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k a May Highlights and 2025 AoPS Online Class Information
jlacosta   0
May 1, 2025
May is an exciting month! National MATHCOUNTS is the second week of May in Washington D.C. and our Founder, Richard Rusczyk will be presenting a seminar, Preparing Strong Math Students for College and Careers, on May 11th.

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0 replies
jlacosta
May 1, 2025
0 replies
Largest Prime Factor
P162008   3
N 3 hours ago by maromex
The largest prime factor of the sum $\sum_{k=1}^{11} k^5$ is $\lambda.$ Find the sum of the digits of $\lambda.$
3 replies
P162008
Yesterday at 12:04 AM
maromex
3 hours ago
Inequalities
sqing   27
N 4 hours ago by sqing
Let $ a,b>0   $ . Prove that
$$ \frac{a}{a^2+a +2b+1}+ \frac{b}{b^2+2a +b+1}  \leq  \frac{2}{5} $$$$ \frac{a}{a^2+2a +b+1}+ \frac{b}{b^2+a +2b+1}  \leq  \frac{2}{5} $$
27 replies
sqing
May 13, 2025
sqing
4 hours ago
Putnam 2014 A3
Kent Merryfield   16
N 4 hours ago by maromex
Let $a_0=5/2$ and $a_k=a_{k-1}^2-2$ for $k\ge 1.$ Compute \[\prod_{k=0}^{\infty}\left(1-\frac1{a_k}\right)\] in closed form.
16 replies
Kent Merryfield
Dec 7, 2014
maromex
4 hours ago
Trigo or Complex no.?
hzbrl   1
N 4 hours ago by hzbrl
(a) Let $y=\cos \phi+\cos 2 \phi$, where $\phi=\frac{2 \pi}{5}$. Verify by direct substitution that $y$ satisfies the quadratic equation $2 y^2=3 y+2$ and deduce that the value of $y$ is $-\frac{1}{2}$.
(b) Let $\theta=\frac{2 \pi}{17}$. Show that $\sum_{k=0}^{16} \cos k \theta=0$
(c) If $z=\cos \theta+\cos 2 \theta+\cos 4 \theta+\cos 8 \theta$, show that the value of $z$ is $-(1-\sqrt{17}) / 4$.



I could solve (a) and (b). Can anyone help me with the 3rd part please?
1 reply
hzbrl
Yesterday at 3:49 AM
hzbrl
4 hours ago
Divisors of factorials can't be always products of consecutive integers
Johann Peter Dirichlet   0
4 hours ago
Let $M$ an even number.

Show that $\frac{n!}{M^2}$ is not the product of consecutive integers for infinitely many naturals $n$.
0 replies
Johann Peter Dirichlet
4 hours ago
0 replies
Looking for someone to work with
midacer   3
N 6 hours ago by midacer
I’m looking for a motivated study partner (or small group) to collaborate on college-level competition math problems, particularly from contests like the Putnam, IMO Shortlist, IMC, and similar. My goal is to improve problem-solving skills, explore advanced topics (e.g., combinatorics, NT, analysis), and prepare for upcoming competitions. I’m new to contests but have a strong general math background(CPGE in Morocco). If interested, reply here or DM me to discuss
3 replies
midacer
Yesterday at 8:22 PM
midacer
6 hours ago
IOQM P22 2024
SomeonecoolLovesMaths   3
N Yesterday at 10:51 PM by SomeonecoolLovesMaths
In a triangle $ABC$, $\angle BAC = 90^{\circ}$. Let $D$ be the point on $BC$ such that $AB + BD = AC + CD$. Suppose $BD : DC = 2:1$. if $\frac{AC}{AB} = \frac{m + \sqrt{p}}{n}$, Where $m,n$ are relatively prime positive integers and $p$ is a prime number, determine the value of $m+n+p$.
3 replies
SomeonecoolLovesMaths
Sep 8, 2024
SomeonecoolLovesMaths
Yesterday at 10:51 PM
AP calc?
Thayaden   30
N Yesterday at 9:53 PM by Pengu14
How are we all feeling on AP calc guys?
30 replies
Thayaden
May 20, 2025
Pengu14
Yesterday at 9:53 PM
Possible values of determinant of 0-1 matrices
mathematics2004   3
N Yesterday at 7:40 PM by Isolemma
Source: 2021 Simon Marais, A3
Let $\mathcal{M}$ be the set of all $2021 \times 2021$ matrices with at most two entries in each row equal to $1$ and all other entries equal to $0$.
Determine the size of the set $\{ \det A : A \in M \}$.
Here $\det A$ denotes the determinant of the matrix $A$.
3 replies
mathematics2004
Nov 2, 2021
Isolemma
Yesterday at 7:40 PM
Calculate the radius of a circle using sidelengths.
richminer   0
Yesterday at 6:17 PM
Given triangle ABC with incircle (I), with D being the touchpoint of (I) and BC. Let M be the tangent point of the A-Mixtilinear circle (internally tangent). A' is the reflection of A through I. Calculate the radius of the circle (MDA') using the side lengths of the triangle ABC.
0 replies
richminer
Yesterday at 6:17 PM
0 replies
Number of real roots
girishpimoli   0
Yesterday at 5:35 PM
Number of real roots of

