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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
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k a My Retirement & New Leadership at AoPS
rrusczyk   1573
N 4 hours ago by SmartGroot
I write today to announce my retirement as CEO from Art of Problem Solving. When I founded AoPS 22 years ago, I never imagined that we would reach so many students and families, or that we would find so many channels through which we discover, inspire, and train the great problem solvers of the next generation. I am very proud of all we have accomplished and I’m thankful for the many supporters who provided inspiration and encouragement along the way. I'm particularly grateful to all of the wonderful members of the AoPS Community!

I’m delighted to introduce our new leaders - Ben Kornell and Andrew Sutherland. Ben has extensive experience in education and edtech prior to joining AoPS as my successor as CEO, including starting like I did as a classroom teacher. He has a deep understanding of the value of our work because he’s an AoPS parent! Meanwhile, Andrew and I have common roots as founders of education companies; he launched Quizlet at age 15! His journey from founder to MIT to technology and product leader as our Chief Product Officer traces a pathway many of our students will follow in the years to come.

Thank you again for your support for Art of Problem Solving and we look forward to working with millions more wonderful problem solvers in the years to come.

And special thanks to all of the amazing AoPS team members who have helped build AoPS. We’ve come a long way from here:IMAGE
1573 replies
rrusczyk
Mar 24, 2025
SmartGroot
4 hours ago
k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

Are you ready to level up with Olympiad training? Registration is open with early bird pricing available for our WOOT programs: MathWOOT (Levels 1 and 2), CodeWOOT, PhysicsWOOT, and ChemWOOT. What is WOOT? WOOT stands for Worldwide Online Olympiad Training and is a 7-month high school math Olympiad preparation and testing program that brings together many of the best students from around the world to learn Olympiad problem solving skills. Classes begin in September!

Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
Our full course list for upcoming classes is below:
All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Mar 2, 2025
0 replies
Practice AMC 10A
freddyfazbear   42
N 13 minutes ago by DhruvJha
Hey everyone!

I’m back with another practice test. Sorry this one took a while to pump out since I have been busy lately.

Post your score/distribution, favorite problems, and thoughts on the difficulty of the test down below. Hope you enjoy!


Practice AMC 10A

1. Find the sum of the infinite geometric series 1/2 + 7/36 + 49/648 + …
A - 18/11, B - 9/22, C - 9/11, D - 18/7, E - 9/14

2. What is the first digit after the decimal point in the square root of 420?
A - 1, B - 2, C - 3, D - 4, E - 5

3. Caden’s calculator is broken and two of the digits are swapped for some reason. When he entered in 9 + 10, he got 21. What is the sum of the two digits that got swapped?
A - 2, B - 3, C - 4, D - 5, E - 6

4. Two circles with radiuses 47 and 96 intersect at two points A and B. Let P be the point 82% of the way from A to B. A line is drawn through P that intersects both circles twice. Let the four intersection points, from left to right be W, X, Y, and Z. Find (PW/PX)*(PY/PZ).
A - 50/5863, B - 47/96, C - 1, D - 96/47, E - 5863/50

5. Two dice are rolled, and the two numbers shown are a and b. How many possible values of ab are there?
A - 17, B - 18, C - 19, D - 20, E - 21

6. What is the largest positive integer that cannot be expressed in the form 6a + 9b + 4c + 20d, where a, b, c, and d are positive integers?
A - 29, B - 38, C - 43, D - 76, E - 82

7. What is the absolute difference of the probabilities of getting at least 6/10 on a 10-question true or false test and at least 3/5 on a 5-question true or false test?
A - 0, B - 1/504, C - 1/252, D - 1/126, E - 1/63

8. How many arrangements of the letters in the word “ginger” are there such that the two vowels have an even number of letters (remember 0 is even) between them (including the original “ginger”)?
A - 72, B - 108, C - 144, D - 216, E - 432

