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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

Are you interested in working towards MATHCOUNTS and don’t know where to start? We have you covered! If you have taken Prealgebra, then you are ready for MATHCOUNTS/AMC 8 Basics. Already aiming for State or National MATHCOUNTS and harder AMC 8 problems? Then our MATHCOUNTS/AMC 8 Advanced course is for you.

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[*]May 21st, 4:00pm PT/7:00pm ET, Mathcamp 2025 Qualifying Quiz Part 2 Math Jam, Problems 5 and 6, Canada/USA Mathcamp staff will discuss solutions to Problems 5 and 6 of the 2025 Mathcamp Qualifying Quiz![/list]
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0 replies
jlacosta
May 1, 2025
0 replies
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k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
J
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k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
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2 headed arrows usage
mathprodigy2011   1
N 30 minutes ago by alcumusftwgrind
Source: 2003 USAMO 4
I can't upload the file but I was working with someone on 2003 USAMO p4. When we saw "if and only if" I thought it meant we have to prove it both directions. However, when we looked at Evan Chen's solution after writing it out; Evan Chen used double headed arrows and left it at that. My question is, how did he use them and how do I know when I can or can not use them?
1 reply
mathprodigy2011
an hour ago
alcumusftwgrind
30 minutes ago
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Isogonal Conjugates of Nagel and Gergonne Point
SerdarBozdag   6
N 41 minutes ago by ohiorizzler1434
Source: http://math.fau.edu/yiu/Oldwebsites/Geometry2013Fall/Geometry2013Chapter12.pdf
Proposition 12.1.
(a) The isogonal conjugate of the Gergonne point is the insimilicenter of
the circumcircle and the incircle.
(b) The isogonal conjugate of the Nagel point is the exsimilicenter of the circumcircle and
the incircle.
Note: I need synthetic solution.
6 replies
SerdarBozdag
Apr 17, 2021
ohiorizzler1434
41 minutes ago
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Looking for someone to work with
midacer   1
N an hour ago by wipid98
I’m looking for a motivated study partner (or small group) to collaborate on college-level competition math problems, particularly from contests like the Putnam, IMO Shortlist, IMC, and similar. My goal is to improve problem-solving skills, explore advanced topics (e.g., combinatorics, NT, analysis), and prepare for upcoming competitions. I’m new to contests but have a strong general math background(CPGE in Morocco). If interested, reply here or DM me to discuss
1 reply
midacer
2 hours ago
wipid98
an hour ago
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USAMO 1983 Problem 2 - Roots of Quintic
Binomial-theorem   33
N 2 hours ago by SomeonecoolLovesMaths
Source: USAMO 1983 Problem 2
Prove that the roots of\[x^5 + ax^4 + bx^3 + cx^2 + dx + e = 0\] cannot all be real if $2a^2 < 5b$.
33 replies
Binomial-theorem
Aug 16, 2011
SomeonecoolLovesMaths
2 hours ago
J
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Compact powers of 2
NO_SQUARES   1
N 3 hours ago by Isolemma
Source: 239 MO 2025 8-9 p3 = 10-11 p2
Let's call a power of two compact if it can be represented as the sum of no more than $10^9$ not necessarily distinct factorials of positive integer numbers. Prove that the set of compact powers of two is finite.
1 reply
NO_SQUARES
May 5, 2025
Isolemma
3 hours ago
J
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Cute NT Problem
M11100111001Y1R   4
N 3 hours ago by RANDOM__USER
Source: Iran TST 2025 Test 4 Problem 1
A number \( n \) is called lucky if it has at least two distinct prime divisors and can be written in the form:
\[ n = p_1^{\alpha_1} + \cdots + p_k^{\alpha_k} \]where \( p_1, \dots, p_k \) are distinct prime numbers that divide \( n \). (Note: it is possible that \( n \) has other prime divisors not among \( p_1, \dots, p_k \).) Prove that for every prime number \( p \), there exists a lucky number \( n \) such that \( p \mid n \).
4 replies
M11100111001Y1R
Today at 7:20 AM
RANDOM__USER
3 hours ago
J
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USAMO 2003 Problem 4
MithsApprentice   72
N 3 hours ago by endless_abyss
Let $ABC$ be a triangle. A circle passing through $A$ and $B$ intersects segments $AC$ and $BC$ at $D$ and $E$, respectively. Lines $AB$ and $DE$ intersect at $F$, while lines $BD$ and $CF$ intersect at $M$. Prove that $MF = MC$ if and only if $MB\cdot MD = MC^2$.
72 replies
MithsApprentice
Sep 27, 2005
endless_abyss
3 hours ago
J
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Easy but unusual junior ineq
Maths_VC   1
N 3 hours ago by blug
Source: Serbia JBMO TST 2025, Problem 2
Real numbers $x, y$ $\ge$ $0$ satisfy $1$ $\le$ $x^2 + y^2$ $\le$ $5$. Determine the minimal and the maximal value of the expression $2x + y$
1 reply
Maths_VC
4 hours ago
blug
3 hours ago
J
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Bosnia and Herzegovina JBMO TST 2009 Problem 1
gobathegreat   1
N 3 hours ago by FishkoBiH
Source: Bosnia and Herzegovina Junior Balkan Mathematical Olympiad TST 2009
Lengths of sides of triangle $ABC$ are positive integers, and smallest side is equal to $2$. Determine the area of triangle $P$ if $v_c = v_a + v_b$, where $v_a$, $v_b$ and $v_c$ are lengths of altitudes in triangle $ABC$ from vertices $A$, $B$ and $C$, respectively.
1 reply
gobathegreat
Sep 17, 2018
FishkoBiH
3 hours ago
J
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USAMO 2001 Problem 2
MithsApprentice   53
N 3 hours ago by lksb
Let $ABC$ be a triangle and let $\omega$ be its incircle. Denote by $D_1$ and $E_1$ the points where $\omega$ is tangent to sides $BC$ and $AC$, respectively. Denote by $D_2$ and $E_2$ the points on sides $BC$ and $AC$, respectively, such that $CD_2=BD_1$ and $CE_2=AE_1$, and denote by $P$ the point of intersection of segments $AD_2$ and $BE_2$. Circle $\omega$ intersects segment $AD_2$ at two points, the closer of which to the vertex $A$ is denoted by $Q$. Prove that $AQ=D_2P$.
53 replies
MithsApprentice
Sep 30, 2005
lksb
3 hours ago
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A=b
k2c901_1   89
N 3 hours ago by reni_wee
Source: Taiwan 1st TST 2006, 1st day, problem 3
Let $a$, $b$ be positive integers such that $b^n+n$ is a multiple of $a^n+n$ for all positive integers $n$. Prove that $a=b$.