$\displaystyle 2\sin(\theta)\cos(3\theta)\sin(5\theta)=-1$
0 replies
girishpimoli
Yesterday at 5:35 PM
0 replies
Factorization Ex.28a Q30
Obvious_Wind_1690   1
N Yesterday at 4:43 PM by Lankou
Please help with factorization. Given is the question


\begin{align*}
a(a+1)x^2+(a+b)xy-b(b-1)y^2\\
\end{align*}
And the given answer is


\begin{align*}
[(a+1)x-(b-1)y][ax+by]\\
\end{align*}
But I am unable to reach the answer.
1 reply
Obvious_Wind_1690
Yesterday at 4:17 AM
Lankou
Yesterday at 4:43 PM
Polynomials
P162008   4
N Yesterday at 4:19 PM by HAL9000sk
If $f(x)$ is a polynomial function such that $f(x) = x\sqrt{1 + (x + 1)\sqrt{1 + (x + 2)\sqrt{1 + (x + 3)\sqrt{1 + \cdots}}}}$ then

A) Degree of $f(x)$ must be greater than $2$

B) $f(-2) = 0$

C) $\sum_{r=1}^{5} \frac{1}{f(r)} = \frac{25}{42}$

D) $\sum_{r=1}^{n} \frac{1}{f(r)} = \frac{n(3n + 5)}{4(n+1)(n+2)}$
4 replies
P162008
Monday at 11:18 PM
HAL9000sk
Yesterday at 4:19 PM
hard inequality
revol_ufiaw   10
N Yesterday at 3:43 PM by sqing
Prove that $(a-b)(b-c)(c-d)(d-a)+(a-c)^2 (b-d)^2\ge 0$ for rational $a, b, c, d$.
10 replies
revol_ufiaw
Yesterday at 1:09 PM
sqing
Yesterday at 3:43 PM
High School Integration Extravaganza Problem Set
Riemann123   13
N Apr 13, 2025 by mygoodfriendusesaops
Source: River Hill High School Spring Integration Bee
Hello AoPS!

Along with user geodash2, I have organized another high-school integration bee (River Hill High School Spring Integration Bee) and wanted to share the problems!

We had enough folks for two concurrent rooms, hence the two sets. (ARML kids from across the county came.)

Keep in mind that these integrals were written for a high-school contest-math audience. I hope you find them enjoyable and insightful; enjoy!