9. After opening his final exam, Jason does not know how to solve a single question. So he decides to pull out his phone and search up the answers. Doing this, Jason has a success rate of anywhere from 94-100% for any given question he uses his phone on. However, if the teacher sees his phone at any point during the test, then Jason gets a 0.5 multiplier on his final test score, as well as he must finish the rest of the test questions without his phone. (Assume Jason uses his phone on every question he does until he finishes the test or gets caught.) Every question is a 5-choice multiple choice question. Jason has a 90% chance of not being caught with his phone. What is the expected value of Jason’s test score, rounded to the nearest tenth of a percent?
A - 89.9%, B - 90.0%, C - 90.1%, D - 90.2%, E - 90.3%

10. A criminal is caught by a police officer. Due to a lack of cooperation, the officer calls in a second officer so they can start the arrest smoothly. Officer 1 takes 26:18 to arrest a criminal, and officer 2 takes 13:09 to arrest a criminal. With these two police officers working together, how long should the arrest take?
A - 4:23, B - 5:26, C - 8:46, D - 17:32, E - 19:44

11. Suppose that on the coordinate grid, the x-axis represents economic freedom, and the y-axis represents social freedom, where -1 <= x, y <= 1 and a higher number for either coordinate represents more freedom along that particular axis. Accordingly, the points (0, 0), (1, 1), (-1, 1), (-1, -1), and (1, -1) represent democracy, anarchy, socialism, communism, and fascism, respectively. A country is classified as whichever point it is closest to. Suppose a theoretical new country is selected by picking a random point within the square bounded by anarchy, socialism, communism, and fascism as its vertices. What is the probability that it is fascist?
A - 1 - (1/4)pi, B - 1/5, C - (1/16)pi, D - 1/4, E - 1/8

12. Statistics show that people in Memphis who eat at KFC n days a week have a (1/10)(n+2) chance of liking kool-aid, and the number of people who eat at KFC n days a week is directly proportional to 8 - n (Note that n can only be an integer from 0 to 7, inclusive). A random person in Memphis is selected. Find the probability that they like kool-aid.
A - 13/30, B - 17/30, C - 19/30, D - 23/30, E - 29/30

13. A southern plantation has a length of 60 meters and a width of 50 meters. On the plantation, there is 1 kg of cotton per square meter waiting to be picked. The master of the plantation initially calls over 25 cotton pickers, each picking cotton at a rate of 5 kg per hour starting at 9 AM. However, he wants all of the cotton to be picked by 9 PM, and realizes that he needs to speed up the process. At 12 PM, the master then encourages his pickers to work faster by whipping them, in which they then all speed up to 6 kg per hour. At 1 PM, the master calls in 15 more pickers which pick at 5 kg per hour. Unfortunately, at 3 PM, the clouds drift away and the hot sun starts beating down, which slows every picker down by 2 kg per hour. At 4 PM, the clouds return, and all pickers return to picking at 5 kg per hour. At 5 PM, the master calls in 30 more pickers, which again pick at 5 kg per hour. At 6 PM, he calls in 30 more pickers. At 7 PM, he whips all the pickers again, speeding them up to 6 kg per hour. But at 8 PM, n pickers suddenly crash out and stop working due to fatigue, and the rest all slow back down to 5 kg per hour because they are tired. The master does not have any more pickers, so if too many of them drop out, he is screwed and will have to go overtime. Find the maximum value of n such that all of the cotton can still be picked on time, done no later than 9 PM.
A - 51, B - 52, C - 53, D - 54, E - 55

14. Find the number of positive integers n less than 69 such that the average of all the squares from 1^2 to n^2, inclusive, is an integer.
A - 11, B - 12, C - 23, D - 24, E - 48

15. Find the number of ordered pairs (a, b) of integers such that (a - b)^2 = 625 - 2ab.
A - 6, B - 10, C - 12, D - 16, E - 20