Proposed by Mohsen Jamali, Iran
89 replies
k2c901_1
Mar 29, 2006
reni_wee
3 hours ago
J
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4th grader qual JMO
HCM2001   42
N 5 hours ago by BS2012
i mean.. whattttt??? just found out about this.. is he on aops? (i'm sure he is) where are you orz lol..
https://www.mathschool.com/blog/results/celebrating-success-douglas-zhang-is-rsm-s-youngest-usajmo-qualifier
42 replies
HCM2001
May 22, 2025
BS2012
5 hours ago
J
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Do you need to attend mop
averageguy   5
N Today at 5:55 PM by babyzombievillager
So I got accepted into a summer program and already paid the fee of around $5000 dollars. It's for 8 weeks (my entire summer) and it's in person. I have a few questions
1. If I was to make MOP this year am I forced to attend?
2.If I don't attend the program but still qualify can I still put on my college application that I qualified for MOP or can you only put MOP qualifier if you actually attend the program.
5 replies
averageguy
Mar 5, 2025
babyzombievillager
Today at 5:55 PM
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2014 amc 10 a problem 23
Rook567   3
N Today at 4:13 PM by Rook567
Why do solutions assume 30 60 90 triangles?
If you assume 45 45 90 you get 5/6 as answer, don’t you?
3 replies
Rook567
Yesterday at 7:31 PM
Rook567
Today at 4:13 PM
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USA(J)MO Statistics Out
BS2012   53
N Apr 24, 2025 by maxamc
Source: MAA edvistas page
https://maa.edvistas.com/eduview/report.aspx?view=1561&mode=6
who were the 2 usamo perfects
53 replies
BS2012
Apr 23, 2025
maxamc
Apr 24, 2025
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USA(J)MO Statistics Out
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Reveal topic tags
USA(J)MO
USAJMO
USAMO
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Source: MAA edvistas page
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blueprimes
360 posts
blueprimes
#48 h  Apr 24, 2025, 9:00 PM • 2 Y
Y by Arcticturn, elasticwealth
joebub56 wrote:
I would argue mts is more fair than amc. Why is a multiple choice test being factored into oly qualification?? And honestly cheating isnt even a big issue because of the way mts is structured. The whole point is for the competition to be more open and not under time pressure

