 $ and $a+b+c=1$. Prove that$$a^3b+b^3c+c^3a+\frac{473}{256}abc\le\frac{27}{256}$$Equality holds when $ a=b=c=\frac{1}{3} $ or $ a=0,b=\frac{3}{4},c=\frac{1}{4} $ or $ a=\frac{1}{4} ,b=0,c=\frac{3}{4} $
or $ a=\frac{3}{4} ,b=\frac{1}{4},c=0. $
6 replies
sqing
Yesterday at 3:55 PM
sqing
43 minutes ago
Prove an equation
nhathhuyyp5c   0
2 hours ago
Given real numbers \( x, y, a, b \) that simultaneously satisfy the conditions \( x^2 - y^2 = 1 \) and

\[
\frac{x^4}{a} - \frac{y^4}{b} = \frac{1}{a - b}.
\]
Prove that for every positive integer \( n \), we have

\[
\left( \frac{x^2}{a} \right)^n + \left( \frac{y^2}{b} \right)^n = \frac{2}{(a - b)^n}.
\]
0 replies
nhathhuyyp5c
2 hours ago
0 replies
2 math problems
Bummer12345   0
2 hours ago
problem 1
problem 2
0 replies
Bummer12345
2 hours ago
0 replies
Number theory national Olympiad
LoRD2022   1
N 4 hours ago by whwlqkd
Find all polynomials with integer coefficients such that, $a^2+b^2-c^2|P(a)+P(b)-P(c)$ for all $a,b,c \in \mathbb{Z}$.
1 reply
LoRD2022
Yesterday at 9:09 PM
whwlqkd
4 hours ago
Prove that $n$ is a prime number or the square of a prime number.
kyotaro   0
5 hours ago
Let $n$ be an odd positive integer satisfying $2^n-1$ with exactly 2 distinct prime factors. Prove that $n$ is a prime number or the square of a prime number.
0 replies
kyotaro
5 hours ago
0 replies
Help me please
ntu0301   0
Today at 7:37 AM
Determine all integers $n>1$ that satisfy the following condition: For every integer k such that $0\le k<n$ there always exists a positive integer $A$ that is divisible by n and $S(n)\equiv k (mod n) $. $S(n)$: sum of elements of $A$
0 replies
ntu0301
Today at 7:37 AM
0 replies
what actually happens after the usamo
bubby617   1
N Today at 7:37 AM by Indpsolver
i keep getting different answers for how the selection process gets down from the usamo winners to the IMO team so can someone set the record straight for me
1 reply
bubby617
Today at 2:47 AM
Indpsolver
Today at 7:37 AM
Geometry Problem
JetFire008   1
N Today at 6:22 AM by JetFire008
Equilateral $\triangle ADC$ is drawn externally on side $AC$ of $\triangle ABC$. Point $P$ is taken on $BD$. Find $\angle APC$ if $BD=PA+PB+PC$.
1 reply
JetFire008
Today at 5:47 AM
JetFire008
Today at 6:22 AM
k Discord Server
mathprodigy2011   14
N Today at 3:00 AM by KF329
Theres a server where we are all like discussing problems+helping each other practice. Hopefully you guys can join.

https://discord.gg/6hN3w4eK
14 replies
mathprodigy2011
Friday at 11:00 PM
KF329
Today at 3:00 AM
USAMO question
bubby617   2
N Today at 2:44 AM by Andyluo
if i had qualified for the usa(j)mo (i wish), would i have been flown out for free like mathcounts nationals or do you have to plan your own trip for going to the usamo
2 replies
bubby617
Today at 2:32 AM
Andyluo
Today at 2:44 AM
A hard inequality
JK1603JK   2
N Today at 2:25 AM by sqing
Let a,b,c\ge 0: a+b+c=3. Prove \frac{1}{abc}+\frac{12}{a^2b+b^2c+c^2a}\ge 5.
2 replies
JK1603JK
Today at 1:40 AM
sqing
Today at 2:25 AM
Number theory question with many (confusing) variables
urfinalopp   2
N Today at 2:07 AM by urfinalopp
Given m,n,p,q \in \mathbb{N+}, find all solutions to 2^{m}3^{n}+5^{p}=7^{q}$

