IMO 2014 #1

by Wolstenholme, Oct 26, 2014, 7:19 PM

Let $a_0 < a_1 < a_2 \ldots$ be an infinite sequence of positive integers. Prove that there exists a unique integer $n\geq 1$ such that
\[a_n < \frac{a_0+a_1+a_2+\cdots+a_n}{n} \leq a_{n+1}.\]

Proof:

Note that the inequality $ a_n < \frac{a_0+a_1+a_2+\cdots+a_n}{n} \leq a_{n+1} $ is equivalent to the statement that $ (n - 1)a_n - a_{n - 1} - a_{n - 2} - \dots - a_1 < a_0 \le na_{n + 1} - a_n - a_{n - 1} - \dots - a_1 $. This motivates us to consider the sequence $ \{b_n\} $ defined by $ b_n = na_n - a_{n - 1} - a_{n - 2} - \dots - a_1 $.

Then it suffices to show that there exists a unique $ n \in \mathbb{N} $ such that $ b_n < a_0 \le b_{n + 1} $. But since $ b_{n + 1} - b_n = n(a_{n + 1} - a_n) > 0 $ we have that this new sequence is strictly increasing which immediately implies the desired result.

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