This has to be ragebait...

AMC is multiple choice and Scantron graded because there are tens of thousands of people taking AMC ever year. Nobody is grading thousands of proofs. And as said before, USAMTS is discontinuous over a month and allows all resources whereas olympiad is 4.5 hours so it is terrible at discerning olympiad skill
This post has been edited 3 times. Last edited by blueprimes, Apr 24, 2025, 9:03 PM
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joebub56
14 posts
joebub56
#49 h  Apr 24, 2025, 9:04 PM
Y by
blueprimes wrote:
joebub56 wrote:
I would argue mts is more fair than amc. Why is a multiple choice test being factored into oly qualification?? And honestly cheating isnt even a big issue because of the way mts is structured. The whole point is for the competition to be more open and not under time pressure

This has to be ragebait...

AMC is multiple choice and Scantron graded because there are tens of thousands of people taking AMC ever year. Nobody is grading thousands of proofs. And as said before, USAMTS is discontinuous over a month and allows all resources whereas olympiad is 4.5 hours so it is terrible at discerning olympiad skill

I

This doesn’t disprove my point? At the end of the day a multiple choice test is a horrible indicator of olympiad skill. Also its not like mts directly determines oly qualification either theres still aime
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ethan2011
348 posts
ethan2011
#50 h  Apr 24, 2025, 9:06 PM • 1 Y
Y by elasticwealth
joebub56 wrote:
I would argue mts is more fair than amc. Why is a multiple choice test being factored into oly qualification?? And honestly cheating isnt even a big issue because of the way mts is structured. The whole point is for the competition to be more open and not under time pressure

Why is a proof test that allows AI and coding factored into oly qualification?
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joebub56
14 posts
joebub56
#51 h  Apr 24, 2025, 9:17 PM
Y by
ethan2011 wrote:
joebub56 wrote:
I would argue mts is more fair than amc. Why is a multiple choice test being factored into oly qualification?? And honestly cheating isnt even a big issue because of the way mts is structured. The whole point is for the competition to be more open and not under time pressure

Why is a proof test that allows AI and coding factored into oly qualification?

its not like ai and coding can do the whole thing for you. and even if you solve a problem with the help of ai, thats still better than doing multiple choice
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jellybeanzzz
499 posts
jellybeanzzz
#52 h  Apr 24, 2025, 9:18 PM
Y by
Honestly I felt that anyone capable of solving all the problems would do it in a few hours. (For example I spent ~15 hours across all 3 contests which was 15 questions + writeups.) So at least for me, the “you get 1 month” thing doesn’t make it different from oly time constraints.

Also several things
1. AI is not allowed
2. The hard step of solving problems with code isn’t the coding itself, it’s proving that your code is rigorous. Most problems this year weren’t solvable with code either.
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joebub56
14 posts
joebub56
#53 h  Apr 24, 2025, 9:21 PM
Y by
jellybeanzzz wrote:
Honestly I felt that anyone capable of solving all the problems would do it in a few hours. (For example I spent ~15 hours across all 3 contests which was 15 questions + writeups.) So at least for me, the “you get 1 month” thing doesn’t make it different from oly time constraints.

