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Given a n*n matrix A, prove that there exists a matrix B such that ABA = A
Solution: I have submitted the attachment
The answer is too symbol dense for me to understand the answer.
What I have undertood:
There is use of direct product in the orthogonal decomposition. The decomposition is made with kernel and some T (which the author didn't mention) but as per orthogonal decomposition it must be its orthogonal complement.
Can anyone explain the answer in much much more detail with less use of symbols ( you can also use symbols but clearly define it).
Also what is phi | T ?
Solution: I have submitted the attachment
The answer is too symbol dense for me to understand the answer.
What I have undertood:
There is use of direct product in the orthogonal decomposition. The decomposition is made with kernel and some T (which the author didn't mention) but as per orthogonal decomposition it must be its orthogonal complement.
Can anyone explain the answer in much much more detail with less use of symbols ( you can also use symbols but clearly define it).
Also what is phi | T ?