does the series 
converge (and absolutely converge)?
.
on 
,
Can I change 1 by a constant 
?
greater than 
Is there any reason why we shouldn't write 
instead?
has at most one solution continuous for 
)
is a fixed real number. (A. 7)
converge?
,
where 
is the identity matrix. If for some matrix 
is identity, does it follow that 
be real numbers. Find the ranges of 
converges.
are group. If 
,
or 
.
are complex numbers such that
and if 
denotes the sum of all products of these 
at a time, prove that
whenever the denominator of the left-hand side is different from 
.
for any positive reals satifying 
?
are real number satisfying
show that the equation 
has at least one real root.
Y by
Q) let 
and 
then is this uniformly convergence on 
comment on uniformly convergence on ![$[0,1]$](//latex.artofproblemsolving.com/e/8/6/e861e10e1c19918756b9c8b7717684593c63aeb8.png)
where in general it is should be uniformly convergence.
My I am trying with some contradicton method like chose
and trying to solve
Next take a in (0,1) and chose a= 2^1/N but not solution
How to solve like this way help.
and 
then is this uniformly convergence on 
comment on uniformly convergence on ![$[0,1]$](http://latex.artofproblemsolving.com/e/8/6/e861e10e1c19918756b9c8b7717684593c63aeb8.png)
where in general it is should be uniformly convergence.My I am trying with some contradicton method like chose
and trying to solve
Next take a in (0,1) and chose a= 2^1/N but not solution
How to solve like this way help.
.![$[0,a]$](http://latex.artofproblemsolving.com/6/8/b/68bacdc4b96052586744d16169ccd8c3233ed09f.png)
for any 
because 
.