Also several things
1. AI is not allowed
2. The hard step of solving problems with code isn’t the coding itself, it’s proving that your code is rigorous. Most problems this year weren’t solvable with code either.

ai is allowed but only for certain things. like you cant just give it the whole problem but you can ask things like "useful formulas for combinatorics". and thats all ai is good for anyways so yeah its not even a big deal
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ethan2011
348 posts
ethan2011
#54 h  Apr 24, 2025, 9:32 PM
Y by
joebub56 wrote:
jellybeanzzz wrote:
Honestly I felt that anyone capable of solving all the problems would do it in a few hours. (For example I spent ~15 hours across all 3 contests which was 15 questions + writeups.) So at least for me, the “you get 1 month” thing doesn’t make it different from oly time constraints.

Also several things
1. AI is not allowed
2. The hard step of solving problems with code isn’t the coding itself, it’s proving that your code is rigorous. Most problems this year weren’t solvable with code either.

ai is allowed but only for certain things. like you cant just give it the whole problem but you can ask things like "useful formulas for combinatorics". and thats all ai is good for anyways so yeah its not even a big deal

you can use AI and they won't notice
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jellybeanzzz
499 posts
jellybeanzzz
#55 h  Apr 24, 2025, 9:35 PM
Y by
ethan2011 wrote:
you can use AI and they won't notice

They noticed actually! They banned dozens of people in just the first round. That’s dozens more bans than AMC cheaters got!
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LostRiptide
29 posts
LostRiptide
#56 h  Apr 24, 2025, 9:40 PM
Y by
jellybeanzzz wrote:
ethan2011 wrote:
you can use AI and they won't notice

They noticed actually! They banned dozens of people in just the first round. That’s dozens more bans than AMC cheaters got!

Makes a very cheatable contest
Bans some of the many cheaters
Many cheaters still remain
SEE! WE'RE BETTER THAN YOU!!! ah argument
Also AMC cheaters also get mass banned bro
This post has been edited 2 times. Last edited by LostRiptide, Apr 24, 2025, 9:46 PM
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BS2012
1057 posts
BS2012
#57 h  Apr 24, 2025, 9:40 PM
Y by
also who said that the only way to cheat on usamts is to use ai
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xTimmyG
265 posts
xTimmyG
#58 h  Apr 24, 2025, 10:27 PM • 8 Y
Y by hsuya1, blueprimes, MathPerson12321, elasticwealth, megarnie, Andyluo, lpieleanu, KevinYang2.71
Anyone who thinks USAMTS cannot be cheated is extremely wrong. People can easily ask AI for a solution, then put it in their own words, so that it is undetectable. Contestants can also just groupsolve or share answers. Something needs to be done about this, as this allows for people who would've gotten a terrible score on the amc (like 50) to easily qualify for AIME.
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bwu_2022
53 posts
bwu_2022
#59 h  Apr 24, 2025, 10:52 PM
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We will see about it next year. I bet the number of people who attend USAMTA will increase significantly.

Look at the leaderboard: https://www.usamts.org/leaderboard/. 6 people got full points last year, and this year, it was 54.
This post has been edited 1 time. Last edited by bwu_2022, Apr 25, 2025, 1:30 AM
Reason: Accuracy
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TiguhBabeHwo
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TiguhBabeHwo
#60 h  Apr 24, 2025, 11:12 PM
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Well yeah obviously because it's the most widespread information in all of jmo qualification threads at this point
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bachkieu
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bachkieu
#61 h  Apr 24, 2025, 11:13 PM
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bwu_2022 wrote:
We will see about it next year. I bet the number of people who attend USAMTA will increase significantly.

Look at the leaderboard: https://www.usamts.org/leaderboard/. 6 people got full points, and this year, it was 54.

i would like to point out i got full last year and 71 this year :skull:
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maxamc
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maxamc
#62 h  Apr 24, 2025, 11:32 PM
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bwu_2022 wrote:
We will see about it next year. I bet the number of people who attend USAMTA will increase significantly.

Look at the leaderboard: https://www.usamts.org/leaderboard/. 6 people got full points, and this year, it was 54.

What is USAMTA?
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