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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
0 on jmo
Rong0625   60
N 26 minutes ago by Andrew2019
How many people actually get a flat 0/42 on jmo? I took it for the first time this year and I had never done oly math before so I really only had 2 weeks to figure it out since I didn’t think I would qual. I went in not expecting much but I didn’t think I wouldn’t be able to get ANYTHING. So I’m pretty sure I got 0/42 (unless i get pity points for writing incorrect solutions). Is that bad, am I sped, and should I be embarrassed? Or do other people actually also get 0?
60 replies
Rong0625
Mar 21, 2025
Andrew2019
26 minutes ago
ARML questions
Jaxman8   2
N 35 minutes ago by the_math_prodigy
I am planning on participating in ARML, and I was wondering 1, how many people are participating in SFBA, and 2, what team I would be on since I got a 5 on the AIME this year.
2 replies
Jaxman8
Yesterday at 10:15 PM
the_math_prodigy
35 minutes ago
How many approaches you got? (A lot)
IAmTheHazard   82
N an hour ago by jasperE3
Source: USAMO 2023/2
Let $\mathbb{R}^+$ be the set of positive real numbers. Find all functions $f \colon \mathbb{R}^+ \to \mathbb{R}^+$ such that, for all $x,y \in \mathbb{R}^+$,
$$f(xy+f(x))=xf(y)+2.$$
82 replies
IAmTheHazard
Mar 23, 2023
jasperE3
an hour ago
9 Fun Proof Endings
elasticwealth   50
N 2 hours ago by idk12345678
It seems like AOPS is going through a stressful phase right now.

Let's lighten the mood by voting on the best proof endings!
50 replies
elasticwealth
Yesterday at 12:26 AM
idk12345678
2 hours ago
No more topics!
prime spam
fruitmonster97   28
N Apr 4, 2025 by Apple_maths60
Source: 2024 AMC 10A #3
What is the sum of the digits of the smallest prime that can be written as a sum of $5$ distinct primes?

$\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }10\qquad\textbf{(E) }11$
28 replies
fruitmonster97
Nov 7, 2024
Apple_maths60
Apr 4, 2025
prime spam
G H J
Source: 2024 AMC 10A #3
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fruitmonster97
2481 posts
#1
Y by
What is the sum of the digits of the smallest prime that can be written as a sum of $5$ distinct primes?

$\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }10\qquad\textbf{(E) }11$
This post has been edited 1 time. Last edited by fruitmonster97, Nov 7, 2024, 8:21 PM
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fruitmonster97
2481 posts
#2
Y by
If $2$ was one of the primes, then the sum would be even, impossible. Otherwise, $3+5+7+11+13=39,$ which isn't prime, but $3+5+7+11+17=43\implies{7}$ is, yielding $\boxed{\textbf{(B)}}.$
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MathRook7817
662 posts
#3 • 1 Y
Y by mithu542
The minimum possible sum of 5 distinct primes that are odd (since the number is prime) is
3+5+7+11+13 = 39
41 is impossible since 15 isn't prime, so the number is 43 (3+5+7+11+17).
Therefore, the answer is 4+3 = 7 (B)
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Jonysun
34 posts
#4
Y by
The answer is indeed $\fbox{43} \Rightarrow B$
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golden_star_123
206 posts
#5
Y by
All the primes have to be odd for the sum to be odd. We may then just bash out the possibilities to notice that the first prime that works is $43$, so the answer is $\boxed{7}$.
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gracemoon124
872 posts
#6 • 2 Y
Y by alexanderhamilton124, songyanxin
sillied ):
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lpieleanu
2918 posts
#7
Y by
Solution
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SomeonecoolLovesMaths
3203 posts
#8
Y by
$$3+5+7+11+17=43$$7 confirmed
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wangzrpi
159 posts
#9
Y by
4+3=7 confirmed :)

Cannot be 2 because then the sum would be even and therefore not prime
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KenWuMath
58 posts
#10
Y by
apparently 15 isnt a prime :D
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wangzrpi
159 posts
#11
Y by
fruitmonster97 wrote:
If $2$ was one of the primes, then the sum would be even, impossible. Otherwise, $3+5+7+11+13=39,$ which isn't prime, but $3+5+7+11+17=43\implies{7}$ is, yielding $\boxed{\textbf{(B)}}.$

Also sum of primes 5-13 is larger
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dolphinday
1325 posts
#12
Y by
I did 11 + 13 = 14 on this one. double checked it too
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GreenBanana666
548 posts
#13
Y by
Its $43$, $4+3=7$. Its B then
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SkatingKitty
223 posts
#14
Y by
I miscalculated and and got 53, or 8 chat I’m cooked again
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mhgelgi
668 posts
#15 • 1 Y
Y by SkatingKitty
SkatingKitty wrote:
I miscalculated and and got 53, or 8 chat I’m cooked again
yeah, same here, we can weep together
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SkatingKitty
223 posts
#16
Y by
I literally left like all of them blank except for like 2 that I got wrong
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mhgelgi
668 posts
#17
Y by
127.5 => 103.5 (4 sillies)
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SkatingKitty
223 posts
#18
Y by
2 sillies- probably bc I don’t know abt my other ones lol
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happypi31415
742 posts
#19
Y by
I put 53 like an idiot :(
This post has been edited 2 times. Last edited by happypi31415, Nov 8, 2024, 5:25 PM
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SkatingKitty
223 posts
#20
Y by
Not the only one here
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SirAppel
877 posts
#21
Y by
answer choice E was 11, and I know that because I almost put E before checking my answers oops (47 susus)
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SkatingKitty
223 posts
#22
Y by
At least you caught your mistake: I forgot to check my answers
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gicyuraok2
1059 posts
#23
Y by
i for sure would have had to come back to this lol

obv i looked at $5+7+11+13+17=53$ first, but $8$ isn't one of the answers (thank god)
accidentally got a spoiler but probably would have found it anyway
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Existing_Human1
209 posts
#24
Y by
POV: Your nervousness causes you to think that 2 + 3 + 5 + 7 + 11 is odd
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SkatingKitty
223 posts
#25
Y by
gicyuraok2 wrote:
i for sure would have had to come back to this lol

obv i looked at $5+7+11+13+17=53$ first, but $8$ isn't one of the answers (thank god)
accidentally got a spoiler but probably would have found it anyway

Rly? Oh whoops I put 8
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mathenrichmentaops
539 posts
#26
Y by
SkatingKitty wrote:
gicyuraok2 wrote:
i for sure would have had to come back to this lol

obv i looked at $5+7+11+13+17=53$ first, but $8$ isn't one of the answers (thank god)
accidentally got a spoiler but probably would have found it anyway

Rly? Oh whoops I put 8

Omg same I think I changed it to B tho
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gicyuraok2
1059 posts
#27
Y by
mathenrichmentaops wrote:
SkatingKitty wrote:
gicyuraok2 wrote:
i for sure would have had to come back to this lol

obv i looked at $5+7+11+13+17=53$ first, but $8$ isn't one of the answers (thank god)
accidentally got a spoiler but probably would have found it anyway

Rly? Oh whoops I put 8

Omg same I think I changed it to B tho

how do you put 8 if it's not one of the answer choices
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EpicShrek49
17 posts
#28
Y by
i sillied the one where it was -1, -6, and 10 for the sum and i thought it was -2, -3, and 10..
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Apple_maths60
24 posts
#30
Y by
Yes we get the prime as 43 so sum is 7
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