Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
D1021 : Does this series converge?
Dattier   1
N 3 hours ago by Dattier
Source: les dattes à Dattier
Is this series $\sum \limits_{k\geq 1} \dfrac{\ln(1+\sin(k))} k$ converge?
1 reply
Dattier
Saturday at 4:29 PM
Dattier
3 hours ago
2022 Putnam B1
giginori   26
N 4 hours ago by ihategeo_1969
Suppose that $P(x)=a_1x+a_2x^2+\ldots+a_nx^n$ is a polynomial with integer coefficients, with $a_1$ odd. Suppose that $e^{P(x)}=b_0+b_1x+b_2x^2+\ldots$ for all $x.$ Prove that $b_k$ is nonzero for all $k \geq 0.$
26 replies
giginori
Dec 4, 2022
ihategeo_1969
4 hours ago
Combinatorial Sum
P162008   0
Today at 2:18 AM
Source: Friend
For non negative integers $q$ and $s$ define

$\binom{q}{s} = \Biggl\{ 0,$ if $q < s$ & $\frac{q!}{s!(q - s)!},$ if $ q \geqslant s$

Define a polynomial $f(x,r)$ for a positive integer r, such that

$f(x,r) = \sum_{i=0}^{r} \binom{n}{i} \binom{m}{r-i} x^i$ where $r,m$ and $n$ are positive integers.

It is given that

$\frac{\left(\prod_{i=0}^{r}\left(\prod_{j=1}^{n+i} j\right)^{r-i+1}\right). f(1,r)}{(n!)^{r+1} \left(\prod_{i=1}^{r}\left(\prod_{j=1}^{i} j\right)\right)} = \left(\sum_{p=0}^{r} \binom{n+p}{p}\right)\left(\sum_{k=0}^{r} \binom{n+k}{k}\right)$

Then, $m$ and $n$ respectively can be

$(a) 2022,2023$

$(b) 2023,2024$

$(c) 2023,2022$

$(d) 2021,2023$
0 replies
P162008
Today at 2:18 AM
0 replies
Triple Sum
P162008   1
N Yesterday at 10:09 PM by ysharifi
Evaluate $\Omega = \sum_{k=1}^{\infty} \sum_{n=k}^{\infty} \sum_{m=1}^{n} \frac{1}{n(n+1)(n+2)km^2}$
1 reply
P162008
Apr 26, 2025
ysharifi
Yesterday at 10:09 PM
No more topics!
high school math
aothatday   8
N Apr 22, 2025 by EthanNg6
Let $x_n$ be a positive root of the equation $x^n=x^2+x+1$. Prove that the following sequence converges: $n^2(x_n-x_{ n+1})$
8 replies
aothatday
Apr 10, 2025
EthanNg6
Apr 22, 2025
high school math
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aothatday
7 posts
#1
Y by
Let $x_n$ be a positive root of the equation $x^n=x^2+x+1$. Prove that the following sequence converges: $n^2(x_n-x_{ n+1})$
This post has been edited 4 times. Last edited by aothatday, Apr 16, 2025, 2:39 PM
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aothatday
7 posts
#2
Y by
yoooooooooo !!
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aothatday
7 posts
#4
Y by
sp0rtman00000 wrote:
It is a very hard problem!
Can you try to prove it? I just fixed the question.
This post has been edited 1 time. Last edited by aothatday, Apr 12, 2025, 8:59 AM
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Kempu33334
609 posts
#6 • 1 Y
Y by aothatday
aothatday wrote:
Let $x_n$ be a positive root of the equation $x_n^n=x^2+x+1$. Prove that the following sequence converges: $n^2(x_n-x_{ n+1})$

If I’m not mistaken, I think it converges to $\boxed{\ln(3)}$, just don’t know how to prove it.
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aothatday
7 posts
#8
Y by
oz.the.wizard wrote:
Nice problem! Denote ${{x}^{2}}+x+1=a$ hence ${{n}^{2}}(\sqrt[n]{a}-\sqrt[n+1]{a})={{n}^{2}}\sqrt[n+1]{a}\left( \frac{\sqrt[n]{a}}{\sqrt[n+1]{a}}-1 \right)={{n}^{2}}\sqrt[n+1]{a}\left( {{a}^{\frac{1}{n(n+1)}}}-1 \right)=$ $=\frac{n}{n+1}\sqrt[n+1]{a}\frac{{{a}^{\frac{1}{n(n+1)}}}-1}{\frac{1}{n(n+1)}}\to \ln a=\ln ({{x}^{2}}+x+1)$
hey I think your conclusion is obvious :)
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hsbhatt
433 posts
#9 • 1 Y
Y by aothatday
Using mean value theorem we get that $(x^2+x+1)^{\frac{1}{n+1}} \ln (x^2+x+1) \le n^2 \left(x_n-x_{n+1} \right) < (x^2+x+1)^{\frac{1}{n}} \ln (x^2+x+1)$

Hence by Sandwich theorem the limit is $ \ln (x^2+x+1)$
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aothatday
7 posts
#10
Y by
hmmmmmm :)
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ZMB038
104 posts
#11
Y by
Why is a forum, called "high school math" in the college math section?
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EthanNg6
31 posts
#12
Y by
Yeah, that doesn't make any sense

I think it would fit better in the high school section
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