16. What is the 420th digit after the decimal point in the decimal expansion of 1/13?
A - 4, B - 5, C - 6, D - 7, E - 8

17. Two congruent towers stand near each other. Both take the shape of a right rectangular prism. A plane that cuts both towers into two pieces passes through the vertical axes of symmetry of both towers and does not cross the floor or roof of either tower. Let the point that the plane crosses the axis of symmetry of the first tower be A, and the point that the plane crosses the axis of symmetry of the second tower be B. A is 81% of the way from the floor to the roof of the first tower, and B is 69% of the way from the floor to the roof of the second tower. What percent of the total mass of both towers combined is above the plane?
A - 19%, B - 25%, C - 50%, D - 75%, E - 81%

18. What is the greatest number of positive integer factors an integer from 1 to 100 can have?
A - 10, B - 12, C - 14, D - 15, E - 16

19. On an analog clock, the minute hand makes one full revolution every hour, and the hour hand makes one full revolution every 12 hours. Both hands move at a constant rate. During which of the following time periods does the minute hand pass the hour hand?
A - 7:35 - 7:36, B - 7:36 - 7:37, C - 7:37 - 7:38, D - 7:38 - 7:39, E - 7:39 - 7:40

20. Find the smallest positive integer that is a leg in three different Pythagorean triples.
A - 12, B - 14, C - 15, D - 20, E - 21

21. How many axes of symmetry does the graph of (x^2)(y^2) = 69 have?
A - 2, B - 3, C - 4, D - 5, E - 6

22. Real numbers a, b, and c are chosen uniformly and at random from 0 to 3. Find the probability that a + b + c is less than 2.
A - 4/81, B - 8/81, C - 4/27, D - 8/27, E - 2/3

23. Let f(n) be the sum of the positive integer divisors of n. Find the sum of the digits of the smallest odd positive integer n such that f(n) is greater than 2n.
A - 15, B - 18, C - 21, D - 24, E - 27

24. Find the last three digits of 24^10.
A - 376, B - 576, C - 626, D - 876, E - 926

25. A basketball has a diameter of 9 inches, and the hoop has a diameter of 18 inches. Peter decides to pick up the basketball and make a throw. Given that Peter has a 1/4 chance of accidentally hitting the backboard and missing the shot, but if he doesn’t, he is guaranteed that the frontmost point of the basketball will be within 18 inches of the center of the hoop at the moment when a great circle of the basketball crosses the plane containing the rim. No part of the ball will extend behind the backboard at any point during the throw, and the rim is attached directly to the backboard. What is the probability that Peter makes a green FN?
A - 3/128, B - 3/64, C - 3/32, D - 3/16, E - 3/8
42 replies
freddyfazbear
Mar 24, 2025
DhruvJha
13 minutes ago
Mathcounts state
happymoose666   12
N 43 minutes ago by fxx11
Hi everyone,
I just have a question. I live in PA and I sadly didn't make it to nationals this year. Is PA a competitive state? I'm new into mathcounts and not sure
12 replies
happymoose666
Mar 24, 2025
fxx11
43 minutes ago
USA Canada math camp
Bread10   35
N an hour ago by abbominable_sn0wman
How difficult is it to get into USA Canada math camp? What should be expected from an accepted applicant in terms of the qualifying quiz, essays and other awards or math context?
35 replies
Bread10
Mar 2, 2025
abbominable_sn0wman
an hour ago
LMT Spring 2025 and Girls' LMT 2025
vrondoS   13
N an hour ago by ethan2011
The Lexington High School Math Team is proud to announce LMT Spring 2025 and our inaugural Girls’ LMT 2025! LMT is a competition for middle school students interested in math. Students can participate individually, or on teams of 4-6 members. This announcement contains information for BOTH competitions.

LMT Spring 2025 will take place from 8:30 AM-5:00 PM on Saturday, May 3rd, at Lexington High School, 251 Waltham St., Lexington, MA 02421.