[center]Warm Up Problems[/center]
\[
\int_{1}^{2} \frac{x^{3}+x^2}{x^5}dx
\]\[\int_{2025}^{2025^{2025}}\frac{1}{\ln\left(2025\right)\cdot x}dx\]\[
\int(\sin^2(x)+\cos^2(x)+\sec^2(x)+\csc^2(x))dx
\]\[
\int_{-2025.2025}^{2025.2025}\sin^{2025}(2025x)\cos^{2025}(2025x)dx
\]\[
    \int_{\frac \pi 6}^{\frac \pi 3} \tan(\theta)^2d\theta
\]\[
\int  \frac{1+\sqrt{t}}{1+t}dt
\]-----
[center]Easier Division Set 1[/center]
\[\int \frac{x^{2}+2x+1}{x^{3}+3x^{2}+3x+3}dx
\]\[\int_{0}^{\frac{3\pi}{2}}\left(\frac{\pi}{2}-x\right)\sin\left(x\right)dx\]\[
\int_{-\pi/2}^{\pi/2}x^3e^{-x^2}\cos(x^2)\sin^2(x)dx
\]\[
\int\frac{1}{\sqrt{12-t^{2}+4t}}dt
\]\[
\int \frac{\sqrt{e^{8x}}}{e^{8x}-1}dx
\]-----
[center]Easier Division Set 2[/center]
\[
\int \frac{e^x}{e^{2x}+1} dx
\]\[
\int_{-5}^5\sqrt{25-u^2}du
\]\[
\int_{-\frac12}^\frac121+x+x^2+x^3\ldots dx
\]\[\int \cos(\cos(\cos(\ln \theta)))\sin(\cos(\ln \theta))\sin(\ln \theta)\frac{1}{\theta}d\theta\]\[\int_{0}^{\frac{1}{6}}\frac{8^{2x}}{64^{2x}-8^{\left(2x+\frac{1}{3}\right)}+2}dx\]-----
[center]Harder Division Set 1[/center]
\[\int_{0}^{\frac{\pi}{2}}\frac{\sin\left(x\right)}{\sin\left(x\right)+\cos\left(x\right)}+\frac{\sin\left(\frac{\pi}{2}-x\right)}{\sin\left(\frac{\pi}{2}-x\right)+\cos\left(\frac{\pi}{2}-x\right)}dx\]\[
\int_0^{\infty}e^{-x}\Bigl(\cos(20x)+\sin(20x)\Bigr) dx
\]\[
\lim_{n\to \infty}\frac{1}{n}\int_{1}^{n}\sin(nt)^2dt
\]\[
\int_{x=0}^{x=1}\left( \int_{y=-x}^{y=x} \frac{y^2}{x^2+y^2}dy\right)dx
\]\[
\int_{0}^{13}\left\lceil\log_{10}\left(2^{\lceil x\rceil }x\right)\right\rceil dx
\]-----
[center]Harder Division Set 2[/center]
\[
\int \frac{6x^2}{x^6+2x^3+2}dx
\]\[
\int -\sin(2\theta)\cos(\theta)d\theta
\]\[
\int_{0}^{5}\sin(\frac{\pi}2 \lfloor{x}\rfloor x) dx
\]\[
\int_{0}^{1} \frac{\sin^{-1}(\sqrt{x})^2}{\sqrt{x-x^2}}dx
\]\[
\int\left(\cot(\theta)+\tan(\theta)\right)^2\cot(2\theta)^{100}d\theta
\]-----
[center]Bonanza Round (ie Fun/Hard/Weird Problems) (In No Particular Order)[/center]
\[
\int \ln\left\{\sqrt[7]{x}^\frac1{\ln\left\{\sqrt[5]{x}^\frac1{\ln\left\{\sqrt[3]{x}^\frac1{\ln\left\{\sqrt{x}\right\}}\right\}}\right\}}\right\}dx
\]\[\int_{1}^{{e}^{\pi}} \cos(\ln(\sqrt{u}))du\]\[
\int_e^{\infty}\frac {1-x\ln{x}}{xe^x}dx
\]\[\int_{0}^{1}\frac{e^{x}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{1}}}}\times\frac{e^{-\frac{x^{2}}{2}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{2}}}}\times\frac{e^{\frac{x^{3}}{3}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{3}}}}\times\frac{e^{-\frac{x^{4}}{4}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{4}}}} \ldots \,dx\]
For $x$ on the domain $-0.2025\leq x\leq 0.2025$ it is known that \[\displaystyle f(x)=\sin\left(\int_{0}^x \sqrt[3]{\cos\left(\frac{\pi}{2} t\right)^3+26}\ dt\right)\]is invertible. What is $\displaystyle (f^{-1})'(0)$?
13 replies
Riemann123
Apr 11, 2025
mygoodfriendusesaops
Apr 13, 2025
High School Integration Extravaganza Problem Set
G H J
G H BBookmark kLocked kLocked NReply
Source: River Hill High School Spring Integration Bee
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Riemann123
14 posts
#1 • 13 Y
Y by centslordm, DeedSpeed, clarkculus, mygoodfriendusesaops, Alex-131, aidan0626, geodash2, abeot, esquire, pinkdino8074, fractalworm, MichelleYMa, Hobz
Hello AoPS!

