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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

Are you interested in working towards MATHCOUNTS and don’t know where to start? We have you covered! If you have taken Prealgebra, then you are ready for MATHCOUNTS/AMC 8 Basics. Already aiming for State or National MATHCOUNTS and harder AMC 8 problems? Then our MATHCOUNTS/AMC 8 Advanced course is for you.

Summer camps are starting next month at the Virtual Campus in math and language arts that are 2 - to 4 - weeks in duration. Spaces are still available - don’t miss your chance to have an enriching summer experience. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following upcoming events:
[list][*]May 9th, 4:30pm PT/7:30pm ET, Casework 2: Overwhelming Evidence — A Text Adventure, a game where participants will work together to navigate the map, solve puzzles, and win! All are welcome.
[*]May 19th, 4:30pm PT/7:30pm ET, What's Next After Beast Academy?, designed for students finishing Beast Academy and ready for Prealgebra 1.
[*]May 20th, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 1 Math Jam, Problems 1 to 4, join the Canada/USA Mathcamp staff for this exciting Math Jam, where they discuss solutions to Problems 1 to 4 of the 2025 Mathcamp Qualifying Quiz!
[*]May 21st, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 2 Math Jam, Problems 5 and 6, Canada/USA Mathcamp staff will discuss solutions to Problems 5 and 6 of the 2025 Mathcamp Qualifying Quiz![/list]
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All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
May 1, 2025
0 replies
4th grader qual JMO
HCM2001   26
N 2 minutes ago by lele0305
i mean.. whattttt??? just found out about this.. is he on aops? (i'm sure he is) where are you orz lol..
https://www.mathschool.com/blog/results/celebrating-success-douglas-zhang-is-rsm-s-youngest-usajmo-qualifier
26 replies
HCM2001
Yesterday at 12:53 AM
lele0305
2 minutes ago
Proof-based math
imbadatmath1233   4
N 2 hours ago by imbadatmath1233
Okay, I need help in deciding on how i am going to prep. My JMO index was 121.5+11 = 231.5(10A) and I missed the cutoff by 1.5. Ive already grieved about this before but I need some help in deciding what I should do next year. I think I can make JMO but my goal is to get 21+ on JMO. However, OTIS applications are already done so does anyone have any other tips on how to prep for JMO. Any help would be very much appreciated. Also, how much time should i spend on computational if i want to prep for olympiad but I don't want to get rusty. Thanks for helping!
4 replies
imbadatmath1233
4 hours ago
imbadatmath1233
2 hours ago
Awesome Math Rec Letter
cowstalker   0
2 hours ago
Hello, I recently looked at the MIT Primes website and saw that they accept recommendation letters from the Awesome Math Summer Program. Has anyone ever gotten a recommendation letter from one of the teachers in Awesome Math? I'm also planning to take AMSP and would like to get a rec letter from my teacher, too, so I was wondering if this is even possible or not.
0 replies
cowstalker
2 hours ago
0 replies
9 USAMO/JMO
BAM10   21
N 4 hours ago by imbadatmath1233
I mock ~90-100 on very recent AMC 10 mock right now. I plan to take AMC 10 final fives(9th), intermediate NT(9th), aime A+B courses in 10th and 11th and maybe mathWOOT 1 (12th). For more info I got 20 on this years AMC 8 with 3 sillies and 32 on MATHCOUNTS chapter. Also what is a realistic timeline to do this
21 replies
BAM10
May 19, 2025
imbadatmath1233
4 hours ago
No more topics!
Graph Theory?!?!??!?2.?!!>2r
pog   11
N May 16, 2025 by tliang2000
Source: 2024 AMC 8 #14
The one-way routes connecting towns $A$, $M$, $C$, $X$, $Y$, and $Z$ are shown in the figure below (not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance from A to Z in kilometers?

IMAGE

$\textbf{(A)}\ 28 \qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 30 \qquad \textbf{(D)}\ 31 \qquad \textbf{(E)}\ 32$
11 replies
pog
Oct 11, 2024
tliang2000
May 16, 2025
Graph Theory?!?!??!?2.?!!>2r
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G H BBookmark kLocked kLocked NReply
Source: 2024 AMC 8 #14
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pog
4917 posts
#1 • 2 Y
Y by rokkc, PikaPika999
The one-way routes connecting towns $A$, $M$, $C$, $X$, $Y$, and $Z$ are shown in the figure below (not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance from A to Z in kilometers?