The competition will include two individual rounds, a Team Round, and a Guts Round, with a break for lunch and mini-events. A detailed schedule is available at https://lhsmath.org/LMT/Schedule.

There is a $15 fee per participant, paid on the day of the competition. Pizza will be provided for lunch, at no additional cost.

Register for LMT at https://lhsmath.org/LMT/Registration/Home.

Girls’ LMT 2025 will be held ONLINE on MathDash from 11:00 AM-4:15 PM EST on Saturday, April 19th, 2025. Participation is open to middle school students who identify as female or non-binary. The competition will include an individual round and a team round with a break for lunch and mini-events. It is free to participate.

Register for GLMT at https://www.lhsmath.org/LMT/Girls_LMT.

More information is available on our website: https://lhsmath.org/LMT/Home. Email lmt.lhsmath@gmail.com with any questions.
13 replies
+1 w
vrondoS
2 hours ago
ethan2011
an hour ago
No more topics!
when p25 faster than p4
ostriches88   31
N Jan 12, 2025 by fruitmonster97
Source: 2024 AMC 10B p25
Each of $27$ bricks (right rectangular prisms) has dimensions $a \times b \times c$, where $a$, $b$, and $c$ are pairwise relatively prime positive integers. These bricks are arranged to form a $3 \times 3 \times 3$ block, as shown on the left below. A $28$th brick with the same dimensions is introduced, and these bricks are reconfigured into a $2 \times 2 \times 7$ block, shown on the right. The new block is $1$ unit taller, $1$ unit wider, and $1$ unit deeper than the old one. What is $a + b + c$?

IMAGE

$
\textbf{(A) }88 \qquad
\textbf{(B) }89 \qquad
\textbf{(C) }90 \qquad
\textbf{(D) }91 \qquad
\textbf{(E) }92 \qquad
$
31 replies
ostriches88
Nov 13, 2024
fruitmonster97
Jan 12, 2025
when p25 faster than p4
G H J
Source: 2024 AMC 10B p25
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ostriches88
1527 posts
#1
Y by
Each of $27$ bricks (right rectangular prisms) has dimensions $a \times b \times c$, where $a$, $b$, and $c$ are pairwise relatively prime positive integers. These bricks are arranged to form a $3 \times 3 \times 3$ block, as shown on the left below. A $28$th brick with the same dimensions is introduced, and these bricks are reconfigured into a $2 \times 2 \times 7$ block, shown on the right. The new block is $1$ unit taller, $1$ unit wider, and $1$ unit deeper than the old one. What is $a + b + c$?

https://cdn.artofproblemsolving.com/attachments/2/d/b18d3d0a9e5005c889b34e79c6dab3aaefeffd.png

$
\textbf{(A) }88 \qquad
\textbf{(B) }89 \qquad
\textbf{(C) }90 \qquad
\textbf{(D) }91 \qquad
\textbf{(E) }92 \qquad
$
This post has been edited 2 times. Last edited by ostriches88, Nov 13, 2024, 6:00 PM
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ostriches88
1527 posts
#2
Y by
basic system of equations yields E
Attachments:
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lucaswujc
293 posts
#3
Y by
real p25 was so easy

was (E) 92
This post has been edited 1 time. Last edited by lucaswujc, Nov 13, 2024, 6:02 PM
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eg4334
616 posts
#4
Y by
most trivial p25 ever?
just a system of equations
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EthanSpoon
637 posts
#5
Y by
Wait I got D
Now I'm scared
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megarnie
5541 posts
#6 • 6 Y
Y by KevinYang2.71, CuriousMathBoy72, vincentwant, fura3334, khina, Sedro
Note that \[\begin{cases} 
2b = 3a + 1 \\
2c = 3b + 1 \\
7a = 3c + 1\\
\end{cases} \]
One can now take modulo $7$ here, and get that $c \equiv 2 \pmod 7, b \equiv 1 \pmod 7, $ and $a \equiv 5 \pmod 7$, so the answer is $5 + 2 + 1 \equiv 1 \pmod 7$, so $\boxed{\textbf{(E)}\ 92}$.
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EaZ_Shadow
1121 posts
#7
Y by
megarnie wrote:
Note that \[\begin{cases} 
2b = 3a + 1 \\
2c = 3b + 1 \\
7a = 3c + 1\\
\end{cases} \]
One can now take modulo $7$ here, and get that $c \equiv 2 \pmod 7, b \equiv 1 \pmod 7, $ and $a \equiv 5 \pmod 7$, so the answer is $5 + 2 + 1 \equiv 1 \pmod 7$, so $\boxed{\textbf{(E)}\ 92}$.