Along with user geodash2, I have organized another high-school integration bee (River Hill High School Spring Integration Bee) and wanted to share the problems!

We had enough folks for two concurrent rooms, hence the two sets. (ARML kids from across the county came.)

Keep in mind that these integrals were written for a high-school contest-math audience. I hope you find them enjoyable and insightful; enjoy!

Warm Up Problems
\[
\int_{1}^{2} \frac{x^{3}+x^2}{x^5}dx
\]\[\int_{2025}^{2025^{2025}}\frac{1}{\ln\left(2025\right)\cdot x}dx\]\[
\int(\sin^2(x)+\cos^2(x)+\sec^2(x)+\csc^2(x))dx
\]\[
\int_{-2025.2025}^{2025.2025}\sin^{2025}(2025x)\cos^{2025}(2025x)dx
\]\[
    \int_{\frac \pi 6}^{\frac \pi 3} \tan(\theta)^2d\theta
\]\[
\int  \frac{1+\sqrt{t}}{1+t}dt
\]
Easier Division Set 1
\[\int \frac{x^{2}+2x+1}{x^{3}+3x^{2}+3x+3}dx
\]\[\int_{0}^{\frac{3\pi}{2}}\left(\frac{\pi}{2}-x\right)\sin\left(x\right)dx\]\[
\int_{-\pi/2}^{\pi/2}x^3e^{-x^2}\cos(x^2)\sin^2(x)dx
\]\[
\int\frac{1}{\sqrt{12-t^{2}+4t}}dt
\]\[
\int \frac{\sqrt{e^{8x}}}{e^{8x}-1}dx
\]
Easier Division Set 2
\[
\int \frac{e^x}{e^{2x}+1} dx
\]\[
\int_{-5}^5\sqrt{25-u^2}du
\]\[
\int_{-\frac12}^\frac121+x+x^2+x^3\ldots dx
\]\[\int \cos(\cos(\cos(\ln \theta)))\sin(\cos(\ln \theta))\sin(\ln \theta)\frac{1}{\theta}d\theta\]\[\int_{0}^{\frac{1}{6}}\frac{8^{2x}}{64^{2x}-8^{\left(2x+\frac{1}{3}\right)}+2}dx\]
Harder Division Set 1
\[\int_{0}^{\frac{\pi}{2}}\frac{\sin\left(x\right)}{\sin\left(x\right)+\cos\left(x\right)}+\frac{\sin\left(\frac{\pi}{2}-x\right)}{\sin\left(\frac{\pi}{2}-x\right)+\cos\left(\frac{\pi}{2}-x\right)}dx\]\[
\int_0^{\infty}e^{-x}\Bigl(\cos(20x)+\sin(20x)\Bigr) dx
\]\[
\lim_{n\to \infty}\frac{1}{n}\int_{1}^{n}\sin(nt)^2dt
\]\[
\int_{x=0}^{x=1}\left( \int_{y=-x}^{y=x} \frac{y^2}{x^2+y^2}dy\right)dx
\]\[
\int_{0}^{13}\left\lceil\log_{10}\left(2^{\lceil x\rceil }x\right)\right\rceil dx
\]
Harder Division Set 2
\[
\int \frac{6x^2}{x^6+2x^3+2}dx
\]\[
\int -\sin(2\theta)\cos(\theta)d\theta
\]\[
\int_{0}^{5}\sin(\frac{\pi}2 \lfloor{x}\rfloor x) dx
\]\[
\int_{0}^{1} \frac{\sin^{-1}(\sqrt{x})^2}{\sqrt{x-x^2}}dx
\]\[
\int\left(\cot(\theta)+\tan(\theta)\right)^2\cot(2\theta)^{100}d\theta
\]
Bonanza Round (ie Fun/Hard/Weird Problems) (In No Particular Order)
\[
\int \ln\left\{\sqrt[7]{x}^\frac1{\ln\left\{\sqrt[5]{x}^\frac1{\ln\left\{\sqrt[3]{x}^\frac1{\ln\left\{\sqrt{x}\right\}}\right\}}\right\}}\right\}dx
\]\[\int_{1}^{{e}^{\pi}} \cos(\ln(\sqrt{u}))du\]\[
\int_e^{\infty}\frac {1-x\ln{x}}{xe^x}dx
\]\[\int_{0}^{1}\frac{e^{x}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{1}}}}\times\frac{e^{-\frac{x^{2}}{2}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{2}}}}\times\frac{e^{\frac{x^{3}}{3}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{3}}}}\times\frac{e^{-\frac{x^{4}}{4}}}{\left(x^{2}+3x+2\right)^{\frac{1}{2^{4}}}} \ldots \,dx\]
For $x$ on the domain $-0.2025\leq x\leq 0.2025$ it is known that \[\displaystyle f(x)=\sin\left(\int_{0}^x \sqrt[3]{\cos\left(\frac{\pi}{2} t\right)^3+26}\ dt\right)\]is invertible. What is $\displaystyle (f^{-1})'(0)$?
This post has been edited 1 time. Last edited by Riemann123, Apr 11, 2025, 2:14 PM
Reason: Forgot a problem
Z K Y
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centslordm
4787 posts
#2 • 9 Y
Y by DeedSpeed, clarkculus, mygoodfriendusesaops, greenturtle3141, aidan0626, geodash2, scannose, jkim0656, ShrewdBunny
I can personally attest to the.
Z K Y
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3ch03s
1326 posts
#3 • 2 Y
Y by centslordm, clarkculus
Easier division 1.1:



