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k a July Highlights and 2025 AoPS Online Class Information
jwelsh   0
Jul 1, 2025
We are halfway through summer, so be sure to carve out some time to keep your skills sharp and explore challenging topics at AoPS Online and our AoPS Academies (including the Virtual Campus)!

[list][*]Over 60 summer classes are starting at the Virtual Campus on July 7th - check out the math and language arts options for middle through high school levels.
[*]At AoPS Online, we have accelerated sections where you can complete a course in half the time by meeting twice/week instead of once/week, starting on July 8th:
[list][*]MATHCOUNTS/AMC 8 Basics
[*]MATHCOUNTS/AMC 8 Advanced
[*]AMC Problem Series[/list]
[*]Plus, AoPS Online has a special seminar July 14 - 17 that is outside the standard fare: Paradoxes and Infinity
[*]We are expanding our in-person AoPS Academy locations - are you looking for a strong community of problem solvers, exemplary instruction, and math and language arts options? Look to see if we have a location near you and enroll in summer camps or academic year classes today! New locations include campuses in California, Georgia, New York, Illinois, and Oregon and more coming soon![/list]

MOP (Math Olympiad Summer Program) just ended and the IMO (International Mathematical Olympiad) is right around the corner! This year’s IMO will be held in Australia, July 10th - 20th. Congratulations to all the MOP students for reaching this incredible level and best of luck to all selected to represent their countries at this year’s IMO! Did you know that, in the last 10 years, 59 USA International Math Olympiad team members have medaled and have taken over 360 AoPS Online courses. Take advantage of our Worldwide Online Olympiad Training (WOOT) courses
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Are you tired of the heat and thinking about Fall? You can plan your Fall schedule now with classes at either AoPS Online, AoPS Academy Virtual Campus, or one of our AoPS Academies around the US.

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0 replies
jwelsh
Jul 1, 2025
0 replies
Exponential Integral as density
MrReq   0
a minute ago
Show that the function
\[
f(x)=
    \begin{cases}
      \displaystyle\int_{x}^{\infty}\! u^{-1}e^{-u}\,du, & x>0,\\[6pt]
      0, & x\le 0
    \end{cases}
\]is a probability density. Determine its characteristic function and give its power–series expansion.
0 replies
MrReq
a minute ago
0 replies
Putnam 2014 A4
Kent Merryfield   40
N an hour ago by GreenKeeper
Suppose $X$ is a random variable that takes on only nonnegative integer values, with $E[X]=1,$ $E[X^2]=2,$ and $E[X^3]=5.$ (Here $E[Y]$ denotes the expectation of the random variable $Y.$) Determine the smallest possible value of the probability of the event $X=0.$
40 replies
Kent Merryfield
Dec 7, 2014
GreenKeeper
an hour ago
Expected value of product of min and max
Kempu33334   0
2 hours ago
Source: Own
Let $n$ variables $X_1$, $X_2$, $\cdots$, $X_n$ be chosen uniformly at random in the range $[0,1]$. Show that the value of \[\mathbb{E}(\min(X)\cdot \max(X)) = \dfrac{1}{n+2}.\]I'm pretty sure this requires calculus (although would love a non-calculus based proof), hence why I posted in College Math.
0 replies
Kempu33334
2 hours ago
0 replies
The order of subgroup divide the degree of representation
samuelnagata   1
N 2 hours ago by Doru2718
Let $G$ be a finite group, $H$ a subgroup of $G$ and $\chi$ a character of a $G$-representation such that $\chi(h)=0,\forall h\in H, h\neq1$. Prove that the order of $H$ divides $\chi(1)$. I don't know many things about group representations. So any idea is useful.
1 reply
samuelnagata
Jan 1, 2017
Doru2718
2 hours ago
Trigonometry equation practice
ehz2701   26
N 5 hours ago by vanstraelen
There is a lack of trigonometric bash practice, and I want to see techniques to do these problems. So here are 10 kinds of problems that are usually out in the wild. How do you tackle these problems? (I had ChatGPT write a code for this.). Please give me some general techniques to solve these kinds of problems, especially set 2b. I’ll add more later.

Leaderboard and Solved Problems

problem set 1a (1-10)

problem set 2a (1-20)

problem set 2b (1-20)
answers 2b

General techniques so far:

Trick 1: one thing to keep in mind is

[center] $\frac{1}{2} = \cos 36 - \sin 18$. [/center]

Many of these seem to be reducible to this. The half can be written as $\cos 60 = \sin 30$, and $\cos 36 = \sin 54$, $\sin 18 = \cos 72$. This is proven in solution 1a-1. We will refer to this as Trick 1.
26 replies
ehz2701
Jul 12, 2025
vanstraelen
5 hours ago
Find the value of angle C
markosa   12
N 5 hours ago by sunken rock
Given a triangle ABC with base BC

angle B = 3x
angle C = x
AP is the bisector of base BC (i.e.) BP = PC
angle APB = 45 degrees

Find x

I know there are multiple methods to solve this problem using cosine law, coord geo
But is there any pure geometrical solution?
12 replies
markosa
Yesterday at 12:45 PM
sunken rock
5 hours ago
10 Problems
Sedro   57
N Today at 3:25 PM by Sedro
Title says most of it. I've been meaning to post a problem set on HSM since at least a few months ago, but since I proposed the most recent problems I made to the 2025 SSMO, I had to wait for that happen. (Hence, most of these problems will probably be familiar if you participated in that contest, though numbers and wording may be changed.) The problems are very roughly arranged by difficulty. Enjoy!

