ELMO SL 2013 G3

by Wolstenholme, Aug 1, 2014, 9:31 PM

In $ \triangle ABC $, a point $ D $ lies on line $ BC $. The circumcircle of $ ABD $ meets $ AC $ at $ F $ (other than $ A $), and the circumcircle of $ ADC $ meets $ AB $ at $ E $ (other than $ A $). Prove that as $ D $ varies, the circumcircle of $ AEF $ always passes through a fixed point other than $ A $, and that this point lies on the median from $ A $ to $ BC $.

Proof:

I will provide a barycentric coordinate solution.

Let $ A = (1, 0, 0), B = (0, 1, 0), C = (0, 0, 1) $ and let $ a = BC, b = CA, c = AB $. Let $ D = (0, r, 1 - r) $ for some real $ r $.

We find that the equation of the circumcircle of $ \triangle{ABD} $ is given by: $ a^2yz + b^2xz + c^2xy = (x + y + z)a^2rz $ and it is easy to see that this intersects line $ AC $ at the point $ E = (a^2r : 0 : b^2 - a^2r) $. Similarly we find that $ F = (a^2(1 - r) : c^2 - a^2(1 - r) : 0) $.

Now it is easy to find that the circumcircle of $ \triangle{AEF} $ has equation $ a^2yz + b^2xz + c^2xy = (x + y + z)(a^2(1 - r)y + a^2rz) $. It is easy to compute that regardless of the value of $ r $, the point $ (a^2 : b^2 + c^2 - a^2 : b^2 + c^2 - a^2) $ lies on this circumcircle, and moreover lies on the $ A $-median of $ \triangle{ABC} $ so we are done.

The motivation for using barycentric coordinates is that despite the large number of circles in this diagram, all are defined by vertices or points on sides of $ \triangle{ABC} $ and so their equations are easy to deal with. Moreover, the condition that our fixed point lies on the relevant median implies that its barycentric coordinates will be nice.

Comment

0 Comments

Archives
+ June 2016
+ April 2016
+ March 2016
+ July 2015
+ February 2015
+ June 2014
Shouts
Submit
  • glad to have found a fellow chipotle lover <3

    by nukelauncher, Aug 13, 2020, 6:40 AM

  • the random chinese tst problem is the only thing I read, but I'll assume your blog is nice and give you a shout even though you probably never use aops anymoer

    by fukano_2, Jun 14, 2020, 6:24 AM

  • wolstenholme - op

    by AopsUser101, Jan 29, 2020, 8:27 PM

  • this blog is so hot

    by mathleticguyyy, Jun 5, 2019, 8:26 PM

  • Hi. Nice Blog!

    by User360702, Jan 10, 2019, 6:03 PM

  • helloooooo

    by songssari, Jun 12, 2016, 8:21 AM

  • shouts make blogs happier

    by briantix, Mar 18, 2016, 9:57 PM

  • You were just featured on AoPS's facebook page.

    by mishka1980, Sep 12, 2015, 10:33 PM

  • This is late, but where is the ARML results post?

    by donot, Aug 31, 2015, 11:07 PM

  • "I am Sam"
    "Sam I am"

    by mathwizard888, Aug 12, 2015, 9:13 PM

  • HW$\textcolor{white}{}$

    by Eugenis, Apr 20, 2015, 10:10 PM

  • Uh-oh ARML practice is Thursday... I should start the homework. :P

    by nosaj, Apr 20, 2015, 12:34 AM

  • Yes I am Sam, and Chebyshev polynomials aren't trivial, although they do make some problems trivial :P

    by Wolstenholme, Apr 15, 2015, 10:00 PM

  • How are Chebyshev Polynomials trivial? :P

    by nosaj, Apr 13, 2015, 4:10 AM

  • Are you Sam?

    by Eugenis, Apr 4, 2015, 2:05 AM

  • @Brian: yes, yes I did #whoneedsalgskillz?

    @gauss1181; hey!

    by Wolstenholme, Mar 1, 2015, 11:25 PM

  • hello!!! :D

    by gauss1181, Nov 27, 2014, 12:19 AM

  • Hi Wolstenholme did you actually use calc on that tstst problem :o

    by briantix, Aug 2, 2014, 12:25 AM

18 shouts
Contributors
Tags
About Owner
  • Posts: 543
  • Joined: Mar 3, 2013
Blog Stats
  • Blog created: Apr 3, 2013
  • Total entries: 112
  • Total visits: 34997
  • Total comments: 167
Search Blog
a