Harder Division 1.1



Harder Division 2.1

:

Bonanza Round 5

Regards
Claudio.
Z K Y
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clarkculus
248 posts
#4 • 4 Y
Y by centslordm, mygoodfriendusesaops, Riemann123, geodash2
How so orz (major props to @Riemann123 for creating and running the event! super fun)

Bonanza 1

Bonanza 2

Bonanza 3

Bonanza 4
This post has been edited 5 times. Last edited by clarkculus, Apr 11, 2025, 11:27 PM
Z K Y
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clarkculus
248 posts
#5 • 3 Y
Y by Riemann123, centslordm, geodash2
Warmup 1

Warmup 2

Warmup 3

Warmup 4

Warmup 5

Warmup 6
This post has been edited 3 times. Last edited by clarkculus, Apr 11, 2025, 4:59 PM
Z K Y
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clarkculus
248 posts
#6 • 2 Y
Y by centslordm, geodash2
Easy 1.2

Easy 1.3

Easy 1.4

Easy 1.5
This post has been edited 3 times. Last edited by clarkculus, Apr 12, 2025, 2:27 AM
Z K Y
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aidan0626
1962 posts
#7 • 2 Y
Y by centslordm, clarkculus
Easy 1
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clarkculus
248 posts
#8 • 1 Y
Y by centslordm
Easy 2.1

Easy 2.2

Easy 2.3

Easy 2.4

Easy 2.5
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aidan0626
1962 posts
#9 • 2 Y
Y by centslordm, clarkculus
hard 1 is troll
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maxamc
585 posts
#10 • 2 Y
Y by centslordm, clarkculus
aidan0626 wrote:
hard 1 is troll

Agreed.

sol
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soryn
5348 posts
#11 • 2 Y
Y by centslordm, clarkculus
Good for preparing for an admission....Thx!
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Hobz
9 posts
#12 • 2 Y
Y by centslordm, clarkculus
This was vary awseom.
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jkim0656
1070 posts
#13 • 1 Y
Y by clarkculus
centslordm wrote:
I can personally attest to the.

yoo centzy
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mygoodfriendusesaops
11 posts
#14 • 1 Y
Y by centslordm
I really like geo dash2 !!!! !! !

(thank you to setters i enjoyed being too dumb to solve the integrals but knowledgeable enough to understand the sols....)
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