that's how I did it... ngl it shoulda been problem 22
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mathprodigy2011
237 posts
#8
Y by
I kinda wish I took 10b now that I saw the test.
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andrewcheng
525 posts
#9 • 2 Y
Y by Alex-131, Piano_Man123
biggest joke on the test P11 was harder than this
This post has been edited 1 time. Last edited by andrewcheng, Nov 13, 2024, 6:21 PM
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PaperMath
958 posts
#10
Y by
P15 should be on the AIME
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Akang11
31 posts
#11
Y by
Real
I skipped this because of time cramp but just solved it using substitution in 2 minutes. This should have been problem 14, none of the problems were hard enough to warrant any Final Five standing this year besides maybe #21 pipes
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Akang11
31 posts
#12 • 1 Y
Y by fura3334
PaperMath wrote:
P15 should be on the AIME

Dude AIME problems are meant to be challenging, not time sinks like #15
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akliu
1736 posts
#13
Y by
ok maa look I know you're trying to teach us to try and skip problems we don't know and look at the later problems in tests just in case
but are you serious right now
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andrewcheng
525 posts
#14
Y by
Akang11 wrote:
Real
I skipped this because of time cramp but just solved it using substitution in 2 minutes. This should have been problem 14, none of the problems were hard enough to warrant any Final Five standing this year besides maybe #21 pipes

fibi was good enough for an early 20 but they should have made the series longer to make it harder to bash
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EaZ_Shadow
1121 posts
#16
Y by
andrewcheng wrote:
biggest joke on the test P11 was harder than this

Nahhhh just pigeonhole plus inequality does the deal
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carcool0
46 posts
#17
Y by
EaZ_Shadow wrote:
andrewcheng wrote:
biggest joke on the test P11 was harder than this

Nahhhh just pigeonhole plus inequality does the deal

If problem 11 was the one about 100 people and languages then you could just look at the answer choices because you know maximum would be (n choose floor(n/2))
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GP102
827 posts
#18
Y by
megarnie wrote:
Note that \[\begin{cases} 
2b = 3a + 1 \\
2c = 3b + 1 \\
7a = 3c + 1\\
\end{cases} \]
One can now take modulo $7$ here, and get that $c \equiv 2 \pmod 7, b \equiv 1 \pmod 7, $ and $a \equiv 5 \pmod 7$, so the answer is $5 + 2 + 1 \equiv 1 \pmod 7$, so $\boxed{\textbf{(E)}\ 92}$.

lol I just plugged each equation into the next until I got a linear equation in one variable
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BS2012
945 posts
#19
Y by
GP102 wrote:
megarnie wrote:
Note that \[\begin{cases} 
2b = 3a + 1 \\
2c = 3b + 1 \\
7a = 3c + 1\\
\end{cases} \]
One can now take modulo $7$ here, and get that $c \equiv 2 \pmod 7, b \equiv 1 \pmod 7, $ and $a \equiv 5 \pmod 7$, so the answer is $5 + 2 + 1 \equiv 1 \pmod 7$, so $\boxed{\textbf{(E)}\ 92}$.