One of the paths I've found is to boil it down to solving two non-simultaneous equations 2^{m_1}+5^{n_1}=7^{q_1} and
7^{m_1}+5^{n_1}=2^{q_1} but its too hard. Any other approaches/solutions or a continuation of this path?
2 replies
urfinalopp
Yesterday at 4:06 PM
urfinalopp
Today at 2:07 AM
2019 Chile Classification / Qualifying NMO Juniors XXXI
parmenides51   6
N Mar 21, 2025 by bhontu
p1. Consider the sequence of positive integers $2, 3, 5, 6, 7, 8, 10, 11 ...$. which are not perfect squares. Calculate the $2019$-th term of the sequence.


p2. In a triangle $ABC$, let $D$ be the midpoint of side $BC$ and $E$ be the midpoint of segment $AD$. Lines $AC$ and $BE$ intersect at $F$. Show that $3AF = AC$.


p3. Find all positive integers $n$ such that $n! + 2019$ is a square perfect.


p4. In a party, there is a certain group of people, none of whom has more than $3$ friends in this. However, if two people are not friends at least they have a friend in this party. What is the largest possible number of people in the party?
6 replies
parmenides51
Oct 11, 2021
bhontu
Mar 21, 2025
2019 Chile Classification / Qualifying NMO Juniors XXXI
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parmenides51
30628 posts
#1 • 2 Y
Y by Lilathebee, ImSh95
p1. Consider the sequence of positive integers $2, 3, 5, 6, 7, 8, 10, 11 ...$. which are not perfect squares. Calculate the $2019$-th term of the sequence.


p2. In a triangle $ABC$, let $D$ be the midpoint of side $BC$ and $E$ be the midpoint of segment $AD$. Lines $AC$ and $BE$ intersect at $F$. Show that $3AF = AC$.


p3. Find all positive integers $n$ such that $n! + 2019$ is a square perfect.


p4. In a party, there is a certain group of people, none of whom has more than $3$ friends in this. However, if two people are not friends at least they have a friend in this party. What is the largest possible number of people in the party?
This post has been edited 3 times. Last edited by parmenides51, Sep 4, 2022, 4:14 PM
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Arrowhead575
2281 posts
#2 • 1 Y
Y by ImSh95
p3
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JanHaj
31 posts
#3 • 1 Y
Y by ImSh95
p1.
Firstly we find the number whose square is strictly less than $2019$:
$$44^2=1936 < 2019 < 2025=45^2$$So,that number is $44$.
This tells us that there are $44$ perfect squares smaller than $2019.$
Now, we define the following sequences as:
$$1, 2, 3, 4, 5..., 2019\quad (1)$$$$2, 3, 5, 6, 7..., 2019\quad (2)$$To get the second sequence we have simply removed the numbers which are perfect squares up to 2019 from sequence $(1)$ (which like we said, there are 44), we now know that sequence $(1)$ has 2019 elements, so to make sequence $(2)$ have 2019 elements we need to add $44$ numbers after the $2019$, so:
$$2, 3, 5, 6, 7..., 2019\Rightarrow 2,3,5...,2019,2020,2021,2022,2023,2024,\boxed{2025},2026...\quad (2.1)$$Notice that after adding those number we have passed $2025$ which is a perfect square,so it must be removed from our sequence.
Now sequence $(2.1)$ has $2018$ elements so we must add $1$ more number to the sequence (for it to have 2019 elements).
Thus, the 2019-th term of this sequence is $2019+44+1=\boxed{2064}$
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MC413551
2228 posts
#4 • 1 Y
Y by ImSh95
For p2 just use mass points
Make A 10 so then D is also 10 and then E is 20.
B is 5 and so is C.
That means F is 15
So the ratio of AF to FC is 1:2
So AF to AC is 1/3
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LolMathZ13PR
1 post
#6
Y by
broder supongo que eres de chile dime como puedo publicar aqui
Quote:
Quote:
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liyufish
12 posts
#7
Y by
A problem that looks like p1 but a little harder:
Consider the sequence $a_n$ which include all positive integers that are not perfect squares. Prove: for any positive integer n, $\lvert a_n-n-\sqrt n \rvert <\frac{1}{2}$
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bhontu
12 posts
#8
Y by
p2 is trivial with menelaus, and p4 is just 5 which is also trivial if you know the proof of R(3,3)=6
This post has been edited 1 time. Last edited by bhontu, Mar 21, 2025, 1:20 PM
Reason: solving p4
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