[asy]
/* AMC8 P14 2024, by NUMANA: BUI VAN HIEU */
import graph;
unitsize(2cm);
real r=0.25;
// Define the nodes and their positions
pair[] nodes = { (0,0), (2,0), (1,1), (3,1), (4,0), (6,0) };
string[] labels = { "A", "M", "X", "Y", "C", "Z" };

// Draw the nodes as circles with labels
for(int i = 0; i < nodes.length; ++i) {
    draw(circle(nodes[i], r));
    label("$" + labels[i] + "$", nodes[i]);
}
// Define the edges with their node indices and labels
int[][] edges = { {0, 1}, {0, 2}, {2, 1}, {2, 3}, {1, 3}, {1, 4}, {3, 4}, {4, 5}, {3, 5} };
string[] edgeLabels = { "8", "5", "2", "10", "6", "14", "5", "10", "17" };
pair[] edgeLabelsPos = { S, SE, SW, S, SE, S, SW, S, NE};
// Draw the edges with labels
for (int i = 0; i < edges.length; ++i) {
    pair start = nodes[edges[i][0]];
    pair end = nodes[edges[i][1]];
    draw(start + r*dir(end-start) -- end-r*dir(end-start), Arrow);
    label("$" + edgeLabels[i] + "$", midpoint(start -- end),  edgeLabelsPos[i]);
}
// Draw the curved edge with label
draw(nodes[1]+r * dir(-45)..controls (3, -0.75) and (5, -0.75)..nodes[5]+r * dir(-135), Arrow);
label("$25$", midpoint(nodes[1]..controls (3, -0.75) and (5, -0.75)..nodes[5]), 2S);
[/asy]

$\textbf{(A)}\ 28 \qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 30 \qquad \textbf{(D)}\ 31 \qquad \textbf{(E)}\ 32$
Z K Y
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golden_star_123
208 posts
#2 • 1 Y
Y by PikaPika999
The triangles can't exist??? 5-2-8 is crazy
Solution
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DreamineYT
298 posts
#3 • 1 Y
Y by PikaPika999
how to do it
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pog
4917 posts
#4 • 1 Y
Y by PikaPika999
golden_star_123 wrote:
The triangles can't exist??? 5-2-8 is crazy
:maybe: I guess the routes are not necessarily linear
This post has been edited 1 time. Last edited by pog, Oct 11, 2024, 4:36 PM
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AMathCountsguy10
979 posts
#5 • 1 Y
Y by PikaPika999
lol :rotfl: this made me laugh
Z K Y
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andliu766
115 posts
#6 • 1 Y
Y by PikaPika999
Me performs Djikstra's algorithm in contest be like: ...
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AshAuktober
1009 posts
#7 • 1 Y
Y by PikaPika999
Go A->X_>M->Y->C->Z to get 28
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fruitmonster97
2501 posts
#9
Y by
We find every single possible route.

AMZ: 33
AMCZ: 32
AMYCZ: 29
AMYZ: 31
AXYZ: 32
AXYCZ: 30
AXMYZ: 30
AXMCZ: 31
AXMYCZ: 28


Our answer is $\boxed{28},$ answer choice $\textbf{(A)}.$
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JH_K2IMO
129 posts
#10
Y by
A--->X--->M--->Y--->C--->Z.(shortest path)
5+2+6+5+10=28.
The answer is (A) 28.
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BS2012
1047 posts
#11
Y by
Delete the path from A to M because AXM is faster
Delete the path from X to Y because XMY is faster
Delete the path from M to C because MYC is faster
Delete the path from Y to Z because VCZ is faster
Delete the path from M to Z because MYCZ is faster
We are left with a single path from A to Z, namely AXMYCZ, which has answer 28.
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Ilikeminecraft
658 posts
#12
Y by
Solved with ST2009 and Awesomeness_in_a_bun

Djikstra's algorithm gives 28
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tliang2000
46 posts
#13
Y by
what’s djikstra’s algorithm
Z K Y
N Quick Reply
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