lol I just plugged each equation into the next until I got a linear equation in one variable
same any mod trick after you get the equations only saves seconds of time, so just plugging it in isn't that bad
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LusenYao
27 posts
#20
Y by
bro who placed these problems im actually crashing out cuz I didn't do 25
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hduran23
4 posts
#21
Y by
Couldn’t that system be solved using Matrices?
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megarnie
5541 posts
#22
Y by
BS2012 wrote:
same any mod trick after you get the equations only saves seconds of time, so just plugging it in isn't that bad

thats cap solving takes like a lot longer tbh (especially when you mess up computation multiple times like me)
This post has been edited 1 time. Last edited by megarnie, Nov 16, 2024, 3:23 AM
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Yiyj1
1185 posts
#23
Y by
I did a buncha substitutions. didnt think of using mods rip
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fura3334
221 posts
#24
Y by
megarnie wrote:
Note that \[\begin{cases} 
2b = 3a + 1 \\
2c = 3b + 1 \\
7a = 3c + 1\\
\end{cases} \]
One can now take modulo $7$ here, and get that $c \equiv 2 \pmod 7, b \equiv 1 \pmod 7, $ and $a \equiv 5 \pmod 7$, so the answer is $5 + 2 + 1 \equiv 1 \pmod 7$, so $\boxed{\textbf{(E)}\ 92}$.

omg pro speedrunner
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carcool0
46 posts
#25
Y by
Yiyj1 wrote:
I did a buncha substitutions. didnt think of using mods rip

same it was still easy though
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Akang11
31 posts
#26
Y by
akliu wrote:
ok maa look I know you're trying to teach us to try and skip problems we don't know and look at the later problems in tests just in case
but are you serious right now

real
my entire school skipped this and now we all really sad
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MathPerson12321
3627 posts
#27
Y by
i mean the problem wasnt even bad at all, js misplaced
carcool0 wrote:
Yiyj1 wrote:
I did a buncha substitutions. didnt think of using mods rip

same it was still easy though

same
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EaZ_Shadow
1121 posts
#28
Y by
LusenYao wrote:
bro who placed these problems im actually crashing out cuz I didn't do 25

Lolllllllll :rotfl: blame maa for this
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tzliu
163 posts
#29
Y by
bro i solved p23 and p24 and i was like if p23 and p24 are misplaced p25 must be rlly rlly hard to balance it out
so i looked at it and cuz im stupid i thought its a hard problem
and i was like i should check so i didn't do it
(also because i hard sold on 10a so i wanna guarantee aime qual or it would be so humilitating cuz i qualed last year)

what is worse is the fact that i accidentally skipped over 22 when checking and i just happened to silly that one

and like all other questions i checked i didn't silly (WE DO NOT TALK ABOUT P16 where i skipped over the word "four" cuz its not a number)
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ostriches88
1527 posts
#30
Y by
tzliu wrote:
(WE DO NOT TALK ABOUT P16 where i skipped over the word "four" cuz its not a number)

im surprised how many other people did this lol
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AngeloChu
471 posts
#31
Y by
lol I got this right in 20 seconds but got p4 wrong I think lol
This post has been edited 1 time. Last edited by AngeloChu, Jan 11, 2025, 5:02 PM
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ilikemath247365
220 posts
#32
Y by
Me getting a 103.5 on this test and not doing this problem. :(
Should've attempted this problem, high chances would've gotten a 109.5 instead!
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fruitmonster97
2400 posts
#33
Y by
uhh ?

just looking at edge lengths yields $3a+1=2b,3c+1=7a,$ and $3b+1=2c.$ We get $a=\tfrac{2b-1}{3},$ so $9c+3=14b-7.$ We also know that $c=\tfrac{3b+1}{2},$ so $\tfrac{27b+9}{2}+10=14b,$ and thus $27b+29=28b,$ so $b=29.$ Then $a=19$ and $c=44,$ so $a+b+c=92,$ answer choice $\boxed{\textbf{(E)}}$
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