Problem 1: An sequence of positive integers $u_1, u_2, \dots, u_8$ has the property for every positive integer $n\le 8$, its $n^\text{th}$ term is greater than the mean of the first $n-1$ terms, and the sum of its first $n$ terms is a multiple of $n$. Let $S$ be the number of such sequences satisfying $u_1+u_2+\cdots + u_8 = 144$. Compute the remainder when $S$ is divided by $1000$.

Problem 2 (solved by fruitmonster97): Rhombus $PQRS$ has side length $3$. Point $X$ lies on segment $PR$ such that line $QX$ is perpendicular to line $PS$. Given that $QX=2$, the area of $PQRS$ can be expressed as $\tfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Compute $m+n$.

Problem 3 (solved by Math-lover1): Positive integers $a$ and $b$ satisfy $a\mid b^2$, $b\mid a^3$, and $a^3b^2 \mid 2025^{36}$. If the number of possible ordered pairs $(a,b)$ is equal to $N$, compute the remainder when $N$ is divided by $1000$.

Problem 4 (solved by CubeAlgo15): Let $ABC$ be a triangle. Point $P$ lies on side $BC$, point $Q$ lies on side $AB$, and point $R$ lies on side $AC$ such that $PQ=BQ$, $CR=PR$, and $\angle APB<90^\circ$. Let $H$ be the foot of the altitude from $A$ to $BC$. Given that $BP=3$, $CP=5$, and $[AQPR] = \tfrac{3}{7} \cdot [ABC]$, the value of $BH\cdot CH$ can be expressed as $\tfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Compute $m+n$.

Problem 5 (solved by maromex): Anna has a three-term arithmetic sequence of integers. She divides each term of her sequence by a positive integer $n>1$ and tells Bob that the three resulting remainders are $20$, $52$, and $R$, in some order. For how many values of $R$ is it possible for Bob to uniquely determine $n$?

Problem 6 (solved by Mathsll-enjoy): There is a unique ordered triple of positive reals $(x,y,z)$ satisfying the system of equations \begin{align*} x^2 + 9 &= (y-\sqrt{192})^2 + 4 \\ y^2 + 4 &= (z-\sqrt{192})^2 + 49 \\ z^2 + 49 &= (x-\sqrt{192})^2 + 9. \end{align*}The value of $100x+10y+z$ can be expressed as $p\sqrt{q}$, where $p$ and $q$ are positive integers such that $q$ is square-free. Compute $p+q$.

Problem 7 (solved by sami1618): Let $S$ be the set of all monotonically increasing six-term sequences whose terms are all integers between $0$ and $6$ inclusive. We say a sequence $s=n_1, n_2, \dots, n_6$ in $S$ is symmetric if for every integer $1\le i \le 6$, the number of terms of $s$ that are at least $i$ is $n_{7-i}$. The probability that a randomly chosen element of $S$ is symmetric is $\tfrac{p}{q}$, where $p$ and $q$ are relatively prime positive integers. Compute $p+q$.

Problem 8: For a positive integer $n$, let $r(n)$ denote the value of the binary number obtained by reading the binary representation of $n$ from right to left. Find the smallest positive integer $k$ such that the equation $n+r(n)=2k$ has at least ten positive integer solutions $n$.

Problem 9 (solved by Math-lover1, sami1618): Let $p$ be a quadratic polynomial with a positive leading coefficient. There exists a positive real number $r$ such that $r < 1 < \tfrac{5}{2r} < 5$ and $p(p(x)) = x$ for $x \in \{ r,1,  \tfrac{5}{2r} , 5\}$. Compute $p(20)$.

Problem 10 (solved by aaravdodhia, sami1618): Find the number of ordered triples of positive integers $(a,b,c)$ such that $a+b+c=995$ and $ab+bc+ca$ is a multiple of $995$.
57 replies
Sedro
Jul 10, 2025
Sedro
Today at 3:25 PM
Trigonometry prove
Studying_geometry   2
N Today at 2:39 PM by CuriousMathBoy72
Prove that $ sin36^\circ - cos18^\circ = \frac{1}{2} $
2 replies
Studying_geometry
Today at 2:18 PM
CuriousMathBoy72
Today at 2:39 PM
PROVINCIAL MATHEMATICS 9 MATH QUESTIONS FOR REFERENCE
tuananh_vvvbb   0
Today at 1:33 PM
Hello friends, I would like to share with you a reference to an HSG question for me to get a score of 70% or more, which is quite difficult. Readers, please refer to me for an explanation. Thank you all very much. Good health.
0 replies
tuananh_vvvbb
Today at 1:33 PM
0 replies
Inequalitis
sqing   11
N Today at 10:07 AM by sqing
Let $ a,b,c\geq  0 , a^2+b^2+c^2 =3.$ Prove that
$$a^3 +b^3 +c^3 +\frac{11}{5}abc  \leq \frac{26}{5}$$
11 replies
sqing
May 31, 2025
sqing
Today at 10:07 AM
Inequalities of integers
nhathhuyyp5c   3
N Today at 9:07 AM by Pal702004
Let $m,n$ be positive integers, $m$ is even such that $\sqrt{2}<\dfrac{m}{n}<\sqrt{2}+\dfrac{1}{2}$. Prove that there exist positive integers $k,l$ satisfying $$\left|\frac{k}{l}-\sqrt{2}\right|<\frac{m}{n}-\sqrt{2}.$$
3 replies
nhathhuyyp5c
Jun 14, 2025
Pal702004
Today at 9:07 AM
Inequalities
sqing   5
N Today at 8:05 AM by sqing
Let $ a,b,c\geq 0, \frac{1}{1+a}+\frac{1}{1+b}+\frac{1}{1+c}=\frac{3}{2}.$ Prove that
$$ \left(a+b+c-\frac{17}{6}\right)^2+9abc   \geq\frac{325}{36}$$$$   \left(a+b+c-\frac{5}{2}\right)^2+12abc \geq\frac{49}{4}$$$$\left(a+b+c-\frac{14}{5}\right)^2+\frac{49}{5}abc \geq\frac{49}{5}$$
5 replies
sqing
Jun 30, 2025
sqing
Today at 8:05 AM
x+y+z+1/x+1/y+1/z=0
nhathhuyyp5c   1
N Today at 7:48 AM by sqing
Let $x,y,z$ be reals such that $|x|,|y|,|z|\geq1$ and $x+y+z+\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=0$. Find $\max P=x+y+z$.
1 reply
nhathhuyyp5c
Today at 6:38 AM
sqing
Today at 7:48 AM
On a generalization of a^3+b^3+c^3-3abc
Sivin   1
N Today at 4:05 AM by Sivin
We note that $x_1^2+x_2^2-2x_1x_2=(x_1-x_2)^2$ and
$${x_1^3+x_2^3+x_3^3-3x_1x_2x_3=(x_1+x_2+x_3)(x_1^2+x_2^2+x_3^2-x_1x_2-x_2x_3-x_3x_1)}$$are reducible polynomials in $\mathbb{C}.$ However, $x_1^4+x_2^4+x_3^4+x_4^4-4x_1x_2x_3x_4$ is an irreducible polynomial in $\mathbb{C}.$ So what are all the $n$ such that the polynomial:
$$f_n(x_1,x_2,\dots,x_n)=x_1^n+x_2^n+\dots+x_n^n-nx_1x_2\dots x_n$$is reducible in $\mathbb{C}$?
1 reply
Sivin
Dec 3, 2024
Sivin
Today at 4:05 AM
Linear Space Decomposition
Suan_16   1
N May 8, 2025 by loup blanc
Let $A$ be a linear transformation on linear space $V$ satisfying:$$A^l=0$$but $$A^{l-1} \neq 0$$, and $V_0$ is the eigensubspace of eigenvalue $0$. Prove that $V$ can be decomposed to $dim V_0$ $A$-cyclic subspace's direct sum.

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1 reply
Suan_16
Apr 18, 2025
loup blanc
May 8, 2025
Linear Space Decomposition
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Suan_16
67 posts
#1
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Let $A$ be a linear transformation on linear space $V$ satisfying:$$A^l=0$$but $$A^{l-1} \neq 0$$, and $V_0$ is the eigensubspace of eigenvalue $0$. Prove that $V$ can be decomposed to $dim V_0$ $A$-cyclic subspace's direct sum.

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This post has been edited 1 time. Last edited by Suan_16, Apr 18, 2025, 12:46 PM
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loup blanc
3630 posts
#2
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Assume that $dim(V)=6$ and $dim(\ker(A))=3,dim(\ker(A^2))=5,dim(\ker(A^3))=6$.
Let $u$ be a basis of a complementary of $\ker(A^2)$ in $V$.
Let $Au,v$ be a basis of a complementary of $\ker(A)$ in $\ker(A^2)$.
Let $A^2u,Av,w$ be a basis of $\ker(A)$.
Now $V=E\oplus F\oplus G$, where $E=span(A^2u,Au,u),F=span(Av,v),G=span(w)$.
The matrix of $A$ associated to this basis is $diag(J_3,J_2,J_1)$, where $J_k$ is the nilpotent Jordan block of dimension $k$.
Each Jordan block is cyclic by construction; moreover, the number of Jordan blocks is -as asked- equal to $dim(\ker(A))$.
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